Windows Authenticated database on WebMethod not working












0














I have tried using SQL Server authenticated Database it worked but with this Windows authenticated DB, I can't figure out what to do.
What could be the problem?



[WebMethod]



public static List<string> GetEmployeeName(string empName)
{
List<string> Models = new List<string>();
using (SqlConnection con = new SqlConnection(@"Data Source=PHAPPCVTSQL04; Initial Catalog=ECP_IQCDATA_SEM; Integrated Security=True;"))
{
using (SqlCommand cmd = new SqlCommand())
{
cmd.CommandText = "SELECT DISTINCT [Model] FROM [MRB_Model-Approver]";
con.Open();
cmd.Parameters.AddWithValue("@SearchModel", empName);
SqlDataReader dr = cmd.ExecuteReader();
while (dr.Read())
{
Models.Add(dr["Model"].ToString());
}
con.Close();
return Models;
}
}
}









share|improve this question



























    0














    I have tried using SQL Server authenticated Database it worked but with this Windows authenticated DB, I can't figure out what to do.
    What could be the problem?



    [WebMethod]



    public static List<string> GetEmployeeName(string empName)
    {
    List<string> Models = new List<string>();
    using (SqlConnection con = new SqlConnection(@"Data Source=PHAPPCVTSQL04; Initial Catalog=ECP_IQCDATA_SEM; Integrated Security=True;"))
    {
    using (SqlCommand cmd = new SqlCommand())
    {
    cmd.CommandText = "SELECT DISTINCT [Model] FROM [MRB_Model-Approver]";
    con.Open();
    cmd.Parameters.AddWithValue("@SearchModel", empName);
    SqlDataReader dr = cmd.ExecuteReader();
    while (dr.Read())
    {
    Models.Add(dr["Model"].ToString());
    }
    con.Close();
    return Models;
    }
    }
    }









    share|improve this question

























      0












      0








      0







      I have tried using SQL Server authenticated Database it worked but with this Windows authenticated DB, I can't figure out what to do.
      What could be the problem?



      [WebMethod]



      public static List<string> GetEmployeeName(string empName)
      {
      List<string> Models = new List<string>();
      using (SqlConnection con = new SqlConnection(@"Data Source=PHAPPCVTSQL04; Initial Catalog=ECP_IQCDATA_SEM; Integrated Security=True;"))
      {
      using (SqlCommand cmd = new SqlCommand())
      {
      cmd.CommandText = "SELECT DISTINCT [Model] FROM [MRB_Model-Approver]";
      con.Open();
      cmd.Parameters.AddWithValue("@SearchModel", empName);
      SqlDataReader dr = cmd.ExecuteReader();
      while (dr.Read())
      {
      Models.Add(dr["Model"].ToString());
      }
      con.Close();
      return Models;
      }
      }
      }









      share|improve this question













      I have tried using SQL Server authenticated Database it worked but with this Windows authenticated DB, I can't figure out what to do.
      What could be the problem?



      [WebMethod]



      public static List<string> GetEmployeeName(string empName)
      {
      List<string> Models = new List<string>();
      using (SqlConnection con = new SqlConnection(@"Data Source=PHAPPCVTSQL04; Initial Catalog=ECP_IQCDATA_SEM; Integrated Security=True;"))
      {
      using (SqlCommand cmd = new SqlCommand())
      {
      cmd.CommandText = "SELECT DISTINCT [Model] FROM [MRB_Model-Approver]";
      con.Open();
      cmd.Parameters.AddWithValue("@SearchModel", empName);
      SqlDataReader dr = cmd.ExecuteReader();
      while (dr.Read())
      {
      Models.Add(dr["Model"].ToString());
      }
      con.Close();
      return Models;
      }
      }
      }






      c# sql asp.net ajax






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      asked Nov 13 '18 at 9:42









      John RobertJohn Robert

      366




      366
























          1 Answer
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          0














          try it



          SqlConnection(@Server=PHAPPCVTSQL04;Database=myDataBase;Trusted_Connection=True);


          Or



          SqlConnection(@Server=.;Database=myDataBase;Trusted_Connection=True);





          share|improve this answer





















          • Thank you Law but still not working with both answer.
            – John Robert
            Nov 14 '18 at 1:14











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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          0














          try it



          SqlConnection(@Server=PHAPPCVTSQL04;Database=myDataBase;Trusted_Connection=True);


          Or



          SqlConnection(@Server=.;Database=myDataBase;Trusted_Connection=True);





          share|improve this answer





















          • Thank you Law but still not working with both answer.
            – John Robert
            Nov 14 '18 at 1:14
















          0














          try it



          SqlConnection(@Server=PHAPPCVTSQL04;Database=myDataBase;Trusted_Connection=True);


          Or



          SqlConnection(@Server=.;Database=myDataBase;Trusted_Connection=True);





          share|improve this answer





















          • Thank you Law but still not working with both answer.
            – John Robert
            Nov 14 '18 at 1:14














          0












          0








          0






          try it



          SqlConnection(@Server=PHAPPCVTSQL04;Database=myDataBase;Trusted_Connection=True);


          Or



          SqlConnection(@Server=.;Database=myDataBase;Trusted_Connection=True);





          share|improve this answer












          try it



          SqlConnection(@Server=PHAPPCVTSQL04;Database=myDataBase;Trusted_Connection=True);


          Or



          SqlConnection(@Server=.;Database=myDataBase;Trusted_Connection=True);






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 13 '18 at 9:49









          Law HongLaw Hong

          1




          1












          • Thank you Law but still not working with both answer.
            – John Robert
            Nov 14 '18 at 1:14


















          • Thank you Law but still not working with both answer.
            – John Robert
            Nov 14 '18 at 1:14
















          Thank you Law but still not working with both answer.
          – John Robert
          Nov 14 '18 at 1:14




          Thank you Law but still not working with both answer.
          – John Robert
          Nov 14 '18 at 1:14


















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