Declare arrays with different sizes in a C typedef struct












0















I know how to dynamic allocate a new array with malloc.
I wonder if there's a way to avoid that in this situation:



#define RX_BUFFER_SIZE    256
#define TX_BUFFER_SIZE 128

typedef struct MyBuffer
{
volatile uint8_t RX[RX_BUFFER_SIZE];
volatile uint8_t TX[TX_BUFFER_SIZE];
volatile uint16_t RX_Head;
volatile uint16_t RX_Tail;
volatile uint16_t TX_Head;
volatile uint16_t TX_Tail;
} MyBuffer_t;

typedef struct MyChannel
{
// other stuff
MyBuffer_t buffer;
} MyChannel_t;


then in my code I create several variables like this:



MyChannel_t ch1;
MyChannel_t ch2;
MyChannel_t ch3;


but I would like to set a different sizes of the arrays for each variable. It's ok to select among a small set, i.e.:



#define RX_BUFFER_SIZE_S    32
#define TX_BUFFER_SIZE_S 16

#define RX_BUFFER_SIZE_M 128
#define TX_BUFFER_SIZE_M 64

#define RX_BUFFER_SIZE_L 256
#define TX_BUFFER_SIZE_L 128


Is there a way to achieve this without using malloc?










share|improve this question























  • If you would declare the sizes in each source file, then include the typedef, then you can.

    – Paul Ogilvie
    Nov 15 '18 at 9:08











  • I would like to set the sizes for each MyChannel_t declared.

    – Mark
    Nov 15 '18 at 9:09











  • You can, if you declare them in different source files as per my suggestion. Otherwise, it is not possible.

    – Paul Ogilvie
    Nov 15 '18 at 9:15











  • Sidenote: Your MyBuffer_t should actually be named My2Buffers_t. I would recommend having only single buffer, head and tail in the structure, and then create distinct RX and TX instances that same type.

    – user694733
    Nov 15 '18 at 10:35
















0















I know how to dynamic allocate a new array with malloc.
I wonder if there's a way to avoid that in this situation:



#define RX_BUFFER_SIZE    256
#define TX_BUFFER_SIZE 128

typedef struct MyBuffer
{
volatile uint8_t RX[RX_BUFFER_SIZE];
volatile uint8_t TX[TX_BUFFER_SIZE];
volatile uint16_t RX_Head;
volatile uint16_t RX_Tail;
volatile uint16_t TX_Head;
volatile uint16_t TX_Tail;
} MyBuffer_t;

typedef struct MyChannel
{
// other stuff
MyBuffer_t buffer;
} MyChannel_t;


then in my code I create several variables like this:



MyChannel_t ch1;
MyChannel_t ch2;
MyChannel_t ch3;


but I would like to set a different sizes of the arrays for each variable. It's ok to select among a small set, i.e.:



#define RX_BUFFER_SIZE_S    32
#define TX_BUFFER_SIZE_S 16

#define RX_BUFFER_SIZE_M 128
#define TX_BUFFER_SIZE_M 64

#define RX_BUFFER_SIZE_L 256
#define TX_BUFFER_SIZE_L 128


Is there a way to achieve this without using malloc?










share|improve this question























  • If you would declare the sizes in each source file, then include the typedef, then you can.

    – Paul Ogilvie
    Nov 15 '18 at 9:08











  • I would like to set the sizes for each MyChannel_t declared.

    – Mark
    Nov 15 '18 at 9:09











  • You can, if you declare them in different source files as per my suggestion. Otherwise, it is not possible.

    – Paul Ogilvie
    Nov 15 '18 at 9:15











  • Sidenote: Your MyBuffer_t should actually be named My2Buffers_t. I would recommend having only single buffer, head and tail in the structure, and then create distinct RX and TX instances that same type.

