Delete all elements in an array - Function appends 'undefined' at the array end
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ height:90px;width:728px;box-sizing:border-box;
}
Here is my code
var x = ;
function random(min,max) {
return Math.floor(Math.random() * (min-max))+min;
}
function random2(a, b) {
for (let i = 0; i < a; i++) {
x.push(random(0,b));
}
}
random2(5, 100);
console.log(x); // [ -43, -27, -38, -21, -79 ]
x.splice(0, x.length);
x.push(random2(5,100));
console.log(x); // [ -24, -97, -99, -43, -66, undefined ]
I simply wanna remove all the elements in the array then add new elements in it.
But when I try to do it with the code above, undefined is also adding to the array.
How can I prevent it?
javascript arrays push splice
edited Nov 16 '18 at 13:36
Vignesh Raja
3,02211121
asked Nov 16 '18 at 13:15
uhbcuhbc
526
|
show 2 more comments
Here is my code
var x = ;
function random(min,max) {
return Math.floor(Math.random() * (min-max))+min;
}
function random2(a, b) {
for (let i = 0; i < a; i++) {
x.push(random(0,b));
}
}
random2(5, 100);
console.log(x); // [ -43, -27, -38, -21, -79 ]
x.splice(0, x.length);
x.push(random2(5,100));
console.log(x); // [ -24, -97, -99, -43, -66, undefined ]
I simply wanna remove all the elements in the array then add new elements in it.
But when I try to do it with the code above, undefined is also adding to the array.
How can I prevent it?
javascript arrays push splice
edited Nov 16 '18 at 13:36
Vignesh Raja
3,02211121
asked Nov 16 '18 at 13:15
uhbcuhbc
526
4
why not just reset it withx =?
– chazsolo
Nov 16 '18 at 13:16
3
so, what aboutx = ;instead of splicing and whatever?
– briosheje
Nov 16 '18 at 13:16
3
orx.length = 0;
– Nina Scholz
Nov 16 '18 at 13:17
1
Why don't you just assign empty array to it? 'x='
– Slobodan Gajić
Nov 16 '18 at 13:17
2
Possible duplicate of How do I empty an array in JavaScript?
– kemicofa
Nov 16 '18 at 13:21
|
show 2 more comments
Here is my code
var x = ;
function random(min,max) {
return Math.floor(Math.random() * (min-max))+min;
}
function random2(a, b) {
for (let i = 0; i < a; i++) {
x.push(random(0,b));
}
}
random2(5, 100);
console.log(x); // [ -43, -27, -38, -21, -79 ]
x.splice(0, x.length);
x.push(random2(5,100));
console.log(x); // [ -24, -97, -99, -43, -66, undefined ]
I simply wanna remove all the elements in the array then add new elements in it.
But when I try to do it with the code above, undefined is also adding to the array.
How can I prevent it?
javascript arrays push splice
edited Nov 16 '18 at 13:36
Vignesh Raja
3,02211121
asked Nov 16 '18 at 13:15
uhbcuhbc
526
Here is my code
var x = ;
function random(min,max) {
return Math.floor(Math.random() * (min-max))+min;
}
function random2(a, b) {
for (let i = 0; i < a; i++) {
x.push(random(0,b));
}
}
random2(5, 100);
console.log(x); // [ -43, -27, -38, -21, -79 ]
x.splice(0, x.length);
x.push(random2(5,100));
console.log(x); // [ -24, -97, -99, -43, -66, undefined ]
I simply wanna remove all the elements in the array then add new elements in it.
But when I try to do it with the code above, undefined is also adding to the array.
