Scala HashSet java.lang.NegativeArraySizeException





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Following code throws exception after inserting 483180000 values. Is this expected. Is there any way to add more than a billion values into a mutable HashSet in Scala. Tried this code with Scala versions 2.11 and 2.12. Both versions throw same exception.



import scala.collection.mutable.HashSet

object TestApp extends App {
val hs = HashSet[Int]()
for (i <- 1 to Int.MaxValue) {
hs += i
}
}

java.lang.NegativeArraySizeException
at scala.collection.mutable.FlatHashTable.growTable(FlatHashTable.scala:218)
at scala.collection.mutable.FlatHashTable.addEntry(FlatHashTable.scala:160)
at scala.collection.mutable.FlatHashTable.addEntry$(FlatHashTable.scala:148)
at scala.collection.mutable.HashSet.addEntry(HashSet.scala:39)
at scala.collection.mutable.FlatHashTable.addElem(FlatHashTable.scala:140)
at scala.collection.mutable.FlatHashTable.addElem$(FlatHashTable.scala:139)
at scala.collection.mutable.HashSet.addElem(HashSet.scala:39)
at scala.collection.mutable.HashSet.$plus$eq(HashSet.scala:58)
at alice.grid.collection.TestApp$.$anonfun$new$2(TestApp.scala:12)
at scala.collection.immutable.Range.foreach$mVc$sp(Range.scala:155)
at alice.grid.collection.TestApp$.delayedEndpoint$alice$grid$collection$TestApp$1(TestApp.scala:11)
at alice.grid.collection.TestApp$delayedInit$body.apply(TestApp.scala:5)
at scala.Function0.apply$mcV$sp(Function0.scala:34)
at scala.Function0.apply$mcV$sp$(Function0.scala:34)
at scala.runtime.AbstractFunction0.apply$mcV$sp(AbstractFunction0.scala:12)
at scala.App.$anonfun$main$1$adapted(App.scala:76)
at scala.collection.immutable.List.foreach(List.scala:388)
at scala.App.main(App.scala:76)
at scala.App.main$(App.scala:74)
at alice.grid.collection.TestApp$.main(TestApp.scala:5)
at alice.grid.collection.TestApp.main(TestApp.scala)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.lang.reflect.Method.invoke(Method.java:498)









share|improve this question





























    1















    Following code throws exception after inserting 483180000 values. Is this expected. Is there any way to add more than a billion values into a mutable HashSet in Scala. Tried this code with Scala versions 2.11 and 2.12. Both versions throw same exception.



    import scala.collection.mutable.HashSet

    object TestApp extends App {
    val hs = HashSet[Int]()
    for (i <- 1 to Int.MaxValue) {
    hs += i
    }
    }

    java.lang.NegativeArraySizeException
    at scala.collection.mutable.FlatHashTable.growTable(FlatHashTable.scala:218)
    at scala.collection.mutable.FlatHashTable.addEntry(FlatHashTable.scala:160)
    at scala.collection.mutable.FlatHashTable.addEntry$(FlatHashTable.scala:148)
    at scala.collection.mutable.HashSet.addEntry(HashSet.scala:39)
    at scala.collection.mutable.FlatHashTable.addElem(FlatHashTable.scala:140)
    at scala.collection.mutable.FlatHashTable.addElem$(FlatHashTable.scala:139)
    at scala.collection.mutable.HashSet.addElem(HashSet.scala:39)
    at scala.collection.mutable.HashSet.$plus$eq(HashSet.scala:58)
    at alice.grid.collection.TestApp$.$anonfun$new$2(TestApp.scala:12)
    at scala.collection.immutable.Range.foreach$mVc$sp(Range.scala:155)
    at alice.grid.collection.TestApp$.delayedEndpoint$alice$grid$collection$TestApp$1(TestApp.scala:11)
    at alice.grid.collection.TestApp$delayedInit$body.apply(TestApp.scala:5)
    at scala.Function0.apply$mcV$sp(Function0.scala:34)
    at scala.Function0.apply$mcV$sp$(Function0.scala:34)
    at scala.runtime.AbstractFunction0.apply$mcV$sp(AbstractFunction0.scala:12)
    at scala.App.$anonfun$main$1$adapted(App.scala:76)
    at scala.collection.immutable.List.foreach(List.scala:388)
    at scala.App.main(App.scala:76)
    at scala.App.main$(App.scala:74)
    at alice.grid.collection.TestApp$.main(TestApp.scala:5)
    at alice.grid.collection.TestApp.main(TestApp.scala)
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
    at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62)
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
    at java.lang.reflect.Method.invoke(Method.java:498)









