Merging 2 dictionaries having duplicate keys with linq

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How to merge 2 dictionaries of IDictionary<Guid, MyObject> where MyObject is a class instance?

IDictionary<Guid, MyObject> d1 = new Dictionary<Guid, MyObject>();

d1.Add(guid1, m1);

d1.Add(guid2, m2);

d1.Add(guid3, m3);

IDictionary<Guid, MyObject> d2 = new Dictionary<Guid, MyObject>();

d2.Add(guid2, m2);

d2.Add(guid3, m3);

d2.Add(guid4, m4);

IDictionary<Guid, MyObject> d3 = d1.Union(d2) ???

That in d3 there are the following entries:

guid1,m1

guid2,m2

guid3,m3

guid4,m4

edited Nov 21 '12 at 6:30

Mechanical snail

19.9k1074100

asked Aug 1 '11 at 19:13

Chesnokov Yuriy

75531529

duplicate of stackoverflow.com/questions/294138/merging-dictionaries-in-c

– hatchet
Aug 1 '11 at 19:22

sorry, I could not find my solutiion there

– Chesnokov Yuriy
Aug 1 '11 at 19:43

possible duplicate of Combine two Dictionaries with linq; more exact duplicate than the other one

– Mechanical snail
Nov 21 '12 at 6:31

add a comment |

How to merge 2 dictionaries of IDictionary<Guid, MyObject> where MyObject is a class instance?

IDictionary<Guid, MyObject> d1 = new Dictionary<Guid, MyObject>();

d1.Add(guid1, m1);

d1.Add(guid2, m2);

d1.Add(guid3, m3);

IDictionary<Guid, MyObject> d2 = new Dictionary<Guid, MyObject>();

d2.Add(guid2, m2);

d2.Add(guid3, m3);

d2.Add(guid4, m4);

IDictionary<Guid, MyObject> d3 = d1.Union(d2) ???

That in d3 there are the following entries:

guid1,m1

guid2,m2

guid3,m3

guid4,m4

edited Nov 21 '12 at 6:30

Mechanical snail

19.9k1074100

asked Aug 1 '11 at 19:13

Chesnokov Yuriy

75531529

duplicate of stackoverflow.com/questions/294138/merging-dictionaries-in-c

– hatchet
Aug 1 '11 at 19:22

sorry, I could not find my solutiion there

– Chesnokov Yuriy
Aug 1 '11 at 19:43

possible duplicate of Combine two Dictionaries with linq; more exact duplicate than the other one

– Mechanical snail
Nov 21 '12 at 6:31

add a comment |

How to merge 2 dictionaries of IDictionary<Guid, MyObject> where MyObject is a class instance?

IDictionary<Guid, MyObject> d1 = new Dictionary<Guid, MyObject>();

d1.Add(guid1, m1);

d1.Add(guid2, m2);

d1.Add(guid3, m3);

IDictionary<Guid, MyObject> d2 = new Dictionary<Guid, MyObject>();

d2.Add(guid2, m2);

d2.Add(guid3, m3);

d2.Add(guid4, m4);

IDictionary<Guid, MyObject> d3 = d1.Union(d2) ???

That in d3 there are the following entries:

guid1,m1

guid2,m2

guid3,m3

guid4,m4

edited Nov 21 '12 at 6:30

Mechanical snail

19.9k1074100

asked Aug 1 '11 at 19:13

Chesnokov Yuriy

75531529

How to merge 2 dictionaries of IDictionary<Guid, MyObject> where MyObject is a class instance?

IDictionary<Guid, MyObject> d1 = new Dictionary<Guid, MyObject>();

d1.Add(guid1, m1);

d1.Add(guid2, m2);

d1.Add(guid3, m3);

IDictionary<Guid, MyObject> d2 = new Dictionary<Guid, MyObject>();

d2.Add(guid2, m2);

d2.Add(guid3, m3);

d2.Add(guid4, m4);

IDictionary<Guid, MyObject> d3 = d1.Union(d2) ???

