Can't return wanting type of data using Cython












0















I want to build a function that can return the most common permutation of six "R" letters plus six "B" letters, the list may looks like this:



a = ['R'] * 6 + ['B'] * 6
random.shuffle(a)
shuffle = ''.join(a)
shuffle


Output: 'BRBRRRBBRBBR'



I want to write a loop of this function to simulate the most common distribution of these strings. I did write a for loop with python and it did work, but after I import cython to accelerate this function, something goes wrong, here is the code:



'''Python Code'''
import random
def random_loop_py(times):
a = ['R'] * 6 + ['B'] * 6
count = {}
for i in range(times):
random.shuffle(a)
shuffle = ''.join(a)
if shuffle in count.keys():
count[shuffle] += 1
else:
count[shuffle] = 1
return count
%timeit random_loop_py(100000)

'''Cython Code'''
%load_ext cython
%%cython
import random
cpdef void random_loop(int size):
a = ['R'] * 6 + ['B'] * 6
count = {}
for i in range(size):
random.shuffle(a)
shuffle = ''.join(a)
if shuffle in count.keys():
count[shuffle] += 1
else:
count[shuffle] = 1
return count.values()


And Error:



Error compiling Cython file:
------------------------------------------------------------
...
shuffle = ''.join(a)
if shuffle in count.keys():
count[shuffle] += 1
else:
count[shuffle] = 1
return count.keys()
^
------------------------------------------------------------

/Users/lee_excited/.ipython/cython/_cython_magic_e70ad62499224c5d4fd4e23d6dcb9e49.pyx:12:21: Return with value in void function
---------------------------------------------------------------------------
TypeError Traceback (most recent call last)
<ipython-input-120-a09f2e5d5e69> in <module>
----> 1 get_ipython().run_cell_magic('cython', '', "import randomncpdef void random_loop(int size):n a = ['R'] * 6 + ['B'] * 6n count = {}n for i in range(size):n random.shuffle(a)n shuffle = ''.join(a)n if shuffle in count.keys():n count[shuffle] += 1n else:n count[shuffle] = 1n return count.keys()n")

~/anaconda3/lib/python3.6/site-packages/IPython/core/interactiveshell.py in run_cell_magic(self, magic_name, line, cell)
2321 magic_arg_s = self.var_expand(line, stack_depth)
2322 with self.builtin_trap:
-> 2323 result = fn(magic_arg_s, cell)
2324 return result
2325

<decorator-gen-127> in cython(self, line, cell)

~/anaconda3/lib/python3.6/site-packages/IPython/core/magic.py in <lambda>(f, *a, **k)
185 # but it's overkill for just that one bit of state.
186 def magic_deco(arg):
--> 187 call = lambda f, *a, **k: f(*a, **k)
188
189 if callable(arg):

~/anaconda3/lib/python3.6/site-packages/Cython/Build/IpythonMagic.py in cython(self, line, cell)
323 if need_cythonize:
324 extensions = self._cythonize(module_name, code, lib_dir, args, quiet=args.quiet)
--> 325 assert len(extensions) == 1
326 extension = extensions[0]
327 self._code_cache[key] = module_name

TypeError: object of type 'NoneType' has no len()


What kind of data should I return to accelerate my simulation, please?










share|improve this question

























  • Please, post your code and exceptions as text.

    – Eli Korvigo
    Nov 14 '18 at 12:38











  • OK, I have added the code.

    – Weizhe Li
    Nov 14 '18 at 12:44











  • Remove the screenshots entirely. Including the output.

    – Mad Physicist
    Nov 14 '18 at 12:50











  • OK, deleted and rearranged issue structure.

    – Weizhe Li
    Nov 14 '18 at 12:57











  • OK, deleted and rearranged issue structure. @MadPhysicist

    – Weizhe Li
    Nov 14 '18 at 13:03
















0















I want to build a function that can return the most common permutation of six "R" letters plus six "B" letters, the list may looks like this:



a = ['R'] * 6 + ['B'] * 6
random.shuffle(a)
shuffle = ''.join(a)
shuffle


Output: 'BRBRRRBBRBBR'



I want to write a loop of this function to simulate the most common distribution of these strings. I did write a for loop with python and it did work, but after I import cython to accelerate this function, something goes wrong, here is the code:



