Read line by line from a text file and print how I want in shell scripting
2
I want to read below file line by line from a text file and print how I want in shell scripting
Text file content:
zero#123456
one#123
two#12345678
I want to print this as:
zero@1-6
one@1-3
two@1-8
I tried the following:
file="readFile.txt"
while IFS= read -r line
do echo "$line"
done <printf '%sn' "$file"
shell
edited Nov 15 '18 at 9:00
tso
3,11821024
asked Nov 15 '18 at 8:57
Santosh KumarSantosh Kumar
161
add a comment |
2
I want to read below file line by line from a text file and print how I want in shell scripting
Text file content:
zero#123456
one#123
two#12345678
I want to print this as:
zero@1-6
one@1-3
two@1-8
I tried the following:
file="readFile.txt"
while IFS= read -r line
do echo "$line"
done <printf '%sn' "$file"
shell
edited Nov 15 '18 at 9:00
tso
3,11821024
asked Nov 15 '18 at 8:57
Santosh KumarSantosh Kumar
161
1
And if you havethree#123789? Should the result bethree@1-9or something likethree@1-3,7-9?
– Dominique
Nov 15 '18 at 10:54
add a comment |
2
2
2
I want to read below file line by line from a text file and print how I want in shell scripting
Text file content:
zero#123456
one#123
two#12345678
I want to print this as:
zero@1-6
one@1-3
two@1-8
I tried the following:
file="readFile.txt"
while IFS= read -r line
do echo "$line"
done <printf '%sn' "$file"
shell
edited Nov 15 '18 at 9:00
tso
3,11821024
asked Nov 15 '18 at 8:57
Santosh KumarSantosh Kumar
161
I want to read below file line by line from a text file and print how I want in shell scripting
Text file content:
zero#123456
one#123
two#12345678
I want to print this as:
zero@1-6
one@1-3
two@1-8
I tried the following:
file="readFile.txt"
while IFS= read -r line
do echo "$line"
done <printf '%sn' "$file"
shell
shell
edited Nov 15 '18 at 9:00
tso
3,11821024
asked Nov 15 '18 at 8:57
Santosh KumarSantosh Kumar
161
edited Nov 15 '18 at 9:00
tso
3,11821024
asked Nov 15 '18 at 8:57
Santosh KumarSantosh Kumar
161
edited Nov 15 '18 at 9:00
tso
3,11821024
edited Nov 15 '18 at 9:00
tso
3,11821024
edited Nov 15 '18 at 9:00
tso
3,11821024
3,11821024
asked Nov 15 '18 at 8:57
Santosh KumarSantosh Kumar
161
asked Nov 15 '18 at 8:57
Santosh KumarSantosh Kumar
161
asked Nov 15 '18 at 8:57
Santosh KumarSantosh Kumar
161
161
1
And if you havethree#123789? Should the result bethree@1-9or something likethree@1-3,7-9?
– Dominique
Nov 15 '18 at 10:54
add a comment |
1
And if you havethree#123789? Should the result bethree@1-9or something likethree@1-3,7-9?
– Dominique
Nov 15 '18 at 10:54
1
1
And if you have
three#123789? Should the result be three@1-9 or something like three@1-3,7-9?– Dominique
Nov 15 '18 at 10:54
And if you have
three#123789? Should the result be three@1-9 or something like three@1-3,7-9?– Dominique
Nov 15 '18 at 10:54
add a comment |
3 Answers
3
active
oldest
votes
1
Create a script like below: my_print.sh
file="readFile.txt"
while IFS= read -r line
do
one=$(echo $line| awk -F'#' '{print $1}') ## This splits the line based on '#' and picks the 1st value. So, we get zero from 'zero#123456 '
len=$(echo $line| awk -F'#' '{print $2}'|wc -c) ## This takes the 2nd value which is 123456 and counts the number of characters
two=$(echo $line| awk -F'#' '{print $2}'| cut -c 1) ## This picks the 1st character from '123456' which is 1
three=$(echo $line| awk -F'#' '{print $2}'| cut -c $((len-1))) ## This picks the last character from '123456' which is 6
echo $one@$two-$three ## This is basically printing the output in the format you wanted 'zero@1-6'
done <"$file"
Run it like:
mayankp@mayank:~/$ sh my_print.sh
mayankp@mayank:~/$ cat output.txt
zero@1-6
one@1-3
two@1-8
Let me know of this helps.
answered Nov 15 '18 at 9:28
Mayank PorwalMayank Porwal
4,9702724
It is working fine but it is just printing one line and not printing the second line. Output: $ cat output.txt zero@1-5
– Santosh Kumar
Nov 15 '18 at 9:45
I am writing the output in a fileoutput.txt. If you just want to print it, check my updated answer.
