Test robustness of one way anova when independence assumption is violated
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ height:90px;width:728px;box-sizing:border-box;
}
As the title, I want to test the robustness of one way anova when the independence assumption is violated. The scenario is there is correlation between different subgroups. I used mvrnorm to generate correlated datasets, and do the simulation for 1000 times to calculate power of anova for each correlation from 0.1 to 0.9.
However it seems for each iteration the p value of anova stays constant. I hope to know the whether it is because of the way I used to generate correlated subsets is inappropriate or because of something else?? I find in fact the p value does change, but very very slightly... I expect to see when correlation increases, the power will decrease??, but in my case the power is either 1 or 0... (I have put sd for each group to be 1 for simplicity).
myfun3 <- function(index, cor, samplesize, mean1, mean2, mean3){
library(MASS)
data = mvrnorm(n=samplesize, mu=c(mean1, mean2, mean3),
Sigma=matrix(c(1, rep(cor, 3), 1, rep(cor, 3), 1), 3, 3), empirical=TRUE)
newdat<- data.frame(data)
library(tidyr)
newdat_long <- gather(newdat, group, y, X1:X3, factor_key = TRUE)
aov_result <- summary(aov(y ~ group, newdat_long))[[1]][["Pr(>F)"]][[1]]
ks_result <- kruskal.test(y ~ group, newdat_long)$p.value
return(list(aov_result, ks_result))
}
cal_power_cor <- function(iteration = 1000, samplesize=30, cor, mean1 = 10, mean2=10.5, mean3=10.8){
result_list <- lapply(1:iteration, myfun3, samplesize = samplesize, cor = cor, mean1 = mean1, mean2 = mean2,
mean3 = mean3)
result <-data.frame(matrix(unlist(result_list), ncol = 2, byrow = T))
colnames(result)<- c("anova", "kruskal")
power_aov <- sum(result$anova<0.05)/1000
power_kruskal <- sum(result$kruskal<0.05)/1000
return(list("power_aov" = power_aov, "power_kruskal" = power_kruskal))
}
cal_power_cor(cor = 0.2)
cal_power_cor(cor = 0.5)
cal_power_cor(cor = 0.9)
r anova robustness
add a comment |
As the title, I want to test the robustness of one way anova when the independence assumption is violated. The scenario is there is correlation between different subgroups. I used mvrnorm to generate correlated datasets, and do the simulation for 1000 times to calculate power of anova for each correlation from 0.1 to 0.9.
However it seems for each iteration the p value of anova stays constant. I hope to know the whether it is because of the way I used to generate correlated subsets is inappropriate or because of something else?? I find in fact the p value does change, but very very slightly... I expect to see when correlation increases, the power will decrease??, but in my case the power is either 1 or 0... (I have put sd for each group to be 1 for simplicity).
myfun3 <- function(index, cor, samplesize, mean1, mean2, mean3){
library(MASS)
data = mvrnorm(n=samplesize, mu=c(mean1, mean2, mean3),
Sigma=matrix(c(1, rep(cor, 3), 1, rep(cor, 3), 1), 3, 3), empirical=TRUE)
newdat<- data.frame(data)
library(tidyr)
newdat_long <- gather(newdat, group, y, X1:X3, factor_key = TRUE)
aov_result <- summary(aov(y ~ group, newdat_long))[[1]][["Pr(>F)"]][[1]]
ks_result <- kruskal.test(y ~ group, newdat_long)$p.value
return(list(aov_result, ks_result))
}
cal_power_cor <- function(iteration = 1000, samplesize=30, cor, mean1 = 10, mean2=10.5, mean3=10.8){
result_list <- lapply(1:iteration, myfun3, samplesize = samplesize, cor = cor, mean1 = mean1, mean2 = mean2,
mean3 = mean3)
result <-data.frame(matrix(unlist(result_list), ncol = 2, byrow = T))
colnames(result)<- c("anova", "kruskal")
power_aov <- sum(result$anova<0.05)/1000
power_kruskal <- sum(result$kruskal<0.05)/1000
return(list("power_aov" = power_aov, "power_kruskal" = power_kruskal))
}
cal_power_cor(cor = 0.2)
cal_power_cor(cor = 0.5)
cal_power_cor(cor = 0.9)
r anova robustness
add a comment |
As the title, I want to test the robustness of one way anova when the independence assumption is violated. The scenario is there is correlation between different subgroups. I used mvrnorm to generate correlated datasets, and do the simulation for 1000 times to calculate power of anova for each correlation from 0.1 to 0.9.