How can I prevent it?
javascript arrays push splice
javascript arrays push splice
edited Nov 16 '18 at 13:36
Vignesh Raja
3,02211121
asked Nov 16 '18 at 13:15
uhbcuhbc
526
edited Nov 16 '18 at 13:36
Vignesh Raja
3,02211121
asked Nov 16 '18 at 13:15
uhbcuhbc
526
edited Nov 16 '18 at 13:36
Vignesh Raja
3,02211121
edited Nov 16 '18 at 13:36
Vignesh Raja
3,02211121
edited Nov 16 '18 at 13:36
Vignesh Raja
3,02211121
3,02211121
asked Nov 16 '18 at 13:15
uhbcuhbc
526
asked Nov 16 '18 at 13:15
uhbcuhbc
526
asked Nov 16 '18 at 13:15
uhbcuhbc
526
526
4
why not just reset it withx =?
– chazsolo
Nov 16 '18 at 13:16
3
so, what aboutx = ;instead of splicing and whatever?
– briosheje
Nov 16 '18 at 13:16
3
orx.length = 0;
– Nina Scholz
Nov 16 '18 at 13:17
1
Why don't you just assign empty array to it? 'x='
– Slobodan Gajić
Nov 16 '18 at 13:17
2
Possible duplicate of How do I empty an array in JavaScript?
– kemicofa
Nov 16 '18 at 13:21
|
show 2 more comments
4
why not just reset it withx =?
– chazsolo
Nov 16 '18 at 13:16
3
so, what aboutx = ;instead of splicing and whatever?
– briosheje
Nov 16 '18 at 13:16
3
orx.length = 0;
– Nina Scholz
Nov 16 '18 at 13:17
1
Why don't you just assign empty array to it? 'x='
– Slobodan Gajić
Nov 16 '18 at 13:17
2
Possible duplicate of How do I empty an array in JavaScript?
– kemicofa
Nov 16 '18 at 13:21
4
4
why not just reset it with
x = ?– chazsolo
Nov 16 '18 at 13:16
why not just reset it with
x = ?– chazsolo
Nov 16 '18 at 13:16
3
3
so, what about
x = ; instead of splicing and whatever?– briosheje
Nov 16 '18 at 13:16
so, what about
x = ; instead of splicing and whatever?– briosheje
Nov 16 '18 at 13:16
3
3
or
x.length = 0;– Nina Scholz
Nov 16 '18 at 13:17
or
x.length = 0;– Nina Scholz
Nov 16 '18 at 13:17
1
1
Why don't you just assign empty array to it? 'x='
– Slobodan Gajić
Nov 16 '18 at 13:17
Why don't you just assign empty array to it? 'x='
– Slobodan Gajić
Nov 16 '18 at 13:17
2
2
Possible duplicate of How do I empty an array in JavaScript?
– kemicofa
Nov 16 '18 at 13:21
Possible duplicate of How do I empty an array in JavaScript?
– kemicofa
Nov 16 '18 at 13:21
|
show 2 more comments
3 Answers
3
active
oldest
votes
You need not to puish the function call, which returns undefined, but just call the function random2, because the function itselft add the elements to the array.
function random(min, max) {
return Math.floor(Math.random() * (min - max)) + min;
}
function random2(a, b) {
for (let i = 0; i < a; i++) {
x.push(random(0, b));
}
}
var x = ;
random2(5, 100);
console.log(x);
x.length = 0; // better performance than x.splice(0, x.length)
random2(5,100); // call without using push
console.log(x); // no undefined anymoreA better approach is to return an array in random2, because this function does not access an outer defined array. To push the values, you could take the spread syntax.
function random(min, max) {
return Math.floor(Math.random() * (min - max)) + min;
}
function random2(a, b) {
return Array.from({ length: a }, _ => random(0, b));
}
var x = random2(5, 100);
console.log(x);
x.length = 0;
x.push(...random2(5, 100));
console.log(x);answered Nov 16 '18 at 13:22
Nina ScholzNina Scholz
196k15109179
After 3h of sleep haven't thought of it, thanks
– uhbc
Nov 16 '18 at 13:26
@nina, Out of the context, isn't it should berandom(a,b)insiderandom2method, assuming the OP need to createminnumber of random numbers betweenminandmaxvalues ? Even the OP is wrong in his implementation.
– Vignesh Raja
Nov 16 '18 at 13:40
@VigneshRaja, please ask op.
