Tuples indexing in python
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I am trying to to put json data into a tuple and print it.
dict_all = json.loads(jsonFormat)
index = 0
for data in dict_all:
key = tuple((dict_all[index]['package_size_code'],
dict_all[index]['fda_ther_equiv_code'],
dict_all[index]['fda_application_number'],
dict_all[index]['clotting_factor_indicator'],
dict_all[index]['year'],
dict_all[index]['fda_product_name'],
dict_all[index]['labeler_name'],
...
index = index + 1
print(key)
The output is:
('60', 'NR', '204153', 'N', '2018', 'LUZU Cream 1% 60gm', 'MEDICIS DERMATOLOGICS, INC.', '99207085060', '0850', 'GM', '2013-11-14T00:00:00', '2014-03-14T00:00:00', 'N', '2014-03-14T00:00:00', '60000', '99207', '1', 'S', '2', '3')
('60', 'AB', '21758', 'N', '2018', 'VANOS CREAM .1%', 'MEDICIS DERMATOLOGICS, INC.', '99207052560', '0525', 'GM', '2005-02-11T00:00:00', '2005-02-21T00:00:00', 'N', '2005-02-21T00:00:00', '60000', '99207', '1', 'I', '2', '3')
....
Seems fine so far. But when I try to print key[0], I get values:
60
60
...
Shouldn't it be:
('60', 'NR', '204153', 'N', '2018', 'LUZU Cream 1% 60gm', 'MEDICIS DERMATOLOGICS, INC.', '99207085060', '0850', 'GM', '2013-11-14T00:00:00', '2014-03-14T00:00:00', 'N', '2014-03-14T00:00:00', '60000', '99207', '1', 'S', '2', '3')
One row is a element in the tuple. I would like it to be as shown above. Not sure where I am going wrong.
python python-3.x
asked Nov 16 '18 at 13:45
Avinash PrabhakarAvinash Prabhakar
13413
|
show 1 more comment
0
I am trying to to put json data into a tuple and print it.
dict_all = json.loads(jsonFormat)
index = 0
for data in dict_all:
key = tuple((dict_all[index]['package_size_code'],
dict_all[index]['fda_ther_equiv_code'],
dict_all[index]['fda_application_number'],
dict_all[index]['clotting_factor_indicator'],
dict_all[index]['year'],
dict_all[index]['fda_product_name'],
dict_all[index]['labeler_name'],
...
index = index + 1
print(key)
The output is:
('60', 'NR', '204153', 'N', '2018', 'LUZU Cream 1% 60gm', 'MEDICIS DERMATOLOGICS, INC.', '99207085060', '0850', 'GM', '2013-11-14T00:00:00', '2014-03-14T00:00:00', 'N', '2014-03-14T00:00:00', '60000', '99207', '1', 'S', '2', '3')
('60', 'AB', '21758', 'N', '2018', 'VANOS CREAM .1%', 'MEDICIS DERMATOLOGICS, INC.', '99207052560', '0525', 'GM', '2005-02-11T00:00:00', '2005-02-21T00:00:00', 'N', '2005-02-21T00:00:00', '60000', '99207', '1', 'I', '2', '3')
....
Seems fine so far. But when I try to print key[0], I get values:
60
60
...
Shouldn't it be:
('60', 'NR', '204153', 'N', '2018', 'LUZU Cream 1% 60gm', 'MEDICIS DERMATOLOGICS, INC.', '99207085060', '0850', 'GM', '2013-11-14T00:00:00', '2014-03-14T00:00:00', 'N', '2014-03-14T00:00:00', '60000', '99207', '1', 'S', '2', '3')
One row is a element in the tuple. I would like it to be as shown above. Not sure where I am going wrong.
python python-3.x
asked Nov 16 '18 at 13:45
Avinash PrabhakarAvinash Prabhakar
13413
1
keyis just a single tuple - you see several because you callprint(key)for each index! Usingkey[0]gets you the first element of the key tuple, but again once for each index.
