Count text matches in files based on unique ID
I have a file which has the following format:
LINK|Grouping_Indicator|ID_Dat|HASH_Akey|HASH_HUKey|
FALSE|75768163|XY100|c5157cba1b5f20|817f8b50bc9
FALSE|75768409|XY102|9f3de314a224f2|b686e4760f5
TRUE|75769393|XY1005|ce0a50207cc86c|f9233c0b8e7
TRUE|75769885|XY1012|ce0a50207cc86c|ef9eb8ea13f
TRUE|75723124|XY1111|df0q45677ee89v|gt8qc9fb24g
I am trying to count the numbers of TRUE where the HASH_Akey is unique.
I've managed to count the numbers of TRUE in total with the following command:
grep -c "TRUE" file.psv
However, I am unsure on how to count "TRUE" where the HASH_Akey is unique.
So the count for "TRUE" from the table above should only return 2
Thanks
grep
add a comment |
I have a file which has the following format:
LINK|Grouping_Indicator|ID_Dat|HASH_Akey|HASH_HUKey|
FALSE|75768163|XY100|c5157cba1b5f20|817f8b50bc9
FALSE|75768409|XY102|9f3de314a224f2|b686e4760f5
TRUE|75769393|XY1005|ce0a50207cc86c|f9233c0b8e7
TRUE|75769885|XY1012|ce0a50207cc86c|ef9eb8ea13f
TRUE|75723124|XY1111|df0q45677ee89v|gt8qc9fb24g
I am trying to count the numbers of TRUE where the HASH_Akey is unique.
I've managed to count the numbers of TRUE in total with the following command:
grep -c "TRUE" file.psv
However, I am unsure on how to count "TRUE" where the HASH_Akey is unique.
So the count for "TRUE" from the table above should only return 2
Thanks
grep
add a comment |
I have a file which has the following format:
LINK|Grouping_Indicator|ID_Dat|HASH_Akey|HASH_HUKey|
FALSE|75768163|XY100|c5157cba1b5f20|817f8b50bc9
FALSE|75768409|XY102|9f3de314a224f2|b686e4760f5
TRUE|75769393|XY1005|ce0a50207cc86c|f9233c0b8e7
TRUE|75769885|XY1012|ce0a50207cc86c|ef9eb8ea13f
TRUE|75723124|XY1111|df0q45677ee89v|gt8qc9fb24g
I am trying to count the numbers of TRUE where the HASH_Akey is unique.
I've managed to count the numbers of TRUE in total with the following command:
grep -c "TRUE" file.psv
However, I am unsure on how to count "TRUE" where the HASH_Akey is unique.
So the count for "TRUE" from the table above should only return 2
Thanks
grep
I have a file which has the following format:
LINK|Grouping_Indicator|ID_Dat|HASH_Akey|HASH_HUKey|
FALSE|75768163|XY100|c5157cba1b5f20|817f8b50bc9
FALSE|75768409|XY102|9f3de314a224f2|b686e4760f5
TRUE|75769393|XY1005|ce0a50207cc86c|f9233c0b8e7
TRUE|75769885|XY1012|ce0a50207cc86c|ef9eb8ea13f
TRUE|75723124|XY1111|df0q45677ee89v|gt8qc9fb24g
I am trying to count the numbers of TRUE where the HASH_Akey is unique.
I've managed to count the numbers of TRUE in total with the following command:
grep -c "TRUE" file.psv
However, I am unsure on how to count "TRUE" where the HASH_Akey is unique.
So the count for "TRUE" from the table above should only return 2
Thanks
grep
grep
asked Nov 12 at 13:27
Nant
235411
235411
add a comment |
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1 Answer
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votes
I would do it with awk:
awk -F'|' '$1=="TRUE"{a[$(NF-1)]}END{print length(a)}' file
with your example, the above one-liner will print 2
You can also do it with:
awk -F'|' '$1=="TRUE"&&!a[$(NF-1)]++' file|wc -l
the line is a little bit shorter but it starts another process (wc
) to do the counting.