– Mayank Porwal
Nov 15 '18 at 9:46
Thanks mayank. I tried it but again I am getting it as just one single line. Even I tried to print it in output.txt
– Santosh Kumar
Nov 15 '18 at 9:59
I pasted the tested solution. It works fine on my machine. Are you running it on the same file as you pasted in your post? Please check, there has to be something very simple that you might be missing.
– Mayank Porwal
Nov 15 '18 at 10:03
Thanks mayank. Could you please explain the steps. It will be helpfull
– Santosh Kumar
Nov 15 '18 at 10:22
|
show 2 more comments
1
It's no shell scripting (missed that first, sorry) but using perl with combined lookahead and lookbehind for a number:
$ perl -pe 's/(?<=[0-9]).*(?=[0-9])/-/' file
Text file content:
zero#1-6
one#1-3
two#1-8
Explained some:
s//-/replace with a-
(?<=[0-9])positive lookbehind, if preceeded by a number
(?=[0-9])positive lookahead, if followed by a number
answered Nov 15 '18 at 10:45
James BrownJames Brown
19.3k31735
add a comment |
1
With sed:
sed -r 's/^(.+)#([0-9])[0-9]*([0-9])s*$/1@2-3/' readFile.txt
-r: using extented regular expressions (just to write some stuff without escaping them by a backslash)
s/expr1/expr2/: substituteexpr1byexpr2
epxr1is described by a regular expression, relevant matching patterns are caught by 3 capturing groups (parenthesized ones).
epxr2retrieves captured strings (1,2,3) and insert them in a formatted output (the one you wanted).
Regular-Expressions.info seems to be interesting to start with them. Also you can check your own regexp with Regx101.com.
Update: Also you could do that with awk:
awk -F'#' '{
gsub(/s*/,"", $2) ;
print $1 "@" substr($2, 1, 1) "-" substr($2, length($2), 1)
}' < test.txt
I added a gsub() call because your file seems to have trailing blank characters.
answered Nov 15 '18 at 9:51
AmessihelAmessihel
2,6241824
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
Create a script like below: my_print.sh
file="readFile.txt"
while IFS= read -r line
do
one=$(echo $line| awk -F'#' '{print $1}') ## This splits the line based on '#' and picks the 1st value. So, we get zero from 'zero#123456 '
len=$(echo $line| awk -F'#' '{print $2}'|wc -c) ## This takes the 2nd value which is 123456 and counts the number of characters
two=$(echo $line| awk -F'#' '{print $2}'| cut -c 1) ## This picks the 1st character from '123456' which is 1
three=$(echo $line| awk -F'#' '{print $2}'| cut -c $((len-1))) ## This picks the last character from '123456' which is 6
echo $one@$two-$three ## This is basically printing the output in the format you wanted 'zero@1-6'
done <"$file"
Run it like:
mayankp@mayank:~/$ sh my_print.sh
mayankp@mayank:~/$ cat output.txt
zero@1-6
one@1-3
two@1-8
Let me know of this helps.
answered Nov 15 '18 at 9:28
Mayank PorwalMayank Porwal
4,9702724
It is working fine but it is just printing one line and not printing the second line. Output: $ cat output.txt zero@1-5
– Santosh Kumar
Nov 15 '18 at 9:45
I am writing the output in a fileoutput.txt. If you just want to print it, check my updated answer.
– Mayank Porwal
Nov 15 '18 at 9:46
Thanks mayank. I tried it but again I am getting it as just one single line. Even I tried to print it in output.txt
– Santosh Kumar
Nov 15 '18 at 9:59
I pasted the tested solution. It works fine on my machine. Are you running it on the same file as you pasted in your post? Please check, there has to be something very simple that you might be missing.
– Mayank Porwal
Nov 15 '18 at 10:03
Thanks mayank. Could you please explain the steps. It will be helpfull
– Santosh Kumar
Nov 15 '18 at 10:22
|
show 2 more comments
1
Create a script like below: my_print.sh
file="readFile.txt"
while IFS= read -r line
do
one=$(echo $line| awk -F'#' '{print $1}') ## This splits the line based on '#' and picks the 1st value. So, we get zero from 'zero#123456 '
len=$(echo $line| awk -F'#' '{print $2}'|wc -c) ## This takes the 2nd value which is 123456 and counts the number of characters
two=$(echo $line| awk -F'#' '{print $2}'| cut -c 1) ## This picks the 1st character from '123456' which is 1
three=$(echo $line| awk -F'#' '{print $2}'| cut -c $((len-1))) ## This picks the last character from '123456' which is 6
echo $one@$two-$three ## This is basically printing the output in the format you wanted 'zero@1-6'
done <"$file"
Run it like:
mayankp@mayank:~/$ sh my_print.sh
mayankp@mayank:~/$ cat output.txt
zero@1-6
one@1-3
two@1-8
Let me know of this helps.
