How to sort and group and divide the array alphabetically in angular2+





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I want to display the content of the buttons according to the alphabetical order and divide them in groups like A-H, I-Q and R-Z. My code is written in angular2+.



Alphabetic division



My array is -



this.dropdownList = [
{ item_text: 'Organisation' },
{ item_text: 'EwayBill' },
{ item_text: 'SAP' },
{ item_text: 'Collection' },
{ item_text: 'Cancel' },
{ item_text: 'Generate' },
{ item_text: 'Payments' },
{ item_text: 'SMS' },
{ item_text: 'Update' }
]









share|improve this question































    0















    I want to display the content of the buttons according to the alphabetical order and divide them in groups like A-H, I-Q and R-Z. My code is written in angular2+.



    Alphabetic division



    My array is -



    this.dropdownList = [
    { item_text: 'Organisation' },
    { item_text: 'EwayBill' },
    { item_text: 'SAP' },
    { item_text: 'Collection' },
    { item_text: 'Cancel' },
    { item_text: 'Generate' },
    { item_text: 'Payments' },
    { item_text: 'SMS' },
    { item_text: 'Update' }
    ]









    share|improve this question



























      0












      0








      0








      I want to display the content of the buttons according to the alphabetical order and divide them in groups like A-H, I-Q and R-Z. My code is written in angular2+.



      Alphabetic division



      My array is -



      this.dropdownList = [
      { item_text: 'Organisation' },
      { item_text: 'EwayBill' },
      { item_text: 'SAP' },
      { item_text: 'Collection' },
      { item_text: 'Cancel' },
      { item_text: 'Generate' },
      { item_text: 'Payments' },
      { item_text: 'SMS' },
      { item_text: 'Update' }
      ]









      share|improve this question
















      I want to display the content of the buttons according to the alphabetical order and divide them in groups like A-H, I-Q and R-Z. My code is written in angular2+.



      Alphabetic division



      My array is -



      this.dropdownList = [
      { item_text: 'Organisation' },
      { item_text: 'EwayBill' },
      { item_text: 'SAP' },
      { item_text: 'Collection' },
      { item_text: 'Cancel' },
      { item_text: 'Generate' },
      { item_text: 'Payments' },
      { item_text: 'SMS' },
      { item_text: 'Update' }
      ]






      arrays angular sorting






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 16 '18 at 15:45









      James Z

      11.2k71936




      11.2k71936










      asked Nov 16 '18 at 13:37









      TechdiveTechdive

      223117




      223117
























          3 Answers
          3






          active

          oldest

          votes


















          2














          This is the solution I came up with. Can be optimised for the cases when we know that the letter ranges don't intersect.



          // some basic interfaces to describe types
          interface Item {
          item_text: string;
          }
          interface LetterRange {
          first: string;
          last: string;
          }

          // the letter ranges
          // this solution allows them to intersect
          // can adjust for any letter ranges
          const ranges: LetterRange = [
          {first: 'a', last: 'h'},
          {first: 'i', last: 'q'},
          {first: 'r', last: 'z'}
          ];


          const dropdownList: Item = [
          { item_text: 'Organisation' },
          { item_text: 'EwayBill' },
          { item_text: 'SAP' },
          { item_text: 'Collection' },
          { item_text: 'Cancel' },
          { item_text: 'Generate' },
          { item_text: 'Payments' },
          { item_text: 'SMS' },
          { item_text: 'Update' }
          ];

          // sort the words alphabetically so that they will appear in the right order
          const sorted: Item = dropdownList.sort((a,b) => a.item_text.localeCompare(b.item_text));

          // array of grouped items (each group is array as well)
          const grouped: Item = sorted.reduce((groups, item) => {
          const firstLetter: string = item.item_text.slice(0,1).toLowerCase();
          console.log(firstLetter);

          // run through each range and check whether the 'firstLetter' fits there
          ranges.forEach((range, index) => {
          if (firstLetter >= range.first.toLowerCase()
          && firstLetter <= range.last.toLowerCase()) {
          groups[index].push(item);
          }
          });
          return groups;
          }, new Array(ranges.length).fill()); // initialise with N empty arrays

          console.log(grouped);

          /*
          [
          [ { item_text: 'Cancel' },
          { item_text: 'Collection' },
          { item_text: 'EwayBill' },
          { item_text: 'Generate' }
          ],
          [
          { item_text: 'Organisation' },
          { item_text: 'Payments' }
          ],
          [ { item_text: 'SAP' },
          { item_text: 'SMS' },
          { item_text: 'Update' }
          ]
          ]
          */







          share|improve this answer

































            1














            Sort it with a compare function https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/sort



            dropdownList.sort(function (item1, item2) {
            if (item1.item_text < item2.item_text)
            return -1;
            if ( item1.item_text > item2.item_text)
            return 1;
            return 0;
            })


            or more simple:



            dropdownList.sort(function (item1, item2) {
            return ('' + item1.item_text).localeCompare(item2.item_text);
            })


            This is copy pasted with changes from https://stackoverflow.com/a/51169/7329611 with credits to Shog9



            After sorting you can slice the array into groups with the slice function https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/slice
            After sorting you should find the indexes of the first occurance of objects with the next higher alphabetical character and set these indexes as slice(from, to)
            So for the first step you have to find the first element with next higher Character wich in your case is 'i' since its follows 'h'



            let breakpoint = dropdownList.find(function(element) {
            return element.item_text.charAt(0).toLowerCase() === 'i';
            })


