Sorting names by their high scores
I want to sort a list of names by their score.
What I have so far is
file = open("scores.txt", 'r')
for line in file:
name = line.strip()
print(name)
file.close()
I'm unsure how to sort them.
Here's the file contents:
Matthew, 13
Luke, 6
John, 3
Bobba, 4
What I want the output to be:
John 3
Bobba 4
Luke 6
Matthew 13
Can anyone help?
python sorting python-3.x
edited May 19 '15 at 11:39
SuperBiasedMan
7,28083256
asked Jul 13 '13 at 17:14
user2365677user2365677
1815
add a comment |
I want to sort a list of names by their score.
What I have so far is
file = open("scores.txt", 'r')
for line in file:
name = line.strip()
print(name)
file.close()
I'm unsure how to sort them.
Here's the file contents:
Matthew, 13
Luke, 6
John, 3
Bobba, 4
What I want the output to be:
John 3
Bobba 4
Luke 6
Matthew 13
Can anyone help?
python sorting python-3.x
edited May 19 '15 at 11:39
SuperBiasedMan
7,28083256
asked Jul 13 '13 at 17:14
user2365677user2365677
1815
add a comment |
I want to sort a list of names by their score.
What I have so far is
file = open("scores.txt", 'r')
for line in file:
name = line.strip()
print(name)
file.close()
I'm unsure how to sort them.
Here's the file contents:
Matthew, 13
Luke, 6
John, 3
Bobba, 4
What I want the output to be:
John 3
Bobba 4
Luke 6
Matthew 13
Can anyone help?
python sorting python-3.x
edited May 19 '15 at 11:39
SuperBiasedMan
7,28083256
asked Jul 13 '13 at 17:14
user2365677user2365677
1815
I want to sort a list of names by their score.
What I have so far is
file = open("scores.txt", 'r')
for line in file:
name = line.strip()
print(name)
file.close()
I'm unsure how to sort them.
Here's the file contents:
Matthew, 13
Luke, 6
John, 3
Bobba, 4
What I want the output to be:
John 3
Bobba 4
Luke 6
Matthew 13
Can anyone help?
python sorting python-3.x
python sorting python-3.x
edited May 19 '15 at 11:39
SuperBiasedMan
7,28083256
asked Jul 13 '13 at 17:14
user2365677user2365677
1815
edited May 19 '15 at 11:39
SuperBiasedMan
7,28083256
asked Jul 13 '13 at 17:14
user2365677user2365677
1815
edited May 19 '15 at 11:39
SuperBiasedMan
7,28083256
edited May 19 '15 at 11:39
SuperBiasedMan
7,28083256
edited May 19 '15 at 11:39
SuperBiasedMan
7,28083256
7,28083256
asked Jul 13 '13 at 17:14
user2365677user2365677
1815
asked Jul 13 '13 at 17:14
user2365677user2365677
1815
asked Jul 13 '13 at 17:14
user2365677user2365677
1815
1815
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
you can use the .split(',') method to split a line into its separate parts, then use int() to convert the score to a number. The .sort() method sorts a list in place, and the key tells it what to sort by.
scores =
with open("scores.txt") as f:
for line in f:
name, score = line.split(',')
score = int(score)
scores.append((name, score))
scores.sort(key=lambda s: s[1])
for name, score in scores:
print(name, score)
This will give you a list of tuples containing (name, score) pairs in sorted order. If you want to print them out with a comma in between them (to keep it consistent) change the print to print(name, score, sep=', ')
The reading of the input file can also be expressed as one (big) line
with open("scores.txt") as f:
scores = [(name, int(score)) for name, score in (line.split(',') for line in f)]
A brief explanation of the key=:
a lambda function is an anonymous function, that is, a function without a name. You generally use these when you need a function only for a small operation. .sort has an optional key keyword argument that takes a function and uses the return of that function in sorting the objects.
So this lambda could also be written as
def ret_score(pair):
return pair[1]
And you could then write .sort(key=ret_score) but since we dont really need that function for anything else, its not necessary to declare it. The lambda syntax is
lambda <arguments> : <return value>
So this lambda takes a pair, and returns the second element in it. You can save a lambda and use it like a regular function if you wish.
>>> square = lambda x: x**2 # takes x, returns x squared
>>> square(3)
9
>>> square(6)
36
answered Jul 13 '13 at 17:21
Ryan HainingRyan Haining
21.6k870122
Is there a way to make it so in prints out Vertically?Like- John 3 Bobba 4 Luke 6 Matthew 13
– user2365677
Jul 13 '13 at 17:28
@user2365677 yes I just added that
– Ryan Haining
Jul 13 '13 at 17:29
Just for information sake, ".sort(key=lambda s: s[1])" i know of the .sort, what does lambda mean? It does work, its what i wanted and thank you :)
– user2365677
Jul 13 '13 at 17:31
@user2365677 I've added a quick explanation oflambdabut it can be a strange thing to understand
– Ryan Haining
Jul 13 '13 at 17:38
AH, thank you very Much :)
– user2365677
Jul 13 '13 at 17:40
|
show 1 more comment
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
you can use the .split(',') method to split a line into its separate parts, then use int() to convert the score to a number. The .sort() method sorts a list in place, and the key tells it what to sort by.