That in d3 there are the following entries:

guid1,m1

guid2,m2

guid3,m3

guid4,m4

c# linq dictionary merge

edited Nov 21 '12 at 6:30

Mechanical snail

19.9k1074100

asked Aug 1 '11 at 19:13

Chesnokov Yuriy

75531529

edited Nov 21 '12 at 6:30

Mechanical snail

19.9k1074100

asked Aug 1 '11 at 19:13

Chesnokov Yuriy

75531529

edited Nov 21 '12 at 6:30

Mechanical snail

19.9k1074100

edited Nov 21 '12 at 6:30

Mechanical snail

19.9k1074100

edited Nov 21 '12 at 6:30

Mechanical snail

19.9k1074100

asked Aug 1 '11 at 19:13

Chesnokov Yuriy

75531529

asked Aug 1 '11 at 19:13

Chesnokov Yuriy

75531529

asked Aug 1 '11 at 19:13

Chesnokov Yuriy

75531529

duplicate of stackoverflow.com/questions/294138/merging-dictionaries-in-c

– hatchet
Aug 1 '11 at 19:22

sorry, I could not find my solutiion there

– Chesnokov Yuriy
Aug 1 '11 at 19:43

possible duplicate of Combine two Dictionaries with linq; more exact duplicate than the other one

– Mechanical snail
Nov 21 '12 at 6:31

add a comment |

duplicate of stackoverflow.com/questions/294138/merging-dictionaries-in-c

– hatchet
Aug 1 '11 at 19:22

sorry, I could not find my solutiion there

– Chesnokov Yuriy
Aug 1 '11 at 19:43

possible duplicate of Combine two Dictionaries with linq; more exact duplicate than the other one

– Mechanical snail
Nov 21 '12 at 6:31

duplicate of stackoverflow.com/questions/294138/merging-dictionaries-in-c

– hatchet
Aug 1 '11 at 19:22

sorry, I could not find my solutiion there

– Chesnokov Yuriy
Aug 1 '11 at 19:43

possible duplicate of Combine two Dictionaries with linq; more exact duplicate than the other one

– Mechanical snail
Nov 21 '12 at 6:31

add a comment |

5 Answers
5

active

oldest

votes

d1.Concat(d2.Where( x=> !d1.Keys.Contains(x.Key)));

edited Nov 16 '18 at 13:42

croxy

2,95072039

answered Aug 1 '11 at 19:20

Eric H

1,2811814

1

thank you very much, that is the correct approach though leading processing of the concatenated set

– Chesnokov Yuriy
Aug 1 '11 at 19:37

@Eric This looks like a good solution. But, if I have IEnuemrable<Dictionary<Guid, MyObject>> colection, how can I match items?

– barteloma
Aug 17 '17 at 13:10

add a comment |

d1.Union(d2).GroupBy (kvp => kvp.Key).ToDictionary(kvp => kvp.Key, kvp => kvp.First().Value); out to do the trick.

IDictionary<Guid, MyObject> d1 = new Dictionary<Guid, MyObject>();

d1.Add(guid1, m1);

d1.Add(guid2, m2);

d1.Add(guid3, m3);

IDictionary<Guid, MyObject> d2 = new Dictionary<Guid, MyObject>();

d2.Add(guid2, m2);

d2.Add(guid3, m3);

d2.Add(guid4, m4);

IDictionary<Guid, MyObject> d3 = 

   d1.Union(d2).GroupBy (kvp => kvp.Key)

       .ToDictionary (kvp => kvp.Key, kvp => kvp.First ().Value);

edited Nov 23 '12 at 21:17

answered Aug 1 '11 at 19:20

agent-j

22.4k43973

thanks but I tried that and Union leads to Exception with 'An item with the same key has already been added'

– Chesnokov Yuriy
Aug 1 '11 at 19:32

I fixed it. ` IDictionary<Guid, MyObject> d3 = d1.Union(d2).GroupBy (kvp => kvp.Key) .ToDictionary (kvp => kvp.Key, kvp => kvp.First ().Value); `

– agent-j
Aug 1 '11 at 22:20

thank you very much, that works, how that line avoids duplicate keys? is that faster than d1.Concat(d2.Where(x => !d1.Keys.Contains(x.Key)))?