'''Python Code'''
import random
def random_loop_py(times):
a = ['R'] * 6 + ['B'] * 6
count = {}
for i in range(times):
random.shuffle(a)
shuffle = ''.join(a)
if shuffle in count.keys():
count[shuffle] += 1
else:
count[shuffle] = 1
return count
%timeit random_loop_py(100000)

'''Cython Code'''
%load_ext cython
%%cython
import random
cpdef void random_loop(int size):
a = ['R'] * 6 + ['B'] * 6
count = {}
for i in range(size):
random.shuffle(a)
shuffle = ''.join(a)
if shuffle in count.keys():
count[shuffle] += 1
else:
count[shuffle] = 1
return count.values()


And Error:



Error compiling Cython file:
------------------------------------------------------------
...
shuffle = ''.join(a)
if shuffle in count.keys():
count[shuffle] += 1
else:
count[shuffle] = 1
return count.keys()
^
------------------------------------------------------------

/Users/lee_excited/.ipython/cython/_cython_magic_e70ad62499224c5d4fd4e23d6dcb9e49.pyx:12:21: Return with value in void function
---------------------------------------------------------------------------
TypeError Traceback (most recent call last)
<ipython-input-120-a09f2e5d5e69> in <module>
----> 1 get_ipython().run_cell_magic('cython', '', "import randomncpdef void random_loop(int size):n a = ['R'] * 6 + ['B'] * 6n count = {}n for i in range(size):n random.shuffle(a)n shuffle = ''.join(a)n if shuffle in count.keys():n count[shuffle] += 1n else:n count[shuffle] = 1n return count.keys()n")

~/anaconda3/lib/python3.6/site-packages/IPython/core/interactiveshell.py in run_cell_magic(self, magic_name, line, cell)
2321 magic_arg_s = self.var_expand(line, stack_depth)
2322 with self.builtin_trap:
-> 2323 result = fn(magic_arg_s, cell)
2324 return result
2325

<decorator-gen-127> in cython(self, line, cell)

~/anaconda3/lib/python3.6/site-packages/IPython/core/magic.py in <lambda>(f, *a, **k)
185 # but it's overkill for just that one bit of state.
186 def magic_deco(arg):
--> 187 call = lambda f, *a, **k: f(*a, **k)
188
189 if callable(arg):

~/anaconda3/lib/python3.6/site-packages/Cython/Build/IpythonMagic.py in cython(self, line, cell)
323 if need_cythonize:
324 extensions = self._cythonize(module_name, code, lib_dir, args, quiet=args.quiet)
--> 325 assert len(extensions) == 1
326 extension = extensions[0]
327 self._code_cache[key] = module_name

TypeError: object of type 'NoneType' has no len()


What kind of data should I return to accelerate my simulation, please?










share|improve this question

























  • Please, post your code and exceptions as text.

    – Eli Korvigo
    Nov 14 '18 at 12:38











  • OK, I have added the code.

    – Weizhe Li
    Nov 14 '18 at 12:44











  • Remove the screenshots entirely. Including the output.

    – Mad Physicist
    Nov 14 '18 at 12:50











  • OK, deleted and rearranged issue structure.

    – Weizhe Li
    Nov 14 '18 at 12:57











  • OK, deleted and rearranged issue structure. @MadPhysicist

    – Weizhe Li
    Nov 14 '18 at 13:03














0












0








0








I want to build a function that can return the most common permutation of six "R" letters plus six "B" letters, the list may looks like this:



a = ['R'] * 6 + ['B'] * 6
random.shuffle(a)
shuffle = ''.join(a)
shuffle


Output: 'BRBRRRBBRBBR'



I want to write a loop of this function to simulate the most common distribution of these strings. I did write a for loop with python and it did work, but after I import cython to accelerate this function, something goes wrong, here is the code:



'''Python Code'''
import random
def random_loop_py(times):
a = ['R'] * 6 + ['B'] * 6
count = {}
for i in range(times):
random.shuffle(a)
shuffle = ''.join(a)
if shuffle in count.keys():
count[shuffle] += 1
else:
count[shuffle] = 1
return count
%timeit random_loop_py(100000)

'''Cython Code'''
%load_ext cython
%%cython
import random
cpdef void random_loop(int size):
a = ['R'] * 6 + ['B'] * 6
count = {}
for i in range(size):
random.shuffle(a)
shuffle = ''.join(a)
if shuffle in count.keys():
count[shuffle] += 1
else:
count[shuffle] = 1
return count.values()