– MisterMiyagi
Nov 16 '18 at 13:48
You are not saving yourkeyvariable anywhere. You just overwrite it each time round the loop.
– quamrana
Nov 16 '18 at 13:48
No,keyis first('60', 'NR', '204153', ...)and you dokey[0]which is60. Next time,keyis the next tuple andkey[0]is still60.
– Austin
Nov 16 '18 at 13:48
Ohhh the print placed in the loop confused me. I thought it was outside. Still not used to python synthax.
– Avinash Prabhakar
Nov 16 '18 at 13:50
1
Actually, the print you've provided here is outside the loop, so this code should have only printed the last value ofkey.
– glibdud
Nov 16 '18 at 13:51
|
show 1 more comment
0
0
0
I am trying to to put json data into a tuple and print it.
dict_all = json.loads(jsonFormat)
index = 0
for data in dict_all:
key = tuple((dict_all[index]['package_size_code'],
dict_all[index]['fda_ther_equiv_code'],
dict_all[index]['fda_application_number'],
dict_all[index]['clotting_factor_indicator'],
dict_all[index]['year'],
dict_all[index]['fda_product_name'],
dict_all[index]['labeler_name'],
...
index = index + 1
print(key)
The output is:
('60', 'NR', '204153', 'N', '2018', 'LUZU Cream 1% 60gm', 'MEDICIS DERMATOLOGICS, INC.', '99207085060', '0850', 'GM', '2013-11-14T00:00:00', '2014-03-14T00:00:00', 'N', '2014-03-14T00:00:00', '60000', '99207', '1', 'S', '2', '3')
('60', 'AB', '21758', 'N', '2018', 'VANOS CREAM .1%', 'MEDICIS DERMATOLOGICS, INC.', '99207052560', '0525', 'GM', '2005-02-11T00:00:00', '2005-02-21T00:00:00', 'N', '2005-02-21T00:00:00', '60000', '99207', '1', 'I', '2', '3')
....
Seems fine so far. But when I try to print key[0], I get values:
60
60
...
Shouldn't it be:
('60', 'NR', '204153', 'N', '2018', 'LUZU Cream 1% 60gm', 'MEDICIS DERMATOLOGICS, INC.', '99207085060', '0850', 'GM', '2013-11-14T00:00:00', '2014-03-14T00:00:00', 'N', '2014-03-14T00:00:00', '60000', '99207', '1', 'S', '2', '3')
One row is a element in the tuple. I would like it to be as shown above. Not sure where I am going wrong.
python python-3.x
asked Nov 16 '18 at 13:45
Avinash PrabhakarAvinash Prabhakar
13413
I am trying to to put json data into a tuple and print it.
dict_all = json.loads(jsonFormat)
index = 0
for data in dict_all:
key = tuple((dict_all[index]['package_size_code'],
dict_all[index]['fda_ther_equiv_code'],
dict_all[index]['fda_application_number'],
dict_all[index]['clotting_factor_indicator'],
dict_all[index]['year'],
dict_all[index]['fda_product_name'],
dict_all[index]['labeler_name'],
...
index = index + 1
print(key)
The output is:
('60', 'NR', '204153', 'N', '2018', 'LUZU Cream 1% 60gm', 'MEDICIS DERMATOLOGICS, INC.', '99207085060', '0850', 'GM', '2013-11-14T00:00:00', '2014-03-14T00:00:00', 'N', '2014-03-14T00:00:00', '60000', '99207', '1', 'S', '2', '3')
('60', 'AB', '21758', 'N', '2018', 'VANOS CREAM .1%', 'MEDICIS DERMATOLOGICS, INC.', '99207052560', '0525', 'GM', '2005-02-11T00:00:00', '2005-02-21T00:00:00', 'N', '2005-02-21T00:00:00', '60000', '99207', '1', 'I', '2', '3')
....
Seems fine so far. But when I try to print key[0], I get values:
60
60
...