– Chesnokov Yuriy
Aug 2 '11 at 5:27

I tested that using Stopwatch, using of Concat is 3 time faster, SO DO NOT USE Union

– NET3
Nov 22 '12 at 23:00

1

Much more readable than accepted answer.

– nawfal
May 26 '16 at 12:40

add a comment |

You could try something like

d1.Concat(d2).Distinct(kv => kv.Key).ToDictionary(kv => kv.Key, kv => kv.Value)

The result of concat makes use of the fact that the dictionary is an IEnumerable<KeyvaluePair<Guid,MyObject>>

Since I do not have a compiler I just checked that Distinct cannot accept just a lambda selecting the property to be compared. However it can accept an EqualityComparer. What I often have in projects is a Generic Equality Comparer that allows to pass in lambdas which define the equality operation.

answered Aug 1 '11 at 19:18

flq

18.3k34469

yes, equality comparer is needed

– Chesnokov Yuriy
Aug 1 '11 at 19:39

add a comment |

When no duplicates keys exist, the following works for 2 (or more) dictionaries:

var dictionaries = new  { d1, d2 };

var result = dictionaries.SelectMany(dict => dict)

                     .ToDictionary(pair => pair.Key, pair => pair.Value);

answered Aug 1 '11 at 19:19

Chaim Zonnenberg

1,549119

1

ok, there are duplicates present

– Chesnokov Yuriy
Aug 1 '11 at 19:40

add a comment |

Union looks good:
http://msdn.microsoft.com/en-us/vcsharp/aa336761.aspx#union1

answered Aug 1 '11 at 19:26

Paul Nikonowicz

2,6431234

that does not work well with class instance in the value

– Chesnokov Yuriy
Aug 1 '11 at 19:35

add a comment |

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5 Answers
5

active

oldest

votes

5 Answers
5

active

oldest

votes

d1.Concat(d2.Where( x=> !d1.Keys.Contains(x.Key)));

edited Nov 16 '18 at 13:42

croxy

2,95072039

answered Aug 1 '11 at 19:20

Eric H

1,2811814

1

thank you very much, that is the correct approach though leading processing of the concatenated set

– Chesnokov Yuriy
Aug 1 '11 at 19:37

@Eric This looks like a good solution. But, if I have IEnuemrable<Dictionary<Guid, MyObject>> colection, how can I match items?

– barteloma
Aug 17 '17 at 13:10

add a comment |

d1.Concat(d2.Where( x=> !d1.Keys.Contains(x.Key)));

edited Nov 16 '18 at 13:42

croxy

2,95072039

answered Aug 1 '11 at 19:20

Eric H

1,2811814

1

thank you very much, that is the correct approach though leading processing of the concatenated set

– Chesnokov Yuriy
Aug 1 '11 at 19:37

@Eric This looks like a good solution. But, if I have IEnuemrable<Dictionary<Guid, MyObject>> colection, how can I match items?