And Error:



Error compiling Cython file:
------------------------------------------------------------
...
shuffle = ''.join(a)
if shuffle in count.keys():
count[shuffle] += 1
else:
count[shuffle] = 1
return count.keys()
^
------------------------------------------------------------

/Users/lee_excited/.ipython/cython/_cython_magic_e70ad62499224c5d4fd4e23d6dcb9e49.pyx:12:21: Return with value in void function
---------------------------------------------------------------------------
TypeError Traceback (most recent call last)
<ipython-input-120-a09f2e5d5e69> in <module>
----> 1 get_ipython().run_cell_magic('cython', '', "import randomncpdef void random_loop(int size):n a = ['R'] * 6 + ['B'] * 6n count = {}n for i in range(size):n random.shuffle(a)n shuffle = ''.join(a)n if shuffle in count.keys():n count[shuffle] += 1n else:n count[shuffle] = 1n return count.keys()n")

~/anaconda3/lib/python3.6/site-packages/IPython/core/interactiveshell.py in run_cell_magic(self, magic_name, line, cell)
2321 magic_arg_s = self.var_expand(line, stack_depth)
2322 with self.builtin_trap:
-> 2323 result = fn(magic_arg_s, cell)
2324 return result
2325

<decorator-gen-127> in cython(self, line, cell)

~/anaconda3/lib/python3.6/site-packages/IPython/core/magic.py in <lambda>(f, *a, **k)
185 # but it's overkill for just that one bit of state.
186 def magic_deco(arg):
--> 187 call = lambda f, *a, **k: f(*a, **k)
188
189 if callable(arg):

~/anaconda3/lib/python3.6/site-packages/Cython/Build/IpythonMagic.py in cython(self, line, cell)
323 if need_cythonize:
324 extensions = self._cythonize(module_name, code, lib_dir, args, quiet=args.quiet)
--> 325 assert len(extensions) == 1
326 extension = extensions[0]
327 self._code_cache[key] = module_name

TypeError: object of type 'NoneType' has no len()


What kind of data should I return to accelerate my simulation, please?










share|improve this question
















I want to build a function that can return the most common permutation of six "R" letters plus six "B" letters, the list may looks like this:



a = ['R'] * 6 + ['B'] * 6
random.shuffle(a)
shuffle = ''.join(a)
shuffle


Output: 'BRBRRRBBRBBR'



I want to write a loop of this function to simulate the most common distribution of these strings. I did write a for loop with python and it did work, but after I import cython to accelerate this function, something goes wrong, here is the code:



'''Python Code'''
import random
def random_loop_py(times):
a = ['R'] * 6 + ['B'] * 6
count = {}
for i in range(times):
random.shuffle(a)
shuffle = ''.join(a)
if shuffle in count.keys():
count[shuffle] += 1
else:
count[shuffle] = 1
return count
%timeit random_loop_py(100000)

'''Cython Code'''
%load_ext cython
%%cython
import random
cpdef void random_loop(int size):
a = ['R'] * 6 + ['B'] * 6
count = {}
for i in range(size):
random.shuffle(a)
shuffle = ''.join(a)
if shuffle in count.keys():
count[shuffle] += 1
else:
count[shuffle] = 1
return count.values()


And Error:



Error compiling Cython file:
------------------------------------------------------------
...
shuffle = ''.join(a)
if shuffle in count.keys():
count[shuffle] += 1
else:
count[shuffle] = 1
return count.keys()
^
------------------------------------------------------------

/Users/lee_excited/.ipython/cython/_cython_magic_e70ad62499224c5d4fd4e23d6dcb9e49.pyx:12:21: Return with value in void function
---------------------------------------------------------------------------
TypeError Traceback (most recent call last)
<ipython-input-120-a09f2e5d5e69> in <module>
----> 1 get_ipython().run_cell_magic('cython', '', "import randomncpdef void random_loop(int size):n a = ['R'] * 6 + ['B'] * 6n count = {}n for i in range(size):n random.shuffle(a)n shuffle = ''.join(a)n if shuffle in count.keys():n count[shuffle] += 1n else:n count[shuffle] = 1n return count.keys()n")