            Next you can slice the original array at



            let slicePoint = dropdownList.indexOf(breakpoint)-1

            dropdownList.slice(slicePoint);


            Ofcourse this requires the array to contain at least one element with 'i' at start.






            share|improve this answer

































              0














              By manipulating the mentioned codes, i framed a code as such -



               Proceed() {


              // some basic interfaces to describe types
              interface Item {
              item_text: string;
              }
              interface LetterRange {
              first: string;
              last: string;
              }

              // the letter ranges
              // this solution allows them to intersect
              // can adjust for any letter ranges
              const rangesAtoH: LetterRange = [
              {first: 'a', last: 'h'},

              ];

              const rangesItoQ: LetterRange = [

              {first: 'i', last: 'q'},

              ];

              const rangesRtoZ: LetterRange = [

              {first: 'r', last: 'z'}
              ];

              const dropdownParameter: Item = [
              { item_text: 'Organisation' },
              { item_text: 'EwayBill' },
              { item_text: 'SAP' },
              { item_text: 'Collection' },
              { item_text: 'Cancel' },
              { item_text: 'Generate' },
              { item_text: 'Payments' },
              { item_text: 'SMS' },
              { item_text: 'Update' }
              ];

              // sort the words alphabetically so that they will appear in the right order
              const sorted: Item = this.dropdownParameter.sort((a,b) => a.item_text.localeCompare(b.item_text));

              console.log("inside Proceed, Sorted = ", sorted)


              // -------------------------- Array 2 - suggestion-----------------------------

              // array of grouped items (each group is array as well)
              const grouped: Item = sorted.reduce((groups, item) => {
              const firstLetter: string = item.item_text.slice(0,1).toLowerCase();
              console.log(firstLetter);

              // run through each range and check whether the 'firstLetter' fits there
              rangesAtoH.forEach((range, index) => {
              if (firstLetter >= range.first.toLowerCase()
              && firstLetter <= range.last.toLowerCase()) {
              groups[index].push(item);
              }
              });
              return groups;
              }, new Array(rangesAtoH.length).fill()); // initialise with N empty arrays

              console.log("grouped", grouped);


              // ---letter range I to Q ------------------

              const groupedItoQ: Item = sorted.reduce((groups, item) => {
              const firstLetter: string = item.item_text.slice(0,1).toLowerCase();
              console.log(firstLetter);

              // run through each range and check whether the 'firstLetter' fits there
              rangesItoQ.forEach((range, index) => {
              if (firstLetter >= range.first.toLowerCase()
              && firstLetter <= range.last.toLowerCase()) {
              groups[index].push(item);
              }
              });
              return groups;
              }, new Array(rangesItoQ.length).fill()); // initialise with N empty arrays

              console.log("grouped I to Q = ", groupedItoQ);


              // ---letter range R to Z ------------------

              const groupedRtoZ: Item = sorted.reduce((groups, item) => {
              const firstLetter: string = item.item_text.slice(0,1).toLowerCase();
              console.log(firstLetter);

              // run through each range and check whether the 'firstLetter' fits there
              rangesRtoZ.forEach((range, index) => {
              if (firstLetter >= range.first.toLowerCase()
              && firstLetter <= range.last.toLowerCase()) {
              groups[index].push(item);
              }
              });
              return groups;
              }, new Array(rangesRtoZ.length).fill()); // initialise with N empty arrays

              console.log("grouped I to Q = ", groupedRtoZ);





              }





              share|improve this answer
























              • Hmm.. Why did you decide to triple the size of the code I suggested? The point was that you have an array of ranges: [RangeAtoH, RangeItoQ, RangeRtoZ]. With the code I've shown you get the output of wordGroups: [WordsInRangeAtoH, WordsInRangeItoQ, WordsInRangeRtoZ]. This works out of the box. No need to change anything. You can output each group simply by accessing wordGroups array. console.log("grouped A to H = ", wordGroups[0]); console.log("grouped I to Q = ", wordGroups[1]); console.log("grouped R to Z = ", wordGroups[2]);

                – Daniil Andreyevich Baunov
                Nov 17 '18 at 9:52











              • No you don't get . All the three arrays have all the values arranged alphabetically. That is why i segregated. Thanks a lot anyway! You solved it originally.

                – Techdive
                Nov 17 '18 at 10:54














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              3 Answers
              3






              active

              oldest

              votes








              3 Answers
              3






              active

              oldest

              votes









              active

              oldest

              votes






              active

              oldest

              votes









              2














              This is the solution I came up with. Can be optimised for the cases when we know that the letter ranges don't intersect.