    – user694733
    Nov 15 '18 at 10:35














0












0








0








I know how to dynamic allocate a new array with malloc.
I wonder if there's a way to avoid that in this situation:



#define RX_BUFFER_SIZE    256
#define TX_BUFFER_SIZE 128

typedef struct MyBuffer
{
volatile uint8_t RX[RX_BUFFER_SIZE];
volatile uint8_t TX[TX_BUFFER_SIZE];
volatile uint16_t RX_Head;
volatile uint16_t RX_Tail;
volatile uint16_t TX_Head;
volatile uint16_t TX_Tail;
} MyBuffer_t;

typedef struct MyChannel
{
// other stuff
MyBuffer_t buffer;
} MyChannel_t;


then in my code I create several variables like this:



MyChannel_t ch1;
MyChannel_t ch2;
MyChannel_t ch3;


but I would like to set a different sizes of the arrays for each variable. It's ok to select among a small set, i.e.:



#define RX_BUFFER_SIZE_S    32
#define TX_BUFFER_SIZE_S 16

#define RX_BUFFER_SIZE_M 128
#define TX_BUFFER_SIZE_M 64

#define RX_BUFFER_SIZE_L 256
#define TX_BUFFER_SIZE_L 128


Is there a way to achieve this without using malloc?










share|improve this question














I know how to dynamic allocate a new array with malloc.
I wonder if there's a way to avoid that in this situation:



#define RX_BUFFER_SIZE    256
#define TX_BUFFER_SIZE 128

typedef struct MyBuffer
{
volatile uint8_t RX[RX_BUFFER_SIZE];
volatile uint8_t TX[TX_BUFFER_SIZE];
volatile uint16_t RX_Head;
volatile uint16_t RX_Tail;
volatile uint16_t TX_Head;
volatile uint16_t TX_Tail;
} MyBuffer_t;

typedef struct MyChannel
{
// other stuff
MyBuffer_t buffer;
} MyChannel_t;


then in my code I create several variables like this:



MyChannel_t ch1;
MyChannel_t ch2;
MyChannel_t ch3;


but I would like to set a different sizes of the arrays for each variable. It's ok to select among a small set, i.e.:



#define RX_BUFFER_SIZE_S    32
#define TX_BUFFER_SIZE_S 16

#define RX_BUFFER_SIZE_M 128
#define TX_BUFFER_SIZE_M 64

#define RX_BUFFER_SIZE_L 256
#define TX_BUFFER_SIZE_L 128


Is there a way to achieve this without using malloc?







c arrays struct typedef






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 15 '18 at 9:03









MarkMark

1,09821437




1,09821437













  • If you would declare the sizes in each source file, then include the typedef, then you can.

    – Paul Ogilvie
    Nov 15 '18 at 9:08











  • I would like to set the sizes for each MyChannel_t declared.

    – Mark
    Nov 15 '18 at 9:09











  • You can, if you declare them in different source files as per my suggestion. Otherwise, it is not possible.

    – Paul Ogilvie
    Nov 15 '18 at 9:15











  • Sidenote: Your MyBuffer_t should actually be named My2Buffers_t. I would recommend having only single buffer, head and tail in the structure, and then create distinct RX and TX instances that same type.

    – user694733
    Nov 15 '18 at 10:35



















  • If you would declare the sizes in each source file, then include the typedef, then you can.

    – Paul Ogilvie
    Nov 15 '18 at 9:08











  • I would like to set the sizes for each MyChannel_t declared.

    – Mark
    Nov 15 '18 at 9:09











  • You can, if you declare them in different source files as per my suggestion. Otherwise, it is not possible.

    – Paul Ogilvie
    Nov 15 '18 at 9:15











  • Sidenote: Your MyBuffer_t should actually be named My2Buffers_t. I would recommend having only single buffer, head and tail in the structure, and then create distinct RX and TX instances that same type.

    – user694733
    Nov 15 '18 at 10:35

















If you would declare the sizes in each source file, then include the typedef, then you can.

– Paul Ogilvie
Nov 15 '18 at 9:08





If you would declare the sizes in each source file, then include the typedef, then you can.

– Paul Ogilvie
Nov 15 '18 at 9:08













I would like to set the sizes for each MyChannel_t declared.

– Mark
Nov 15 '18 at 9:09





I would like to set the sizes for each MyChannel_t declared.

– Mark
Nov 15 '18 at 9:09













You can, if you declare them in different source files as per my suggestion. Otherwise, it is not possible.

– Paul Ogilvie
Nov 15 '18 at 9:15





You can, if you declare them in different source files as per my suggestion. Otherwise, it is not possible.

– Paul Ogilvie
Nov 15 '18 at 9:15













Sidenote: Your MyBuffer_t should actually be named My2Buffers_t. I would recommend having only single buffer, head and tail in the structure, and then create distinct RX and TX instances that same type.