~/anaconda3/lib/python3.6/site-packages/IPython/core/interactiveshell.py in run_cell_magic(self, magic_name, line, cell)
2321 magic_arg_s = self.var_expand(line, stack_depth)
2322 with self.builtin_trap:
-> 2323 result = fn(magic_arg_s, cell)
2324 return result
2325

<decorator-gen-127> in cython(self, line, cell)

~/anaconda3/lib/python3.6/site-packages/IPython/core/magic.py in <lambda>(f, *a, **k)
185 # but it's overkill for just that one bit of state.
186 def magic_deco(arg):
--> 187 call = lambda f, *a, **k: f(*a, **k)
188
189 if callable(arg):

~/anaconda3/lib/python3.6/site-packages/Cython/Build/IpythonMagic.py in cython(self, line, cell)
323 if need_cythonize:
324 extensions = self._cythonize(module_name, code, lib_dir, args, quiet=args.quiet)
--> 325 assert len(extensions) == 1
326 extension = extensions[0]
327 self._code_cache[key] = module_name

TypeError: object of type 'NoneType' has no len()


What kind of data should I return to accelerate my simulation, please?







python cython cythonize






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 14 '18 at 12:56







Weizhe Li

















asked Nov 14 '18 at 12:36









Weizhe LiWeizhe Li

12




12













  • Please, post your code and exceptions as text.

    – Eli Korvigo
    Nov 14 '18 at 12:38











  • OK, I have added the code.

    – Weizhe Li
    Nov 14 '18 at 12:44











  • Remove the screenshots entirely. Including the output.

    – Mad Physicist
    Nov 14 '18 at 12:50











  • OK, deleted and rearranged issue structure.

    – Weizhe Li
    Nov 14 '18 at 12:57











  • OK, deleted and rearranged issue structure. @MadPhysicist

    – Weizhe Li
    Nov 14 '18 at 13:03



















  • Please, post your code and exceptions as text.

    – Eli Korvigo
    Nov 14 '18 at 12:38











  • OK, I have added the code.

    – Weizhe Li
    Nov 14 '18 at 12:44











  • Remove the screenshots entirely. Including the output.

    – Mad Physicist
    Nov 14 '18 at 12:50











  • OK, deleted and rearranged issue structure.

    – Weizhe Li
    Nov 14 '18 at 12:57











  • OK, deleted and rearranged issue structure. @MadPhysicist

    – Weizhe Li
    Nov 14 '18 at 13:03

















Please, post your code and exceptions as text.

– Eli Korvigo
Nov 14 '18 at 12:38





Please, post your code and exceptions as text.

– Eli Korvigo
Nov 14 '18 at 12:38













OK, I have added the code.

– Weizhe Li
Nov 14 '18 at 12:44





OK, I have added the code.

– Weizhe Li
Nov 14 '18 at 12:44













Remove the screenshots entirely. Including the output.

– Mad Physicist
Nov 14 '18 at 12:50





Remove the screenshots entirely. Including the output.

– Mad Physicist
Nov 14 '18 at 12:50













OK, deleted and rearranged issue structure.

– Weizhe Li
Nov 14 '18 at 12:57





OK, deleted and rearranged issue structure.

– Weizhe Li
Nov 14 '18 at 12:57













OK, deleted and rearranged issue structure. @MadPhysicist

– Weizhe Li
Nov 14 '18 at 13:03





OK, deleted and rearranged issue structure. @MadPhysicist

– Weizhe Li
Nov 14 '18 at 13:03












1 Answer
1






active

oldest

votes


















0














Your function has a void return type:



cpdef void random_loop(int size):
...
return count.values()


Consequently, you are not supposed to return anything from it, and the exception message is very clear on that. Change the return type to list:



cpdef list random_loop(int size):
...
return list(count.values())


P.S.



Your function is not very Cython-friendly: I don't think you will get significant performance improvements.



Update



I can't reproduce your error after the fix



In [9]: %%cython
...: import random
...: cpdef list random_loop(int size):
...: a = ['R'] * 6 + ['B'] * 6
...: count = {}
...: for i in range(size):
...: random.shuffle(a)
...: shuffle = ''.join(a)
...: if shuffle in count.keys():
...: count[shuffle] += 1
...: else:
...: count[shuffle] = 1
...: return list(count.values())
...:

In [10]: random_loop(10)
Out[10]: [1, 1, 1, 1, 1, 1, 1, 1, 1, 1]


As you can see, it compiles perfectly fine.






share|improve this answer


























  • Tried, still Error /(ㄒoㄒ)/~~

    – Weizhe Li
    Nov 14 '18 at 12:45











  • @WeizheLi You should clarify whether that is the same error or a new one

    – Eli Korvigo
    Nov 14 '18 at 12:45











  • Same error as previous one.