– barteloma
Aug 17 '17 at 13:10

add a comment |

d1.Concat(d2.Where( x=> !d1.Keys.Contains(x.Key)));

edited Nov 16 '18 at 13:42

croxy

2,95072039

answered Aug 1 '11 at 19:20

Eric H

1,2811814

d1.Concat(d2.Where( x=> !d1.Keys.Contains(x.Key)));

edited Nov 16 '18 at 13:42

croxy

2,95072039

answered Aug 1 '11 at 19:20

Eric H

1,2811814

edited Nov 16 '18 at 13:42

croxy

2,95072039

edited Nov 16 '18 at 13:42

croxy

2,95072039

edited Nov 16 '18 at 13:42

croxy

2,95072039

answered Aug 1 '11 at 19:20

Eric H

1,2811814

answered Aug 1 '11 at 19:20

Eric H

1,2811814

answered Aug 1 '11 at 19:20

Eric H

1,2811814

1

thank you very much, that is the correct approach though leading processing of the concatenated set

– Chesnokov Yuriy
Aug 1 '11 at 19:37

@Eric This looks like a good solution. But, if I have IEnuemrable<Dictionary<Guid, MyObject>> colection, how can I match items?

– barteloma
Aug 17 '17 at 13:10

add a comment |

1

thank you very much, that is the correct approach though leading processing of the concatenated set

– Chesnokov Yuriy
Aug 1 '11 at 19:37

@Eric This looks like a good solution. But, if I have IEnuemrable<Dictionary<Guid, MyObject>> colection, how can I match items?

– barteloma
Aug 17 '17 at 13:10

thank you very much, that is the correct approach though leading processing of the concatenated set

– Chesnokov Yuriy
Aug 1 '11 at 19:37

@Eric This looks like a good solution. But, if I have IEnuemrable<Dictionary<Guid, MyObject>> colection, how can I match items?

– barteloma
Aug 17 '17 at 13:10

add a comment |

d1.Union(d2).GroupBy (kvp => kvp.Key).ToDictionary(kvp => kvp.Key, kvp => kvp.First().Value); out to do the trick.

IDictionary<Guid, MyObject> d1 = new Dictionary<Guid, MyObject>();

d1.Add(guid1, m1);

d1.Add(guid2, m2);

d1.Add(guid3, m3);

IDictionary<Guid, MyObject> d2 = new Dictionary<Guid, MyObject>();

d2.Add(guid2, m2);

d2.Add(guid3, m3);

d2.Add(guid4, m4);

IDictionary<Guid, MyObject> d3 = 

   d1.Union(d2).GroupBy (kvp => kvp.Key)

       .ToDictionary (kvp => kvp.Key, kvp => kvp.First ().Value);

edited Nov 23 '12 at 21:17

answered Aug 1 '11 at 19:20

agent-j

22.4k43973

thanks but I tried that and Union leads to Exception with 'An item with the same key has already been added'

– Chesnokov Yuriy
Aug 1 '11 at 19:32

I fixed it. ` IDictionary<Guid, MyObject> d3 = d1.Union(d2).GroupBy (kvp => kvp.Key) .ToDictionary (kvp => kvp.Key, kvp => kvp.First ().Value); `

– agent-j
Aug 1 '11 at 22:20

thank you very much, that works, how that line avoids duplicate keys? is that faster than d1.Concat(d2.Where(x => !d1.Keys.Contains(x.Key)))?

– Chesnokov Yuriy
Aug 2 '11 at 5:27

I tested that using Stopwatch, using of Concat is 3 time faster, SO DO NOT USE Union

– NET3
Nov 22 '12 at 23:00

1

Much more readable than accepted answer.

– nawfal
May 26 '16 at 12:40

add a comment |

d1.Union(d2).GroupBy (kvp => kvp.Key).ToDictionary(kvp => kvp.Key, kvp => kvp.First().Value); out to do the trick.

