Split column into multiple rows in Postgres












26















Suppose I have a table like this:



    subject     | flag
----------------+------
this is a test | 2


subject is of type text, and flag is of type int. I would like to transform this table to something like this in Postgres:



    token       | flag
----------------+------
this | 2
is | 2
a | 2
test | 2


Is there an easy way to do this?










share|improve this question





























    26















    Suppose I have a table like this:



        subject     | flag
    ----------------+------
    this is a test | 2


    subject is of type text, and flag is of type int. I would like to transform this table to something like this in Postgres:



        token       | flag
    ----------------+------
    this | 2
    is | 2
    a | 2
    test | 2


    Is there an easy way to do this?










    share|improve this question



























      26












      26








      26


      3






      Suppose I have a table like this:



          subject     | flag
      ----------------+------
      this is a test | 2


      subject is of type text, and flag is of type int. I would like to transform this table to something like this in Postgres:



          token       | flag
      ----------------+------
      this | 2
      is | 2
      a | 2
      test | 2


      Is there an easy way to do this?










      share|improve this question
















      Suppose I have a table like this:



          subject     | flag
      ----------------+------
      this is a test | 2


      subject is of type text, and flag is of type int. I would like to transform this table to something like this in Postgres:



          token       | flag
      ----------------+------
      this | 2
      is | 2
      a | 2
      test | 2


      Is there an easy way to do this?







      sql postgresql split set-returning-functions






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Apr 2 '15 at 18:59









      Erwin Brandstetter

      348k68635813




      348k68635813










      asked Apr 2 '15 at 18:31









      mgoldwassermgoldwasser

      5,15383972




      5,15383972
























          1 Answer
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          41














          In Postgres 9.3+ use a LATERAL join:



          SELECT s.token, flag
          FROM tbl t, unnest(string_to_array(t.subject, ' ')) s(token)
          WHERE flag = 2;


          Note that the shorthand form of a LATERAL join only returns rows, if unnest() actually returns row(s).



          You could also use regexp_split_to_table(), but that's typically slower because regular expression matching costs a bit more.

          Related:




          • SQL select rows containing substring in text field

          • PostgreSQL unnest() with element number






          share|improve this answer

























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            1 Answer
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            active

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            active

            oldest

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            active

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            41














            In Postgres 9.3+ use a LATERAL join:



            SELECT s.token, flag
            FROM tbl t, unnest(string_to_array(t.subject, ' ')) s(token)
            WHERE flag = 2;


            Note that the shorthand form of a LATERAL join only returns rows, if unnest() actually returns row(s).



            You could also use regexp_split_to_table(), but that's typically slower because regular expression matching costs a bit more.

            Related:




            • SQL select rows containing substring in text field

            • PostgreSQL unnest() with element number






            share|improve this answer






























              41














              In Postgres 9.3+ use a LATERAL join:



              SELECT s.token, flag
              FROM tbl t, unnest(string_to_array(t.subject, ' ')) s(token)
              WHERE flag = 2;


              Note that the shorthand form of a LATERAL join only returns rows, if unnest() actually returns row(s).



              You could also use regexp_split_to_table(), but that's typically slower because regular expression matching costs a bit more.

              Related:




              • SQL select rows containing substring in text field

              • PostgreSQL unnest() with element number






              share|improve this answer




























                41












                41








                41







                In Postgres 9.3+ use a LATERAL join:



                SELECT s.token, flag
                FROM tbl t, unnest(string_to_array(t.subject, ' ')) s(token)
                WHERE flag = 2;


                Note that the shorthand form of a LATERAL join only returns rows, if unnest() actually returns row(s).



                You could also use regexp_split_to_table(), but that's typically slower because regular expression matching costs a bit more.

                Related:




                • SQL select rows containing substring in text field

                • PostgreSQL unnest() with element number






                share|improve this answer















                In Postgres 9.3+ use a LATERAL join:



                SELECT s.token, flag
                FROM tbl t, unnest(string_to_array(t.subject, ' ')) s(token)
                WHERE flag = 2;


                Note that the shorthand form of a LATERAL join only returns rows, if unnest() actually returns row(s).



                You could also use regexp_split_to_table(), but that's typically slower because regular expression matching costs a bit more.

                Related:




                • SQL select rows containing substring in text field

                • PostgreSQL unnest() with element number







                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited May 23 '17 at 12:25









                Community

                11




                11










                answered Apr 2 '15 at 18:34









                Erwin BrandstetterErwin Brandstetter

                348k68635813




                348k68635813
































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