Shouldn't it be:
('60', 'NR', '204153', 'N', '2018', 'LUZU Cream 1% 60gm', 'MEDICIS DERMATOLOGICS, INC.', '99207085060', '0850', 'GM', '2013-11-14T00:00:00', '2014-03-14T00:00:00', 'N', '2014-03-14T00:00:00', '60000', '99207', '1', 'S', '2', '3')
One row is a element in the tuple. I would like it to be as shown above. Not sure where I am going wrong.
python python-3.x
python python-3.x
asked Nov 16 '18 at 13:45
Avinash PrabhakarAvinash Prabhakar
13413
asked Nov 16 '18 at 13:45
Avinash PrabhakarAvinash Prabhakar
13413
asked Nov 16 '18 at 13:45
Avinash PrabhakarAvinash Prabhakar
13413
asked Nov 16 '18 at 13:45
Avinash PrabhakarAvinash Prabhakar
13413
asked Nov 16 '18 at 13:45
Avinash PrabhakarAvinash Prabhakar
13413
13413
1
keyis just a single tuple - you see several because you callprint(key)for each index! Usingkey[0]gets you the first element of the key tuple, but again once for each index.
– MisterMiyagi
Nov 16 '18 at 13:48
You are not saving yourkeyvariable anywhere. You just overwrite it each time round the loop.
– quamrana
Nov 16 '18 at 13:48
No,keyis first('60', 'NR', '204153', ...)and you dokey[0]which is60. Next time,keyis the next tuple andkey[0]is still60.
– Austin
Nov 16 '18 at 13:48
Ohhh the print placed in the loop confused me. I thought it was outside. Still not used to python synthax.
– Avinash Prabhakar
Nov 16 '18 at 13:50
1
Actually, the print you've provided here is outside the loop, so this code should have only printed the last value ofkey.
– glibdud
Nov 16 '18 at 13:51
|
show 1 more comment
1
keyis just a single tuple - you see several because you callprint(key)for each index! Usingkey[0]gets you the first element of the key tuple, but again once for each index.
– MisterMiyagi
Nov 16 '18 at 13:48
You are not saving yourkeyvariable anywhere. You just overwrite it each time round the loop.
– quamrana
Nov 16 '18 at 13:48
No,keyis first('60', 'NR', '204153', ...)and you dokey[0]which is60. Next time,keyis the next tuple andkey[0]is still60.
– Austin
Nov 16 '18 at 13:48
Ohhh the print placed in the loop confused me. I thought it was outside. Still not used to python synthax.
– Avinash Prabhakar
Nov 16 '18 at 13:50
1
Actually, the print you've provided here is outside the loop, so this code should have only printed the last value ofkey.
– glibdud
Nov 16 '18 at 13:51
1
1
key is just a single tuple - you see several because you call print(key) for each index! Using key[0] gets you the first element of the key tuple, but again once for each index.– MisterMiyagi
Nov 16 '18 at 13:48
key is just a single tuple - you see several because you call print(key) for each index! Using key[0] gets you the first element of the key tuple, but again once for each index.– MisterMiyagi
Nov 16 '18 at 13:48
You are not saving your
key variable anywhere. You just overwrite it each time round the loop.– quamrana
Nov 16 '18 at 13:48
You are not saving your
key variable anywhere. You just overwrite it each time round the loop.– quamrana
Nov 16 '18 at 13:48
No,
key is first ('60', 'NR', '204153', ...) and you do key[0] which is 60. Next time, key is the next tuple and key[0] is still 60.– Austin
Nov 16 '18 at 13:48
No,
key is first ('60', 'NR', '204153', ...) and you do key[0] which is 60. Next time, key is the next tuple and key[0] is still 60.– Austin
Nov 16 '18 at 13:48
Ohhh the print placed in the loop confused me. I thought it was outside. Still not used to python synthax.
– Avinash Prabhakar
Nov 16 '18 at 13:50
Ohhh the print placed in the loop confused me. I thought it was outside. Still not used to python synthax.
