Match text between two strings with regular expression
10
I would like to use a regular expression that matches any text between two strings:
Part 1. Part 2. Part 3 then more text
In this example, I would like to search for "Part 1" and "Part 3" and then get everything in between which would be: ". Part 2. "
I'm using Python 2x.
python regex python-2.x
edited Sep 20 '15 at 14:02
Calum
1,52321334
asked Sep 20 '15 at 13:38
Carlos MuñizCarlos Muñiz
59461627
add a comment |
10
I would like to use a regular expression that matches any text between two strings:
Part 1. Part 2. Part 3 then more text
In this example, I would like to search for "Part 1" and "Part 3" and then get everything in between which would be: ". Part 2. "
I'm using Python 2x.
python regex python-2.x
edited Sep 20 '15 at 14:02
Calum
1,52321334
asked Sep 20 '15 at 13:38
Carlos MuñizCarlos Muñiz
59461627
add a comment |
10
10
10
2
I would like to use a regular expression that matches any text between two strings:
Part 1. Part 2. Part 3 then more text
In this example, I would like to search for "Part 1" and "Part 3" and then get everything in between which would be: ". Part 2. "
I'm using Python 2x.
python regex python-2.x
edited Sep 20 '15 at 14:02
Calum
1,52321334
asked Sep 20 '15 at 13:38
Carlos MuñizCarlos Muñiz
59461627
I would like to use a regular expression that matches any text between two strings:
Part 1. Part 2. Part 3 then more text
In this example, I would like to search for "Part 1" and "Part 3" and then get everything in between which would be: ". Part 2. "
I'm using Python 2x.
python regex python-2.x
python regex python-2.x
edited Sep 20 '15 at 14:02
Calum
1,52321334
asked Sep 20 '15 at 13:38
Carlos MuñizCarlos Muñiz
59461627
edited Sep 20 '15 at 14:02
Calum
1,52321334
asked Sep 20 '15 at 13:38
Carlos MuñizCarlos Muñiz
59461627
edited Sep 20 '15 at 14:02
Calum
1,52321334
edited Sep 20 '15 at 14:02
Calum
1,52321334
edited Sep 20 '15 at 14:02
Calum
1,52321334
1,52321334
asked Sep 20 '15 at 13:38
Carlos MuñizCarlos Muñiz
59461627
asked Sep 20 '15 at 13:38
Carlos MuñizCarlos Muñiz
59461627
asked Sep 20 '15 at 13:38
Carlos MuñizCarlos Muñiz
59461627
59461627
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
18
Use re.search
>>> import re
>>> s = 'Part 1. Part 2. Part 3 then more text'
>>> re.search(r'Part 1.(.*?)Part 3', s).group(1)
' Part 2. '
>>> re.search(r'Part 1(.*?)Part 3', s).group(1)
'. Part 2. '
Or use re.findall, if there are more than one occurances.
answered Sep 20 '15 at 13:40
Avinash RajAvinash Raj
143k14117164
1
Note that the wanted answer is". Part 2. ", so the regular expression should be r'Part 1(.*?)Part 3'. See my answer blow.
– lord63. j
Sep 20 '15 at 14:06
ya, it would be perfect if it's a comment.
– Avinash Raj
Sep 20 '15 at 14:08
add a comment |
4
With regular expression:
>>> import re
>>> s = 'Part 1. Part 2. Part 3 then more text'
>>> re.search(r'Part 1(.*?)Part 3', s).group(1)
'. Part 2. '
Without regular expression, this one works for your example:
>>> s = 'Part 1. Part 2. Part 3 then more text'
>>> a, b = s.find('Part 1'), s.find('Part 3')
>>> s[a+6:b]
'. Part 2. '
answered Sep 20 '15 at 14:04
lord63. jlord63. j
2,7741923
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
18
Use re.search
>>> import re
>>> s = 'Part 1. Part 2. Part 3 then more text'
>>> re.search(r'Part 1.(.*?)Part 3', s).group(1)
' Part 2. '
>>> re.search(r'Part 1(.*?)Part 3', s).group(1)
'. Part 2. '
Or use re.findall, if there are more than one occurances.
answered Sep 20 '15 at 13:40
Avinash RajAvinash Raj
143k14117164
1
Note that the wanted answer is". Part 2. ", so the regular expression should be r'Part 1(.*?)Part 3'. See my answer blow.
– lord63. j
Sep 20 '15 at 14:06
ya, it would be perfect if it's a comment.
– Avinash Raj
Sep 20 '15 at 14:08
add a comment |
18
Use re.search
>>> import re
>>> s = 'Part 1. Part 2. Part 3 then more text'
>>> re.search(r'Part 1.(.*?)Part 3', s).group(1)
' Part 2. '
>>> re.search(r'Part 1(.*?)Part 3', s).group(1)
'. Part 2. '
Or use re.findall, if there are more than one occurances.
answered Sep 20 '15 at 13:40
Avinash RajAvinash Raj
143k14117164
1
Note that the wanted answer is". Part 2. ", so the regular expression should be r'Part 1(.*?)Part 3'. See my answer blow.
