Dealing with priority encoder when output is described by 3 seperate signals












1















I dont know how to deal with the third part of the priority encoder where if more than one 1 appear in the inputs the output will be the number of the most significant 1. At first i thought maybe making the for loop so the i decreases but i couldnt really apply it. And i am pretty sure there is an easier way than creating all the 4 bit combinations for the VD.



The truth table:
http://prntscr.com/limnd8
and examples of how it should work :



D3=0, D2=0, D1=0, D0=0 --> Υ1=0, Υ0=0, Zeros =1



D3=1, D2=1, D1=0, D0=1 --> Υ1=1, Υ0=1, Zeros =0



D3=0, D2=1, D1=0, D0=1 --> Υ1=1, Υ0=0, Zeros =0



module priorityenc_behav( D0, D1, D2, D3, Y0, Y1, Z);

input D0, D1, D2, D3;
output reg Y0, Y1, Z;
reg [3:0] VD;
integer i;


always @ (D0,D1,D2,D3)
begin
VD = 4'b0000;
if ({D3,D2,D1,D0} == 4'b0000)
{Y1,Y0,Z} = 3'b001;

VD = 4'b1111;
for (i=3; i>=0; i=i-1)
begin
if ((2**i) == {D3,D2,D1,D0})
begin
{Y1,Y0} = i;
Z = 0;
end
//////////////////////////
else if(VD[ == {D3,D2,D1,D0})
begin
{Y1,Y0} = i;
Z = 0;
//////////////////////
end
end


end
endmodule


I modified it very little bit but i cant control the else if statement correctly



module priorityenc_behav( D0, D1, D2, D3, Y0, Y1, Z);

input D0, D1, D2, D3;
output reg Y0, Y1, Z;
//reg [3:0] VD;
integer i;


always @ (D0,D1,D2,D3)
begin

if ({D3,D2,D1,D0} == 4'b0000)
{Y1,Y0,Z} = 3'b001;

for (i=3; i>=0; i=i-1)
begin
if ({D3,D2,D1,D0} == (2**i))
begin
{Y1,Y0} = i;
Z = 0;
end
else if({D3,D2,D1,D0}>2**i)
begin
{Y1,Y0} = i;
Z = 0;
end
end


end
endmodule


Ok, I reverted my for back so i increases and it works i think . I will leave it a little more if someone want to see anything or he/she can make the code make less space but leaving the signals as they are(or if they add one reg like the commented one kinda)










share|improve this question

























  • start with using the bitwiseor instead of the comparison: if ( ( (2**i) | {D3,D2,D1,D0})) != 0). This will ignore other '1'.

    – Serge
    Nov 15 '18 at 11:58













  • but thats the purpose of writing that(mine). to ignore other ~1~ and only those with 1 ~1~ will make the statement true. Your statement has no logical meaning (maybe)

    – lowspacetop
    Nov 15 '18 at 13:06













  • prevent* not ignore

    – lowspacetop
    Nov 15 '18 at 13:15











  • then explain it better. You said that you need the first (most significant) '1'. I did not say that your program will work as is, but this would help you to figure out the rest. If this is too complicated, try to use casez instead.

    – Serge
    Nov 15 '18 at 13:27











  • i explained ,added truth table and examples and also noted the part of the code that needs correction and completion. i dont think much more can be explained. but appreciate it. and y using case will help but i need to find that particular solution

    – lowspacetop
    Nov 15 '18 at 13:34
















1















I dont know how to deal with the third part of the priority encoder where if more than one 1 appear in the inputs the output will be the number of the most significant 1. At first i thought maybe making the for loop so the i decreases but i couldnt really apply it. And i am pretty sure there is an easier way than creating all the 4 bit combinations for the VD.



The truth table:
http://prntscr.com/limnd8
and examples of how it should work :



D3=0, D2=0, D1=0, D0=0 --> Υ1=0, Υ0=0, Zeros =1



D3=1, D2=1, D1=0, D0=1 --> Υ1=1, Υ0=1, Zeros =0



D3=0, D2=1, D1=0, D0=1 --> Υ1=1, Υ0=0, Zeros =0



module priorityenc_behav( D0, D1, D2, D3, Y0, Y1, Z);

input D0, D1, D2, D3;
output reg Y0, Y1, Z;
reg [3:0] VD;
integer i;


always @ (D0,D1,D2,D3)
begin
VD = 4'b0000;
if ({D3,D2,D1,D0} == 4'b0000)
{Y1,Y0,Z} = 3'b001;

