UnresolvedAddressException in java and database





.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ height:90px;width:728px;box-sizing:border-box;
}







0















I cannot understand why my address is not authorized.
I have a client and when it connects to the server, it transmits its data including the ip and port. The server in turn has to send signals to the client at a certain time (the client responds to them) But when I try to go through all the clients, an exception is thrown.
Code:



public void run() {
ResultSet res;
while (true) {
try {
Thread.sleep(5000);
res = DatabaseHandler.getAddresses();
while (res.next()) {
for (int i = 1; i <= res.getMetaData().getColumnCount() - 1; i++) {
System.out.println(res.getString(i) + Integer.parseInt(res.getString(i+1)));
try (SocketChannel sc = SocketChannel.open
(new InetSocketAddress(res.getString(i),Integer.parseInt(res.getString(i+1))))) {

ByteBuffer buffer = ByteBuffer.allocate(4);
buffer.clear();
buffer.putInt(MessageTyps.SIGNAL_REQUEST);
buffer.flip();
while(buffer.hasRemaining()) {
sc.write(buffer);
}
DatabaseHandler.incrementCount(res.getString(i),Integer.parseInt(res.getString(i+1)));

} catch (Exception e1) {
e1.printStackTrace();
}
}
}
} catch (SQLException e) {
e.printStackTrace();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}









share|improve this question























  • Can you share the stack trace? Also, what parameters are being used to initialize the connection? It's probably good to start with trivial code that verifies that you can connect to the DB with those params,

    – sofend
    Nov 16 '18 at 21:46


















0















I cannot understand why my address is not authorized.
I have a client and when it connects to the server, it transmits its data including the ip and port. The server in turn has to send signals to the client at a certain time (the client responds to them) But when I try to go through all the clients, an exception is thrown.
Code:



public void run() {
ResultSet res;
while (true) {
try {
Thread.sleep(5000);
res = DatabaseHandler.getAddresses();
while (res.next()) {
for (int i = 1; i <= res.getMetaData().getColumnCount() - 1; i++) {
System.out.println(res.getString(i) + Integer.parseInt(res.getString(i+1)));
try (SocketChannel sc = SocketChannel.open
(new InetSocketAddress(res.getString(i),Integer.parseInt(res.getString(i+1))))) {

ByteBuffer buffer = ByteBuffer.allocate(4);
buffer.clear();
buffer.putInt(MessageTyps.SIGNAL_REQUEST);
buffer.flip();
while(buffer.hasRemaining()) {
sc.write(buffer);
}
DatabaseHandler.incrementCount(res.getString(i),Integer.parseInt(res.getString(i+1)));

} catch (Exception e1) {
e1.printStackTrace();
}
}
}
} catch (SQLException e) {
e.printStackTrace();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}









share|improve this question























  • Can you share the stack trace? Also, what parameters are being used to initialize the connection? It's probably good to start with trivial code that verifies that you can connect to the DB with those params,

    – sofend
    Nov 16 '18 at 21:46














0












0








0








I cannot understand why my address is not authorized.
I have a client and when it connects to the server, it transmits its data including the ip and port. The server in turn has to send signals to the client at a certain time (the client responds to them) But when I try to go through all the clients, an exception is thrown.
Code:



public void run() {
ResultSet res;
while (true) {
try {
Thread.sleep(5000);
res = DatabaseHandler.getAddresses();
while (res.next()) {
for (int i = 1; i <= res.getMetaData().getColumnCount() - 1; i++) {
System.out.println(res.getString(i) + Integer.parseInt(res.getString(i+1)));
try (SocketChannel sc = SocketChannel.open
(new InetSocketAddress(res.getString(i),Integer.parseInt(res.getString(i+1))))) {

ByteBuffer buffer = ByteBuffer.allocate(4);
buffer.clear();
buffer.putInt(MessageTyps.SIGNAL_REQUEST);
buffer.flip();
while(buffer.hasRemaining()) {
sc.write(buffer);
}
DatabaseHandler.incrementCount(res.getString(i),Integer.parseInt(res.getString(i+1)));

} catch (Exception e1) {
e1.printStackTrace();
}
}
}
} catch (SQLException e) {
e.printStackTrace();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}









share|improve this question














I cannot understand why my address is not authorized.
I have a client and when it connects to the server, it transmits its data including the ip and port. The server in turn has to send signals to the client at a certain time (the client responds to them) But when I try to go through all the clients, an exception is thrown.
Code:



public void run() {
ResultSet res;
while (true) {
try {
Thread.sleep(5000);
res = DatabaseHandler.getAddresses();
while (res.next()) {
for (int i = 1; i <= res.getMetaData().getColumnCount() - 1; i++) {
System.out.println(res.getString(i) + Integer.parseInt(res.getString(i+1)));
try (SocketChannel sc = SocketChannel.open
(new InetSocketAddress(res.getString(i),Integer.parseInt(res.getString(i+1))))) {

ByteBuffer buffer = ByteBuffer.allocate(4);
buffer.clear();
buffer.putInt(MessageTyps.SIGNAL_REQUEST);
buffer.flip();
while(buffer.hasRemaining()) {
sc.write(buffer);
}
DatabaseHandler.incrementCount(res.getString(i),Integer.parseInt(res.getString(i+1)));

} catch (Exception e1) {
e1.printStackTrace();
}
}
}
} catch (SQLException e) {
e.printStackTrace();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}






java sql exception






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 16 '18 at 20:44









RedCapeRedCape

53




53













  • Can you share the stack trace? Also, what parameters are being used to initialize the connection? It's probably good to start with trivial code that verifies that you can connect to the DB with those params,

    – sofend
    Nov 16 '18 at 21:46



















  • Can you share the stack trace? Also, what parameters are being used to initialize the connection? It's probably good to start with trivial code that verifies that you can connect to the DB with those params,

    – sofend
    Nov 16 '18 at 21:46

















Can you share the stack trace? Also, what parameters are being used to initialize the connection? It's probably good to start with trivial code that verifies that you can connect to the DB with those params,

– sofend
Nov 16 '18 at 21:46





Can you share the stack trace? Also, what parameters are being used to initialize the connection? It's probably good to start with trivial code that verifies that you can connect to the DB with those params,

– sofend
Nov 16 '18 at 21:46












0






active

oldest

votes












Your Answer






StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});


}
});














draft saved

draft discarded


















StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53345133%2funresolvedaddressexception-in-java-and-database%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown

























0






active

oldest

votes








0






active

oldest

votes









active

oldest

votes






active

oldest

votes
















draft saved

draft discarded




















































Thanks for contributing an answer to Stack Overflow!


  • Please be sure to answer the question. Provide details and share your research!

But avoid



  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.


To learn more, see our tips on writing great answers.




draft saved


draft discarded














StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53345133%2funresolvedaddressexception-in-java-and-database%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







Popular posts from this blog

Bressuire

Vorschmack

Quarantine