              // some basic interfaces to describe types
              interface Item {
              item_text: string;
              }
              interface LetterRange {
              first: string;
              last: string;
              }

              // the letter ranges
              // this solution allows them to intersect
              // can adjust for any letter ranges
              const ranges: LetterRange = [
              {first: 'a', last: 'h'},
              {first: 'i', last: 'q'},
              {first: 'r', last: 'z'}
              ];


              const dropdownList: Item = [
              { item_text: 'Organisation' },
              { item_text: 'EwayBill' },
              { item_text: 'SAP' },
              { item_text: 'Collection' },
              { item_text: 'Cancel' },
              { item_text: 'Generate' },
              { item_text: 'Payments' },
              { item_text: 'SMS' },
              { item_text: 'Update' }
              ];

              // sort the words alphabetically so that they will appear in the right order
              const sorted: Item = dropdownList.sort((a,b) => a.item_text.localeCompare(b.item_text));

              // array of grouped items (each group is array as well)
              const grouped: Item = sorted.reduce((groups, item) => {
              const firstLetter: string = item.item_text.slice(0,1).toLowerCase();
              console.log(firstLetter);

              // run through each range and check whether the 'firstLetter' fits there
              ranges.forEach((range, index) => {
              if (firstLetter >= range.first.toLowerCase()
              && firstLetter <= range.last.toLowerCase()) {
              groups[index].push(item);
              }
              });
              return groups;
              }, new Array(ranges.length).fill()); // initialise with N empty arrays

              console.log(grouped);

              /*
              [
              [ { item_text: 'Cancel' },
              { item_text: 'Collection' },
              { item_text: 'EwayBill' },
              { item_text: 'Generate' }
              ],
              [
              { item_text: 'Organisation' },
              { item_text: 'Payments' }
              ],
              [ { item_text: 'SAP' },
              { item_text: 'SMS' },
              { item_text: 'Update' }
              ]
              ]
              */







              share|improve this answer






























                2














                This is the solution I came up with. Can be optimised for the cases when we know that the letter ranges don't intersect.



                // some basic interfaces to describe types
                interface Item {
                item_text: string;
                }
                interface LetterRange {
                first: string;
                last: string;
                }

                // the letter ranges
                // this solution allows them to intersect
                // can adjust for any letter ranges
                const ranges: LetterRange = [
                {first: 'a', last: 'h'},
                {first: 'i', last: 'q'},
                {first: 'r', last: 'z'}
                ];


                const dropdownList: Item = [
                { item_text: 'Organisation' },
                { item_text: 'EwayBill' },
                { item_text: 'SAP' },
                { item_text: 'Collection' },
                { item_text: 'Cancel' },
                { item_text: 'Generate' },
                { item_text: 'Payments' },
                { item_text: 'SMS' },
                { item_text: 'Update' }
                ];

                // sort the words alphabetically so that they will appear in the right order
                const sorted: Item = dropdownList.sort((a,b) => a.item_text.localeCompare(b.item_text));

                // array of grouped items (each group is array as well)
                const grouped: Item = sorted.reduce((groups, item) => {
                const firstLetter: string = item.item_text.slice(0,1).toLowerCase();
                console.log(firstLetter);

                // run through each range and check whether the 'firstLetter' fits there
                ranges.forEach((range, index) => {
                if (firstLetter >= range.first.toLowerCase()
                && firstLetter <= range.last.toLowerCase()) {
                groups[index].push(item);
                }
                });
                return groups;
                }, new Array(ranges.length).fill()); // initialise with N empty arrays

                console.log(grouped);

                /*
                [
                [ { item_text: 'Cancel' },
                { item_text: 'Collection' },
                { item_text: 'EwayBill' },
                { item_text: 'Generate' }
                ],
                [
                { item_text: 'Organisation' },
                { item_text: 'Payments' }
                ],
                [ { item_text: 'SAP' },
                { item_text: 'SMS' },
                { item_text: 'Update' }
                ]
                ]
                */







                share|improve this answer




























                  2












                  2








                  2







                  This is the solution I came up with. Can be optimised for the cases when we know that the letter ranges don't intersect.



                  // some basic interfaces to describe types
                  interface Item {
                  item_text: string;
                  }
                  interface LetterRange {
                  first: string;
                  last: string;
                  }

                  // the letter ranges
                  // this solution allows them to intersect
                  // can adjust for any letter ranges
                  const ranges: LetterRange = [
                  {first: 'a', last: 'h'},
                  {first: 'i', last: 'q'},
                  {first: 'r', last: 'z'}
                  ];


                  const dropdownList: Item = [
                  { item_text: 'Organisation' },
                  { item_text: 'EwayBill' },
                  { item_text: 'SAP' },
                  { item_text: 'Collection' },
                  { item_text: 'Cancel' },
                  { item_text: 'Generate' },
                  { item_text: 'Payments' },
                  { item_text: 'SMS' },
                  { item_text: 'Update' }
                  ];

                  // sort the words alphabetically so that they will appear in the right order
                  const sorted: Item = dropdownList.sort((a,b) => a.item_text.localeCompare(b.item_text));

                  // array of grouped items (each group is array as well)
                  const grouped: Item = sorted.reduce((groups, item) => {
                  const firstLetter: string = item.item_text.slice(0,1).toLowerCase();
                  console.log(firstLetter);

                  // run through each range and check whether the 'firstLetter' fits there
                  ranges.forEach((range, index) => {
                  if (firstLetter >= range.first.toLowerCase()
                  && firstLetter <= range.last.toLowerCase()) {
                  groups[index].push(item);
                  }
                  });
                  return groups;
                  }, new Array(ranges.length).fill()); // initialise with N empty arrays

                  console.log(grouped);

                  /*
                  [
                  [ { item_text: 'Cancel' },
                  { item_text: 'Collection' },
                  { item_text: 'EwayBill' },
                  { item_text: 'Generate' }
                  ],
                  [
                  { item_text: 'Organisation' },
                  { item_text: 'Payments' }
                  ],
                  [ { item_text: 'SAP' },
                  { item_text: 'SMS' },
                  { item_text: 'Update' }
                  ]
                  ]
                  */







                  share|improve this answer















                  This is the solution I came up with. Can be optimised for the cases when we know that the letter ranges don't intersect.