answered Nov 15 '18 at 9:28
Mayank PorwalMayank Porwal
4,9702724
It is working fine but it is just printing one line and not printing the second line. Output: $ cat output.txt zero@1-5
– Santosh Kumar
Nov 15 '18 at 9:45
I am writing the output in a fileoutput.txt. If you just want to print it, check my updated answer.
– Mayank Porwal
Nov 15 '18 at 9:46
Thanks mayank. I tried it but again I am getting it as just one single line. Even I tried to print it in output.txt
– Santosh Kumar
Nov 15 '18 at 9:59
I pasted the tested solution. It works fine on my machine. Are you running it on the same file as you pasted in your post? Please check, there has to be something very simple that you might be missing.
– Mayank Porwal
Nov 15 '18 at 10:03
Thanks mayank. Could you please explain the steps. It will be helpfull
– Santosh Kumar
Nov 15 '18 at 10:22
|
show 2 more comments
1
1
1
Create a script like below: my_print.sh
file="readFile.txt"
while IFS= read -r line
do
one=$(echo $line| awk -F'#' '{print $1}') ## This splits the line based on '#' and picks the 1st value. So, we get zero from 'zero#123456 '
len=$(echo $line| awk -F'#' '{print $2}'|wc -c) ## This takes the 2nd value which is 123456 and counts the number of characters
two=$(echo $line| awk -F'#' '{print $2}'| cut -c 1) ## This picks the 1st character from '123456' which is 1
three=$(echo $line| awk -F'#' '{print $2}'| cut -c $((len-1))) ## This picks the last character from '123456' which is 6
echo $one@$two-$three ## This is basically printing the output in the format you wanted 'zero@1-6'
done <"$file"
Run it like:
mayankp@mayank:~/$ sh my_print.sh
mayankp@mayank:~/$ cat output.txt
zero@1-6
one@1-3
two@1-8
Let me know of this helps.
answered Nov 15 '18 at 9:28
Mayank PorwalMayank Porwal
4,9702724
Create a script like below: my_print.sh
file="readFile.txt"
while IFS= read -r line
do
one=$(echo $line| awk -F'#' '{print $1}') ## This splits the line based on '#' and picks the 1st value. So, we get zero from 'zero#123456 '
len=$(echo $line| awk -F'#' '{print $2}'|wc -c) ## This takes the 2nd value which is 123456 and counts the number of characters
two=$(echo $line| awk -F'#' '{print $2}'| cut -c 1) ## This picks the 1st character from '123456' which is 1
three=$(echo $line| awk -F'#' '{print $2}'| cut -c $((len-1))) ## This picks the last character from '123456' which is 6
echo $one@$two-$three ## This is basically printing the output in the format you wanted 'zero@1-6'
done <"$file"
Run it like:
mayankp@mayank:~/$ sh my_print.sh
mayankp@mayank:~/$ cat output.txt
zero@1-6
one@1-3
two@1-8
Let me know of this helps.
answered Nov 15 '18 at 9:28
Mayank PorwalMayank Porwal
4,9702724
edited Nov 15 '18 at 10:28
answered Nov 15 '18 at 9:28
Mayank PorwalMayank Porwal
4,9702724
answered Nov 15 '18 at 9:28
Mayank PorwalMayank Porwal
4,9702724
answered Nov 15 '18 at 9:28
Mayank PorwalMayank Porwal
4,9702724
4,9702724
It is working fine but it is just printing one line and not printing the second line. Output: $ cat output.txt zero@1-5
– Santosh Kumar
Nov 15 '18 at 9:45
I am writing the output in a fileoutput.txt. If you just want to print it, check my updated answer.
– Mayank Porwal
Nov 15 '18 at 9:46
Thanks mayank. I tried it but again I am getting it as just one single line. Even I tried to print it in output.txt
– Santosh Kumar
Nov 15 '18 at 9:59
I pasted the tested solution. It works fine on my machine. Are you running it on the same file as you pasted in your post? Please check, there has to be something very simple that you might be missing.
