Fetch 2 records for each group name of element of column 1 that in column 2 have the most value
1
I have a table that like below. Now i want to fetch 2 records for each group name of element of column 1 that in column 2 have the most value. For example, Fetch 85 and 75 for A, 65 and 45 for B ...
I use oracle database.
TNX
----------------------
|Column 1 | Column 2 |
----------------------
| A | 85 |
----------------------
| A | 75 |
---------------------
| A | 60 |
---------------------
| A | 50 |
---------------------
| B | 65 |
---------------------
| B | 45 |
---------------------
| B | 35 |
---------------------
| B | 25 |
---------------------
sql oracle
asked Nov 13 '18 at 9:43
YaserYaser
154
add a comment |
1
I have a table that like below. Now i want to fetch 2 records for each group name of element of column 1 that in column 2 have the most value. For example, Fetch 85 and 75 for A, 65 and 45 for B ...
I use oracle database.
TNX
----------------------
|Column 1 | Column 2 |
----------------------
| A | 85 |
----------------------
| A | 75 |
---------------------
| A | 60 |
---------------------
| A | 50 |
---------------------
| B | 65 |
---------------------
| B | 45 |
---------------------
| B | 35 |
---------------------
| B | 25 |
---------------------
sql oracle
asked Nov 13 '18 at 9:43
YaserYaser
154
add a comment |
1
1
1
I have a table that like below. Now i want to fetch 2 records for each group name of element of column 1 that in column 2 have the most value. For example, Fetch 85 and 75 for A, 65 and 45 for B ...
I use oracle database.
TNX
----------------------
|Column 1 | Column 2 |
----------------------
| A | 85 |
----------------------
| A | 75 |
---------------------
| A | 60 |
---------------------
| A | 50 |
---------------------
| B | 65 |
---------------------
| B | 45 |
---------------------
| B | 35 |
---------------------
| B | 25 |
---------------------
sql oracle
asked Nov 13 '18 at 9:43
YaserYaser
154
I have a table that like below. Now i want to fetch 2 records for each group name of element of column 1 that in column 2 have the most value. For example, Fetch 85 and 75 for A, 65 and 45 for B ...
I use oracle database.
TNX
----------------------
|Column 1 | Column 2 |
----------------------
| A | 85 |
----------------------
| A | 75 |
---------------------
| A | 60 |
---------------------
| A | 50 |
---------------------
| B | 65 |
---------------------
| B | 45 |
---------------------
| B | 35 |
---------------------
| B | 25 |
---------------------
sql oracle
sql oracle
asked Nov 13 '18 at 9:43
YaserYaser
154
asked Nov 13 '18 at 9:43
YaserYaser
154
edited Nov 13 '18 at 9:46
Yaser
asked Nov 13 '18 at 9:43
YaserYaser
154
asked Nov 13 '18 at 9:43
YaserYaser
154
asked Nov 13 '18 at 9:43
YaserYaser
154
154
add a comment |
add a comment |
4 Answers
4
active
oldest
votes
0
You can use row_number() :
select t.*
from (select t.*,
row_number() over (partition by col1 order by col2 desc) as seq
from table t
) t
where seq <= 2;
However, fetch first . . . clause also helpful :
select t.*
from table t
where t.col2 in (select t1.col2
from table t1
where t1.col1 = t.col1
order by t1.col2 desc
fetch first 2 rows only
);
answered Nov 13 '18 at 9:45
Yogesh SharmaYogesh Sharma
28.5k51336
TNX. Your first query is ok, but second query is wrong. The resault of second query is not equal by another.