– user694733
Nov 15 '18 at 10:35





Sidenote: Your MyBuffer_t should actually be named My2Buffers_t. I would recommend having only single buffer, head and tail in the structure, and then create distinct RX and TX instances that same type.

– user694733
Nov 15 '18 at 10:35












1 Answer
1






active

oldest

votes


















2














Declare your buffers as pointers:



typedef struct MyBuffer 
{
volatile uint8_t * RX;
volatile uint8_t * TX;
size_t rxSize;
size_t txSize;
volatile uint16_t RX_Head;
...


And then use separate static allocation for the buffers, and use them to initialize your object.



volatile uint8_t ch1_rx_buffer[RX_BUFFER_SIZE_S];
volatile uint8_t ch1_tx_buffer[TX_BUFFER_SIZE_S];
MyChannel_t ch1 = {
.buffer = {
ch1_rx_buffer,
ch1_tx_buffer,
sizeof ch1_rx_buffer,
sizeof ch1_tx_buffer,
...
}
}





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    oldest

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    active

    oldest

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    2














    Declare your buffers as pointers:



    typedef struct MyBuffer 
    {
    volatile uint8_t * RX;
    volatile uint8_t * TX;
    size_t rxSize;
    size_t txSize;
    volatile uint16_t RX_Head;
    ...


    And then use separate static allocation for the buffers, and use them to initialize your object.



    volatile uint8_t ch1_rx_buffer[RX_BUFFER_SIZE_S];
    volatile uint8_t ch1_tx_buffer[TX_BUFFER_SIZE_S];
    MyChannel_t ch1 = {
    .buffer = {
    ch1_rx_buffer,
    ch1_tx_buffer,
    sizeof ch1_rx_buffer,
    sizeof ch1_tx_buffer,
    ...
    }
    }





    share|improve this answer






























      2














      Declare your buffers as pointers:



      typedef struct MyBuffer 
      {
      volatile uint8_t * RX;
      volatile uint8_t * TX;
      size_t rxSize;
      size_t txSize;
      volatile uint16_t RX_Head;
      ...


      And then use separate static allocation for the buffers, and use them to initialize your object.



      volatile uint8_t ch1_rx_buffer[RX_BUFFER_SIZE_S];
      volatile uint8_t ch1_tx_buffer[TX_BUFFER_SIZE_S];
      MyChannel_t ch1 = {
      .buffer = {
      ch1_rx_buffer,
      ch1_tx_buffer,
      sizeof ch1_rx_buffer,
      sizeof ch1_tx_buffer,
      ...
      }
      }





      share|improve this answer




























        2












        2








        2







        Declare your buffers as pointers:



        typedef struct MyBuffer 
        {
        volatile uint8_t * RX;
        volatile uint8_t * TX;
        size_t rxSize;
        size_t txSize;
        volatile uint16_t RX_Head;
        ...


        And then use separate static allocation for the buffers, and use them to initialize your object.



        volatile uint8_t ch1_rx_buffer[RX_BUFFER_SIZE_S];
        volatile uint8_t ch1_tx_buffer[TX_BUFFER_SIZE_S];
        MyChannel_t ch1 = {
        .buffer = {
        ch1_rx_buffer,
        ch1_tx_buffer,
        sizeof ch1_rx_buffer,
        sizeof ch1_tx_buffer,
        ...
        }
        }





        share|improve this answer















        Declare your buffers as pointers:



        typedef struct MyBuffer 
        {
        volatile uint8_t * RX;
        volatile uint8_t * TX;
        size_t rxSize;
        size_t txSize;
        volatile uint16_t RX_Head;
        ...


        And then use separate static allocation for the buffers, and use them to initialize your object.



        volatile uint8_t ch1_rx_buffer[RX_BUFFER_SIZE_S];
        volatile uint8_t ch1_tx_buffer[TX_BUFFER_SIZE_S];
        MyChannel_t ch1 = {
        .buffer = {
        ch1_rx_buffer,
        ch1_tx_buffer,
        sizeof ch1_rx_buffer,
        sizeof ch1_tx_buffer,
        ...
        }
        }






        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Nov 15 '18 at 9:16

























        answered Nov 15 '18 at 9:11









        user694733user694733

        11.1k12850




        11.1k12850
































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