                  // some basic interfaces to describe types
                  interface Item {
                  item_text: string;
                  }
                  interface LetterRange {
                  first: string;
                  last: string;
                  }

                  // the letter ranges
                  // this solution allows them to intersect
                  // can adjust for any letter ranges
                  const ranges: LetterRange = [
                  {first: 'a', last: 'h'},
                  {first: 'i', last: 'q'},
                  {first: 'r', last: 'z'}
                  ];


                  const dropdownList: Item = [
                  { item_text: 'Organisation' },
                  { item_text: 'EwayBill' },
                  { item_text: 'SAP' },
                  { item_text: 'Collection' },
                  { item_text: 'Cancel' },
                  { item_text: 'Generate' },
                  { item_text: 'Payments' },
                  { item_text: 'SMS' },
                  { item_text: 'Update' }
                  ];

                  // sort the words alphabetically so that they will appear in the right order
                  const sorted: Item = dropdownList.sort((a,b) => a.item_text.localeCompare(b.item_text));

                  // array of grouped items (each group is array as well)
                  const grouped: Item = sorted.reduce((groups, item) => {
                  const firstLetter: string = item.item_text.slice(0,1).toLowerCase();
                  console.log(firstLetter);

                  // run through each range and check whether the 'firstLetter' fits there
                  ranges.forEach((range, index) => {
                  if (firstLetter >= range.first.toLowerCase()
                  && firstLetter <= range.last.toLowerCase()) {
                  groups[index].push(item);
                  }
                  });
                  return groups;
                  }, new Array(ranges.length).fill()); // initialise with N empty arrays

                  console.log(grouped);

                  /*
                  [
                  [ { item_text: 'Cancel' },
                  { item_text: 'Collection' },
                  { item_text: 'EwayBill' },
                  { item_text: 'Generate' }
                  ],
                  [
                  { item_text: 'Organisation' },
                  { item_text: 'Payments' }
                  ],
                  [ { item_text: 'SAP' },
                  { item_text: 'SMS' },
                  { item_text: 'Update' }
                  ]
                  ]
                  */








                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited Nov 16 '18 at 14:50

























                  answered Nov 16 '18 at 14:35









                  Daniil Andreyevich BaunovDaniil Andreyevich Baunov

                  1,137528




                  1,137528

























                      1














                      Sort it with a compare function https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/sort



                      dropdownList.sort(function (item1, item2) {
                      if (item1.item_text < item2.item_text)
                      return -1;
                      if ( item1.item_text > item2.item_text)
                      return 1;
                      return 0;
                      })


                      or more simple:



                      dropdownList.sort(function (item1, item2) {
                      return ('' + item1.item_text).localeCompare(item2.item_text);
                      })


                      This is copy pasted with changes from https://stackoverflow.com/a/51169/7329611 with credits to Shog9



                      After sorting you can slice the array into groups with the slice function https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/slice
                      After sorting you should find the indexes of the first occurance of objects with the next higher alphabetical character and set these indexes as slice(from, to)
                      So for the first step you have to find the first element with next higher Character wich in your case is 'i' since its follows 'h'



                      let breakpoint = dropdownList.find(function(element) {
                      return element.item_text.charAt(0).toLowerCase() === 'i';
                      })


                      Next you can slice the original array at



                      let slicePoint = dropdownList.indexOf(breakpoint)-1

                      dropdownList.slice(slicePoint);


                      Ofcourse this requires the array to contain at least one element with 'i' at start.






                      share|improve this answer






























                        1














                        Sort it with a compare function https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/sort



                        dropdownList.sort(function (item1, item2) {
                        if (item1.item_text < item2.item_text)
                        return -1;
                        if ( item1.item_text > item2.item_text)
                        return 1;
                        return 0;
                        })


                        or more simple:



                        dropdownList.sort(function (item1, item2) {
                        return ('' + item1.item_text).localeCompare(item2.item_text);
                        })


                        This is copy pasted with changes from https://stackoverflow.com/a/51169/7329611 with credits to Shog9



                        After sorting you can slice the array into groups with the slice function https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/slice
                        After sorting you should find the indexes of the first occurance of objects with the next higher alphabetical character and set these indexes as slice(from, to)
                        So for the first step you have to find the first element with next higher Character wich in your case is 'i' since its follows 'h'



                        let breakpoint = dropdownList.find(function(element) {
                        return element.item_text.charAt(0).toLowerCase() === 'i';
                        })


                        Next you can slice the original array at



                        let slicePoint = dropdownList.indexOf(breakpoint)-1

                        dropdownList.slice(slicePoint);


                        Ofcourse this requires the array to contain at least one element with 'i' at start.






