Match text between two strings with regular expression












10















I would like to use a regular expression that matches any text between two strings:



Part 1. Part 2. Part 3 then more text


In this example, I would like to search for "Part 1" and "Part 3" and then get everything in between which would be: ". Part 2. "



I'm using Python 2x.






python regex python-2.x







share|improve this question





























    10















    I would like to use a regular expression that matches any text between two strings:



    Part 1. Part 2. Part 3 then more text


    In this example, I would like to search for "Part 1" and "Part 3" and then get everything in between which would be: ". Part 2. "



    I'm using Python 2x.






    python regex python-2.x







    share|improve this question



























      10












      10








      10


      2






      I would like to use a regular expression that matches any text between two strings:



      Part 1. Part 2. Part 3 then more text


      In this example, I would like to search for "Part 1" and "Part 3" and then get everything in between which would be: ". Part 2. "



      I'm using Python 2x.






      python regex python-2.x







      share|improve this question
















      I would like to use a regular expression that matches any text between two strings:



      Part 1. Part 2. Part 3 then more text


      In this example, I would like to search for "Part 1" and "Part 3" and then get everything in between which would be: ". Part 2. "



      I'm using Python 2x.






      python regex python-2.x




      python regex python-2.x






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Sep 20 '15 at 14:02









      Calum

      1,52321334




      1,52321334










      asked Sep 20 '15 at 13:38









      Carlos MuñizCarlos Muñiz

      59461627




      59461627
























          2 Answers
          2






          active

          oldest

          votes


















          18














          Use re.search



          >>> import re
          
>>> s = 'Part 1. Part 2. Part 3 then more text'
          
>>> re.search(r'Part 1.(.*?)Part 3', s).group(1)
          
' Part 2. '
          
>>> re.search(r'Part 1(.*?)Part 3', s).group(1)
          
'. Part 2. '


          Or use re.findall, if there are more than one occurances.






          share|improve this answer





















          • 1





            Note that the wanted answer is ". Part 2. ", so the regular expression should be r'Part 1(.*?)Part 3'. See my answer blow.

            – lord63. j
            Sep 20 '15 at 14:06











          • ya, it would be perfect if it's a comment.

            – Avinash Raj
            Sep 20 '15 at 14:08



















          4














          With regular expression:



          >>> import re
          
>>> s = 'Part 1. Part 2. Part 3 then more text'
          
>>> re.search(r'Part 1(.*?)Part 3', s).group(1)
          
'. Part 2. '


          Without regular expression, this one works for your example:



          >>> s = 'Part 1. Part 2. Part 3 then more text'
          
>>> a, b = s.find('Part 1'), s.find('Part 3')
          
>>> s[a+6:b]
          
'. Part 2. '





          share|improve this answer























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            2 Answers
            2






            active

            oldest

            votes








            2 Answers
            2






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            18














            Use re.search



            >>> import re
            
>>> s = 'Part 1. Part 2. Part 3 then more text'
            
>>> re.search(r'Part 1.(.*?)Part 3', s).group(1)
            
' Part 2. '
            
>>> re.search(r'Part 1(.*?)Part 3', s).group(1)
            
'. Part 2. '


            Or use re.findall, if there are more than one occurances.






            share|improve this answer





















            • 1





              Note that the wanted answer is ". Part 2. ", so the regular expression should be r'Part 1(.*?)Part 3'. See my answer blow.

              – lord63. j
              Sep 20 '15 at 14:06











            • ya, it would be perfect if it's a comment.

              – Avinash Raj
              Sep 20 '15 at 14:08
















            18














            Use re.search



            >>> import re
            
>>> s = 'Part 1. Part 2. Part 3 then more text'
            
>>> re.search(r'Part 1.(.*?)Part 3', s).group(1)
            
' Part 2. '
            
>>> re.search(r'Part 1(.*?)Part 3', s).group(1)
            
'. Part 2. '


            Or use re.findall, if there are more than one occurances.






            share|improve this answer





















            • 1





              Note that the wanted answer is ". Part 2. ", so the regular expression should be r'Part 1(.*?)Part 3'. See my answer blow.

              – lord63. j
              Sep 20 '15 at 14:06











            • ya, it would be perfect if it's a comment.