VD = 4'b1111;
for (i=3; i>=0; i=i-1)
begin
if ((2**i) == {D3,D2,D1,D0})
begin
{Y1,Y0} = i;
Z = 0;
end
//////////////////////////
else if(VD[ == {D3,D2,D1,D0})
begin
{Y1,Y0} = i;
Z = 0;
//////////////////////
end
end


end
endmodule


I modified it very little bit but i cant control the else if statement correctly



module priorityenc_behav( D0, D1, D2, D3, Y0, Y1, Z);

input D0, D1, D2, D3;
output reg Y0, Y1, Z;
//reg [3:0] VD;
integer i;


always @ (D0,D1,D2,D3)
begin

if ({D3,D2,D1,D0} == 4'b0000)
{Y1,Y0,Z} = 3'b001;

for (i=3; i>=0; i=i-1)
begin
if ({D3,D2,D1,D0} == (2**i))
begin
{Y1,Y0} = i;
Z = 0;
end
else if({D3,D2,D1,D0}>2**i)
begin
{Y1,Y0} = i;
Z = 0;
end
end


end
endmodule


Ok, I reverted my for back so i increases and it works i think . I will leave it a little more if someone want to see anything or he/she can make the code make less space but leaving the signals as they are(or if they add one reg like the commented one kinda)










share|improve this question

























  • start with using the bitwiseor instead of the comparison: if ( ( (2**i) | {D3,D2,D1,D0})) != 0). This will ignore other '1'.

    – Serge
    Nov 15 '18 at 11:58













  • but thats the purpose of writing that(mine). to ignore other ~1~ and only those with 1 ~1~ will make the statement true. Your statement has no logical meaning (maybe)

    – lowspacetop
    Nov 15 '18 at 13:06













  • prevent* not ignore

    – lowspacetop
    Nov 15 '18 at 13:15











  • then explain it better. You said that you need the first (most significant) '1'. I did not say that your program will work as is, but this would help you to figure out the rest. If this is too complicated, try to use casez instead.

    – Serge
    Nov 15 '18 at 13:27











  • i explained ,added truth table and examples and also noted the part of the code that needs correction and completion. i dont think much more can be explained. but appreciate it. and y using case will help but i need to find that particular solution

    – lowspacetop
    Nov 15 '18 at 13:34














1












1








1








I dont know how to deal with the third part of the priority encoder where if more than one 1 appear in the inputs the output will be the number of the most significant 1. At first i thought maybe making the for loop so the i decreases but i couldnt really apply it. And i am pretty sure there is an easier way than creating all the 4 bit combinations for the VD.



The truth table:
http://prntscr.com/limnd8
and examples of how it should work :



D3=0, D2=0, D1=0, D0=0 --> Υ1=0, Υ0=0, Zeros =1



D3=1, D2=1, D1=0, D0=1 --> Υ1=1, Υ0=1, Zeros =0



D3=0, D2=1, D1=0, D0=1 --> Υ1=1, Υ0=0, Zeros =0



module priorityenc_behav( D0, D1, D2, D3, Y0, Y1, Z);

input D0, D1, D2, D3;
output reg Y0, Y1, Z;
reg [3:0] VD;
integer i;


always @ (D0,D1,D2,D3)
begin
VD = 4'b0000;
if ({D3,D2,D1,D0} == 4'b0000)
{Y1,Y0,Z} = 3'b001;

VD = 4'b1111;
for (i=3; i>=0; i=i-1)
begin
if ((2**i) == {D3,D2,D1,D0})
begin
{Y1,Y0} = i;
Z = 0;
end
//////////////////////////
else if(VD[ == {D3,D2,D1,D0})
begin
{Y1,Y0} = i;
Z = 0;
//////////////////////
end
end


end
endmodule


I modified it very little bit but i cant control the else if statement correctly



module priorityenc_behav( D0, D1, D2, D3, Y0, Y1, Z);

input D0, D1, D2, D3;
output reg Y0, Y1, Z;
//reg [3:0] VD;
integer i;


always @ (D0,D1,D2,D3)
begin

if ({D3,D2,D1,D0} == 4'b0000)
{Y1,Y0,Z} = 3'b001;

for (i=3; i>=0; i=i-1)
begin
if ({D3,D2,D1,D0} == (2**i))
begin
{Y1,Y0} = i;
Z = 0;
end
else if({D3,D2,D1,D0}>2**i)
begin
{Y1,Y0} = i;
Z = 0;
end
end


end
endmodule


Ok, I reverted my for back so i increases and it works i think . I will leave it a little more if someone want to see anything or he/she can make the code make less space but leaving the signals as they are(or if they add one reg like the commented one kinda)










share|improve this question
















I dont know how to deal with the third part of the priority encoder where if more than one 1 appear in the inputs the output will be the number of the most significant 1. At first i thought maybe making the for loop so the i decreases but i couldnt really apply it. And i am pretty sure there is an easier way than creating all the 4 bit combinations for the VD.



The truth table:
http://prntscr.com/limnd8
and examples of how it should work :



D3=0, D2=0, D1=0, D0=0 --> Υ1=0, Υ0=0, Zeros =1



D3=1, D2=1, D1=0, D0=1 --> Υ1=1, Υ0=1, Zeros =0



D3=0, D2=1, D1=0, D0=1 --> Υ1=1, Υ0=0, Zeros =0



module priorityenc_behav( D0, D1, D2, D3, Y0, Y1, Z);

input D0, D1, D2, D3;
output reg Y0, Y1, Z;
reg [3:0] VD;
integer i;


always @ (D0,D1,D2,D3)
begin
VD = 4'b0000;
if ({D3,D2,D1,D0} == 4'b0000)
{Y1,Y0,Z} = 3'b001;

VD = 4'b1111;
for (i=3; i>=0; i=i-1)
begin
if ((2**i) == {D3,D2,D1,D0})
begin
{Y1,Y0} = i;
Z = 0;
end
//////////////////////////
else if(VD[ == {D3,D2,D1,D0})
begin
{Y1,Y0} = i;
Z = 0;
//////////////////////
end
end


end
endmodule


I modified it very little bit but i cant control the else if statement correctly



module priorityenc_behav( D0, D1, D2, D3, Y0, Y1, Z);

input D0, D1, D2, D3;
output reg Y0, Y1, Z;
//reg [3:0] VD;
integer i;


always @ (D0,D1,D2,D3)
begin

if ({D3,D2,D1,D0} == 4'b0000)
{Y1,Y0,Z} = 3'b001;

for (i=3; i>=0; i=i-1)
begin
if ({D3,D2,D1,D0} == (2**i))
begin
{Y1,Y0} = i;
Z = 0;
end
else if({D3,D2,D1,D0}>2**i)
begin
{Y1,Y0} = i;
Z = 0;
end
end


end
endmodule


Ok, I reverted my for back so i increases and it works i think . I will leave it a little more if someone want to see anything or he/she can make the code make less space but leaving the signals as they are(or if they add one reg like the commented one kinda)







verilog






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share|improve this question













share|improve this question




share|improve this question








edited Nov 15 '18 at 14:54







lowspacetop

















asked Nov 15 '18 at 9:44









lowspacetoplowspacetop

376




376













  • start with using the bitwiseor instead of the comparison: if ( ( (2**i) | {D3,D2,D1,D0})) != 0). This will ignore other '1'.

    – Serge
    Nov 15 '18 at 11:58













  • but thats the purpose of writing that(mine). to ignore other ~1~ and only those with 1 ~1~ will make the statement true. Your statement has no logical meaning (maybe)

    – lowspacetop
    Nov 15 '18 at 13:06













  • prevent* not ignore

    – lowspacetop
    Nov 15 '18 at 13:15











  • then explain it better. You said that you need the first (most significant) '1'. I did not say that your program will work as is, but this would help you to figure out the rest. If this is too complicated, try to use casez instead.

    – Serge
    Nov 15 '18 at 13:27











  • i explained ,added truth table and examples and also noted the part of the code that needs correction and completion. i dont think much more can be explained. but appreciate it. and y using case will help but i need to find that particular solution

    – lowspacetop
    Nov 15 '18 at 13:34



















  • start with using the bitwiseor instead of the comparison: if ( ( (2**i) | {D3,D2,D1,D0})) != 0). This will ignore other '1'.

    – Serge
    Nov 15 '18 at 11:58













  • but thats the purpose of writing that(mine). to ignore other ~1~ and only those with 1 ~1~ will make the statement true. Your statement has no logical meaning (maybe)

    – lowspacetop
    Nov 15 '18 at 13:06













  • prevent* not ignore

    – lowspacetop
    Nov 15 '18 at 13:15











  • then explain it better. You said that you need the first (most significant) '1'. I did not say that your program will work as is, but this would help you to figure out the rest. If this is too complicated, try to use casez instead.

    – Serge
    Nov 15 '18 at 13:27











  • i explained ,added truth table and examples and also noted the part of the code that needs correction and completion. i dont think much more can be explained. but appreciate it. and y using case will help but i need to find that particular solution

    – lowspacetop
    Nov 15 '18 at 13:34

















start with using the bitwiseor instead of the comparison: if ( ( (2**i) | {D3,D2,D1,D0})) != 0). This will ignore other '1'.