– Mayank Porwal
Nov 15 '18 at 10:03
Thanks mayank. Could you please explain the steps. It will be helpfull
– Santosh Kumar
Nov 15 '18 at 10:22
|
show 2 more comments
It is working fine but it is just printing one line and not printing the second line. Output: $ cat output.txt zero@1-5
– Santosh Kumar
Nov 15 '18 at 9:45
I am writing the output in a fileoutput.txt. If you just want to print it, check my updated answer.
– Mayank Porwal
Nov 15 '18 at 9:46
Thanks mayank. I tried it but again I am getting it as just one single line. Even I tried to print it in output.txt
– Santosh Kumar
Nov 15 '18 at 9:59
I pasted the tested solution. It works fine on my machine. Are you running it on the same file as you pasted in your post? Please check, there has to be something very simple that you might be missing.
– Mayank Porwal
Nov 15 '18 at 10:03
Thanks mayank. Could you please explain the steps. It will be helpfull
– Santosh Kumar
Nov 15 '18 at 10:22
It is working fine but it is just printing one line and not printing the second line. Output: $ cat output.txt zero@1-5
– Santosh Kumar
Nov 15 '18 at 9:45
It is working fine but it is just printing one line and not printing the second line. Output: $ cat output.txt zero@1-5
– Santosh Kumar
Nov 15 '18 at 9:45
I am writing the output in a file
output.txt. If you just want to print it, check my updated answer.– Mayank Porwal
Nov 15 '18 at 9:46
I am writing the output in a file
output.txt. If you just want to print it, check my updated answer.– Mayank Porwal
Nov 15 '18 at 9:46
Thanks mayank. I tried it but again I am getting it as just one single line. Even I tried to print it in output.txt
– Santosh Kumar
Nov 15 '18 at 9:59
Thanks mayank. I tried it but again I am getting it as just one single line. Even I tried to print it in output.txt
– Santosh Kumar
Nov 15 '18 at 9:59
I pasted the tested solution. It works fine on my machine. Are you running it on the same file as you pasted in your post? Please check, there has to be something very simple that you might be missing.
– Mayank Porwal
Nov 15 '18 at 10:03
I pasted the tested solution. It works fine on my machine. Are you running it on the same file as you pasted in your post? Please check, there has to be something very simple that you might be missing.
– Mayank Porwal
Nov 15 '18 at 10:03
Thanks mayank. Could you please explain the steps. It will be helpfull
– Santosh Kumar
Nov 15 '18 at 10:22
Thanks mayank. Could you please explain the steps. It will be helpfull
– Santosh Kumar
Nov 15 '18 at 10:22
|
show 2 more comments
1
It's no shell scripting (missed that first, sorry) but using perl with combined lookahead and lookbehind for a number:
$ perl -pe 's/(?<=[0-9]).*(?=[0-9])/-/' file
Text file content:
zero#1-6
one#1-3
two#1-8
Explained some:
s//-/replace with a-
(?<=[0-9])positive lookbehind, if preceeded by a number
(?=[0-9])positive lookahead, if followed by a number
answered Nov 15 '18 at 10:45
James BrownJames Brown
19.3k31735
add a comment |
1
It's no shell scripting (missed that first, sorry) but using perl with combined lookahead and lookbehind for a number:
$ perl -pe 's/(?<=[0-9]).*(?=[0-9])/-/' file
Text file content:
zero#1-6
one#1-3
two#1-8
Explained some:
s//-/replace with a-
(?<=[0-9])positive lookbehind, if preceeded by a number
(?=[0-9])positive lookahead, if followed by a number
answered Nov 15 '18 at 10:45
James BrownJames Brown
19.3k31735
add a comment |
1
1
1
It's no shell scripting (missed that first, sorry) but using perl with combined lookahead and lookbehind for a number:
$ perl -pe 's/(?<=[0-9]).*(?=[0-9])/-/' file
Text file content:
zero#1-6
one#1-3
two#1-8
Explained some:
s//-/replace with a-
(?<=[0-9])positive lookbehind, if preceeded by a number
(?=[0-9])positive lookahead, if followed by a number
answered Nov 15 '18 at 10:45
James BrownJames Brown
19.3k31735
It's no shell scripting (missed that first, sorry) but using perl with combined lookahead and lookbehind for a number:
$ perl -pe 's/(?<=[0-9]).*(?=[0-9])/-/' file
Text file content:
zero#1-6
one#1-3
two#1-8
Explained some:
s//-/replace with a-
(?<=[0-9])positive lookbehind, if preceeded by a number
(?=[0-9])positive lookahead, if followed by a number
answered Nov 15 '18 at 10:45
James BrownJames Brown
19.3k31735
edited Nov 15 '18 at 10:51
answered Nov 15 '18 at 10:45
James BrownJames Brown
19.3k31735
answered Nov 15 '18 at 10:45
James BrownJames Brown
19.3k31735
answered Nov 15 '18 at 10:45
James BrownJames Brown
19.3k31735
19.3k31735
add a comment |
add a comment |
1
With sed:
sed -r 's/^(.+)#([0-9])[0-9]*([0-9])s*$/1@2-3/' readFile.txt
-r: using extented regular expressions (just to write some stuff without escaping them by a backslash)
s/expr1/expr2/: substituteexpr1byexpr2
epxr1is described by a regular expression, relevant matching patterns are caught by 3 capturing groups (parenthesized ones).
