regular expression to identify and extract two different strings from parent string
I have the following string: your lead count is @_sfdc.Account.phonenumber.value, you are having @_hrms.leaves.leavescount per year.
From this, I want to fetch @_sfdc.Account.phonenumber.value and @_hrms.leaves.leavescount. It should fetch all dot separated stings even if we have more than one like in this case.
Currently I have tried with this regex: /@_sfdc.([a-zA-Z]).+/g;
javascript regex
edited Nov 15 '18 at 13:08
GavinoGrifoni
564928
asked Nov 15 '18 at 10:59
Praveen RPraveen R
62
add a comment |
I have the following string: your lead count is @_sfdc.Account.phonenumber.value, you are having @_hrms.leaves.leavescount per year.
From this, I want to fetch @_sfdc.Account.phonenumber.value and @_hrms.leaves.leavescount. It should fetch all dot separated stings even if we have more than one like in this case.
Currently I have tried with this regex: /@_sfdc.([a-zA-Z]).+/g;
javascript regex
edited Nov 15 '18 at 13:08
GavinoGrifoni
564928
asked Nov 15 '18 at 10:59
Praveen RPraveen R
62
add a comment |
I have the following string: your lead count is @_sfdc.Account.phonenumber.value, you are having @_hrms.leaves.leavescount per year.
From this, I want to fetch @_sfdc.Account.phonenumber.value and @_hrms.leaves.leavescount. It should fetch all dot separated stings even if we have more than one like in this case.
Currently I have tried with this regex: /@_sfdc.([a-zA-Z]).+/g;
javascript regex
edited Nov 15 '18 at 13:08
GavinoGrifoni
564928
asked Nov 15 '18 at 10:59
Praveen RPraveen R
62
I have the following string: your lead count is @_sfdc.Account.phonenumber.value, you are having @_hrms.leaves.leavescount per year.
From this, I want to fetch @_sfdc.Account.phonenumber.value and @_hrms.leaves.leavescount. It should fetch all dot separated stings even if we have more than one like in this case.
Currently I have tried with this regex: /@_sfdc.([a-zA-Z]).+/g;
javascript regex
javascript regex
edited Nov 15 '18 at 13:08
GavinoGrifoni
564928
asked Nov 15 '18 at 10:59
Praveen RPraveen R
62
edited Nov 15 '18 at 13:08
GavinoGrifoni
564928
asked Nov 15 '18 at 10:59
Praveen RPraveen R
62
edited Nov 15 '18 at 13:08
GavinoGrifoni
564928
edited Nov 15 '18 at 13:08
GavinoGrifoni
564928
edited Nov 15 '18 at 13:08
GavinoGrifoni
564928
564928
asked Nov 15 '18 at 10:59
Praveen RPraveen R
62
asked Nov 15 '18 at 10:59
Praveen RPraveen R
62
asked Nov 15 '18 at 10:59
Praveen RPraveen R
62
62
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
/@_[w.]+/g
This matches "@_", followed by any sequence of letters, numbers, or dots (.).
answered Nov 15 '18 at 11:03
puddipuddi
75138
add a comment |
You were on the right path, almost there! The main error here is that . is a reserved character in a regex which means "any character". To actually match a dot character, you need to escape it with a backslash: .
So, your regex becomes /@_sfdc.([a-zA-Z]).+/g
Another thing to notice is that you want to match letters and dots in the same group, while your current expression requires the match to end with a dot.
So, let's move that dot inside the matching group square brackets:
/@_sfdc.([a-zA-Z.])+/g.
Also you say that you want to match both the @_sfdc and @_hrms prefixes, so let's change that.
There are two ways to do this:
- looking specifically for
@_sfdcand@_hrms:/@_(sfdc|hrms).([a-zA-Z.])+/g
- or matching any string that starts with
@_:/@_([a-zA-Z.])+/g. In this case,hrms.andsfdc.are captured by the same block that captures the rest of the string ([a-zA-Z.]+)
answered Nov 15 '18 at 12:25
GavinoGrifoniGavinoGrifoni
564928
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
/@_[w.]+/g
This matches "@_", followed by any sequence of letters, numbers, or dots (.).
answered Nov 15 '18 at 11:03
puddipuddi
75138
add a comment |
/@_[w.]+/g
This matches "@_", followed by any sequence of letters, numbers, or dots (.).
answered Nov 15 '18 at 11:03
puddipuddi
75138
add a comment |
/@_[w.]+/g
This matches "@_", followed by any sequence of letters, numbers, or dots (.).
answered Nov 15 '18 at 11:03
puddipuddi
75138
/@_[w.]+/g
This matches "@_", followed by any sequence of letters, numbers, or dots (.).
answered Nov 15 '18 at 11:03
puddipuddi
75138
answered Nov 15 '18 at 11:03
puddipuddi
75138
answered Nov 15 '18 at 11:03
puddipuddi
75138
answered Nov 15 '18 at 11:03
puddipuddi
75138
75138
add a comment |
add a comment |
You were on the right path, almost there! The main error here is that . is a reserved character in a regex which means "any character". To actually match a dot character, you need to escape it with a backslash: .
