Postfix Calculator Java -cannot resolve or is not a field
I am encountering this error in the postfix calculator: the integerOperand cannot be resolved or is not a field. Below I have shown the main code, and the code from the IntegerOperand class file. How can I fix this? I am trying to call the add function from the IntegerOperand class.
public class IntegerOperand implements CalculatorOperand<IntegerOperand> {
BigInteger value;
IntegerOperand (BigInteger value) {
this.value = value;
}
public IntegerOperand add (IntegerOperand that) {
return new IntegerOperand(this.value.add(that.value));
}
public IntegerOperand subtract (IntegerOperand that) {
return new IntegerOperand(this.value.subtract(that.value));
}
public IntegerOperand multiply (IntegerOperand that) {
return new IntegerOperand(this.value.multiply(that.value));
}
public String toString () {
return value.toString();
}
}
public void operation (OperationType operation) {
T t1;
T t2;
if(stack.isEmpty())
{
t2= stack.pop();
t1= stack.pop();
stack.push(t1.IntegerOperand.add(t2));
}
}
java list stack
edited Nov 13 at 13:21
Stephan
333211
asked Nov 12 at 13:25
MunchiesOats
61
add a comment |
I am encountering this error in the postfix calculator: the integerOperand cannot be resolved or is not a field. Below I have shown the main code, and the code from the IntegerOperand class file. How can I fix this? I am trying to call the add function from the IntegerOperand class.
public class IntegerOperand implements CalculatorOperand<IntegerOperand> {
BigInteger value;
IntegerOperand (BigInteger value) {
this.value = value;
}
public IntegerOperand add (IntegerOperand that) {
return new IntegerOperand(this.value.add(that.value));
}
public IntegerOperand subtract (IntegerOperand that) {
return new IntegerOperand(this.value.subtract(that.value));
}
public IntegerOperand multiply (IntegerOperand that) {
return new IntegerOperand(this.value.multiply(that.value));
}
public String toString () {
return value.toString();
}
}
public void operation (OperationType operation) {
T t1;
T t2;
if(stack.isEmpty())
{
t2= stack.pop();
t1= stack.pop();
stack.push(t1.IntegerOperand.add(t2));
}
}
java list stack
edited Nov 13 at 13:21
Stephan
333211
asked Nov 12 at 13:25
MunchiesOats
61
add a comment |
I am encountering this error in the postfix calculator: the integerOperand cannot be resolved or is not a field. Below I have shown the main code, and the code from the IntegerOperand class file. How can I fix this? I am trying to call the add function from the IntegerOperand class.
public class IntegerOperand implements CalculatorOperand<IntegerOperand> {
BigInteger value;
IntegerOperand (BigInteger value) {
this.value = value;
}
public IntegerOperand add (IntegerOperand that) {
return new IntegerOperand(this.value.add(that.value));
}
public IntegerOperand subtract (IntegerOperand that) {
return new IntegerOperand(this.value.subtract(that.value));
}
public IntegerOperand multiply (IntegerOperand that) {
return new IntegerOperand(this.value.multiply(that.value));
}
public String toString () {
return value.toString();
}
}
public void operation (OperationType operation) {
T t1;
T t2;
if(stack.isEmpty())
{
t2= stack.pop();
t1= stack.pop();
stack.push(t1.IntegerOperand.add(t2));
}
}
java list stack
edited Nov 13 at 13:21
Stephan
333211
asked Nov 12 at 13:25
MunchiesOats
61
I am encountering this error in the postfix calculator: the integerOperand cannot be resolved or is not a field. Below I have shown the main code, and the code from the IntegerOperand class file. How can I fix this? I am trying to call the add function from the IntegerOperand class.
public class IntegerOperand implements CalculatorOperand<IntegerOperand> {
BigInteger value;
IntegerOperand (BigInteger value) {
this.value = value;
}
public IntegerOperand add (IntegerOperand that) {
return new IntegerOperand(this.value.add(that.value));
}
public IntegerOperand subtract (IntegerOperand that) {
return new IntegerOperand(this.value.subtract(that.value));
}
public IntegerOperand multiply (IntegerOperand that) {
return new IntegerOperand(this.value.multiply(that.value));
}
public String toString () {
return value.toString();
}
}
public void operation (OperationType operation) {
T t1;
T t2;
if(stack.isEmpty())
{
t2= stack.pop();
t1= stack.pop();
stack.push(t1.IntegerOperand.add(t2));
}
}
java list stack
java list stack
edited Nov 13 at 13:21
Stephan
333211
asked Nov 12 at 13:25
MunchiesOats
61
edited Nov 13 at 13:21
Stephan
333211
asked Nov 12 at 13:25
MunchiesOats
61
edited Nov 13 at 13:21
Stephan
333211
edited Nov 13 at 13:21
Stephan
333211
edited Nov 13 at 13:21
Stephan
333211
333211
asked Nov 12 at 13:25
MunchiesOats
61
asked Nov 12 at 13:25
MunchiesOats
61
asked Nov 12 at 13:25
MunchiesOats
61
61
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
The main issue is that you are not calling the function correctly.
// You don't need the class name
//stack.push(t1.IntegerOperand.add(t2));
stack.push(t1.add(t2));
Second, you check if the stack is empty, then if it is, you try to pop from it. But you should check if the stack is not empty: if (!stack.isEmpty()). But since you then do 2 calls to pop you should instead check if there are at least 2 items in the stack.
if (stack.size() >= 2) {
t2 = stack.pop();
t1 = stack.pop();
stack.push(t1.add(t2));
}
answered Nov 12 at 13:42
Johnny Mopp
6,77722344
Thank you! However, the function has to allow for stacks with less than 2 items in the stack, and the code cannot modify the stack if it contains less than 2 items. What should I consider in this case?