– lord63. j
Sep 20 '15 at 14:06
ya, it would be perfect if it's a comment.
– Avinash Raj
Sep 20 '15 at 14:08
add a comment |
18
18
18
Use re.search
>>> import re
>>> s = 'Part 1. Part 2. Part 3 then more text'
>>> re.search(r'Part 1.(.*?)Part 3', s).group(1)
' Part 2. '
>>> re.search(r'Part 1(.*?)Part 3', s).group(1)
'. Part 2. '
Or use re.findall, if there are more than one occurances.
answered Sep 20 '15 at 13:40
Avinash RajAvinash Raj
143k14117164
Use re.search
>>> import re
>>> s = 'Part 1. Part 2. Part 3 then more text'
>>> re.search(r'Part 1.(.*?)Part 3', s).group(1)
' Part 2. '
>>> re.search(r'Part 1(.*?)Part 3', s).group(1)
'. Part 2. '
Or use re.findall, if there are more than one occurances.
answered Sep 20 '15 at 13:40
Avinash RajAvinash Raj
143k14117164
edited Sep 20 '15 at 14:08
answered Sep 20 '15 at 13:40
Avinash RajAvinash Raj
143k14117164
answered Sep 20 '15 at 13:40
Avinash RajAvinash Raj
143k14117164
answered Sep 20 '15 at 13:40
Avinash RajAvinash Raj
143k14117164
143k14117164
1
Note that the wanted answer is". Part 2. ", so the regular expression should be r'Part 1(.*?)Part 3'. See my answer blow.
– lord63. j
Sep 20 '15 at 14:06
ya, it would be perfect if it's a comment.
– Avinash Raj
Sep 20 '15 at 14:08
add a comment |
1
Note that the wanted answer is". Part 2. ", so the regular expression should be r'Part 1(.*?)Part 3'. See my answer blow.
– lord63. j
Sep 20 '15 at 14:06
ya, it would be perfect if it's a comment.
– Avinash Raj
Sep 20 '15 at 14:08
1
1
Note that the wanted answer is
". Part 2. ", so the regular expression should be r'Part 1(.*?)Part 3'. See my answer blow.– lord63. j
Sep 20 '15 at 14:06
Note that the wanted answer is
". Part 2. ", so the regular expression should be r'Part 1(.*?)Part 3'. See my answer blow.– lord63. j
Sep 20 '15 at 14:06
ya, it would be perfect if it's a comment.
– Avinash Raj
Sep 20 '15 at 14:08
ya, it would be perfect if it's a comment.
– Avinash Raj
Sep 20 '15 at 14:08
add a comment |
4
With regular expression:
>>> import re
>>> s = 'Part 1. Part 2. Part 3 then more text'
>>> re.search(r'Part 1(.*?)Part 3', s).group(1)
'. Part 2. '
Without regular expression, this one works for your example:
>>> s = 'Part 1. Part 2. Part 3 then more text'
>>> a, b = s.find('Part 1'), s.find('Part 3')
>>> s[a+6:b]
'. Part 2. '
answered Sep 20 '15 at 14:04
lord63. jlord63. j
2,7741923
add a comment |
4
With regular expression:
>>> import re
>>> s = 'Part 1. Part 2. Part 3 then more text'
>>> re.search(r'Part 1(.*?)Part 3', s).group(1)
'. Part 2. '
Without regular expression, this one works for your example:
>>> s = 'Part 1. Part 2. Part 3 then more text'
>>> a, b = s.find('Part 1'), s.find('Part 3')
>>> s[a+6:b]
'. Part 2. '
answered Sep 20 '15 at 14:04
lord63. jlord63. j
2,7741923
add a comment |
4
4
4
With regular expression:
>>> import re
>>> s = 'Part 1. Part 2. Part 3 then more text'
>>> re.search(r'Part 1(.*?)Part 3', s).group(1)
'. Part 2. '
Without regular expression, this one works for your example:
>>> s = 'Part 1. Part 2. Part 3 then more text'
>>> a, b = s.find('Part 1'), s.find('Part 3')
>>> s[a+6:b]
'. Part 2. '
answered Sep 20 '15 at 14:04
lord63. jlord63. j
2,7741923
With regular expression:
>>> import re
>>> s = 'Part 1. Part 2. Part 3 then more text'
>>> re.search(r'Part 1(.*?)Part 3', s).group(1)
'. Part 2. '
Without regular expression, this one works for your example:
>>> s = 'Part 1. Part 2. Part 3 then more text'
>>> a, b = s.find('Part 1'), s.find('Part 3')
>>> s[a+6:b]
'. Part 2. '
answered Sep 20 '15 at 14:04
lord63. jlord63. j
2,7741923
answered Sep 20 '15 at 14:04
lord63. jlord63. j
2,7741923
answered Sep 20 '15 at 14:04
lord63. jlord63. j
2,7741923
answered Sep 20 '15 at 14:04
lord63. jlord63. j
2,7741923
2,7741923
add a comment |
add a comment |
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