– Yaser
Nov 13 '18 at 12:11
add a comment |
0
use row_number window function
with t1 as
(
select col1,col2
,row_number() over(partition by col1 order by col2 desc) rn
from table_name
) select * from t1 where rn<=2
answered Nov 13 '18 at 9:45
Zaynul Abadin TuhinZaynul Abadin Tuhin
11.5k2831
add a comment |
0
Try using row_number()
select * from
(
select *, row_number() over(partition by col1 order by col2 desc) as rn
from tablename
) A where rn in (1,2)
answered Nov 13 '18 at 9:45
fa06fa06
11.5k2917
add a comment |
0
Try this
Here is demo solution
SQL
select col1,col2 from (select col1,col2, rank() over(partition by col1 order by col2 desc) as rn from t) q where q.rn<=2;
answered Nov 13 '18 at 10:26
BrekhnaaBrekhnaa
363
add a comment |
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
You can use row_number() :
select t.*
from (select t.*,
row_number() over (partition by col1 order by col2 desc) as seq
from table t
) t
where seq <= 2;
However, fetch first . . . clause also helpful :
select t.*
from table t
where t.col2 in (select t1.col2
from table t1
where t1.col1 = t.col1
order by t1.col2 desc
fetch first 2 rows only
);
answered Nov 13 '18 at 9:45
Yogesh SharmaYogesh Sharma
28.5k51336
TNX. Your first query is ok, but second query is wrong. The resault of second query is not equal by another.
– Yaser
Nov 13 '18 at 12:11
add a comment |
0
You can use row_number() :
select t.*
from (select t.*,
row_number() over (partition by col1 order by col2 desc) as seq
from table t
) t
where seq <= 2;
However, fetch first . . . clause also helpful :
select t.*
from table t
where t.col2 in (select t1.col2
from table t1
where t1.col1 = t.col1
order by t1.col2 desc
fetch first 2 rows only
);
answered Nov 13 '18 at 9:45
Yogesh SharmaYogesh Sharma
28.5k51336
TNX. Your first query is ok, but second query is wrong. The resault of second query is not equal by another.
– Yaser
Nov 13 '18 at 12:11
add a comment |
0
0
0
You can use row_number() :
select t.*
from (select t.*,
row_number() over (partition by col1 order by col2 desc) as seq
from table t
) t
where seq <= 2;
However, fetch first . . . clause also helpful :
select t.*
from table t
where t.col2 in (select t1.col2
from table t1
where t1.col1 = t.col1
order by t1.col2 desc
fetch first 2 rows only
);
answered Nov 13 '18 at 9:45
Yogesh SharmaYogesh Sharma
28.5k51336
You can use row_number() :
select t.*
from (select t.*,
row_number() over (partition by col1 order by col2 desc) as seq
from table t
) t
where seq <= 2;
However, fetch first . . . clause also helpful :
select t.*
from table t
where t.col2 in (select t1.col2
from table t1
where t1.col1 = t.col1
order by t1.col2 desc
fetch first 2 rows only
);
answered Nov 13 '18 at 9:45
Yogesh SharmaYogesh Sharma
28.5k51336
edited Nov 13 '18 at 12:12
answered Nov 13 '18 at 9:45
Yogesh SharmaYogesh Sharma
28.5k51336
answered Nov 13 '18 at 9:45
Yogesh SharmaYogesh Sharma
28.5k51336
answered Nov 13 '18 at 9:45
Yogesh SharmaYogesh Sharma
28.5k51336
28.5k51336
TNX. Your first query is ok, but second query is wrong. The resault of second query is not equal by another.
– Yaser
Nov 13 '18 at 12:11
add a comment |
TNX. Your first query is ok, but second query is wrong. The resault of second query is not equal by another.
– Yaser
Nov 13 '18 at 12:11
TNX. Your first query is ok, but second query is wrong. The resault of second query is not equal by another.
– Yaser
Nov 13 '18 at 12:11
TNX. Your first query is ok, but second query is wrong. The resault of second query is not equal by another.