    – Weizhe Li
    Nov 14 '18 at 12:46











  • Actually I tried print(count.values()) and it works, about 10 times acceleration, so I tried to directly return the dict, but something went wrong. sad.

    – Weizhe Li
    Nov 14 '18 at 12:48











  • @WeizheLi I can't reproduce your error. See the update

    – Eli Korvigo
    Nov 14 '18 at 12:49













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1 Answer
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active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









0














Your function has a void return type:



cpdef void random_loop(int size):
...
return count.values()


Consequently, you are not supposed to return anything from it, and the exception message is very clear on that. Change the return type to list:



cpdef list random_loop(int size):
...
return list(count.values())


P.S.



Your function is not very Cython-friendly: I don't think you will get significant performance improvements.



Update



I can't reproduce your error after the fix



In [9]: %%cython
...: import random
...: cpdef list random_loop(int size):
...: a = ['R'] * 6 + ['B'] * 6
...: count = {}
...: for i in range(size):
...: random.shuffle(a)
...: shuffle = ''.join(a)
...: if shuffle in count.keys():
...: count[shuffle] += 1
...: else:
...: count[shuffle] = 1
...: return list(count.values())
...:

In [10]: random_loop(10)
Out[10]: [1, 1, 1, 1, 1, 1, 1, 1, 1, 1]


As you can see, it compiles perfectly fine.






share|improve this answer


























  • Tried, still Error /(ㄒoㄒ)/~~

    – Weizhe Li
    Nov 14 '18 at 12:45











  • @WeizheLi You should clarify whether that is the same error or a new one

    – Eli Korvigo
    Nov 14 '18 at 12:45











  • Same error as previous one.

    – Weizhe Li
    Nov 14 '18 at 12:46











  • Actually I tried print(count.values()) and it works, about 10 times acceleration, so I tried to directly return the dict, but something went wrong. sad.

    – Weizhe Li
    Nov 14 '18 at 12:48











  • @WeizheLi I can't reproduce your error. See the update

    – Eli Korvigo
    Nov 14 '18 at 12:49


















0














Your function has a void return type:



cpdef void random_loop(int size):
...
return count.values()


Consequently, you are not supposed to return anything from it, and the exception message is very clear on that. Change the return type to list:



cpdef list random_loop(int size):
...
return list(count.values())


P.S.



Your function is not very Cython-friendly: I don't think you will get significant performance improvements.



Update



I can't reproduce your error after the fix



In [9]: %%cython
...: import random
...: cpdef list random_loop(int size):
...: a = ['R'] * 6 + ['B'] * 6
...: count = {}
...: for i in range(size):
...: random.shuffle(a)
...: shuffle = ''.join(a)
...: if shuffle in count.keys():
...: count[shuffle] += 1
...: else:
...: count[shuffle] = 1
...: return list(count.values())
...:

In [10]: random_loop(10)
Out[10]: [1, 1, 1, 1, 1, 1, 1, 1, 1, 1]


As you can see, it compiles perfectly fine.






share|improve this answer


























  • Tried, still Error /(ㄒoㄒ)/~~

    – Weizhe Li
    Nov 14 '18 at 12:45











  • @WeizheLi You should clarify whether that is the same error or a new one

    – Eli Korvigo
    Nov 14 '18 at 12:45











  • Same error as previous one.

    – Weizhe Li
    Nov 14 '18 at 12:46











  • Actually I tried print(count.values()) and it works, about 10 times acceleration, so I tried to directly return the dict, but something went wrong. sad.

    – Weizhe Li
    Nov 14 '18 at 12:48











  • @WeizheLi I can't reproduce your error. See the update

    – Eli Korvigo
    Nov 14 '18 at 12:49
















0












0








0







Your function has a void return type:



cpdef void random_loop(int size):
...
return count.values()


Consequently, you are not supposed to return anything from it, and the exception message is very clear on that. Change the return type to list:



cpdef list random_loop(int size):
...
return list(count.values())


P.S.



Your function is not very Cython-friendly: I don't think you will get significant performance improvements.