                        share|improve this answer




























                          1












                          1








                          1







                          Sort it with a compare function https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/sort



                          dropdownList.sort(function (item1, item2) {
                          if (item1.item_text < item2.item_text)
                          return -1;
                          if ( item1.item_text > item2.item_text)
                          return 1;
                          return 0;
                          })


                          or more simple:



                          dropdownList.sort(function (item1, item2) {
                          return ('' + item1.item_text).localeCompare(item2.item_text);
                          })


                          This is copy pasted with changes from https://stackoverflow.com/a/51169/7329611 with credits to Shog9



                          After sorting you can slice the array into groups with the slice function https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/slice
                          After sorting you should find the indexes of the first occurance of objects with the next higher alphabetical character and set these indexes as slice(from, to)
                          So for the first step you have to find the first element with next higher Character wich in your case is 'i' since its follows 'h'



                          let breakpoint = dropdownList.find(function(element) {
                          return element.item_text.charAt(0).toLowerCase() === 'i';
                          })


                          Next you can slice the original array at



                          let slicePoint = dropdownList.indexOf(breakpoint)-1

                          dropdownList.slice(slicePoint);


                          Ofcourse this requires the array to contain at least one element with 'i' at start.






                          share|improve this answer















                          Sort it with a compare function https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/sort



                          dropdownList.sort(function (item1, item2) {
                          if (item1.item_text < item2.item_text)
                          return -1;
                          if ( item1.item_text > item2.item_text)
                          return 1;
                          return 0;
                          })


                          or more simple:



                          dropdownList.sort(function (item1, item2) {
                          return ('' + item1.item_text).localeCompare(item2.item_text);
                          })


                          This is copy pasted with changes from https://stackoverflow.com/a/51169/7329611 with credits to Shog9



                          After sorting you can slice the array into groups with the slice function https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/slice
                          After sorting you should find the indexes of the first occurance of objects with the next higher alphabetical character and set these indexes as slice(from, to)
                          So for the first step you have to find the first element with next higher Character wich in your case is 'i' since its follows 'h'



                          let breakpoint = dropdownList.find(function(element) {
                          return element.item_text.charAt(0).toLowerCase() === 'i';
                          })


                          Next you can slice the original array at



                          let slicePoint = dropdownList.indexOf(breakpoint)-1

                          dropdownList.slice(slicePoint);


                          Ofcourse this requires the array to contain at least one element with 'i' at start.







                          share|improve this answer














                          share|improve this answer



                          share|improve this answer








                          edited Nov 16 '18 at 14:26

























                          answered Nov 16 '18 at 13:56









                          Severin KlugSeverin Klug

                          294




                          294























                              0














                              By manipulating the mentioned codes, i framed a code as such -



                               Proceed() {


                              // some basic interfaces to describe types
                              interface Item {
                              item_text: string;
                              }
                              interface LetterRange {
                              first: string;
                              last: string;
                              }

                              // the letter ranges
                              // this solution allows them to intersect
                              // can adjust for any letter ranges
                              const rangesAtoH: LetterRange = [
                              {first: 'a', last: 'h'},

                              ];

                              const rangesItoQ: LetterRange = [

                              {first: 'i', last: 'q'},

                              ];

                              const rangesRtoZ: LetterRange = [

                              {first: 'r', last: 'z'}
                              ];

                              const dropdownParameter: Item = [
                              { item_text: 'Organisation' },
                              { item_text: 'EwayBill' },
                              { item_text: 'SAP' },
                              { item_text: 'Collection' },
                              { item_text: 'Cancel' },
                              { item_text: 'Generate' },
                              { item_text: 'Payments' },
                              { item_text: 'SMS' },
                              { item_text: 'Update' }
                              ];

                              // sort the words alphabetically so that they will appear in the right order
                              const sorted: Item = this.dropdownParameter.sort((a,b) => a.item_text.localeCompare(b.item_text));

                              console.log("inside Proceed, Sorted = ", sorted)


                              // -------------------------- Array 2 - suggestion-----------------------------

                              // array of grouped items (each group is array as well)
                              const grouped: Item = sorted.reduce((groups, item) => {
                              const firstLetter: string = item.item_text.slice(0,1).toLowerCase();
                              console.log(firstLetter);

                              // run through each range and check whether the 'firstLetter' fits there
                              rangesAtoH.forEach((range, index) => {
                              if (firstLetter >= range.first.toLowerCase()
                              && firstLetter <= range.last.toLowerCase()) {
                              groups[index].push(item);
                              }
                              });
                              return groups;
                              }, new Array(rangesAtoH.length).fill()); // initialise with N empty arrays

                              console.log("grouped", grouped);


                              // ---letter range I to Q ------------------

                              const groupedItoQ: Item = sorted.reduce((groups, item) => {
                              const firstLetter: string = item.item_text.slice(0,1).toLowerCase();
                              console.log(firstLetter);

                              // run through each range and check whether the 'firstLetter' fits there
                              rangesItoQ.forEach((range, index) => {
                              if (firstLetter >= range.first.toLowerCase()
                              && firstLetter <= range.last.toLowerCase()) {
                              groups[index].push(item);
                              }
                              });
                              return groups;
                              }, new Array(rangesItoQ.length).fill()); // initialise with N empty arrays

                              console.log("grouped I to Q = ", groupedItoQ);


                              // ---letter range R to Z ------------------

                              const groupedRtoZ: Item = sorted.reduce((groups, item) => {
                              const firstLetter: string = item.item_text.slice(0,1).toLowerCase();
                              console.log(firstLetter);