– Serge
Nov 15 '18 at 11:58







start with using the bitwiseor instead of the comparison: if ( ( (2**i) | {D3,D2,D1,D0})) != 0). This will ignore other '1'.

– Serge
Nov 15 '18 at 11:58















but thats the purpose of writing that(mine). to ignore other ~1~ and only those with 1 ~1~ will make the statement true. Your statement has no logical meaning (maybe)

– lowspacetop
Nov 15 '18 at 13:06







but thats the purpose of writing that(mine). to ignore other ~1~ and only those with 1 ~1~ will make the statement true. Your statement has no logical meaning (maybe)

– lowspacetop
Nov 15 '18 at 13:06















prevent* not ignore

– lowspacetop
Nov 15 '18 at 13:15





prevent* not ignore

– lowspacetop
Nov 15 '18 at 13:15













then explain it better. You said that you need the first (most significant) '1'. I did not say that your program will work as is, but this would help you to figure out the rest. If this is too complicated, try to use casez instead.

– Serge
Nov 15 '18 at 13:27





then explain it better. You said that you need the first (most significant) '1'. I did not say that your program will work as is, but this would help you to figure out the rest. If this is too complicated, try to use casez instead.

– Serge
Nov 15 '18 at 13:27













i explained ,added truth table and examples and also noted the part of the code that needs correction and completion. i dont think much more can be explained. but appreciate it. and y using case will help but i need to find that particular solution

– lowspacetop
Nov 15 '18 at 13:34





i explained ,added truth table and examples and also noted the part of the code that needs correction and completion. i dont think much more can be explained. but appreciate it. and y using case will help but i need to find that particular solution

– lowspacetop
Nov 15 '18 at 13:34












1 Answer
1






active

oldest

votes


















2














Here is a variant based on your code which works. The idea is that you check using the first '1' in the Ds and stop checking after it. To check them you can use bitwise &.



module priorityenc_behav( D0, D1, D2, D3, Y0, Y1, Z);
input D0, D1, D2, D3;
output reg Y0, Y1, Z;

integer i;
reg flag;


always @* begin
if ({D3,D2,D1,D0} == 4'b0000)
{Y1,Y0,Z} = 3'b001;
else begin
flag = 0;
for (i=3; i>=0; i=i-1) begin
if (flag == 0 && ({D3,D2,D1,D0} & (4'b0001 << i)) != 0) begin
flag = 1;
{Y1, Y0} = i;
Z = 1'b0;
end
end
end
end

endmodule


The other version is much simpler and more readable in your case:



module priorityenc_behav( D0, D1, D2, D3, Y0, Y1, Z);

input D0, D1, D2, D3;
output reg Y0, Y1, Z;

always @* begin
casez({D3,D2,D1,D0})
4'b0000: {Y1,Y0,Z} = 3'b001;
4'b0001: {Y1,Y0,Z} = 3'b000;
4'b001?: {Y1,Y0,Z} = 3'b010;
4'b01??: {Y1,Y0,Z} = 3'b100;
4'b1???: {Y1,Y0,Z} = 3'b110;
endcase
end
endmodule





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    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    2














    Here is a variant based on your code which works. The idea is that you check using the first '1' in the Ds and stop checking after it. To check them you can use bitwise &.



    module priorityenc_behav( D0, D1, D2, D3, Y0, Y1, Z);
    input D0, D1, D2, D3;
    output reg Y0, Y1, Z;

    integer i;
    reg flag;


    always @* begin
    if ({D3,D2,D1,D0} == 4'b0000)
    {Y1,Y0,Z} = 3'b001;
    else begin
    flag = 0;
    for (i=3; i>=0; i=i-1) begin
    if (flag == 0 && ({D3,D2,D1,D0} & (4'b0001 << i)) != 0) begin
    flag = 1;
    {Y1, Y0} = i;
    Z = 1'b0;
    end
    end
    end
    end

    endmodule


    The other version is much simpler and more readable in your case:



    module priorityenc_behav( D0, D1, D2, D3, Y0, Y1, Z);

    input D0, D1, D2, D3;
    output reg Y0, Y1, Z;

    always @* begin
    casez({D3,D2,D1,D0})
    4'b0000: {Y1,Y0,Z} = 3'b001;
    4'b0001: {Y1,Y0,Z} = 3'b000;
    4'b001?: {Y1,Y0,Z} = 3'b010;
    4'b01??: {Y1,Y0,Z} = 3'b100;
    4'b1???: {Y1,Y0,Z} = 3'b110;
    endcase
    end
    endmodule





    share|improve this answer




























      2














      Here is a variant based on your code which works. The idea is that you check using the first '1' in the Ds and stop checking after it. To check them you can use bitwise &.