– MunchiesOats
Nov 12 at 14:13
@ChloePupaiboon This code will not modify the stack if it has less than 2 items. For stacks with one item, you could add anelseto handle that case.
– Johnny Mopp
Nov 12 at 14:21
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
The main issue is that you are not calling the function correctly.
// You don't need the class name
//stack.push(t1.IntegerOperand.add(t2));
stack.push(t1.add(t2));
Second, you check if the stack is empty, then if it is, you try to pop from it. But you should check if the stack is not empty: if (!stack.isEmpty()). But since you then do 2 calls to pop you should instead check if there are at least 2 items in the stack.
if (stack.size() >= 2) {
t2 = stack.pop();
t1 = stack.pop();
stack.push(t1.add(t2));
}
answered Nov 12 at 13:42
Johnny Mopp
6,77722344
Thank you! However, the function has to allow for stacks with less than 2 items in the stack, and the code cannot modify the stack if it contains less than 2 items. What should I consider in this case?
– MunchiesOats
Nov 12 at 14:13
@ChloePupaiboon This code will not modify the stack if it has less than 2 items. For stacks with one item, you could add anelseto handle that case.
– Johnny Mopp
Nov 12 at 14:21
add a comment |
The main issue is that you are not calling the function correctly.
// You don't need the class name
//stack.push(t1.IntegerOperand.add(t2));
stack.push(t1.add(t2));
Second, you check if the stack is empty, then if it is, you try to pop from it. But you should check if the stack is not empty: if (!stack.isEmpty()). But since you then do 2 calls to pop you should instead check if there are at least 2 items in the stack.
if (stack.size() >= 2) {
t2 = stack.pop();
t1 = stack.pop();
stack.push(t1.add(t2));
}
answered Nov 12 at 13:42
Johnny Mopp
6,77722344
Thank you! However, the function has to allow for stacks with less than 2 items in the stack, and the code cannot modify the stack if it contains less than 2 items. What should I consider in this case?
– MunchiesOats
Nov 12 at 14:13
@ChloePupaiboon This code will not modify the stack if it has less than 2 items. For stacks with one item, you could add anelseto handle that case.
– Johnny Mopp
Nov 12 at 14:21
add a comment |
The main issue is that you are not calling the function correctly.
// You don't need the class name
//stack.push(t1.IntegerOperand.add(t2));
stack.push(t1.add(t2));
Second, you check if the stack is empty, then if it is, you try to pop from it. But you should check if the stack is not empty: if (!stack.isEmpty()). But since you then do 2 calls to pop you should instead check if there are at least 2 items in the stack.
if (stack.size() >= 2) {
t2 = stack.pop();
t1 = stack.pop();
stack.push(t1.add(t2));
}
answered Nov 12 at 13:42
Johnny Mopp
6,77722344
The main issue is that you are not calling the function correctly.
// You don't need the class name
//stack.push(t1.IntegerOperand.add(t2));
stack.push(t1.add(t2));
Second, you check if the stack is empty, then if it is, you try to pop from it. But you should check if the stack is not empty: if (!stack.isEmpty()). But since you then do 2 calls to pop you should instead check if there are at least 2 items in the stack.
if (stack.size() >= 2) {
t2 = stack.pop();
t1 = stack.pop();
stack.push(t1.add(t2));
}
answered Nov 12 at 13:42
Johnny Mopp
6,77722344
answered Nov 12 at 13:42
Johnny Mopp
6,77722344
answered Nov 12 at 13:42
Johnny Mopp
6,77722344
answered Nov 12 at 13:42
Johnny Mopp
6,77722344
6,77722344
Thank you! However, the function has to allow for stacks with less than 2 items in the stack, and the code cannot modify the stack if it contains less than 2 items. What should I consider in this case?
– MunchiesOats
Nov 12 at 14:13
@ChloePupaiboon This code will not modify the stack if it has less than 2 items. For stacks with one item, you could add anelseto handle that case.
– Johnny Mopp
Nov 12 at 14:21
add a comment |
Thank you! However, the function has to allow for stacks with less than 2 items in the stack, and the code cannot modify the stack if it contains less than 2 items. What should I consider in this case?
– MunchiesOats
Nov 12 at 14:13
@ChloePupaiboon This code will not modify the stack if it has less than 2 items. For stacks with one item, you could add anelseto handle that case.
– Johnny Mopp
Nov 12 at 14:21
Thank you! However, the function has to allow for stacks with less than 2 items in the stack, and the code cannot modify the stack if it contains less than 2 items. What should I consider in this case?
– MunchiesOats
Nov 12 at 14:13
Thank you! However, the function has to allow for stacks with less than 2 items in the stack, and the code cannot modify the stack if it contains less than 2 items. What should I consider in this case?
– MunchiesOats
Nov 12 at 14:13
@ChloePupaiboon This code will not modify the stack if it has less than 2 items. For stacks with one item, you could add an
else to handle that case.– Johnny Mopp
Nov 12 at 14:21
@ChloePupaiboon This code will not modify the stack if it has less than 2 items. For stacks with one item, you could add an
else to handle that case.– Johnny Mopp
Nov 12 at 14:21
add a comment |
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