IDictionary<Guid, MyObject> d1 = new Dictionary<Guid, MyObject>();

d1.Add(guid1, m1);

d1.Add(guid2, m2);

d1.Add(guid3, m3);

IDictionary<Guid, MyObject> d2 = new Dictionary<Guid, MyObject>();

d2.Add(guid2, m2);

d2.Add(guid3, m3);

d2.Add(guid4, m4);

IDictionary<Guid, MyObject> d3 = 

   d1.Union(d2).GroupBy (kvp => kvp.Key)

       .ToDictionary (kvp => kvp.Key, kvp => kvp.First ().Value);

edited Nov 23 '12 at 21:17

answered Aug 1 '11 at 19:20

agent-j

22.4k43973

thanks but I tried that and Union leads to Exception with 'An item with the same key has already been added'

– Chesnokov Yuriy
Aug 1 '11 at 19:32

I fixed it. ` IDictionary<Guid, MyObject> d3 = d1.Union(d2).GroupBy (kvp => kvp.Key) .ToDictionary (kvp => kvp.Key, kvp => kvp.First ().Value); `

– agent-j
Aug 1 '11 at 22:20

thank you very much, that works, how that line avoids duplicate keys? is that faster than d1.Concat(d2.Where(x => !d1.Keys.Contains(x.Key)))?

– Chesnokov Yuriy
Aug 2 '11 at 5:27

I tested that using Stopwatch, using of Concat is 3 time faster, SO DO NOT USE Union

– NET3
Nov 22 '12 at 23:00

1

Much more readable than accepted answer.

– nawfal
May 26 '16 at 12:40

add a comment |

d1.Union(d2).GroupBy (kvp => kvp.Key).ToDictionary(kvp => kvp.Key, kvp => kvp.First().Value); out to do the trick.

IDictionary<Guid, MyObject> d1 = new Dictionary<Guid, MyObject>();

d1.Add(guid1, m1);

d1.Add(guid2, m2);

d1.Add(guid3, m3);

IDictionary<Guid, MyObject> d2 = new Dictionary<Guid, MyObject>();

d2.Add(guid2, m2);

d2.Add(guid3, m3);

d2.Add(guid4, m4);

IDictionary<Guid, MyObject> d3 = 

   d1.Union(d2).GroupBy (kvp => kvp.Key)

       .ToDictionary (kvp => kvp.Key, kvp => kvp.First ().Value);

edited Nov 23 '12 at 21:17

answered Aug 1 '11 at 19:20

agent-j

22.4k43973

d1.Union(d2).GroupBy (kvp => kvp.Key).ToDictionary(kvp => kvp.Key, kvp => kvp.First().Value); out to do the trick.

IDictionary<Guid, MyObject> d1 = new Dictionary<Guid, MyObject>();

d1.Add(guid1, m1);

d1.Add(guid2, m2);

d1.Add(guid3, m3);

IDictionary<Guid, MyObject> d2 = new Dictionary<Guid, MyObject>();

d2.Add(guid2, m2);

d2.Add(guid3, m3);

d2.Add(guid4, m4);

IDictionary<Guid, MyObject> d3 = 

   d1.Union(d2).GroupBy (kvp => kvp.Key)

       .ToDictionary (kvp => kvp.Key, kvp => kvp.First ().Value);

edited Nov 23 '12 at 21:17

answered Aug 1 '11 at 19:20

agent-j

22.4k43973

edited Nov 23 '12 at 21:17

answered Aug 1 '11 at 19:20

agent-j

22.4k43973

answered Aug 1 '11 at 19:20

agent-j

22.4k43973

answered Aug 1 '11 at 19:20

agent-j

22.4k43973

thanks but I tried that and Union leads to Exception with 'An item with the same key has already been added'

– Chesnokov Yuriy
Aug 1 '11 at 19:32

I fixed it. ` IDictionary<Guid, MyObject> d3 = d1.Union(d2).GroupBy (kvp => kvp.Key) .ToDictionary (kvp => kvp.Key, kvp => kvp.First ().Value); `

– agent-j
Aug 1 '11 at 22:20

thank you very much, that works, how that line avoids duplicate keys? is that faster than d1.Concat(d2.Where(x => !d1.Keys.Contains(x.Key)))?

– Chesnokov Yuriy
Aug 2 '11 at 5:27

I tested that using Stopwatch, using of Concat is 3 time faster, SO DO NOT USE Union

– NET3
Nov 22 '12 at 23:00

1

Much more readable than accepted answer.