– Nina Scholz
Nov 16 '18 at 13:42
add a comment |
To empty an array, there are multiple ways as explained here with some benchmark results and explanation regarding their performance.
As an aggregation, asssume var a = [1,2,3,4,5]
a =a.length = 0a.splice(0, a.length)a = new Array()while(a.pop()){}while(a.shift()){}
You have called the function random2 inside the push method. So random2 method first inserts the values in the array x and returns the default value undefined (Reference), which in turn gets pushed into the array. Hence the value.
answered Nov 16 '18 at 13:28
Vignesh RajaVignesh Raja
3,02211121
Thank you. That's correct, couldn't realise that first but thank to Nina, helped me realise that.
– uhbc
Nov 16 '18 at 13:33
1
Glad you got it. :)
– Vignesh Raja
Nov 16 '18 at 13:34
@uhbc Out of the context, isn't it should berandom(a,b)insiderandom2method, assuming you need to createminnumber of random numbers betweenminandmaxvalues ?
– Vignesh Raja
Nov 16 '18 at 13:44
add a comment |
Set the length to zero
x.length = 0;
answered Nov 16 '18 at 13:17
Josef FazekasJosef Fazekas
30037
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
You need not to puish the function call, which returns undefined, but just call the function random2, because the function itselft add the elements to the array.
function random(min, max) {
return Math.floor(Math.random() * (min - max)) + min;
}
function random2(a, b) {
for (let i = 0; i < a; i++) {
x.push(random(0, b));
}
}
var x = ;
random2(5, 100);
console.log(x);
x.length = 0; // better performance than x.splice(0, x.length)
random2(5,100); // call without using push
console.log(x); // no undefined anymoreA better approach is to return an array in random2, because this function does not access an outer defined array. To push the values, you could take the spread syntax.
function random(min, max) {
return Math.floor(Math.random() * (min - max)) + min;
}
function random2(a, b) {
return Array.from({ length: a }, _ => random(0, b));
}
var x = random2(5, 100);
console.log(x);
x.length = 0;
x.push(...random2(5, 100));
console.log(x);answered Nov 16 '18 at 13:22
Nina ScholzNina Scholz
196k15109179
After 3h of sleep haven't thought of it, thanks
– uhbc
Nov 16 '18 at 13:26
@nina, Out of the context, isn't it should berandom(a,b)insiderandom2method, assuming the OP need to createminnumber of random numbers betweenminandmaxvalues ? Even the OP is wrong in his implementation.
– Vignesh Raja
Nov 16 '18 at 13:40
@VigneshRaja, please ask op.
– Nina Scholz
Nov 16 '18 at 13:42
add a comment |
You need not to puish the function call, which returns undefined, but just call the function random2, because the function itselft add the elements to the array.
function random(min, max) {
return Math.floor(Math.random() * (min - max)) + min;
}
function random2(a, b) {
for (let i = 0; i < a; i++) {
x.push(random(0, b));
}
}
var x = ;
random2(5, 100);
console.log(x);
x.length = 0; // better performance than x.splice(0, x.length)
random2(5,100); // call without using push
console.log(x); // no undefined anymoreA better approach is to return an array in random2, because this function does not access an outer defined array. To push the values, you could take the spread syntax.
function random(min, max) {
return Math.floor(Math.random() * (min - max)) + min;
}
function random2(a, b) {
return Array.from({ length: a }, _ => random(0, b));
}
var x = random2(5, 100);
console.log(x);
x.length = 0;
x.push(...random2(5, 100));
console.log(x);answered Nov 16 '18 at 13:22
Nina ScholzNina Scholz
196k15109179
After 3h of sleep haven't thought of it, thanks
– uhbc
Nov 16 '18 at 13:26
@nina, Out of the context, isn't it should berandom(a,b)insiderandom2method, assuming the OP need to createminnumber of random numbers betweenminandmaxvalues ? Even the OP is wrong in his implementation.
– Vignesh Raja
Nov 16 '18 at 13:40
@VigneshRaja, please ask op.
