Closure not returning the desired output
I am wondering why my function does not return the lines. I'm using closures and my goal is to display each line from a decoded text. I was able to achieve this using Python.
Here's my Python code:
def get_line():
lines = base64_decode()
index = 0
def closure():
nonlocal index
def go_next():
nonlocal index
next_line = line[index]
index += 1
return next_line
if index != len(lines):
return go_next()
else:
index = 0
return go_next()
return closure
Here's my Go code:
package main
import (
"encoding/base64"
"fmt"
"log"
"strings"
)
func base64Decode() string {
str := "REDACTED"
data, err := base64.StdEncoding.DecodeString(str)
if err != nil {
log.Fatal("Error:", err)
}
return string(data)
}
func getLine(str string) func() string {
i := 0
lines := strings.Split(str, "n")
return func() string {
if i != len(lines) {
nextLine := lines[i]
i++
return nextLine
}
return ""
}
}
func main() {
fmt.Println(getLine(base64Decode()))
}
What happens when I run this is it only prints: 0x1095850
instead of This is the first line
from the text.
function go closures
add a comment |
I am wondering why my function does not return the lines. I'm using closures and my goal is to display each line from a decoded text. I was able to achieve this using Python.
Here's my Python code:
def get_line():
lines = base64_decode()
index = 0
def closure():
nonlocal index
def go_next():
nonlocal index
next_line = line[index]
index += 1
return next_line
if index != len(lines):
return go_next()
else:
index = 0
return go_next()
return closure
Here's my Go code:
package main
import (
"encoding/base64"
"fmt"
"log"
"strings"
)
func base64Decode() string {
str := "REDACTED"
data, err := base64.StdEncoding.DecodeString(str)
if err != nil {
log.Fatal("Error:", err)
}
return string(data)
}
func getLine(str string) func() string {
i := 0
lines := strings.Split(str, "n")
return func() string {
if i != len(lines) {
nextLine := lines[i]
i++
return nextLine
}
return ""
}
}
func main() {
fmt.Println(getLine(base64Decode()))
}
What happens when I run this is it only prints: 0x1095850
instead of This is the first line
from the text.
function go closures
1
Your function returns a function. You're printing the function (what you see is its address) instead of calling the function and printing its return value.
– Adrian
Nov 15 '18 at 18:04
add a comment |
I am wondering why my function does not return the lines. I'm using closures and my goal is to display each line from a decoded text. I was able to achieve this using Python.
Here's my Python code:
def get_line():
lines = base64_decode()
index = 0
def closure():
nonlocal index
def go_next():
nonlocal index
next_line = line[index]
index += 1
return next_line
if index != len(lines):
return go_next()
else:
index = 0
return go_next()
return closure
Here's my Go code:
package main
import (
"encoding/base64"
"fmt"
"log"
"strings"
)
func base64Decode() string {
str := "REDACTED"
data, err := base64.StdEncoding.DecodeString(str)
if err != nil {
log.Fatal("Error:", err)
}
return string(data)
}
func getLine(str string) func() string {
i := 0
lines := strings.Split(str, "n")
return func() string {
if i != len(lines) {
nextLine := lines[i]
i++
return nextLine
}
return ""
}
}
func main() {
fmt.Println(getLine(base64Decode()))
}
What happens when I run this is it only prints: 0x1095850
instead of This is the first line
from the text.
function go closures
I am wondering why my function does not return the lines. I'm using closures and my goal is to display each line from a decoded text. I was able to achieve this using Python.
Here's my Python code:
def get_line():
lines = base64_decode()
index = 0
def closure():
nonlocal index
def go_next():
nonlocal index
next_line = line[index]
index += 1
return next_line
if index != len(lines):
return go_next()
else:
index = 0
return go_next()
return closure
Here's my Go code:
package main
import (
"encoding/base64"
"fmt"
"log"
"strings"
)
func base64Decode() string {
str := "REDACTED"
data, err := base64.StdEncoding.DecodeString(str)
if err != nil {
log.Fatal("Error:", err)
}
return string(data)
}
func getLine(str string) func() string {
i := 0
lines := strings.Split(str, "n")
return func() string {
if i != len(lines) {
nextLine := lines[i]
i++
return nextLine
}
return ""
}
}
func main() {
fmt.Println(getLine(base64Decode()))
}
What happens when I run this is it only prints: 0x1095850
instead of This is the first line
from the text.
function go closures
function go closures
edited Nov 16 '18 at 8:23
Flimzy
39.5k116699
39.5k116699
asked Nov 15 '18 at 17:43
sedawkgrepsedawkgrep
1051213
1051213
1
Your function returns a function. You're printing the function (what you see is its address) instead of calling the function and printing its return value.
– Adrian
Nov 15 '18 at 18:04
add a comment |
1
Your function returns a function. You're printing the function (what you see is its address) instead of calling the function and printing its return value.
– Adrian
Nov 15 '18 at 18:04
1
1
Your function returns a function. You're printing the function (what you see is its address) instead of calling the function and printing its return value.
– Adrian
Nov 15 '18 at 18:04
Your function returns a function. You're printing the function (what you see is its address) instead of calling the function and printing its return value.
– Adrian
Nov 15 '18 at 18:04
add a comment |
1 Answer
1
active
oldest
votes
You have to invoke the function:
func main() {
fmt.Println(getLine(base64Decode())())
}
add a comment |
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1 Answer
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active
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You have to invoke the function:
func main() {
fmt.Println(getLine(base64Decode())())
}
add a comment |
You have to invoke the function:
func main() {
fmt.Println(getLine(base64Decode())())
}
add a comment |
You have to invoke the function:
func main() {
fmt.Println(getLine(base64Decode())())
}
You have to invoke the function:
func main() {
fmt.Println(getLine(base64Decode())())
}
answered Nov 15 '18 at 17:49
nightfury1204nightfury1204
1,769410
1,769410
add a comment |
add a comment |
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1
Your function returns a function. You're printing the function (what you see is its address) instead of calling the function and printing its return value.
– Adrian
Nov 15 '18 at 18:04