So, your regex becomes /@_sfdc.([a-zA-Z]).+/g
Another thing to notice is that you want to match letters and dots in the same group, while your current expression requires the match to end with a dot.
So, let's move that dot inside the matching group square brackets:
/@_sfdc.([a-zA-Z.])+/g.
Also you say that you want to match both the @_sfdc and @_hrms prefixes, so let's change that.
There are two ways to do this:
- looking specifically for
@_sfdcand@_hrms:/@_(sfdc|hrms).([a-zA-Z.])+/g
- or matching any string that starts with
@_:/@_([a-zA-Z.])+/g. In this case,hrms.andsfdc.are captured by the same block that captures the rest of the string ([a-zA-Z.]+)
answered Nov 15 '18 at 12:25
GavinoGrifoniGavinoGrifoni
564928
add a comment |
You were on the right path, almost there! The main error here is that . is a reserved character in a regex which means "any character". To actually match a dot character, you need to escape it with a backslash: .
So, your regex becomes /@_sfdc.([a-zA-Z]).+/g
Another thing to notice is that you want to match letters and dots in the same group, while your current expression requires the match to end with a dot.
So, let's move that dot inside the matching group square brackets:
/@_sfdc.([a-zA-Z.])+/g.
Also you say that you want to match both the @_sfdc and @_hrms prefixes, so let's change that.
There are two ways to do this:
- looking specifically for
@_sfdcand@_hrms:/@_(sfdc|hrms).([a-zA-Z.])+/g
- or matching any string that starts with
@_:/@_([a-zA-Z.])+/g. In this case,hrms.andsfdc.are captured by the same block that captures the rest of the string ([a-zA-Z.]+)
answered Nov 15 '18 at 12:25
GavinoGrifoniGavinoGrifoni
564928
add a comment |
You were on the right path, almost there! The main error here is that . is a reserved character in a regex which means "any character". To actually match a dot character, you need to escape it with a backslash: .
So, your regex becomes /@_sfdc.([a-zA-Z]).+/g
Another thing to notice is that you want to match letters and dots in the same group, while your current expression requires the match to end with a dot.
So, let's move that dot inside the matching group square brackets:
/@_sfdc.([a-zA-Z.])+/g.
Also you say that you want to match both the @_sfdc and @_hrms prefixes, so let's change that.
There are two ways to do this:
- looking specifically for
@_sfdcand@_hrms:/@_(sfdc|hrms).([a-zA-Z.])+/g
- or matching any string that starts with
@_:/@_([a-zA-Z.])+/g. In this case,hrms.andsfdc.are captured by the same block that captures the rest of the string ([a-zA-Z.]+)
answered Nov 15 '18 at 12:25
GavinoGrifoniGavinoGrifoni
564928
You were on the right path, almost there! The main error here is that . is a reserved character in a regex which means "any character". To actually match a dot character, you need to escape it with a backslash: .
So, your regex becomes /@_sfdc.([a-zA-Z]).+/g
Another thing to notice is that you want to match letters and dots in the same group, while your current expression requires the match to end with a dot.
So, let's move that dot inside the matching group square brackets:
/@_sfdc.([a-zA-Z.])+/g.
Also you say that you want to match both the @_sfdc and @_hrms prefixes, so let's change that.
There are two ways to do this:
- looking specifically for
@_sfdcand@_hrms:/@_(sfdc|hrms).([a-zA-Z.])+/g
- or matching any string that starts with
@_:/@_([a-zA-Z.])+/g. In this case,hrms.andsfdc.are captured by the same block that captures the rest of the string ([a-zA-Z.]+)
answered Nov 15 '18 at 12:25
GavinoGrifoniGavinoGrifoni
564928
answered Nov 15 '18 at 12:25
GavinoGrifoniGavinoGrifoni
564928
answered Nov 15 '18 at 12:25
GavinoGrifoniGavinoGrifoni
564928
answered Nov 15 '18 at 12:25
GavinoGrifoniGavinoGrifoni
564928
564928
add a comment |
add a comment |
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