However it seems for each iteration the p value of anova stays constant. I hope to know the whether it is because of the way I used to generate correlated subsets is inappropriate or because of something else?? I find in fact the p value does change, but very very slightly... I expect to see when correlation increases, the power will decrease??, but in my case the power is either 1 or 0... (I have put sd for each group to be 1 for simplicity).
myfun3 <- function(index, cor, samplesize, mean1, mean2, mean3){
library(MASS)
data = mvrnorm(n=samplesize, mu=c(mean1, mean2, mean3),
Sigma=matrix(c(1, rep(cor, 3), 1, rep(cor, 3), 1), 3, 3), empirical=TRUE)
newdat<- data.frame(data)
library(tidyr)
newdat_long <- gather(newdat, group, y, X1:X3, factor_key = TRUE)
aov_result <- summary(aov(y ~ group, newdat_long))[[1]][["Pr(>F)"]][[1]]
ks_result <- kruskal.test(y ~ group, newdat_long)$p.value
return(list(aov_result, ks_result))
}
cal_power_cor <- function(iteration = 1000, samplesize=30, cor, mean1 = 10, mean2=10.5, mean3=10.8){
result_list <- lapply(1:iteration, myfun3, samplesize = samplesize, cor = cor, mean1 = mean1, mean2 = mean2,
mean3 = mean3)
result <-data.frame(matrix(unlist(result_list), ncol = 2, byrow = T))
colnames(result)<- c("anova", "kruskal")
power_aov <- sum(result$anova<0.05)/1000
power_kruskal <- sum(result$kruskal<0.05)/1000
return(list("power_aov" = power_aov, "power_kruskal" = power_kruskal))
}
cal_power_cor(cor = 0.2)
cal_power_cor(cor = 0.5)
cal_power_cor(cor = 0.9)
r anova robustness
As the title, I want to test the robustness of one way anova when the independence assumption is violated. The scenario is there is correlation between different subgroups. I used mvrnorm to generate correlated datasets, and do the simulation for 1000 times to calculate power of anova for each correlation from 0.1 to 0.9.
However it seems for each iteration the p value of anova stays constant. I hope to know the whether it is because of the way I used to generate correlated subsets is inappropriate or because of something else?? I find in fact the p value does change, but very very slightly... I expect to see when correlation increases, the power will decrease??, but in my case the power is either 1 or 0... (I have put sd for each group to be 1 for simplicity).
myfun3 <- function(index, cor, samplesize, mean1, mean2, mean3){
library(MASS)
data = mvrnorm(n=samplesize, mu=c(mean1, mean2, mean3),
Sigma=matrix(c(1, rep(cor, 3), 1, rep(cor, 3), 1), 3, 3), empirical=TRUE)
newdat<- data.frame(data)
library(tidyr)
newdat_long <- gather(newdat, group, y, X1:X3, factor_key = TRUE)
aov_result <- summary(aov(y ~ group, newdat_long))[[1]][["Pr(>F)"]][[1]]
ks_result <- kruskal.test(y ~ group, newdat_long)$p.value
return(list(aov_result, ks_result))
}
cal_power_cor <- function(iteration = 1000, samplesize=30, cor, mean1 = 10, mean2=10.5, mean3=10.8){
result_list <- lapply(1:iteration, myfun3, samplesize = samplesize, cor = cor, mean1 = mean1, mean2 = mean2,
mean3 = mean3)
result <-data.frame(matrix(unlist(result_list), ncol = 2, byrow = T))
colnames(result)<- c("anova", "kruskal")
power_aov <- sum(result$anova<0.05)/1000
power_kruskal <- sum(result$kruskal<0.05)/1000
return(list("power_aov" = power_aov, "power_kruskal" = power_kruskal))
}
cal_power_cor(cor = 0.2)
cal_power_cor(cor = 0.5)
cal_power_cor(cor = 0.9)
r anova robustness
r anova robustness
edited Nov 16 '18 at 20:54
Teng Li
asked Nov 16 '18 at 20:49
Teng LiTeng Li
84
84
add a comment |
add a comment |
0
active
oldest
votes
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53345181%2ftest-robustness-of-one-way-anova-when-independence-assumption-is-violated%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
0
active
oldest
votes
0
active
oldest
votes
active
oldest
votes
active
oldest
votes
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53345181%2ftest-robustness-of-one-way-anova-when-independence-assumption-is-violated%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown