MYSQL combining, counting and separating instances of rows with same id but different values
1
Currently I have a query that looks like
with the query being written as such:
SELECT username, exerciseId, frustrated, bored
FROM affecttutor.selfreportfrustration
order by username;
and I am trying to make it look like this
what would be the possible ways to go about doing it? Thanks for your time!
mysql
edited Nov 15 '18 at 9:09
Madhur Bhaiya
19.6k62236
asked Nov 15 '18 at 9:04
John NoJohn No
203
add a comment |
1
Currently I have a query that looks like
with the query being written as such:
SELECT username, exerciseId, frustrated, bored
FROM affecttutor.selfreportfrustration
order by username;
and I am trying to make it look like this
what would be the possible ways to go about doing it? Thanks for your time!
mysql
edited Nov 15 '18 at 9:09
Madhur Bhaiya
19.6k62236
asked Nov 15 '18 at 9:04
John NoJohn No
203
This kind of problem can be symptomatic of poor design. Consider whether there's scope to redesign your schema.
– Strawberry
Nov 15 '18 at 10:00
add a comment |
1
1
1
Currently I have a query that looks like
with the query being written as such:
SELECT username, exerciseId, frustrated, bored
FROM affecttutor.selfreportfrustration
order by username;
and I am trying to make it look like this
what would be the possible ways to go about doing it? Thanks for your time!
mysql
edited Nov 15 '18 at 9:09
Madhur Bhaiya
19.6k62236
asked Nov 15 '18 at 9:04
John NoJohn No
203
Currently I have a query that looks like
with the query being written as such:
SELECT username, exerciseId, frustrated, bored
FROM affecttutor.selfreportfrustration
order by username;
and I am trying to make it look like this
what would be the possible ways to go about doing it? Thanks for your time!
mysql
mysql
edited Nov 15 '18 at 9:09
Madhur Bhaiya
19.6k62236
asked Nov 15 '18 at 9:04
John NoJohn No
203
edited Nov 15 '18 at 9:09
Madhur Bhaiya
19.6k62236
asked Nov 15 '18 at 9:04
John NoJohn No
203
edited Nov 15 '18 at 9:09
Madhur Bhaiya
19.6k62236
edited Nov 15 '18 at 9:09
Madhur Bhaiya
19.6k62236
edited Nov 15 '18 at 9:09
Madhur Bhaiya
19.6k62236
19.6k62236
asked Nov 15 '18 at 9:04
John NoJohn No
203
asked Nov 15 '18 at 9:04
John NoJohn No
203
asked Nov 15 '18 at 9:04
John NoJohn No
203
203
This kind of problem can be symptomatic of poor design. Consider whether there's scope to redesign your schema.
– Strawberry
Nov 15 '18 at 10:00
add a comment |
This kind of problem can be symptomatic of poor design. Consider whether there's scope to redesign your schema.
– Strawberry
Nov 15 '18 at 10:00
This kind of problem can be symptomatic of poor design. Consider whether there's scope to redesign your schema.
– Strawberry
Nov 15 '18 at 10:00
This kind of problem can be symptomatic of poor design. Consider whether there's scope to redesign your schema.
– Strawberry
Nov 15 '18 at 10:00
add a comment |
1 Answer
1
active
oldest
votes
1
You can try using conditional aggregation
select
username,exerciseid,
count(case when frustrated='Y' then 1 end) as frustrated,
count(case when frustrated<>'Y' then 1 end) as notfrustrated,
count(case when bored<>'N' then 1 end) as bored ,
count(case when bored='N' then 1 end) as notbored
from affecttutor.selfreportfrustration
group by username,exerciseid
edited Nov 15 '18 at 9:10
Madhur Bhaiya
19.6k62236
answered Nov 15 '18 at 9:08
fa06fa06
15.1k2917
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
You can try using conditional aggregation
select
username,exerciseid,
count(case when frustrated='Y' then 1 end) as frustrated,
count(case when frustrated<>'Y' then 1 end) as notfrustrated,
count(case when bored<>'N' then 1 end) as bored ,
count(case when bored='N' then 1 end) as notbored
from affecttutor.selfreportfrustration
group by username,exerciseid
edited Nov 15 '18 at 9:10
Madhur Bhaiya
19.6k62236
answered Nov 15 '18 at 9:08
fa06fa06
15.1k2917
add a comment |
1
You can try using conditional aggregation
select
username,exerciseid,
count(case when frustrated='Y' then 1 end) as frustrated,
count(case when frustrated<>'Y' then 1 end) as notfrustrated,
count(case when bored<>'N' then 1 end) as bored ,
count(case when bored='N' then 1 end) as notbored
from affecttutor.selfreportfrustration
group by username,exerciseid
edited Nov 15 '18 at 9:10
Madhur Bhaiya
19.6k62236
answered Nov 15 '18 at 9:08
fa06fa06
15.1k2917
add a comment |
1
1
1
You can try using conditional aggregation
select
username,exerciseid,
count(case when frustrated='Y' then 1 end) as frustrated,
count(case when frustrated<>'Y' then 1 end) as notfrustrated,
count(case when bored<>'N' then 1 end) as bored ,
count(case when bored='N' then 1 end) as notbored
from affecttutor.selfreportfrustration
group by username,exerciseid
edited Nov 15 '18 at 9:10
Madhur Bhaiya
19.6k62236
answered Nov 15 '18 at 9:08
fa06fa06
15.1k2917
You can try using conditional aggregation
select
username,exerciseid,
count(case when frustrated='Y' then 1 end) as frustrated,
count(case when frustrated<>'Y' then 1 end) as notfrustrated,
count(case when bored<>'N' then 1 end) as bored ,
count(case when bored='N' then 1 end) as notbored
from affecttutor.selfreportfrustration
group by username,exerciseid
edited Nov 15 '18 at 9:10
Madhur Bhaiya
19.6k62236
answered Nov 15 '18 at 9:08
fa06fa06
15.1k2917
edited Nov 15 '18 at 9:10
Madhur Bhaiya
19.6k62236
edited Nov 15 '18 at 9:10
Madhur Bhaiya
19.6k62236
edited Nov 15 '18 at 9:10
Madhur Bhaiya
19.6k62236
19.6k62236
answered Nov 15 '18 at 9:08
fa06fa06
15.1k2917
answered Nov 15 '18 at 9:08
fa06fa06
15.1k2917
answered Nov 15 '18 at 9:08
fa06fa06
15.1k2917
15.1k2917
add a comment |
add a comment |
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This kind of problem can be symptomatic of poor design. Consider whether there's scope to redesign your schema.
– Strawberry
Nov 15 '18 at 10:00