– Avinash Prabhakar
Nov 16 '18 at 13:50
1
1
Actually, the print you've provided here is outside the loop, so this code should have only printed the last value of
key.– glibdud
Nov 16 '18 at 13:51
Actually, the print you've provided here is outside the loop, so this code should have only printed the last value of
key.– glibdud
Nov 16 '18 at 13:51
|
show 1 more comment
1 Answer
1
active
oldest
votes
1
You might have meant to do this:
dict_all = json.loads(jsonFormat)
index = 0
key =
for data in dict_all:
key.append(tuple((dict_all[index]['package_size_code'],
dict_all[index]['fda_ther_equiv_code'],
dict_all[index]['fda_application_number'],
dict_all[index]['clotting_factor_indicator'],
dict_all[index]['year'],
dict_all[index]['fda_product_name'],
dict_all[index]['labeler_name'],
...
)
index = index + 1
print(key)
print(key[0])
The key variable is now a list which above gets printed out once after the loop has finished. And as an example, prints the first element of the list.
answered Nov 16 '18 at 13:50
quamranaquamrana
13.6k74054
Thanks. I should have used list from the very beginning.
– Avinash Prabhakar
Nov 16 '18 at 13:53
I was actually trying to use tuple as Sqlite3 uses them for inserts but it looks like list itself is enough.
– Avinash Prabhakar
Nov 16 '18 at 13:58
So tuples are not needed at all. I am just doing what you did but without the tuple thing.
– Avinash Prabhakar
Nov 16 '18 at 13:59
add a comment |
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1
You might have meant to do this:
dict_all = json.loads(jsonFormat)
index = 0
key =
for data in dict_all:
key.append(tuple((dict_all[index]['package_size_code'],
dict_all[index]['fda_ther_equiv_code'],
dict_all[index]['fda_application_number'],
dict_all[index]['clotting_factor_indicator'],
dict_all[index]['year'],
dict_all[index]['fda_product_name'],
dict_all[index]['labeler_name'],
...
)
index = index + 1
print(key)
print(key[0])
The key variable is now a list which above gets printed out once after the loop has finished. And as an example, prints the first element of the list.
answered Nov 16 '18 at 13:50
quamranaquamrana
13.6k74054
Thanks. I should have used list from the very beginning.
– Avinash Prabhakar
Nov 16 '18 at 13:53
I was actually trying to use tuple as Sqlite3 uses them for inserts but it looks like list itself is enough.
– Avinash Prabhakar
Nov 16 '18 at 13:58
So tuples are not needed at all. I am just doing what you did but without the tuple thing.
– Avinash Prabhakar
Nov 16 '18 at 13:59
add a comment |
1
You might have meant to do this:
dict_all = json.loads(jsonFormat)
index = 0
key =
for data in dict_all:
key.append(tuple((dict_all[index]['package_size_code'],
dict_all[index]['fda_ther_equiv_code'],
dict_all[index]['fda_application_number'],
dict_all[index]['clotting_factor_indicator'],
dict_all[index]['year'],
dict_all[index]['fda_product_name'],
dict_all[index]['labeler_name'],
...
)
index = index + 1
print(key)
print(key[0])
The key variable is now a list which above gets printed out once after the loop has finished. And as an example, prints the first element of the list.
answered Nov 16 '18 at 13:50
quamranaquamrana
13.6k74054
Thanks. I should have used list from the very beginning.
– Avinash Prabhakar
Nov 16 '18 at 13:53
I was actually trying to use tuple as Sqlite3 uses them for inserts but it looks like list itself is enough.
– Avinash Prabhakar
Nov 16 '18 at 13:58
So tuples are not needed at all. I am just doing what you did but without the tuple thing.
– Avinash Prabhakar
Nov 16 '18 at 13:59
add a comment |
1
1
1
You might have meant to do this:
dict_all = json.loads(jsonFormat)
index = 0
key =
for data in dict_all:
key.append(tuple((dict_all[index]['package_size_code'],
dict_all[index]['fda_ther_equiv_code'],
dict_all[index]['fda_application_number'],
dict_all[index]['clotting_factor_indicator'],
dict_all[index]['year'],
dict_all[index]['fda_product_name'],
dict_all[index]['labeler_name'],
...