– Nina Scholz
Nov 16 '18 at 13:42
add a comment |
You need not to puish the function call, which returns undefined, but just call the function random2, because the function itselft add the elements to the array.
function random(min, max) {
return Math.floor(Math.random() * (min - max)) + min;
}
function random2(a, b) {
for (let i = 0; i < a; i++) {
x.push(random(0, b));
}
}
var x = ;
random2(5, 100);
console.log(x);
x.length = 0; // better performance than x.splice(0, x.length)
random2(5,100); // call without using push
console.log(x); // no undefined anymoreA better approach is to return an array in random2, because this function does not access an outer defined array. To push the values, you could take the spread syntax.
function random(min, max) {
return Math.floor(Math.random() * (min - max)) + min;
}
function random2(a, b) {
return Array.from({ length: a }, _ => random(0, b));
}
var x = random2(5, 100);
console.log(x);
x.length = 0;
x.push(...random2(5, 100));
console.log(x);answered Nov 16 '18 at 13:22
Nina ScholzNina Scholz
196k15109179
You need not to puish the function call, which returns undefined, but just call the function random2, because the function itselft add the elements to the array.
function random(min, max) {
return Math.floor(Math.random() * (min - max)) + min;
}
function random2(a, b) {
for (let i = 0; i < a; i++) {
x.push(random(0, b));
}
}
var x = ;
random2(5, 100);
console.log(x);
x.length = 0; // better performance than x.splice(0, x.length)
random2(5,100); // call without using push
console.log(x); // no undefined anymoreA better approach is to return an array in random2, because this function does not access an outer defined array. To push the values, you could take the spread syntax.
function random(min, max) {
return Math.floor(Math.random() * (min - max)) + min;
}
function random2(a, b) {
return Array.from({ length: a }, _ => random(0, b));
}
var x = random2(5, 100);
console.log(x);
x.length = 0;
x.push(...random2(5, 100));
console.log(x);function random(min, max) {
return Math.floor(Math.random() * (min - max)) + min;
}
function random2(a, b) {
for (let i = 0; i < a; i++) {
x.push(random(0, b));
}
}
var x = ;
random2(5, 100);
console.log(x);
x.length = 0; // better performance than x.splice(0, x.length)
random2(5,100); // call without using push
console.log(x); // no undefined anymorefunction random(min, max) {
return Math.floor(Math.random() * (min - max)) + min;
}
function random2(a, b) {
for (let i = 0; i < a; i++) {
x.push(random(0, b));
}
}
var x = ;
random2(5, 100);
console.log(x);
x.length = 0; // better performance than x.splice(0, x.length)
random2(5,100); // call without using push
console.log(x); // no undefined anymorefunction random(min, max) {
return Math.floor(Math.random() * (min - max)) + min;
}
function random2(a, b) {
return Array.from({ length: a }, _ => random(0, b));
}
var x = random2(5, 100);
console.log(x);
x.length = 0;
x.push(...random2(5, 100));
console.log(x);function random(min, max) {
return Math.floor(Math.random() * (min - max)) + min;
}
function random2(a, b) {
return Array.from({ length: a }, _ => random(0, b));
}
var x = random2(5, 100);
console.log(x);
x.length = 0;
x.push(...random2(5, 100));
console.log(x);answered Nov 16 '18 at 13:22
Nina ScholzNina Scholz
196k15109179
edited Nov 16 '18 at 13:30
answered Nov 16 '18 at 13:22
Nina ScholzNina Scholz
196k15109179
answered Nov 16 '18 at 13:22
Nina ScholzNina Scholz
196k15109179
answered Nov 16 '18 at 13:22
Nina ScholzNina Scholz
196k15109179
196k15109179
After 3h of sleep haven't thought of it, thanks
– uhbc
Nov 16 '18 at 13:26
@nina, Out of the context, isn't it should berandom(a,b)insiderandom2method, assuming the OP need to createminnumber of random numbers betweenminandmaxvalues ? Even the OP is wrong in his implementation.
