Match text between two strings with regular expression

I would like to use a regular expression that matches any text between two strings:

Part 1. Part 2. Part 3 then more text

In this example, I would like to search for "Part 1" and "Part 3" and then get everything in between which would be: ". Part 2. "

I'm using Python 2x.

edited Sep 20 '15 at 14:02

Calum

1,52321334

asked Sep 20 '15 at 13:38

Carlos Muñiz

59461627

add a comment |

I would like to use a regular expression that matches any text between two strings:

Part 1. Part 2. Part 3 then more text

In this example, I would like to search for "Part 1" and "Part 3" and then get everything in between which would be: ". Part 2. "

I'm using Python 2x.

edited Sep 20 '15 at 14:02

Calum

1,52321334

asked Sep 20 '15 at 13:38

Carlos Muñiz

59461627

add a comment |

I would like to use a regular expression that matches any text between two strings:

Part 1. Part 2. Part 3 then more text

In this example, I would like to search for "Part 1" and "Part 3" and then get everything in between which would be: ". Part 2. "

I'm using Python 2x.

edited Sep 20 '15 at 14:02

Calum

1,52321334

asked Sep 20 '15 at 13:38

Carlos Muñiz

59461627

I would like to use a regular expression that matches any text between two strings:

Part 1. Part 2. Part 3 then more text

In this example, I would like to search for "Part 1" and "Part 3" and then get everything in between which would be: ". Part 2. "

I'm using Python 2x.

python regex python-2.x

edited Sep 20 '15 at 14:02

Calum

1,52321334

asked Sep 20 '15 at 13:38

Carlos Muñiz

59461627

edited Sep 20 '15 at 14:02

Calum

1,52321334

asked Sep 20 '15 at 13:38

Carlos Muñiz

59461627

edited Sep 20 '15 at 14:02

Calum

1,52321334

edited Sep 20 '15 at 14:02

Calum

1,52321334

edited Sep 20 '15 at 14:02

Calum

1,52321334

asked Sep 20 '15 at 13:38

Carlos Muñiz

59461627

asked Sep 20 '15 at 13:38

Carlos Muñiz

59461627

asked Sep 20 '15 at 13:38

Carlos Muñiz

59461627

add a comment |

2 Answers
2

active

oldest

votes

Use re.search

>>> import re

>>> s = 'Part 1. Part 2. Part 3 then more text'

>>> re.search(r'Part 1.(.*?)Part 3', s).group(1)

' Part 2. '

>>> re.search(r'Part 1(.*?)Part 3', s).group(1)

'. Part 2. '

Or use re.findall, if there are more than one occurances.

edited Sep 20 '15 at 14:08

answered Sep 20 '15 at 13:40

Avinash Raj

143k14117164

1

Note that the wanted answer is ". Part 2. ", so the regular expression should be r'Part 1(.*?)Part 3'. See my answer blow.

– lord63. j
Sep 20 '15 at 14:06

ya, it would be perfect if it's a comment.

– Avinash Raj
Sep 20 '15 at 14:08

add a comment |

With regular expression:

>>> import re

>>> s = 'Part 1. Part 2. Part 3 then more text'

>>> re.search(r'Part 1(.*?)Part 3', s).group(1)

'. Part 2. '

Without regular expression, this one works for your example:

>>> s = 'Part 1. Part 2. Part 3 then more text'

>>> a, b = s.find('Part 1'), s.find('Part 3')

>>> s[a+6:b]

'. Part 2. '

answered Sep 20 '15 at 14:04

lord63. j

2,7741923

add a comment |

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2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

Use re.search

>>> import re

>>> s = 'Part 1. Part 2. Part 3 then more text'

>>> re.search(r'Part 1.(.*?)Part 3', s).group(1)

' Part 2. '

>>> re.search(r'Part 1(.*?)Part 3', s).group(1)

'. Part 2. '

Or use re.findall, if there are more than one occurances.

edited Sep 20 '15 at 14:08

answered Sep 20 '15 at 13:40

Avinash Raj

143k14117164

1

Note that the wanted answer is ". Part 2. ", so the regular expression should be r'Part 1(.*?)Part 3'. See my answer blow.

– lord63. j
Sep 20 '15 at 14:06

ya, it would be perfect if it's a comment.

– Avinash Raj
Sep 20 '15 at 14:08

add a comment |

Use re.search

>>> import re

>>> s = 'Part 1. Part 2. Part 3 then more text'

>>> re.search(r'Part 1.(.*?)Part 3', s).group(1)

' Part 2. '

>>> re.search(r'Part 1(.*?)Part 3', s).group(1)

'. Part 2. '

Or use re.findall, if there are more than one occurances.

edited Sep 20 '15 at 14:08

answered Sep 20 '15 at 13:40

Avinash Raj

143k14117164

1

Note that the wanted answer is ". Part 2. ", so the regular expression should be r'Part 1(.*?)Part 3'. See my answer blow.