Update



I can't reproduce your error after the fix



In [9]: %%cython
...: import random
...: cpdef list random_loop(int size):
...: a = ['R'] * 6 + ['B'] * 6
...: count = {}
...: for i in range(size):
...: random.shuffle(a)
...: shuffle = ''.join(a)
...: if shuffle in count.keys():
...: count[shuffle] += 1
...: else:
...: count[shuffle] = 1
...: return list(count.values())
...:

In [10]: random_loop(10)
Out[10]: [1, 1, 1, 1, 1, 1, 1, 1, 1, 1]


As you can see, it compiles perfectly fine.






share|improve this answer















Your function has a void return type:



cpdef void random_loop(int size):
...
return count.values()


Consequently, you are not supposed to return anything from it, and the exception message is very clear on that. Change the return type to list:



cpdef list random_loop(int size):
...
return list(count.values())


P.S.



Your function is not very Cython-friendly: I don't think you will get significant performance improvements.



Update



I can't reproduce your error after the fix



In [9]: %%cython
...: import random
...: cpdef list random_loop(int size):
...: a = ['R'] * 6 + ['B'] * 6
...: count = {}
...: for i in range(size):
...: random.shuffle(a)
...: shuffle = ''.join(a)
...: if shuffle in count.keys():
...: count[shuffle] += 1
...: else:
...: count[shuffle] = 1
...: return list(count.values())
...:

In [10]: random_loop(10)
Out[10]: [1, 1, 1, 1, 1, 1, 1, 1, 1, 1]


As you can see, it compiles perfectly fine.







share|improve this answer














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edited Nov 14 '18 at 12:53

























answered Nov 14 '18 at 12:41









Eli KorvigoEli Korvigo

6,12022747




6,12022747













  • Tried, still Error /(ㄒoㄒ)/~~

    – Weizhe Li
    Nov 14 '18 at 12:45











  • @WeizheLi You should clarify whether that is the same error or a new one

    – Eli Korvigo
    Nov 14 '18 at 12:45











  • Same error as previous one.

    – Weizhe Li
    Nov 14 '18 at 12:46











  • Actually I tried print(count.values()) and it works, about 10 times acceleration, so I tried to directly return the dict, but something went wrong. sad.

    – Weizhe Li
    Nov 14 '18 at 12:48











  • @WeizheLi I can't reproduce your error. See the update

    – Eli Korvigo
    Nov 14 '18 at 12:49





















  • Tried, still Error /(ㄒoㄒ)/~~

    – Weizhe Li
    Nov 14 '18 at 12:45











  • @WeizheLi You should clarify whether that is the same error or a new one

    – Eli Korvigo
    Nov 14 '18 at 12:45











  • Same error as previous one.

    – Weizhe Li
    Nov 14 '18 at 12:46











  • Actually I tried print(count.values()) and it works, about 10 times acceleration, so I tried to directly return the dict, but something went wrong. sad.

    – Weizhe Li
    Nov 14 '18 at 12:48











  • @WeizheLi I can't reproduce your error. See the update

    – Eli Korvigo
    Nov 14 '18 at 12:49



















Tried, still Error /(ㄒoㄒ)/~~

– Weizhe Li
Nov 14 '18 at 12:45





Tried, still Error /(ㄒoㄒ)/~~

– Weizhe Li
Nov 14 '18 at 12:45













@WeizheLi You should clarify whether that is the same error or a new one

– Eli Korvigo
Nov 14 '18 at 12:45





@WeizheLi You should clarify whether that is the same error or a new one

– Eli Korvigo
Nov 14 '18 at 12:45













Same error as previous one.

– Weizhe Li
Nov 14 '18 at 12:46





Same error as previous one.

– Weizhe Li
Nov 14 '18 at 12:46













Actually I tried print(count.values()) and it works, about 10 times acceleration, so I tried to directly return the dict, but something went wrong. sad.

– Weizhe Li
Nov 14 '18 at 12:48





Actually I tried print(count.values()) and it works, about 10 times acceleration, so I tried to directly return the dict, but something went wrong. sad.

– Weizhe Li
Nov 14 '18 at 12:48













@WeizheLi I can't reproduce your error. See the update

– Eli Korvigo
Nov 14 '18 at 12:49







@WeizheLi I can't reproduce your error. See the update

– Eli Korvigo
Nov 14 '18 at 12:49






















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