                              // run through each range and check whether the 'firstLetter' fits there
                              rangesRtoZ.forEach((range, index) => {
                              if (firstLetter >= range.first.toLowerCase()
                              && firstLetter <= range.last.toLowerCase()) {
                              groups[index].push(item);
                              }
                              });
                              return groups;
                              }, new Array(rangesRtoZ.length).fill()); // initialise with N empty arrays

                              console.log("grouped I to Q = ", groupedRtoZ);





                              }





                              share|improve this answer
























                              • Hmm.. Why did you decide to triple the size of the code I suggested? The point was that you have an array of ranges: [RangeAtoH, RangeItoQ, RangeRtoZ]. With the code I've shown you get the output of wordGroups: [WordsInRangeAtoH, WordsInRangeItoQ, WordsInRangeRtoZ]. This works out of the box. No need to change anything. You can output each group simply by accessing wordGroups array. console.log("grouped A to H = ", wordGroups[0]); console.log("grouped I to Q = ", wordGroups[1]); console.log("grouped R to Z = ", wordGroups[2]);

                                – Daniil Andreyevich Baunov
                                Nov 17 '18 at 9:52











                              • No you don't get . All the three arrays have all the values arranged alphabetically. That is why i segregated. Thanks a lot anyway! You solved it originally.

                                – Techdive
                                Nov 17 '18 at 10:54


















                              0














                              By manipulating the mentioned codes, i framed a code as such -



                               Proceed() {


                              // some basic interfaces to describe types
                              interface Item {
                              item_text: string;
                              }
                              interface LetterRange {
                              first: string;
                              last: string;
                              }

                              // the letter ranges
                              // this solution allows them to intersect
                              // can adjust for any letter ranges
                              const rangesAtoH: LetterRange = [
                              {first: 'a', last: 'h'},

                              ];

                              const rangesItoQ: LetterRange = [

                              {first: 'i', last: 'q'},

                              ];

                              const rangesRtoZ: LetterRange = [

                              {first: 'r', last: 'z'}
                              ];

                              const dropdownParameter: Item = [
                              { item_text: 'Organisation' },
                              { item_text: 'EwayBill' },
                              { item_text: 'SAP' },
                              { item_text: 'Collection' },
                              { item_text: 'Cancel' },
                              { item_text: 'Generate' },
                              { item_text: 'Payments' },
                              { item_text: 'SMS' },
                              { item_text: 'Update' }
                              ];

                              // sort the words alphabetically so that they will appear in the right order
                              const sorted: Item = this.dropdownParameter.sort((a,b) => a.item_text.localeCompare(b.item_text));

                              console.log("inside Proceed, Sorted = ", sorted)


                              // -------------------------- Array 2 - suggestion-----------------------------

                              // array of grouped items (each group is array as well)
                              const grouped: Item = sorted.reduce((groups, item) => {
                              const firstLetter: string = item.item_text.slice(0,1).toLowerCase();
                              console.log(firstLetter);

                              // run through each range and check whether the 'firstLetter' fits there
                              rangesAtoH.forEach((range, index) => {
                              if (firstLetter >= range.first.toLowerCase()
                              && firstLetter <= range.last.toLowerCase()) {
                              groups[index].push(item);
                              }
                              });
                              return groups;
                              }, new Array(rangesAtoH.length).fill()); // initialise with N empty arrays

                              console.log("grouped", grouped);


                              // ---letter range I to Q ------------------

                              const groupedItoQ: Item = sorted.reduce((groups, item) => {
                              const firstLetter: string = item.item_text.slice(0,1).toLowerCase();
                              console.log(firstLetter);

                              // run through each range and check whether the 'firstLetter' fits there
                              rangesItoQ.forEach((range, index) => {
                              if (firstLetter >= range.first.toLowerCase()
                              && firstLetter <= range.last.toLowerCase()) {
                              groups[index].push(item);
                              }
                              });
                              return groups;
                              }, new Array(rangesItoQ.length).fill()); // initialise with N empty arrays

                              console.log("grouped I to Q = ", groupedItoQ);


                              // ---letter range R to Z ------------------

                              const groupedRtoZ: Item = sorted.reduce((groups, item) => {
                              const firstLetter: string = item.item_text.slice(0,1).toLowerCase();
                              console.log(firstLetter);

                              // run through each range and check whether the 'firstLetter' fits there
                              rangesRtoZ.forEach((range, index) => {
                              if (firstLetter >= range.first.toLowerCase()
                              && firstLetter <= range.last.toLowerCase()) {
                              groups[index].push(item);
                              }
                              });
                              return groups;
                              }, new Array(rangesRtoZ.length).fill()); // initialise with N empty arrays

                              console.log("grouped I to Q = ", groupedRtoZ);





                              }





                              share|improve this answer
























                              • Hmm.. Why did you decide to triple the size of the code I suggested? The point was that you have an array of ranges: [RangeAtoH, RangeItoQ, RangeRtoZ]. With the code I've shown you get the output of wordGroups: [WordsInRangeAtoH, WordsInRangeItoQ, WordsInRangeRtoZ]. This works out of the box. No need to change anything. You can output each group simply by accessing wordGroups array. console.log("grouped A to H = ", wordGroups[0]); console.log("grouped I to Q = ", wordGroups[1]); console.log("grouped R to Z = ", wordGroups[2]);

                                – Daniil Andreyevich Baunov
                                Nov 17 '18 at 9:52











                              • No you don't get . All the three arrays have all the values arranged alphabetically. That is why i segregated. Thanks a lot anyway! You solved it originally.

