How to yield a list to stream values to flask?












1















I have this list which is dynamically generated by querying the database, but for the purposes of this question, I use a static list for demonstration.



I want to stream values to a web page so I thought a generator is best to use. Below is my python code:



list111 = [1,2,3,4,5]
for i in list111:
def events():
print(i)
yield "data: %snn" % (i)
return Response(events(), content_type='text/event-stream')`


I am expecting this script to print 1 to 5 but instead it keeps on printing 1. Is it the wrong way to yield a list?



This is what I am using on the client side (for reference purposes):



if (!!window.EventSource) {
var source = new EventSource('/upload');
console.log(source)
source.onmessage = function(e) {
console.log(e)
var byte = e.data;
console.log(e.data)
}
}









share|improve this question

























  • You return in the first iteration of the loop, so it only returns the events generator yielding a single "data: 1nn".

    – L3viathan
    Nov 15 '18 at 9:48











  • should I add return inside events

    – Duck_dragon
    Nov 15 '18 at 9:54











  • You want to return a generator yielding several strings? Put the loop inside events

    – L3viathan
    Nov 15 '18 at 9:59











  • @L3viathan thanks got it.

    – Duck_dragon
    Nov 15 '18 at 10:04
















1















I have this list which is dynamically generated by querying the database, but for the purposes of this question, I use a static list for demonstration.



I want to stream values to a web page so I thought a generator is best to use. Below is my python code:



list111 = [1,2,3,4,5]
for i in list111:
def events():
print(i)
yield "data: %snn" % (i)
return Response(events(), content_type='text/event-stream')`


I am expecting this script to print 1 to 5 but instead it keeps on printing 1. Is it the wrong way to yield a list?



This is what I am using on the client side (for reference purposes):



if (!!window.EventSource) {
var source = new EventSource('/upload');
console.log(source)
source.onmessage = function(e) {
console.log(e)
var byte = e.data;
console.log(e.data)
}
}









share|improve this question

























  • You return in the first iteration of the loop, so it only returns the events generator yielding a single "data: 1nn".

    – L3viathan
    Nov 15 '18 at 9:48











  • should I add return inside events

    – Duck_dragon
    Nov 15 '18 at 9:54











  • You want to return a generator yielding several strings? Put the loop inside events

    – L3viathan
    Nov 15 '18 at 9:59











  • @L3viathan thanks got it.

    – Duck_dragon
    Nov 15 '18 at 10:04














1












1








1








I have this list which is dynamically generated by querying the database, but for the purposes of this question, I use a static list for demonstration.



I want to stream values to a web page so I thought a generator is best to use. Below is my python code:



list111 = [1,2,3,4,5]
for i in list111:
def events():
print(i)
yield "data: %snn" % (i)
return Response(events(), content_type='text/event-stream')`


I am expecting this script to print 1 to 5 but instead it keeps on printing 1. Is it the wrong way to yield a list?



This is what I am using on the client side (for reference purposes):



if (!!window.EventSource) {
var source = new EventSource('/upload');
console.log(source)
source.onmessage = function(e) {
console.log(e)
var byte = e.data;
console.log(e.data)
}
}









share|improve this question
















I have this list which is dynamically generated by querying the database, but for the purposes of this question, I use a static list for demonstration.



I want to stream values to a web page so I thought a generator is best to use. Below is my python code:



list111 = [1,2,3,4,5]
for i in list111:
def events():
print(i)
yield "data: %snn" % (i)
return Response(events(), content_type='text/event-stream')`


I am expecting this script to print 1 to 5 but instead it keeps on printing 1. Is it the wrong way to yield a list?



This is what I am using on the client side (for reference purposes):



if (!!window.EventSource) {
var source = new EventSource('/upload');
console.log(source)
source.onmessage = function(e) {
console.log(e)
var byte = e.data;
console.log(e.data)
}
}






python python-3.x






share|improve this question















share|improve this question













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share|improve this question








edited Nov 15 '18 at 10:17









martineau

68.5k1090183




68.5k1090183










asked Nov 15 '18 at 9:41









Duck_dragonDuck_dragon

628




628













  • You return in the first iteration of the loop, so it only returns the events generator yielding a single "data: 1nn".

    – L3viathan
    Nov 15 '18 at 9:48











  • should I add return inside events

    – Duck_dragon
    Nov 15 '18 at 9:54











  • You want to return a generator yielding several strings? Put the loop inside events

    – L3viathan
    Nov 15 '18 at 9:59











  • @L3viathan thanks got it.

    – Duck_dragon
    Nov 15 '18 at 10:04



















  • You return in the first iteration of the loop, so it only returns the events generator yielding a single "data: 1nn".

    – L3viathan
    Nov 15 '18 at 9:48











  • should I add return inside events

    – Duck_dragon
    Nov 15 '18 at 9:54











  • You want to return a generator yielding several strings? Put the loop inside events

    – L3viathan
    Nov 15 '18 at 9:59











  • @L3viathan thanks got it.

    – Duck_dragon
    Nov 15 '18 at 10:04

















You return in the first iteration of the loop, so it only returns the events generator yielding a single "data: 1nn".

– L3viathan
Nov 15 '18 at 9:48





You return in the first iteration of the loop, so it only returns the events generator yielding a single "data: 1nn".

– L3viathan
Nov 15 '18 at 9:48













should I add return inside events

– Duck_dragon
Nov 15 '18 at 9:54





should I add return inside events

– Duck_dragon
Nov 15 '18 at 9:54













You want to return a generator yielding several strings? Put the loop inside events

– L3viathan
Nov 15 '18 at 9:59





You want to return a generator yielding several strings? Put the loop inside events

– L3viathan
Nov 15 '18 at 9:59













@L3viathan thanks got it.

– Duck_dragon
Nov 15 '18 at 10:04





@L3viathan thanks got it.

– Duck_dragon
Nov 15 '18 at 10:04












1 Answer
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I got it as @L3viathan pointed out I am returning after the first iteration only. What I need to return was the for loop inside my event function.



 list111 = [1,2,3,4,5]
def events():
for i in list111:
print(i)
yield "data: %snn" % (i)
return Response(events(), content_type='text/event-stream')`





share|improve this answer























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    I got it as @L3viathan pointed out I am returning after the first iteration only. What I need to return was the for loop inside my event function.



     list111 = [1,2,3,4,5]
    def events():
    for i in list111:
    print(i)
    yield "data: %snn" % (i)
    return Response(events(), content_type='text/event-stream')`





    share|improve this answer




























      1














      I got it as @L3viathan pointed out I am returning after the first iteration only. What I need to return was the for loop inside my event function.



       list111 = [1,2,3,4,5]
      def events():
      for i in list111:
      print(i)
      yield "data: %snn" % (i)
      return Response(events(), content_type='text/event-stream')`





      share|improve this answer


























        1












        1








        1







        I got it as @L3viathan pointed out I am returning after the first iteration only. What I need to return was the for loop inside my event function.



         list111 = [1,2,3,4,5]
        def events():
        for i in list111:
        print(i)
        yield "data: %snn" % (i)
        return Response(events(), content_type='text/event-stream')`





        share|improve this answer













        I got it as @L3viathan pointed out I am returning after the first iteration only. What I need to return was the for loop inside my event function.



         list111 = [1,2,3,4,5]
        def events():
        for i in list111:
        print(i)
        yield "data: %snn" % (i)
        return Response(events(), content_type='text/event-stream')`






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 15 '18 at 10:04









        Duck_dragonDuck_dragon

        628




        628
































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