scores =
with open("scores.txt") as f:
for line in f:
name, score = line.split(',')
score = int(score)
scores.append((name, score))
scores.sort(key=lambda s: s[1])
for name, score in scores:
print(name, score)
This will give you a list of tuples containing (name, score) pairs in sorted order. If you want to print them out with a comma in between them (to keep it consistent) change the print to print(name, score, sep=', ')
The reading of the input file can also be expressed as one (big) line
with open("scores.txt") as f:
scores = [(name, int(score)) for name, score in (line.split(',') for line in f)]
A brief explanation of the key=:
a lambda function is an anonymous function, that is, a function without a name. You generally use these when you need a function only for a small operation. .sort has an optional key keyword argument that takes a function and uses the return of that function in sorting the objects.
So this lambda could also be written as
def ret_score(pair):
return pair[1]
And you could then write .sort(key=ret_score) but since we dont really need that function for anything else, its not necessary to declare it. The lambda syntax is
lambda <arguments> : <return value>
So this lambda takes a pair, and returns the second element in it. You can save a lambda and use it like a regular function if you wish.
>>> square = lambda x: x**2 # takes x, returns x squared
>>> square(3)
9
>>> square(6)
36
answered Jul 13 '13 at 17:21
Ryan HainingRyan Haining
21.6k870122
Is there a way to make it so in prints out Vertically?Like- John 3 Bobba 4 Luke 6 Matthew 13
– user2365677
Jul 13 '13 at 17:28
@user2365677 yes I just added that
– Ryan Haining
Jul 13 '13 at 17:29
Just for information sake, ".sort(key=lambda s: s[1])" i know of the .sort, what does lambda mean? It does work, its what i wanted and thank you :)
– user2365677
Jul 13 '13 at 17:31
@user2365677 I've added a quick explanation oflambdabut it can be a strange thing to understand
– Ryan Haining
Jul 13 '13 at 17:38
AH, thank you very Much :)
– user2365677
Jul 13 '13 at 17:40
|
show 1 more comment
you can use the .split(',') method to split a line into its separate parts, then use int() to convert the score to a number. The .sort() method sorts a list in place, and the key tells it what to sort by.
scores =
with open("scores.txt") as f:
for line in f:
name, score = line.split(',')
score = int(score)
scores.append((name, score))
scores.sort(key=lambda s: s[1])
for name, score in scores:
print(name, score)
This will give you a list of tuples containing (name, score) pairs in sorted order. If you want to print them out with a comma in between them (to keep it consistent) change the print to print(name, score, sep=', ')
The reading of the input file can also be expressed as one (big) line
with open("scores.txt") as f:
scores = [(name, int(score)) for name, score in (line.split(',') for line in f)]
A brief explanation of the key=:
a lambda function is an anonymous function, that is, a function without a name. You generally use these when you need a function only for a small operation. .sort has an optional key keyword argument that takes a function and uses the return of that function in sorting the objects.
So this lambda could also be written as
def ret_score(pair):
return pair[1]
And you could then write .sort(key=ret_score) but since we dont really need that function for anything else, its not necessary to declare it. The lambda syntax is
lambda <arguments> : <return value>
So this lambda takes a pair, and returns the second element in it. You can save a lambda and use it like a regular function if you wish.
>>> square = lambda x: x**2 # takes x, returns x squared
>>> square(3)
9
>>> square(6)
36
answered Jul 13 '13 at 17:21
Ryan HainingRyan Haining
21.6k870122
Is there a way to make it so in prints out Vertically?Like- John 3 Bobba 4 Luke 6 Matthew 13
– user2365677
Jul 13 '13 at 17:28
@user2365677 yes I just added that
– Ryan Haining
Jul 13 '13 at 17:29
Just for information sake, ".sort(key=lambda s: s[1])" i know of the .sort, what does lambda mean? It does work, its what i wanted and thank you :)
– user2365677
Jul 13 '13 at 17:31
@user2365677 I've added a quick explanation oflambdabut it can be a strange thing to understand
– Ryan Haining
Jul 13 '13 at 17:38
AH, thank you very Much :)
– user2365677
Jul 13 '13 at 17:40
|
show 1 more comment
you can use the .split(',') method to split a line into its separate parts, then use int() to convert the score to a number. The .sort() method sorts a list in place, and the key tells it what to sort by.
scores =
with open("scores.txt") as f:
for line in f:
name, score = line.split(',')
score = int(score)
scores.append((name, score))
scores.sort(key=lambda s: s[1])
for name, score in scores:
print(name, score)
This will give you a list of tuples containing (name, score) pairs in sorted order. If you want to print them out with a comma in between them (to keep it consistent) change the print to print(name, score, sep=', ')
The reading of the input file can also be expressed as one (big) line
with open("scores.txt") as f:
scores = [(name, int(score)) for name, score in (line.split(',') for line in f)]
A brief explanation of the key=:
a lambda function is an anonymous function, that is, a function without a name. You generally use these when you need a function only for a small operation. .sort has an optional key keyword argument that takes a function and uses the return of that function in sorting the objects.