– Yaser
Nov 13 '18 at 12:11
add a comment |
0
use row_number window function
with t1 as
(
select col1,col2
,row_number() over(partition by col1 order by col2 desc) rn
from table_name
) select * from t1 where rn<=2
answered Nov 13 '18 at 9:45
Zaynul Abadin TuhinZaynul Abadin Tuhin
11.5k2831
add a comment |
0
use row_number window function
with t1 as
(
select col1,col2
,row_number() over(partition by col1 order by col2 desc) rn
from table_name
) select * from t1 where rn<=2
answered Nov 13 '18 at 9:45
Zaynul Abadin TuhinZaynul Abadin Tuhin
11.5k2831
add a comment |
0
0
0
use row_number window function
with t1 as
(
select col1,col2
,row_number() over(partition by col1 order by col2 desc) rn
from table_name
) select * from t1 where rn<=2
answered Nov 13 '18 at 9:45
Zaynul Abadin TuhinZaynul Abadin Tuhin
11.5k2831
use row_number window function
with t1 as
(
select col1,col2
,row_number() over(partition by col1 order by col2 desc) rn
from table_name
) select * from t1 where rn<=2
answered Nov 13 '18 at 9:45
Zaynul Abadin TuhinZaynul Abadin Tuhin
11.5k2831
answered Nov 13 '18 at 9:45
Zaynul Abadin TuhinZaynul Abadin Tuhin
11.5k2831
answered Nov 13 '18 at 9:45
Zaynul Abadin TuhinZaynul Abadin Tuhin
11.5k2831
answered Nov 13 '18 at 9:45
Zaynul Abadin TuhinZaynul Abadin Tuhin
11.5k2831
11.5k2831
add a comment |
add a comment |
0
Try using row_number()
select * from
(
select *, row_number() over(partition by col1 order by col2 desc) as rn
from tablename
) A where rn in (1,2)
answered Nov 13 '18 at 9:45
fa06fa06
11.5k2917
add a comment |
0
Try using row_number()
select * from
(
select *, row_number() over(partition by col1 order by col2 desc) as rn
from tablename
) A where rn in (1,2)
answered Nov 13 '18 at 9:45
fa06fa06
11.5k2917
add a comment |
0
0
0
Try using row_number()
select * from
(
select *, row_number() over(partition by col1 order by col2 desc) as rn
from tablename
) A where rn in (1,2)
answered Nov 13 '18 at 9:45
fa06fa06
11.5k2917
Try using row_number()
select * from
(
select *, row_number() over(partition by col1 order by col2 desc) as rn
from tablename
) A where rn in (1,2)
answered Nov 13 '18 at 9:45
fa06fa06
11.5k2917
edited Nov 13 '18 at 9:53
answered Nov 13 '18 at 9:45
fa06fa06
11.5k2917
answered Nov 13 '18 at 9:45
fa06fa06
11.5k2917
answered Nov 13 '18 at 9:45
fa06fa06
11.5k2917
11.5k2917
add a comment |
add a comment |
0
Try this
Here is demo solution
SQL
select col1,col2 from (select col1,col2, rank() over(partition by col1 order by col2 desc) as rn from t) q where q.rn<=2;
answered Nov 13 '18 at 10:26
BrekhnaaBrekhnaa
363
add a comment |
0
Try this
Here is demo solution
SQL
select col1,col2 from (select col1,col2, rank() over(partition by col1 order by col2 desc) as rn from t) q where q.rn<=2;
answered Nov 13 '18 at 10:26
BrekhnaaBrekhnaa
363
add a comment |
0
0
0
Try this
Here is demo solution
SQL
select col1,col2 from (select col1,col2, rank() over(partition by col1 order by col2 desc) as rn from t) q where q.rn<=2;
answered Nov 13 '18 at 10:26
BrekhnaaBrekhnaa
363
Try this
Here is demo solution
SQL
select col1,col2 from (select col1,col2, rank() over(partition by col1 order by col2 desc) as rn from t) q where q.rn<=2;
answered Nov 13 '18 at 10:26
BrekhnaaBrekhnaa
363
answered Nov 13 '18 at 10:26
BrekhnaaBrekhnaa
363
answered Nov 13 '18 at 10:26
BrekhnaaBrekhnaa
363
answered Nov 13 '18 at 10:26
BrekhnaaBrekhnaa
363
363
add a comment |
add a comment |
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