How to store char as variables in pascal and other questions
I am very new to programming and I'm trying to make a program (in Pascal) that stores a letter chosen by the user several times, like this:
sizes: set of char = ['a' .. 'f'];
Nings: integer = 1 or 2 or 3 or 4 or 5;
writeln ('Choose the number of pizzas (min:1 e max:5)');
read (Nings);
while (Nings => 1) do
Begin
writeln ('a- extra small');
writeln ('b- small');
writeln ('c- regular');
writeln ('d- medium');
writeln ('e- large');
writeln ('f- extra large');
read (sizes);
Nings:= Nings-1;
End;
As I said I'm very new at this, and I wanted to store a number of letters equal to the number of pizzas chosen, and I don't know how. (This is just a piece of the code.) Any help would be appreciated!
char pascal
edited Nov 12 at 21:05
ankabout
668210
asked Nov 12 at 20:09
Gabriela
11
add a comment |
I am very new to programming and I'm trying to make a program (in Pascal) that stores a letter chosen by the user several times, like this:
sizes: set of char = ['a' .. 'f'];
Nings: integer = 1 or 2 or 3 or 4 or 5;
writeln ('Choose the number of pizzas (min:1 e max:5)');
read (Nings);
while (Nings => 1) do
Begin
writeln ('a- extra small');
writeln ('b- small');
writeln ('c- regular');
writeln ('d- medium');
writeln ('e- large');
writeln ('f- extra large');
read (sizes);
Nings:= Nings-1;
End;
As I said I'm very new at this, and I wanted to store a number of letters equal to the number of pizzas chosen, and I don't know how. (This is just a piece of the code.) Any help would be appreciated!
char pascal
edited Nov 12 at 21:05
ankabout
668210
asked Nov 12 at 20:09
Gabriela
11
add a comment |
I am very new to programming and I'm trying to make a program (in Pascal) that stores a letter chosen by the user several times, like this:
sizes: set of char = ['a' .. 'f'];
Nings: integer = 1 or 2 or 3 or 4 or 5;
writeln ('Choose the number of pizzas (min:1 e max:5)');
read (Nings);
while (Nings => 1) do
Begin
writeln ('a- extra small');
writeln ('b- small');
writeln ('c- regular');
writeln ('d- medium');
writeln ('e- large');
writeln ('f- extra large');
read (sizes);
Nings:= Nings-1;
End;
As I said I'm very new at this, and I wanted to store a number of letters equal to the number of pizzas chosen, and I don't know how. (This is just a piece of the code.) Any help would be appreciated!
char pascal
edited Nov 12 at 21:05
ankabout
668210
asked Nov 12 at 20:09
Gabriela
11
I am very new to programming and I'm trying to make a program (in Pascal) that stores a letter chosen by the user several times, like this:
sizes: set of char = ['a' .. 'f'];
Nings: integer = 1 or 2 or 3 or 4 or 5;
writeln ('Choose the number of pizzas (min:1 e max:5)');
read (Nings);
while (Nings => 1) do
Begin
writeln ('a- extra small');
writeln ('b- small');
writeln ('c- regular');
writeln ('d- medium');
writeln ('e- large');
writeln ('f- extra large');
read (sizes);
Nings:= Nings-1;
End;
As I said I'm very new at this, and I wanted to store a number of letters equal to the number of pizzas chosen, and I don't know how. (This is just a piece of the code.) Any help would be appreciated!
char pascal
char pascal
edited Nov 12 at 21:05
ankabout
668210
asked Nov 12 at 20:09
Gabriela
11
edited Nov 12 at 21:05
ankabout
668210
asked Nov 12 at 20:09
Gabriela
11
edited Nov 12 at 21:05
ankabout
668210
edited Nov 12 at 21:05
ankabout
668210
edited Nov 12 at 21:05
ankabout
668210
668210
asked Nov 12 at 20:09
Gabriela
11
asked Nov 12 at 20:09
Gabriela
11
asked Nov 12 at 20:09
Gabriela
11
11
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
You need to review what a set type is. Internally a set consists of single bits for each value the set can hold. Your set of char can only keep track of one 'a', one 'b', etc ('a' is, or is not, in the set; 'b' is, or is not, in the set ...).