                                – Techdive
                                Nov 17 '18 at 10:54
















                              0












                              0








                              0







                              By manipulating the mentioned codes, i framed a code as such -



                               Proceed() {


                              // some basic interfaces to describe types
                              interface Item {
                              item_text: string;
                              }
                              interface LetterRange {
                              first: string;
                              last: string;
                              }

                              // the letter ranges
                              // this solution allows them to intersect
                              // can adjust for any letter ranges
                              const rangesAtoH: LetterRange = [
                              {first: 'a', last: 'h'},

                              ];

                              const rangesItoQ: LetterRange = [

                              {first: 'i', last: 'q'},

                              ];

                              const rangesRtoZ: LetterRange = [

                              {first: 'r', last: 'z'}
                              ];

                              const dropdownParameter: Item = [
                              { item_text: 'Organisation' },
                              { item_text: 'EwayBill' },
                              { item_text: 'SAP' },
                              { item_text: 'Collection' },
                              { item_text: 'Cancel' },
                              { item_text: 'Generate' },
                              { item_text: 'Payments' },
                              { item_text: 'SMS' },
                              { item_text: 'Update' }
                              ];

                              // sort the words alphabetically so that they will appear in the right order
                              const sorted: Item = this.dropdownParameter.sort((a,b) => a.item_text.localeCompare(b.item_text));

                              console.log("inside Proceed, Sorted = ", sorted)


                              // -------------------------- Array 2 - suggestion-----------------------------

                              // array of grouped items (each group is array as well)
                              const grouped: Item = sorted.reduce((groups, item) => {
                              const firstLetter: string = item.item_text.slice(0,1).toLowerCase();
                              console.log(firstLetter);

                              // run through each range and check whether the 'firstLetter' fits there
                              rangesAtoH.forEach((range, index) => {
                              if (firstLetter >= range.first.toLowerCase()
                              && firstLetter <= range.last.toLowerCase()) {
                              groups[index].push(item);
                              }
                              });
                              return groups;
                              }, new Array(rangesAtoH.length).fill()); // initialise with N empty arrays

                              console.log("grouped", grouped);


                              // ---letter range I to Q ------------------

                              const groupedItoQ: Item = sorted.reduce((groups, item) => {
                              const firstLetter: string = item.item_text.slice(0,1).toLowerCase();
                              console.log(firstLetter);

                              // run through each range and check whether the 'firstLetter' fits there
                              rangesItoQ.forEach((range, index) => {
                              if (firstLetter >= range.first.toLowerCase()
                              && firstLetter <= range.last.toLowerCase()) {
                              groups[index].push(item);
                              }
                              });
                              return groups;
                              }, new Array(rangesItoQ.length).fill()); // initialise with N empty arrays

                              console.log("grouped I to Q = ", groupedItoQ);


                              // ---letter range R to Z ------------------

                              const groupedRtoZ: Item = sorted.reduce((groups, item) => {
                              const firstLetter: string = item.item_text.slice(0,1).toLowerCase();
                              console.log(firstLetter);

                              // run through each range and check whether the 'firstLetter' fits there
                              rangesRtoZ.forEach((range, index) => {
                              if (firstLetter >= range.first.toLowerCase()
                              && firstLetter <= range.last.toLowerCase()) {
                              groups[index].push(item);
                              }
                              });
                              return groups;
                              }, new Array(rangesRtoZ.length).fill()); // initialise with N empty arrays

                              console.log("grouped I to Q = ", groupedRtoZ);





                              }





                              share|improve this answer













                              By manipulating the mentioned codes, i framed a code as such -



                               Proceed() {


                              // some basic interfaces to describe types
                              interface Item {
                              item_text: string;
                              }
                              interface LetterRange {
                              first: string;
                              last: string;
                              }

                              // the letter ranges
                              // this solution allows them to intersect
                              // can adjust for any letter ranges
                              const rangesAtoH: LetterRange = [
                              {first: 'a', last: 'h'},

                              ];

                              const rangesItoQ: LetterRange = [

                              {first: 'i', last: 'q'},

                              ];

                              const rangesRtoZ: LetterRange = [

                              {first: 'r', last: 'z'}
                              ];

                              const dropdownParameter: Item = [
                              { item_text: 'Organisation' },
                              { item_text: 'EwayBill' },
                              { item_text: 'SAP' },
                              { item_text: 'Collection' },
                              { item_text: 'Cancel' },
                              { item_text: 'Generate' },
                              { item_text: 'Payments' },
                              { item_text: 'SMS' },
                              { item_text: 'Update' }
                              ];

                              // sort the words alphabetically so that they will appear in the right order
                              const sorted: Item = this.dropdownParameter.sort((a,b) => a.item_text.localeCompare(b.item_text));

                              console.log("inside Proceed, Sorted = ", sorted)


                              // -------------------------- Array 2 - suggestion-----------------------------

                              // array of grouped items (each group is array as well)
                              const grouped: Item = sorted.reduce((groups, item) => {
                              const firstLetter: string = item.item_text.slice(0,1).toLowerCase();
                              console.log(firstLetter);