Hi @Kent, Thanks for the answer. In your first solution, where do you specify that you're looking for unique values in Column "Hash_Akey" ?
– Nant
Nov 12 at 14:12
I guess it's "NF-1"
– Nant
Nov 12 at 14:19
1
yes @Nant it isNF-1
– Kent
Nov 12 at 14:54
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
I would do it with awk:
awk -F'|' '$1=="TRUE"{a[$(NF-1)]}END{print length(a)}' file
with your example, the above one-liner will print 2
You can also do it with:
awk -F'|' '$1=="TRUE"&&!a[$(NF-1)]++' file|wc -l
the line is a little bit shorter but it starts another process (wc
) to do the counting.
Hi @Kent, Thanks for the answer. In your first solution, where do you specify that you're looking for unique values in Column "Hash_Akey" ?
– Nant
Nov 12 at 14:12
I guess it's "NF-1"
– Nant
Nov 12 at 14:19
1
yes @Nant it isNF-1
– Kent
Nov 12 at 14:54
add a comment |
I would do it with awk:
awk -F'|' '$1=="TRUE"{a[$(NF-1)]}END{print length(a)}' file
with your example, the above one-liner will print 2
You can also do it with:
awk -F'|' '$1=="TRUE"&&!a[$(NF-1)]++' file|wc -l
the line is a little bit shorter but it starts another process (wc
) to do the counting.
Hi @Kent, Thanks for the answer. In your first solution, where do you specify that you're looking for unique values in Column "Hash_Akey" ?
– Nant
Nov 12 at 14:12
I guess it's "NF-1"
– Nant
Nov 12 at 14:19
1
yes @Nant it isNF-1
– Kent
Nov 12 at 14:54
add a comment |
I would do it with awk:
awk -F'|' '$1=="TRUE"{a[$(NF-1)]}END{print length(a)}' file
with your example, the above one-liner will print 2
You can also do it with:
awk -F'|' '$1=="TRUE"&&!a[$(NF-1)]++' file|wc -l
the line is a little bit shorter but it starts another process (wc
) to do the counting.
I would do it with awk:
awk -F'|' '$1=="TRUE"{a[$(NF-1)]}END{print length(a)}' file
with your example, the above one-liner will print 2
You can also do it with:
awk -F'|' '$1=="TRUE"&&!a[$(NF-1)]++' file|wc -l
the line is a little bit shorter but it starts another process (wc
) to do the counting.
answered Nov 12 at 13:34
Kent
143k25152213
143k25152213
Hi @Kent, Thanks for the answer. In your first solution, where do you specify that you're looking for unique values in Column "Hash_Akey" ?
– Nant
Nov 12 at 14:12
I guess it's "NF-1"
– Nant
Nov 12 at 14:19
1
yes @Nant it isNF-1
– Kent
Nov 12 at 14:54
add a comment |
Hi @Kent, Thanks for the answer. In your first solution, where do you specify that you're looking for unique values in Column "Hash_Akey" ?
– Nant
Nov 12 at 14:12
I guess it's "NF-1"
– Nant
Nov 12 at 14:19
1
yes @Nant it isNF-1
– Kent
Nov 12 at 14:54
Hi @Kent, Thanks for the answer. In your first solution, where do you specify that you're looking for unique values in Column "Hash_Akey" ?
– Nant
Nov 12 at 14:12
Hi @Kent, Thanks for the answer. In your first solution, where do you specify that you're looking for unique values in Column "Hash_Akey" ?
– Nant
Nov 12 at 14:12
I guess it's "NF-1"
– Nant
Nov 12 at 14:19
I guess it's "NF-1"
– Nant
Nov 12 at 14:19
1
1
yes @Nant it is
NF-1
– Kent
Nov 12 at 14:54
yes @Nant it is
NF-1
– Kent
Nov 12 at 14:54
add a comment |
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