epxr2retrieves captured strings (1,2,3) and insert them in a formatted output (the one you wanted).
Regular-Expressions.info seems to be interesting to start with them. Also you can check your own regexp with Regx101.com.
Update: Also you could do that with awk:
awk -F'#' '{
gsub(/s*/,"", $2) ;
print $1 "@" substr($2, 1, 1) "-" substr($2, length($2), 1)
}' < test.txt
I added a gsub() call because your file seems to have trailing blank characters.
answered Nov 15 '18 at 9:51
AmessihelAmessihel
2,6241824
add a comment |
1
With sed:
sed -r 's/^(.+)#([0-9])[0-9]*([0-9])s*$/1@2-3/' readFile.txt
-r: using extented regular expressions (just to write some stuff without escaping them by a backslash)
s/expr1/expr2/: substituteexpr1byexpr2
epxr1is described by a regular expression, relevant matching patterns are caught by 3 capturing groups (parenthesized ones).
epxr2retrieves captured strings (1,2,3) and insert them in a formatted output (the one you wanted).
Regular-Expressions.info seems to be interesting to start with them. Also you can check your own regexp with Regx101.com.
Update: Also you could do that with awk:
awk -F'#' '{
gsub(/s*/,"", $2) ;
print $1 "@" substr($2, 1, 1) "-" substr($2, length($2), 1)
}' < test.txt
I added a gsub() call because your file seems to have trailing blank characters.
answered Nov 15 '18 at 9:51
AmessihelAmessihel
2,6241824
add a comment |
1
1
1
With sed:
sed -r 's/^(.+)#([0-9])[0-9]*([0-9])s*$/1@2-3/' readFile.txt
-r: using extented regular expressions (just to write some stuff without escaping them by a backslash)
s/expr1/expr2/: substituteexpr1byexpr2
epxr1is described by a regular expression, relevant matching patterns are caught by 3 capturing groups (parenthesized ones).
epxr2retrieves captured strings (1,2,3) and insert them in a formatted output (the one you wanted).
Regular-Expressions.info seems to be interesting to start with them. Also you can check your own regexp with Regx101.com.
Update: Also you could do that with awk:
awk -F'#' '{
gsub(/s*/,"", $2) ;
print $1 "@" substr($2, 1, 1) "-" substr($2, length($2), 1)
}' < test.txt
I added a gsub() call because your file seems to have trailing blank characters.
answered Nov 15 '18 at 9:51
AmessihelAmessihel
2,6241824
With sed:
sed -r 's/^(.+)#([0-9])[0-9]*([0-9])s*$/1@2-3/' readFile.txt
-r: using extented regular expressions (just to write some stuff without escaping them by a backslash)
s/expr1/expr2/: substituteexpr1byexpr2
epxr1is described by a regular expression, relevant matching patterns are caught by 3 capturing groups (parenthesized ones).
epxr2retrieves captured strings (1,2,3) and insert them in a formatted output (the one you wanted).
Regular-Expressions.info seems to be interesting to start with them. Also you can check your own regexp with Regx101.com.
Update: Also you could do that with awk:
awk -F'#' '{
gsub(/s*/,"", $2) ;
print $1 "@" substr($2, 1, 1) "-" substr($2, length($2), 1)
}' < test.txt
I added a gsub() call because your file seems to have trailing blank characters.
answered Nov 15 '18 at 9:51
AmessihelAmessihel
2,6241824
edited Nov 15 '18 at 11:01
answered Nov 15 '18 at 9:51
AmessihelAmessihel
2,6241824
answered Nov 15 '18 at 9:51
AmessihelAmessihel
2,6241824
answered Nov 15 '18 at 9:51
AmessihelAmessihel
2,6241824
2,6241824
add a comment |
add a comment |
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And if you have
three#123789? Should the result bethree@1-9or something likethree@1-3,7-9?– Dominique
Nov 15 '18 at 10:54