Since you need to keep track of up to five pizzas, each one of any of the six sizes you offer, you need to store the size information in an array, say array[1..5] of char. You can use the Nings variable as index to the sizes array, like read(sizes[Nings]) in the while loop.
Btw, variables of limited range are declared in one of two ways:
1) as a type that declares the values and then a variable of that type:
type
TNings = 1..5;
var
Nings: TNings;
2) using numeric or character subranges as type in the variable declaration:
Nings: 1..5
answered Nov 12 at 21:33
Tom Brunberg
13.1k62239
add a comment |
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1 Answer
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oldest
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1 Answer
1
active
oldest
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active
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active
oldest
votes
You need to review what a set type is. Internally a set consists of single bits for each value the set can hold. Your set of char can only keep track of one 'a', one 'b', etc ('a' is, or is not, in the set; 'b' is, or is not, in the set ...).
Since you need to keep track of up to five pizzas, each one of any of the six sizes you offer, you need to store the size information in an array, say array[1..5] of char. You can use the Nings variable as index to the sizes array, like read(sizes[Nings]) in the while loop.
Btw, variables of limited range are declared in one of two ways:
1) as a type that declares the values and then a variable of that type:
type
TNings = 1..5;
var
Nings: TNings;
2) using numeric or character subranges as type in the variable declaration:
Nings: 1..5
answered Nov 12 at 21:33
Tom Brunberg
13.1k62239
add a comment |
You need to review what a set type is. Internally a set consists of single bits for each value the set can hold. Your set of char can only keep track of one 'a', one 'b', etc ('a' is, or is not, in the set; 'b' is, or is not, in the set ...).
Since you need to keep track of up to five pizzas, each one of any of the six sizes you offer, you need to store the size information in an array, say array[1..5] of char. You can use the Nings variable as index to the sizes array, like read(sizes[Nings]) in the while loop.
Btw, variables of limited range are declared in one of two ways:
1) as a type that declares the values and then a variable of that type:
type
TNings = 1..5;
var
Nings: TNings;
2) using numeric or character subranges as type in the variable declaration:
Nings: 1..5
answered Nov 12 at 21:33
Tom Brunberg
13.1k62239
add a comment |
You need to review what a set type is. Internally a set consists of single bits for each value the set can hold. Your set of char can only keep track of one 'a', one 'b', etc ('a' is, or is not, in the set; 'b' is, or is not, in the set ...).
Since you need to keep track of up to five pizzas, each one of any of the six sizes you offer, you need to store the size information in an array, say array[1..5] of char. You can use the Nings variable as index to the sizes array, like read(sizes[Nings]) in the while loop.
Btw, variables of limited range are declared in one of two ways:
1) as a type that declares the values and then a variable of that type:
type
TNings = 1..5;
var
Nings: TNings;
2) using numeric or character subranges as type in the variable declaration:
Nings: 1..5
answered Nov 12 at 21:33
Tom Brunberg
13.1k62239
You need to review what a set type is. Internally a set consists of single bits for each value the set can hold. Your set of char can only keep track of one 'a', one 'b', etc ('a' is, or is not, in the set; 'b' is, or is not, in the set ...).
Since you need to keep track of up to five pizzas, each one of any of the six sizes you offer, you need to store the size information in an array, say array[1..5] of char. You can use the Nings variable as index to the sizes array, like read(sizes[Nings]) in the while loop.
Btw, variables of limited range are declared in one of two ways:
1) as a type that declares the values and then a variable of that type:
type
TNings = 1..5;
var
Nings: TNings;
2) using numeric or character subranges as type in the variable declaration:
Nings: 1..5
answered Nov 12 at 21:33
Tom Brunberg
13.1k62239
edited Nov 12 at 21:52
answered Nov 12 at 21:33
Tom Brunberg
13.1k62239
answered Nov 12 at 21:33
Tom Brunberg
13.1k62239
answered Nov 12 at 21:33
Tom Brunberg
13.1k62239
13.1k62239
add a comment |
add a comment |
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