              – Avinash Raj
              Sep 20 '15 at 14:08














            18












            18








            18







            Use re.search



            >>> import re
            
>>> s = 'Part 1. Part 2. Part 3 then more text'
            
>>> re.search(r'Part 1.(.*?)Part 3', s).group(1)
            
' Part 2. '
            
>>> re.search(r'Part 1(.*?)Part 3', s).group(1)
            
'. Part 2. '


            Or use re.findall, if there are more than one occurances.






            share|improve this answer















            Use re.search



            >>> import re
            
>>> s = 'Part 1. Part 2. Part 3 then more text'
            
>>> re.search(r'Part 1.(.*?)Part 3', s).group(1)
            
' Part 2. '
            
>>> re.search(r'Part 1(.*?)Part 3', s).group(1)
            
'. Part 2. '


            Or use re.findall, if there are more than one occurances.







            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited Sep 20 '15 at 14:08

























            answered Sep 20 '15 at 13:40









            Avinash RajAvinash Raj

            143k14117164




            143k14117164








            • 1





              Note that the wanted answer is ". Part 2. ", so the regular expression should be r'Part 1(.*?)Part 3'. See my answer blow.

              – lord63. j
              Sep 20 '15 at 14:06











            • ya, it would be perfect if it's a comment.

              – Avinash Raj
              Sep 20 '15 at 14:08














            • 1





              Note that the wanted answer is ". Part 2. ", so the regular expression should be r'Part 1(.*?)Part 3'. See my answer blow.

              – lord63. j
              Sep 20 '15 at 14:06











            • ya, it would be perfect if it's a comment.

              – Avinash Raj
              Sep 20 '15 at 14:08








            1




            1





            Note that the wanted answer is ". Part 2. ", so the regular expression should be r'Part 1(.*?)Part 3'. See my answer blow.

            – lord63. j
            Sep 20 '15 at 14:06





            Note that the wanted answer is ". Part 2. ", so the regular expression should be r'Part 1(.*?)Part 3'. See my answer blow.

            – lord63. j
            Sep 20 '15 at 14:06













            ya, it would be perfect if it's a comment.

            – Avinash Raj
            Sep 20 '15 at 14:08





            ya, it would be perfect if it's a comment.

            – Avinash Raj
            Sep 20 '15 at 14:08













            4














            With regular expression:



            >>> import re
            
>>> s = 'Part 1. Part 2. Part 3 then more text'
            
>>> re.search(r'Part 1(.*?)Part 3', s).group(1)
            
'. Part 2. '


            Without regular expression, this one works for your example:



            >>> s = 'Part 1. Part 2. Part 3 then more text'
            
>>> a, b = s.find('Part 1'), s.find('Part 3')
            
>>> s[a+6:b]
            
'. Part 2. '





            share|improve this answer




























              4














              With regular expression:



              >>> import re
              
>>> s = 'Part 1. Part 2. Part 3 then more text'
              
>>> re.search(r'Part 1(.*?)Part 3', s).group(1)
              
'. Part 2. '


              Without regular expression, this one works for your example:



              >>> s = 'Part 1. Part 2. Part 3 then more text'
              
>>> a, b = s.find('Part 1'), s.find('Part 3')
              
>>> s[a+6:b]
              
'. Part 2. '





              share|improve this answer


























                4












                4








                4







                With regular expression:



                >>> import re
                
>>> s = 'Part 1. Part 2. Part 3 then more text'
                
>>> re.search(r'Part 1(.*?)Part 3', s).group(1)
                
'. Part 2. '


                Without regular expression, this one works for your example:



                >>> s = 'Part 1. Part 2. Part 3 then more text'
                
>>> a, b = s.find('Part 1'), s.find('Part 3')
                
>>> s[a+6:b]
                
'. Part 2. '





                share|improve this answer













                With regular expression:



                >>> import re
                
>>> s = 'Part 1. Part 2. Part 3 then more text'
                
>>> re.search(r'Part 1(.*?)Part 3', s).group(1)
                
'. Part 2. '


                Without regular expression, this one works for your example:



                >>> s = 'Part 1. Part 2. Part 3 then more text'
                
>>> a, b = s.find('Part 1'), s.find('Part 3')
                
>>> s[a+6:b]
                
'. Part 2. '






                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Sep 20 '15 at 14:04









                lord63. jlord63. j

                2,7741923




                2,7741923






























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