beautify by serializing class to generate token in C#
I need to prepare some token make request over rest API. I already did this and works fine but as you guess its kinda look like very dirty way to handle this.
var dict = new Dictionary<string, string>();
dict.Add("Parameter1", tokenData.par1);
dict.Add("Parameter2", tokenData.par2);
using (HttpClient cliesssnt = new HttpClient())
{
cliesssnt.DefaultRequestHeaders.Accept.Add(new MediaTypeWithQualityHeaderValue("application/json"));
var token =new FormUrlEncodedContent(dict);
HttpResponseMessage respossnse =
cliesssnt.PostAsync("https://someurl", token ).Result;
var result= respossnse.Content.ReadAsStringAsync().Result;
}
class:
public class ERaporAuthVM
{
[JsonProperty("Parameter1")]
public int par1 { get; set; }
[JsonProperty("Parameter2")]
public string par2 { get; set; }
}
I wish I could do something like this to preapre this token;
var token = JsonSerializer<ERaporAuthVM>(tokenData);
but how can I make it work this way?
asp.net rest
add a comment |
I need to prepare some token make request over rest API. I already did this and works fine but as you guess its kinda look like very dirty way to handle this.
var dict = new Dictionary<string, string>();
dict.Add("Parameter1", tokenData.par1);
dict.Add("Parameter2", tokenData.par2);
using (HttpClient cliesssnt = new HttpClient())
{
cliesssnt.DefaultRequestHeaders.Accept.Add(new MediaTypeWithQualityHeaderValue("application/json"));
var token =new FormUrlEncodedContent(dict);
HttpResponseMessage respossnse =
cliesssnt.PostAsync("https://someurl", token ).Result;
var result= respossnse.Content.ReadAsStringAsync().Result;
}
class:
public class ERaporAuthVM
{
[JsonProperty("Parameter1")]
public int par1 { get; set; }
[JsonProperty("Parameter2")]
public string par2 { get; set; }
}
I wish I could do something like this to preapre this token;
var token = JsonSerializer<ERaporAuthVM>(tokenData);
but how can I make it work this way?
asp.net rest
You can try to createdict
dynamically via reflection
– Slava Utesinov
Nov 13 '18 at 9:49
@SlavaUtesinov "Talk is cheap, show me the code!" Linus Torvalds. :)
– TyForHelpDude
Nov 13 '18 at 9:51
add a comment |
I need to prepare some token make request over rest API. I already did this and works fine but as you guess its kinda look like very dirty way to handle this.
var dict = new Dictionary<string, string>();
dict.Add("Parameter1", tokenData.par1);
dict.Add("Parameter2", tokenData.par2);
using (HttpClient cliesssnt = new HttpClient())
{
cliesssnt.DefaultRequestHeaders.Accept.Add(new MediaTypeWithQualityHeaderValue("application/json"));
var token =new FormUrlEncodedContent(dict);
HttpResponseMessage respossnse =
cliesssnt.PostAsync("https://someurl", token ).Result;
var result= respossnse.Content.ReadAsStringAsync().Result;
}
class:
public class ERaporAuthVM
{
[JsonProperty("Parameter1")]
public int par1 { get; set; }
[JsonProperty("Parameter2")]
public string par2 { get; set; }
}
I wish I could do something like this to preapre this token;
var token = JsonSerializer<ERaporAuthVM>(tokenData);
but how can I make it work this way?
asp.net rest
I need to prepare some token make request over rest API. I already did this and works fine but as you guess its kinda look like very dirty way to handle this.
var dict = new Dictionary<string, string>();
dict.Add("Parameter1", tokenData.par1);
dict.Add("Parameter2", tokenData.par2);
using (HttpClient cliesssnt = new HttpClient())
{
cliesssnt.DefaultRequestHeaders.Accept.Add(new MediaTypeWithQualityHeaderValue("application/json"));
var token =new FormUrlEncodedContent(dict);
HttpResponseMessage respossnse =
cliesssnt.PostAsync("https://someurl", token ).Result;
var result= respossnse.Content.ReadAsStringAsync().Result;
}
class:
public class ERaporAuthVM
{
[JsonProperty("Parameter1")]
public int par1 { get; set; }
[JsonProperty("Parameter2")]
public string par2 { get; set; }
}
I wish I could do something like this to preapre this token;
var token = JsonSerializer<ERaporAuthVM>(tokenData);
but how can I make it work this way?