                              // run through each range and check whether the 'firstLetter' fits there
                              rangesAtoH.forEach((range, index) => {
                              if (firstLetter >= range.first.toLowerCase()
                              && firstLetter <= range.last.toLowerCase()) {
                              groups[index].push(item);
                              }
                              });
                              return groups;
                              }, new Array(rangesAtoH.length).fill()); // initialise with N empty arrays

                              console.log("grouped", grouped);


                              // ---letter range I to Q ------------------

                              const groupedItoQ: Item = sorted.reduce((groups, item) => {
                              const firstLetter: string = item.item_text.slice(0,1).toLowerCase();
                              console.log(firstLetter);

                              // run through each range and check whether the 'firstLetter' fits there
                              rangesItoQ.forEach((range, index) => {
                              if (firstLetter >= range.first.toLowerCase()
                              && firstLetter <= range.last.toLowerCase()) {
                              groups[index].push(item);
                              }
                              });
                              return groups;
                              }, new Array(rangesItoQ.length).fill()); // initialise with N empty arrays

                              console.log("grouped I to Q = ", groupedItoQ);


                              // ---letter range R to Z ------------------

                              const groupedRtoZ: Item = sorted.reduce((groups, item) => {
                              const firstLetter: string = item.item_text.slice(0,1).toLowerCase();
                              console.log(firstLetter);

                              // run through each range and check whether the 'firstLetter' fits there
                              rangesRtoZ.forEach((range, index) => {
                              if (firstLetter >= range.first.toLowerCase()
                              && firstLetter <= range.last.toLowerCase()) {
                              groups[index].push(item);
                              }
                              });
                              return groups;
                              }, new Array(rangesRtoZ.length).fill()); // initialise with N empty arrays

                              console.log("grouped I to Q = ", groupedRtoZ);





                              }






                              share|improve this answer












                              share|improve this answer



                              share|improve this answer










                              answered Nov 17 '18 at 9:20









                              TechdiveTechdive

                              223117




                              223117













                              • Hmm.. Why did you decide to triple the size of the code I suggested? The point was that you have an array of ranges: [RangeAtoH, RangeItoQ, RangeRtoZ]. With the code I've shown you get the output of wordGroups: [WordsInRangeAtoH, WordsInRangeItoQ, WordsInRangeRtoZ]. This works out of the box. No need to change anything. You can output each group simply by accessing wordGroups array. console.log("grouped A to H = ", wordGroups[0]); console.log("grouped I to Q = ", wordGroups[1]); console.log("grouped R to Z = ", wordGroups[2]);

                                – Daniil Andreyevich Baunov
                                Nov 17 '18 at 9:52











                              • No you don't get . All the three arrays have all the values arranged alphabetically. That is why i segregated. Thanks a lot anyway! You solved it originally.

                                – Techdive
                                Nov 17 '18 at 10:54





















                              • Hmm.. Why did you decide to triple the size of the code I suggested? The point was that you have an array of ranges: [RangeAtoH, RangeItoQ, RangeRtoZ]. With the code I've shown you get the output of wordGroups: [WordsInRangeAtoH, WordsInRangeItoQ, WordsInRangeRtoZ]. This works out of the box. No need to change anything. You can output each group simply by accessing wordGroups array. console.log("grouped A to H = ", wordGroups[0]); console.log("grouped I to Q = ", wordGroups[1]); console.log("grouped R to Z = ", wordGroups[2]);

                                – Daniil Andreyevich Baunov
                                Nov 17 '18 at 9:52











                              • No you don't get . All the three arrays have all the values arranged alphabetically. That is why i segregated. Thanks a lot anyway! You solved it originally.

                                – Techdive
                                Nov 17 '18 at 10:54



















                              Hmm.. Why did you decide to triple the size of the code I suggested? The point was that you have an array of ranges: [RangeAtoH, RangeItoQ, RangeRtoZ]. With the code I've shown you get the output of wordGroups: [WordsInRangeAtoH, WordsInRangeItoQ, WordsInRangeRtoZ]. This works out of the box. No need to change anything. You can output each group simply by accessing wordGroups array. console.log("grouped A to H = ", wordGroups[0]); console.log("grouped I to Q = ", wordGroups[1]); console.log("grouped R to Z = ", wordGroups[2]);

                              – Daniil Andreyevich Baunov
                              Nov 17 '18 at 9:52





                              Hmm.. Why did you decide to triple the size of the code I suggested? The point was that you have an array of ranges: [RangeAtoH, RangeItoQ, RangeRtoZ]. With the code I've shown you get the output of wordGroups: [WordsInRangeAtoH, WordsInRangeItoQ, WordsInRangeRtoZ]. This works out of the box. No need to change anything. You can output each group simply by accessing wordGroups array. console.log("grouped A to H = ", wordGroups[0]); console.log("grouped I to Q = ", wordGroups[1]); console.log("grouped R to Z = ", wordGroups[2]);

                              – Daniil Andreyevich Baunov
                              Nov 17 '18 at 9:52













                              No you don't get . All the three arrays have all the values arranged alphabetically. That is why i segregated. Thanks a lot anyway! You solved it originally.

                              – Techdive
                              Nov 17 '18 at 10:54







                              No you don't get . All the three arrays have all the values arranged alphabetically. That is why i segregated. Thanks a lot anyway! You solved it originally.

                              – Techdive
                              Nov 17 '18 at 10:54




















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