)
index = index + 1
print(key)
print(key[0])
The key variable is now a list which above gets printed out once after the loop has finished. And as an example, prints the first element of the list.
answered Nov 16 '18 at 13:50
quamranaquamrana
13.6k74054
You might have meant to do this:
dict_all = json.loads(jsonFormat)
index = 0
key =
for data in dict_all:
key.append(tuple((dict_all[index]['package_size_code'],
dict_all[index]['fda_ther_equiv_code'],
dict_all[index]['fda_application_number'],
dict_all[index]['clotting_factor_indicator'],
dict_all[index]['year'],
dict_all[index]['fda_product_name'],
dict_all[index]['labeler_name'],
...
)
index = index + 1
print(key)
print(key[0])
The key variable is now a list which above gets printed out once after the loop has finished. And as an example, prints the first element of the list.
answered Nov 16 '18 at 13:50
quamranaquamrana
13.6k74054
answered Nov 16 '18 at 13:50
quamranaquamrana
13.6k74054
answered Nov 16 '18 at 13:50
quamranaquamrana
13.6k74054
answered Nov 16 '18 at 13:50
quamranaquamrana
13.6k74054
13.6k74054
Thanks. I should have used list from the very beginning.
– Avinash Prabhakar
Nov 16 '18 at 13:53
I was actually trying to use tuple as Sqlite3 uses them for inserts but it looks like list itself is enough.
– Avinash Prabhakar
Nov 16 '18 at 13:58
So tuples are not needed at all. I am just doing what you did but without the tuple thing.
– Avinash Prabhakar
Nov 16 '18 at 13:59
add a comment |
Thanks. I should have used list from the very beginning.
– Avinash Prabhakar
Nov 16 '18 at 13:53
I was actually trying to use tuple as Sqlite3 uses them for inserts but it looks like list itself is enough.
– Avinash Prabhakar
Nov 16 '18 at 13:58
So tuples are not needed at all. I am just doing what you did but without the tuple thing.
– Avinash Prabhakar
Nov 16 '18 at 13:59
Thanks. I should have used list from the very beginning.
– Avinash Prabhakar
Nov 16 '18 at 13:53
Thanks. I should have used list from the very beginning.
– Avinash Prabhakar
Nov 16 '18 at 13:53
I was actually trying to use tuple as Sqlite3 uses them for inserts but it looks like list itself is enough.
– Avinash Prabhakar
Nov 16 '18 at 13:58
I was actually trying to use tuple as Sqlite3 uses them for inserts but it looks like list itself is enough.
– Avinash Prabhakar
Nov 16 '18 at 13:58
So tuples are not needed at all. I am just doing what you did but without the tuple thing.
– Avinash Prabhakar
Nov 16 '18 at 13:59
So tuples are not needed at all. I am just doing what you did but without the tuple thing.
– Avinash Prabhakar
Nov 16 '18 at 13:59
add a comment |
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1
keyis just a single tuple - you see several because you callprint(key)for each index! Usingkey[0]gets you the first element of the key tuple, but again once for each index.– MisterMiyagi
Nov 16 '18 at 13:48
You are not saving your
keyvariable anywhere. You just overwrite it each time round the loop.– quamrana
Nov 16 '18 at 13:48
No,
keyis first('60', 'NR', '204153', ...)and you dokey[0]which is60. Next time,keyis the next tuple andkey[0]is still60.– Austin
Nov 16 '18 at 13:48
Ohhh the print placed in the loop confused me. I thought it was outside. Still not used to python synthax.
– Avinash Prabhakar
Nov 16 '18 at 13:50
1
Actually, the print you've provided here is outside the loop, so this code should have only printed the last value of
key.– glibdud
Nov 16 '18 at 13:51