      module priorityenc_behav( D0, D1, D2, D3, Y0, Y1, Z);
      input D0, D1, D2, D3;
      output reg Y0, Y1, Z;

      integer i;
      reg flag;


      always @* begin
      if ({D3,D2,D1,D0} == 4'b0000)
      {Y1,Y0,Z} = 3'b001;
      else begin
      flag = 0;
      for (i=3; i>=0; i=i-1) begin
      if (flag == 0 && ({D3,D2,D1,D0} & (4'b0001 << i)) != 0) begin
      flag = 1;
      {Y1, Y0} = i;
      Z = 1'b0;
      end
      end
      end
      end

      endmodule


      The other version is much simpler and more readable in your case:



      module priorityenc_behav( D0, D1, D2, D3, Y0, Y1, Z);

      input D0, D1, D2, D3;
      output reg Y0, Y1, Z;

      always @* begin
      casez({D3,D2,D1,D0})
      4'b0000: {Y1,Y0,Z} = 3'b001;
      4'b0001: {Y1,Y0,Z} = 3'b000;
      4'b001?: {Y1,Y0,Z} = 3'b010;
      4'b01??: {Y1,Y0,Z} = 3'b100;
      4'b1???: {Y1,Y0,Z} = 3'b110;
      endcase
      end
      endmodule





      share|improve this answer


























        2












        2








        2







        Here is a variant based on your code which works. The idea is that you check using the first '1' in the Ds and stop checking after it. To check them you can use bitwise &.



        module priorityenc_behav( D0, D1, D2, D3, Y0, Y1, Z);
        input D0, D1, D2, D3;
        output reg Y0, Y1, Z;

        integer i;
        reg flag;


        always @* begin
        if ({D3,D2,D1,D0} == 4'b0000)
        {Y1,Y0,Z} = 3'b001;
        else begin
        flag = 0;
        for (i=3; i>=0; i=i-1) begin
        if (flag == 0 && ({D3,D2,D1,D0} & (4'b0001 << i)) != 0) begin
        flag = 1;
        {Y1, Y0} = i;
        Z = 1'b0;
        end
        end
        end
        end

        endmodule


        The other version is much simpler and more readable in your case:



        module priorityenc_behav( D0, D1, D2, D3, Y0, Y1, Z);

        input D0, D1, D2, D3;
        output reg Y0, Y1, Z;

        always @* begin
        casez({D3,D2,D1,D0})
        4'b0000: {Y1,Y0,Z} = 3'b001;
        4'b0001: {Y1,Y0,Z} = 3'b000;
        4'b001?: {Y1,Y0,Z} = 3'b010;
        4'b01??: {Y1,Y0,Z} = 3'b100;
        4'b1???: {Y1,Y0,Z} = 3'b110;
        endcase
        end
        endmodule





        share|improve this answer













        Here is a variant based on your code which works. The idea is that you check using the first '1' in the Ds and stop checking after it. To check them you can use bitwise &.



        module priorityenc_behav( D0, D1, D2, D3, Y0, Y1, Z);
        input D0, D1, D2, D3;
        output reg Y0, Y1, Z;

        integer i;
        reg flag;


        always @* begin
        if ({D3,D2,D1,D0} == 4'b0000)
        {Y1,Y0,Z} = 3'b001;
        else begin
        flag = 0;
        for (i=3; i>=0; i=i-1) begin
        if (flag == 0 && ({D3,D2,D1,D0} & (4'b0001 << i)) != 0) begin
        flag = 1;
        {Y1, Y0} = i;
        Z = 1'b0;
        end
        end
        end
        end

        endmodule


        The other version is much simpler and more readable in your case:



        module priorityenc_behav( D0, D1, D2, D3, Y0, Y1, Z);

        input D0, D1, D2, D3;
        output reg Y0, Y1, Z;

        always @* begin
        casez({D3,D2,D1,D0})
        4'b0000: {Y1,Y0,Z} = 3'b001;
        4'b0001: {Y1,Y0,Z} = 3'b000;
        4'b001?: {Y1,Y0,Z} = 3'b010;
        4'b01??: {Y1,Y0,Z} = 3'b100;
        4'b1???: {Y1,Y0,Z} = 3'b110;
        endcase
        end
        endmodule






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 16 '18 at 2:52









        SergeSerge

        3,82721015




        3,82721015
































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