asp.net rest
asp.net rest
asked Nov 13 '18 at 9:42
TyForHelpDudeTyForHelpDude
1,44732546
1,44732546
You can try to createdict
dynamically via reflection
– Slava Utesinov
Nov 13 '18 at 9:49
@SlavaUtesinov "Talk is cheap, show me the code!" Linus Torvalds. :)
– TyForHelpDude
Nov 13 '18 at 9:51
add a comment |
You can try to createdict
dynamically via reflection
– Slava Utesinov
Nov 13 '18 at 9:49
@SlavaUtesinov "Talk is cheap, show me the code!" Linus Torvalds. :)
– TyForHelpDude
Nov 13 '18 at 9:51
You can try to create
dict
dynamically via reflection– Slava Utesinov
Nov 13 '18 at 9:49
You can try to create
dict
dynamically via reflection– Slava Utesinov
Nov 13 '18 at 9:49
@SlavaUtesinov "Talk is cheap, show me the code!" Linus Torvalds. :)
– TyForHelpDude
Nov 13 '18 at 9:51
@SlavaUtesinov "Talk is cheap, show me the code!" Linus Torvalds. :)
– TyForHelpDude
Nov 13 '18 at 9:51
add a comment |
1 Answer
1
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oldest
votes
public FormUrlEncodedContent JsonSerializer<T>(T input) where T : class
{
var result = new Dictionary<string, string>();
foreach(var prop in input.GetType().GetProperties())
{
var value = prop.GetValue(input);
//to-do: get name from JsonPropertyAttribute if exists
result.Add(prop.Name, value == null ? null : value.ToString());
}
return new FormUrlEncodedContent(result);
}
Usage:
var token = JsonSerializer(tokenData);
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
public FormUrlEncodedContent JsonSerializer<T>(T input) where T : class
{
var result = new Dictionary<string, string>();
foreach(var prop in input.GetType().GetProperties())
{
var value = prop.GetValue(input);
//to-do: get name from JsonPropertyAttribute if exists
result.Add(prop.Name, value == null ? null : value.ToString());
}
return new FormUrlEncodedContent(result);
}
Usage:
var token = JsonSerializer(tokenData);
add a comment |
public FormUrlEncodedContent JsonSerializer<T>(T input) where T : class
{
var result = new Dictionary<string, string>();
foreach(var prop in input.GetType().GetProperties())
{
var value = prop.GetValue(input);
//to-do: get name from JsonPropertyAttribute if exists
result.Add(prop.Name, value == null ? null : value.ToString());
}
return new FormUrlEncodedContent(result);
}
Usage:
var token = JsonSerializer(tokenData);
add a comment |
public FormUrlEncodedContent JsonSerializer<T>(T input) where T : class
{
var result = new Dictionary<string, string>();
foreach(var prop in input.GetType().GetProperties())
{
var value = prop.GetValue(input);
//to-do: get name from JsonPropertyAttribute if exists
result.Add(prop.Name, value == null ? null : value.ToString());
}
return new FormUrlEncodedContent(result);
}
Usage:
var token = JsonSerializer(tokenData);
public FormUrlEncodedContent JsonSerializer<T>(T input) where T : class
{
var result = new Dictionary<string, string>();
foreach(var prop in input.GetType().GetProperties())
{
var value = prop.GetValue(input);
//to-do: get name from JsonPropertyAttribute if exists
result.Add(prop.Name, value == null ? null : value.ToString());
}
return new FormUrlEncodedContent(result);
}
Usage:
var token = JsonSerializer(tokenData);
edited Nov 14 '18 at 6:04
answered Nov 13 '18 at 9:55
Slava UtesinovSlava Utesinov
10.7k2922
10.7k2922
add a comment |
add a comment |
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You can try to create
dict
dynamically via reflection– Slava Utesinov
Nov 13 '18 at 9:49
@SlavaUtesinov "Talk is cheap, show me the code!" Linus Torvalds. :)
– TyForHelpDude
Nov 13 '18 at 9:51