– Vignesh Raja
Nov 16 '18 at 13:40
@VigneshRaja, please ask op.
– Nina Scholz
Nov 16 '18 at 13:42
add a comment |
After 3h of sleep haven't thought of it, thanks
– uhbc
Nov 16 '18 at 13:26
@nina, Out of the context, isn't it should berandom(a,b)insiderandom2method, assuming the OP need to createminnumber of random numbers betweenminandmaxvalues ? Even the OP is wrong in his implementation.
– Vignesh Raja
Nov 16 '18 at 13:40
@VigneshRaja, please ask op.
– Nina Scholz
Nov 16 '18 at 13:42
After 3h of sleep haven't thought of it, thanks
– uhbc
Nov 16 '18 at 13:26
After 3h of sleep haven't thought of it, thanks
– uhbc
Nov 16 '18 at 13:26
@nina, Out of the context, isn't it should be
random(a,b) inside random2 method, assuming the OP need to create min number of random numbers between min and max values ? Even the OP is wrong in his implementation.– Vignesh Raja
Nov 16 '18 at 13:40
@nina, Out of the context, isn't it should be
random(a,b) inside random2 method, assuming the OP need to create min number of random numbers between min and max values ? Even the OP is wrong in his implementation.– Vignesh Raja
Nov 16 '18 at 13:40
@VigneshRaja, please ask op.
– Nina Scholz
Nov 16 '18 at 13:42
@VigneshRaja, please ask op.
– Nina Scholz
Nov 16 '18 at 13:42
add a comment |
To empty an array, there are multiple ways as explained here with some benchmark results and explanation regarding their performance.
As an aggregation, asssume var a = [1,2,3,4,5]
a =a.length = 0a.splice(0, a.length)a = new Array()while(a.pop()){}while(a.shift()){}
You have called the function random2 inside the push method. So random2 method first inserts the values in the array x and returns the default value undefined (Reference), which in turn gets pushed into the array. Hence the value.
answered Nov 16 '18 at 13:28
Vignesh RajaVignesh Raja
3,02211121
Thank you. That's correct, couldn't realise that first but thank to Nina, helped me realise that.
– uhbc
Nov 16 '18 at 13:33
1
Glad you got it. :)
– Vignesh Raja
Nov 16 '18 at 13:34
@uhbc Out of the context, isn't it should berandom(a,b)insiderandom2method, assuming you need to createminnumber of random numbers betweenminandmaxvalues ?
– Vignesh Raja
Nov 16 '18 at 13:44
add a comment |
To empty an array, there are multiple ways as explained here with some benchmark results and explanation regarding their performance.
As an aggregation, asssume var a = [1,2,3,4,5]
a =a.length = 0a.splice(0, a.length)a = new Array()while(a.pop()){}while(a.shift()){}
You have called the function random2 inside the push method. So random2 method first inserts the values in the array x and returns the default value undefined (Reference), which in turn gets pushed into the array. Hence the value.
answered Nov 16 '18 at 13:28
Vignesh RajaVignesh Raja
3,02211121
Thank you. That's correct, couldn't realise that first but thank to Nina, helped me realise that.
– uhbc
Nov 16 '18 at 13:33
1
Glad you got it. :)
– Vignesh Raja
Nov 16 '18 at 13:34
@uhbc Out of the context, isn't it should berandom(a,b)insiderandom2method, assuming you need to createminnumber of random numbers betweenminandmaxvalues ?
– Vignesh Raja
Nov 16 '18 at 13:44
add a comment |
To empty an array, there are multiple ways as explained here with some benchmark results and explanation regarding their performance.
As an aggregation, asssume var a = [1,2,3,4,5]
a =a.length = 0a.splice(0, a.length)a = new Array()while(a.pop()){}while(a.shift()){}
You have called the function random2 inside the push method. So random2 method first inserts the values in the array x and returns the default value undefined (Reference), which in turn gets pushed into the array. Hence the value.
answered Nov 16 '18 at 13:28
Vignesh RajaVignesh Raja
3,02211121
To empty an array, there are multiple ways as explained here with some benchmark results and explanation regarding their performance.