So this lambda could also be written as
def ret_score(pair):
return pair[1]
And you could then write .sort(key=ret_score) but since we dont really need that function for anything else, its not necessary to declare it. The lambda syntax is
lambda <arguments> : <return value>
So this lambda takes a pair, and returns the second element in it. You can save a lambda and use it like a regular function if you wish.
>>> square = lambda x: x**2 # takes x, returns x squared
>>> square(3)
9
>>> square(6)
36
answered Jul 13 '13 at 17:21
Ryan HainingRyan Haining
21.6k870122
you can use the .split(',') method to split a line into its separate parts, then use int() to convert the score to a number. The .sort() method sorts a list in place, and the key tells it what to sort by.
scores =
with open("scores.txt") as f:
for line in f:
name, score = line.split(',')
score = int(score)
scores.append((name, score))
scores.sort(key=lambda s: s[1])
for name, score in scores:
print(name, score)
This will give you a list of tuples containing (name, score) pairs in sorted order. If you want to print them out with a comma in between them (to keep it consistent) change the print to print(name, score, sep=', ')
The reading of the input file can also be expressed as one (big) line
with open("scores.txt") as f:
scores = [(name, int(score)) for name, score in (line.split(',') for line in f)]
A brief explanation of the key=:
a lambda function is an anonymous function, that is, a function without a name. You generally use these when you need a function only for a small operation. .sort has an optional key keyword argument that takes a function and uses the return of that function in sorting the objects.
So this lambda could also be written as
def ret_score(pair):
return pair[1]
And you could then write .sort(key=ret_score) but since we dont really need that function for anything else, its not necessary to declare it. The lambda syntax is
lambda <arguments> : <return value>
So this lambda takes a pair, and returns the second element in it. You can save a lambda and use it like a regular function if you wish.
>>> square = lambda x: x**2 # takes x, returns x squared
>>> square(3)
9
>>> square(6)
36
answered Jul 13 '13 at 17:21
Ryan HainingRyan Haining
21.6k870122
edited Jul 13 '13 at 17:45
answered Jul 13 '13 at 17:21
Ryan HainingRyan Haining
21.6k870122
answered Jul 13 '13 at 17:21
Ryan HainingRyan Haining
21.6k870122
answered Jul 13 '13 at 17:21
Ryan HainingRyan Haining
21.6k870122
21.6k870122
Is there a way to make it so in prints out Vertically?Like- John 3 Bobba 4 Luke 6 Matthew 13
– user2365677
Jul 13 '13 at 17:28
@user2365677 yes I just added that
– Ryan Haining
Jul 13 '13 at 17:29
Just for information sake, ".sort(key=lambda s: s[1])" i know of the .sort, what does lambda mean? It does work, its what i wanted and thank you :)
– user2365677
Jul 13 '13 at 17:31
@user2365677 I've added a quick explanation oflambdabut it can be a strange thing to understand
– Ryan Haining
Jul 13 '13 at 17:38
AH, thank you very Much :)
– user2365677
Jul 13 '13 at 17:40
|
show 1 more comment
Is there a way to make it so in prints out Vertically?Like- John 3 Bobba 4 Luke 6 Matthew 13
– user2365677
Jul 13 '13 at 17:28
@user2365677 yes I just added that
– Ryan Haining
Jul 13 '13 at 17:29
Just for information sake, ".sort(key=lambda s: s[1])" i know of the .sort, what does lambda mean? It does work, its what i wanted and thank you :)
– user2365677
Jul 13 '13 at 17:31
@user2365677 I've added a quick explanation oflambdabut it can be a strange thing to understand
– Ryan Haining
Jul 13 '13 at 17:38
AH, thank you very Much :)
– user2365677
Jul 13 '13 at 17:40
Is there a way to make it so in prints out Vertically?Like- John 3 Bobba 4 Luke 6 Matthew 13
– user2365677
Jul 13 '13 at 17:28
Is there a way to make it so in prints out Vertically?Like- John 3 Bobba 4 Luke 6 Matthew 13
– user2365677
Jul 13 '13 at 17:28
@user2365677 yes I just added that
– Ryan Haining
Jul 13 '13 at 17:29
@user2365677 yes I just added that
– Ryan Haining
Jul 13 '13 at 17:29
Just for information sake, ".sort(key=lambda s: s[1])" i know of the .sort, what does lambda mean? It does work, its what i wanted and thank you :)
– user2365677
Jul 13 '13 at 17:31
Just for information sake, ".sort(key=lambda s: s[1])" i know of the .sort, what does lambda mean? It does work, its what i wanted and thank you :)
– user2365677
Jul 13 '13 at 17:31
@user2365677 I've added a quick explanation of
lambda but it can be a strange thing to understand– Ryan Haining
Jul 13 '13 at 17:38
@user2365677 I've added a quick explanation of
lambda but it can be a strange thing to understand– Ryan Haining
Jul 13 '13 at 17:38
AH, thank you very Much :)
– user2365677
Jul 13 '13 at 17:40
AH, thank you very Much :)
– user2365677
Jul 13 '13 at 17:40
|
show 1 more comment
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