– nawfal
May 26 '16 at 12:40

add a comment |

thanks but I tried that and Union leads to Exception with 'An item with the same key has already been added'

– Chesnokov Yuriy
Aug 1 '11 at 19:32

I fixed it. ` IDictionary<Guid, MyObject> d3 = d1.Union(d2).GroupBy (kvp => kvp.Key) .ToDictionary (kvp => kvp.Key, kvp => kvp.First ().Value); `

– agent-j
Aug 1 '11 at 22:20

thank you very much, that works, how that line avoids duplicate keys? is that faster than d1.Concat(d2.Where(x => !d1.Keys.Contains(x.Key)))?

– Chesnokov Yuriy
Aug 2 '11 at 5:27

I tested that using Stopwatch, using of Concat is 3 time faster, SO DO NOT USE Union

– NET3
Nov 22 '12 at 23:00

1

Much more readable than accepted answer.

– nawfal
May 26 '16 at 12:40

thanks but I tried that and Union leads to Exception with 'An item with the same key has already been added'

– Chesnokov Yuriy
Aug 1 '11 at 19:32

I fixed it. ` IDictionary<Guid, MyObject> d3 = d1.Union(d2).GroupBy (kvp => kvp.Key) .ToDictionary (kvp => kvp.Key, kvp => kvp.First ().Value); `

– agent-j
Aug 1 '11 at 22:20

thank you very much, that works, how that line avoids duplicate keys? is that faster than d1.Concat(d2.Where(x => !d1.Keys.Contains(x.Key)))?

– Chesnokov Yuriy
Aug 2 '11 at 5:27

I tested that using Stopwatch, using of Concat is 3 time faster, SO DO NOT USE Union

– NET3
Nov 22 '12 at 23:00

Much more readable than accepted answer.

– nawfal
May 26 '16 at 12:40

add a comment |

You could try something like

d1.Concat(d2).Distinct(kv => kv.Key).ToDictionary(kv => kv.Key, kv => kv.Value)

The result of concat makes use of the fact that the dictionary is an IEnumerable<KeyvaluePair<Guid,MyObject>>

answered Aug 1 '11 at 19:18

flq

18.3k34469

yes, equality comparer is needed

– Chesnokov Yuriy
Aug 1 '11 at 19:39

add a comment |

You could try something like

d1.Concat(d2).Distinct(kv => kv.Key).ToDictionary(kv => kv.Key, kv => kv.Value)

The result of concat makes use of the fact that the dictionary is an IEnumerable<KeyvaluePair<Guid,MyObject>>

answered Aug 1 '11 at 19:18

flq

18.3k34469

yes, equality comparer is needed

– Chesnokov Yuriy
Aug 1 '11 at 19:39

add a comment |

You could try something like

d1.Concat(d2).Distinct(kv => kv.Key).ToDictionary(kv => kv.Key, kv => kv.Value)

The result of concat makes use of the fact that the dictionary is an IEnumerable<KeyvaluePair<Guid,MyObject>>

answered Aug 1 '11 at 19:18

flq

18.3k34469

You could try something like

d1.Concat(d2).Distinct(kv => kv.Key).ToDictionary(kv => kv.Key, kv => kv.Value)

The result of concat makes use of the fact that the dictionary is an IEnumerable<KeyvaluePair<Guid,MyObject>>

answered Aug 1 '11 at 19:18

flq

18.3k34469

answered Aug 1 '11 at 19:18

flq

18.3k34469

answered Aug 1 '11 at 19:18

flq

18.3k34469

answered Aug 1 '11 at 19:18

flq

18.3k34469

yes, equality comparer is needed

– Chesnokov Yuriy
Aug 1 '11 at 19:39

add a comment |

yes, equality comparer is needed

– Chesnokov Yuriy
Aug 1 '11 at 19:39

yes, equality comparer is needed

– Chesnokov Yuriy
Aug 1 '11 at 19:39

add a comment |

When no duplicates keys exist, the following works for 2 (or more) dictionaries:

var dictionaries = new  { d1, d2 };

var result = dictionaries.SelectMany(dict => dict)