As an aggregation, asssume var a = [1,2,3,4,5]
a =a.length = 0a.splice(0, a.length)a = new Array()while(a.pop()){}while(a.shift()){}
You have called the function random2 inside the push method. So random2 method first inserts the values in the array x and returns the default value undefined (Reference), which in turn gets pushed into the array. Hence the value.
answered Nov 16 '18 at 13:28
Vignesh RajaVignesh Raja
3,02211121
answered Nov 16 '18 at 13:28
Vignesh RajaVignesh Raja
3,02211121
answered Nov 16 '18 at 13:28
Vignesh RajaVignesh Raja
3,02211121
answered Nov 16 '18 at 13:28
Vignesh RajaVignesh Raja
3,02211121
3,02211121
Thank you. That's correct, couldn't realise that first but thank to Nina, helped me realise that.
– uhbc
Nov 16 '18 at 13:33
1
Glad you got it. :)
– Vignesh Raja
Nov 16 '18 at 13:34
@uhbc Out of the context, isn't it should berandom(a,b)insiderandom2method, assuming you need to createminnumber of random numbers betweenminandmaxvalues ?
– Vignesh Raja
Nov 16 '18 at 13:44
add a comment |
Thank you. That's correct, couldn't realise that first but thank to Nina, helped me realise that.
– uhbc
Nov 16 '18 at 13:33
1
Glad you got it. :)
– Vignesh Raja
Nov 16 '18 at 13:34
@uhbc Out of the context, isn't it should berandom(a,b)insiderandom2method, assuming you need to createminnumber of random numbers betweenminandmaxvalues ?
– Vignesh Raja
Nov 16 '18 at 13:44
Thank you. That's correct, couldn't realise that first but thank to Nina, helped me realise that.
– uhbc
Nov 16 '18 at 13:33
Thank you. That's correct, couldn't realise that first but thank to Nina, helped me realise that.
– uhbc
Nov 16 '18 at 13:33
1
1
Glad you got it. :)
– Vignesh Raja
Nov 16 '18 at 13:34
Glad you got it. :)
– Vignesh Raja
Nov 16 '18 at 13:34
@uhbc Out of the context, isn't it should be
random(a,b) inside random2 method, assuming you need to create min number of random numbers between min and max values ?– Vignesh Raja
Nov 16 '18 at 13:44
@uhbc Out of the context, isn't it should be
random(a,b) inside random2 method, assuming you need to create min number of random numbers between min and max values ?– Vignesh Raja
Nov 16 '18 at 13:44
add a comment |
Set the length to zero
x.length = 0;
answered Nov 16 '18 at 13:17
Josef FazekasJosef Fazekas
30037
add a comment |
Set the length to zero
x.length = 0;
answered Nov 16 '18 at 13:17
Josef FazekasJosef Fazekas
30037
add a comment |
Set the length to zero
x.length = 0;
answered Nov 16 '18 at 13:17
Josef FazekasJosef Fazekas
30037
Set the length to zero
x.length = 0;
answered Nov 16 '18 at 13:17
Josef FazekasJosef Fazekas
30037
answered Nov 16 '18 at 13:17
Josef FazekasJosef Fazekas
30037
answered Nov 16 '18 at 13:17
Josef FazekasJosef Fazekas
30037
answered Nov 16 '18 at 13:17
Josef FazekasJosef Fazekas
30037
30037
add a comment |
add a comment |
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4
why not just reset it with
x =?– chazsolo
Nov 16 '18 at 13:16
3
so, what about
x = ;instead of splicing and whatever?– briosheje
Nov 16 '18 at 13:16
3
or
x.length = 0;– Nina Scholz
Nov 16 '18 at 13:17
1
Why don't you just assign empty array to it? 'x='
– Slobodan Gajić
Nov 16 '18 at 13:17
2
Possible duplicate of How do I empty an array in JavaScript?
– kemicofa
Nov 16 '18 at 13:21