– lord63. j
Sep 20 '15 at 14:06

ya, it would be perfect if it's a comment.

– Avinash Raj
Sep 20 '15 at 14:08

add a comment |

Use re.search

>>> import re

>>> s = 'Part 1. Part 2. Part 3 then more text'

>>> re.search(r'Part 1.(.*?)Part 3', s).group(1)

' Part 2. '

>>> re.search(r'Part 1(.*?)Part 3', s).group(1)

'. Part 2. '

Or use re.findall, if there are more than one occurances.

edited Sep 20 '15 at 14:08

answered Sep 20 '15 at 13:40

Avinash Raj

143k14117164

Use re.search

>>> import re

>>> s = 'Part 1. Part 2. Part 3 then more text'

>>> re.search(r'Part 1.(.*?)Part 3', s).group(1)

' Part 2. '

>>> re.search(r'Part 1(.*?)Part 3', s).group(1)

'. Part 2. '

Or use re.findall, if there are more than one occurances.

edited Sep 20 '15 at 14:08

answered Sep 20 '15 at 13:40

Avinash Raj

143k14117164

edited Sep 20 '15 at 14:08

answered Sep 20 '15 at 13:40

Avinash Raj

143k14117164

answered Sep 20 '15 at 13:40

Avinash Raj

143k14117164

answered Sep 20 '15 at 13:40

Avinash Raj

143k14117164

1

Note that the wanted answer is ". Part 2. ", so the regular expression should be r'Part 1(.*?)Part 3'. See my answer blow.

– lord63. j
Sep 20 '15 at 14:06

ya, it would be perfect if it's a comment.

– Avinash Raj
Sep 20 '15 at 14:08

add a comment |

1

Note that the wanted answer is ". Part 2. ", so the regular expression should be r'Part 1(.*?)Part 3'. See my answer blow.

– lord63. j
Sep 20 '15 at 14:06

ya, it would be perfect if it's a comment.

– Avinash Raj
Sep 20 '15 at 14:08

Note that the wanted answer is ". Part 2. ", so the regular expression should be r'Part 1(.*?)Part 3'. See my answer blow.

– lord63. j
Sep 20 '15 at 14:06

ya, it would be perfect if it's a comment.

– Avinash Raj
Sep 20 '15 at 14:08

add a comment |

With regular expression:

>>> import re

>>> s = 'Part 1. Part 2. Part 3 then more text'

>>> re.search(r'Part 1(.*?)Part 3', s).group(1)

'. Part 2. '

Without regular expression, this one works for your example:

>>> s = 'Part 1. Part 2. Part 3 then more text'

>>> a, b = s.find('Part 1'), s.find('Part 3')

>>> s[a+6:b]

'. Part 2. '

answered Sep 20 '15 at 14:04

lord63. j

2,7741923

add a comment |

With regular expression:

>>> import re

>>> s = 'Part 1. Part 2. Part 3 then more text'

>>> re.search(r'Part 1(.*?)Part 3', s).group(1)

'. Part 2. '

Without regular expression, this one works for your example:

>>> s = 'Part 1. Part 2. Part 3 then more text'

>>> a, b = s.find('Part 1'), s.find('Part 3')

>>> s[a+6:b]

'. Part 2. '

answered Sep 20 '15 at 14:04

lord63. j

2,7741923

add a comment |

With regular expression:

>>> import re

>>> s = 'Part 1. Part 2. Part 3 then more text'

>>> re.search(r'Part 1(.*?)Part 3', s).group(1)

'. Part 2. '

Without regular expression, this one works for your example:

>>> s = 'Part 1. Part 2. Part 3 then more text'

>>> a, b = s.find('Part 1'), s.find('Part 3')

>>> s[a+6:b]

'. Part 2. '

answered Sep 20 '15 at 14:04

lord63. j

2,7741923

With regular expression:

>>> import re

>>> s = 'Part 1. Part 2. Part 3 then more text'

>>> re.search(r'Part 1(.*?)Part 3', s).group(1)

'. Part 2. '

Without regular expression, this one works for your example:

>>> s = 'Part 1. Part 2. Part 3 then more text'

>>> a, b = s.find('Part 1'), s.find('Part 3')

>>> s[a+6:b]

'. Part 2. '

answered Sep 20 '15 at 14:04

lord63. j

2,7741923

answered Sep 20 '15 at 14:04

lord63. j

2,7741923

answered Sep 20 '15 at 14:04

lord63. j

2,7741923

answered Sep 20 '15 at 14:04

lord63. j

2,7741923

add a comment |

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