                     .ToDictionary(pair => pair.Key, pair => pair.Value);

answered Aug 1 '11 at 19:19

Chaim Zonnenberg

1,549119

1

ok, there are duplicates present

– Chesnokov Yuriy
Aug 1 '11 at 19:40

add a comment |

When no duplicates keys exist, the following works for 2 (or more) dictionaries:

var dictionaries = new  { d1, d2 };

var result = dictionaries.SelectMany(dict => dict)

                     .ToDictionary(pair => pair.Key, pair => pair.Value);

answered Aug 1 '11 at 19:19

Chaim Zonnenberg

1,549119

1

ok, there are duplicates present

– Chesnokov Yuriy
Aug 1 '11 at 19:40

add a comment |

When no duplicates keys exist, the following works for 2 (or more) dictionaries:

var dictionaries = new  { d1, d2 };

var result = dictionaries.SelectMany(dict => dict)

                     .ToDictionary(pair => pair.Key, pair => pair.Value);

answered Aug 1 '11 at 19:19

Chaim Zonnenberg

1,549119

When no duplicates keys exist, the following works for 2 (or more) dictionaries:

var dictionaries = new  { d1, d2 };

var result = dictionaries.SelectMany(dict => dict)

                     .ToDictionary(pair => pair.Key, pair => pair.Value);

answered Aug 1 '11 at 19:19

Chaim Zonnenberg

1,549119

answered Aug 1 '11 at 19:19

Chaim Zonnenberg

1,549119

answered Aug 1 '11 at 19:19

Chaim Zonnenberg

1,549119

answered Aug 1 '11 at 19:19

Chaim Zonnenberg

1,549119

1

ok, there are duplicates present

– Chesnokov Yuriy
Aug 1 '11 at 19:40

add a comment |

1

ok, there are duplicates present

– Chesnokov Yuriy
Aug 1 '11 at 19:40

ok, there are duplicates present

– Chesnokov Yuriy
Aug 1 '11 at 19:40

add a comment |

Union looks good:
http://msdn.microsoft.com/en-us/vcsharp/aa336761.aspx#union1

answered Aug 1 '11 at 19:26

Paul Nikonowicz

2,6431234

that does not work well with class instance in the value

– Chesnokov Yuriy
Aug 1 '11 at 19:35

add a comment |

Union looks good:
http://msdn.microsoft.com/en-us/vcsharp/aa336761.aspx#union1

answered Aug 1 '11 at 19:26

Paul Nikonowicz

2,6431234

that does not work well with class instance in the value

– Chesnokov Yuriy
Aug 1 '11 at 19:35

add a comment |

Union looks good:
http://msdn.microsoft.com/en-us/vcsharp/aa336761.aspx#union1

answered Aug 1 '11 at 19:26

Paul Nikonowicz

2,6431234

Union looks good:
http://msdn.microsoft.com/en-us/vcsharp/aa336761.aspx#union1

answered Aug 1 '11 at 19:26

Paul Nikonowicz

2,6431234

answered Aug 1 '11 at 19:26

Paul Nikonowicz

2,6431234

answered Aug 1 '11 at 19:26

Paul Nikonowicz

2,6431234

answered Aug 1 '11 at 19:26

Paul Nikonowicz

2,6431234

that does not work well with class instance in the value

– Chesnokov Yuriy
Aug 1 '11 at 19:35

add a comment |

that does not work well with class instance in the value

– Chesnokov Yuriy
Aug 1 '11 at 19:35

that does not work well with class instance in the value

– Chesnokov Yuriy
Aug 1 '11 at 19:35

add a comment |

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