    share|improve this question

























      1












      1








      1








      Following code throws exception after inserting 483180000 values. Is this expected. Is there any way to add more than a billion values into a mutable HashSet in Scala. Tried this code with Scala versions 2.11 and 2.12. Both versions throw same exception.



      import scala.collection.mutable.HashSet

      object TestApp extends App {
      val hs = HashSet[Int]()
      for (i <- 1 to Int.MaxValue) {
      hs += i
      }
      }

      java.lang.NegativeArraySizeException
      at scala.collection.mutable.FlatHashTable.growTable(FlatHashTable.scala:218)
      at scala.collection.mutable.FlatHashTable.addEntry(FlatHashTable.scala:160)
      at scala.collection.mutable.FlatHashTable.addEntry$(FlatHashTable.scala:148)
      at scala.collection.mutable.HashSet.addEntry(HashSet.scala:39)
      at scala.collection.mutable.FlatHashTable.addElem(FlatHashTable.scala:140)
      at scala.collection.mutable.FlatHashTable.addElem$(FlatHashTable.scala:139)
      at scala.collection.mutable.HashSet.addElem(HashSet.scala:39)
      at scala.collection.mutable.HashSet.$plus$eq(HashSet.scala:58)
      at alice.grid.collection.TestApp$.$anonfun$new$2(TestApp.scala:12)
      at scala.collection.immutable.Range.foreach$mVc$sp(Range.scala:155)
      at alice.grid.collection.TestApp$.delayedEndpoint$alice$grid$collection$TestApp$1(TestApp.scala:11)
      at alice.grid.collection.TestApp$delayedInit$body.apply(TestApp.scala:5)
      at scala.Function0.apply$mcV$sp(Function0.scala:34)
      at scala.Function0.apply$mcV$sp$(Function0.scala:34)
      at scala.runtime.AbstractFunction0.apply$mcV$sp(AbstractFunction0.scala:12)
      at scala.App.$anonfun$main$1$adapted(App.scala:76)
      at scala.collection.immutable.List.foreach(List.scala:388)
      at scala.App.main(App.scala:76)
      at scala.App.main$(App.scala:74)
      at alice.grid.collection.TestApp$.main(TestApp.scala:5)
      at alice.grid.collection.TestApp.main(TestApp.scala)
      at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
      at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62)
      at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
      at java.lang.reflect.Method.invoke(Method.java:498)









      share|improve this question














      Following code throws exception after inserting 483180000 values. Is this expected. Is there any way to add more than a billion values into a mutable HashSet in Scala. Tried this code with Scala versions 2.11 and 2.12. Both versions throw same exception.



      import scala.collection.mutable.HashSet

      object TestApp extends App {
      val hs = HashSet[Int]()
      for (i <- 1 to Int.MaxValue) {
      hs += i
      }
      }

      java.lang.NegativeArraySizeException
      at scala.collection.mutable.FlatHashTable.growTable(FlatHashTable.scala:218)
      at scala.collection.mutable.FlatHashTable.addEntry(FlatHashTable.scala:160)
      at scala.collection.mutable.FlatHashTable.addEntry$(FlatHashTable.scala:148)
      at scala.collection.mutable.HashSet.addEntry(HashSet.scala:39)
      at scala.collection.mutable.FlatHashTable.addElem(FlatHashTable.scala:140)
      at scala.collection.mutable.FlatHashTable.addElem$(FlatHashTable.scala:139)
      at scala.collection.mutable.HashSet.addElem(HashSet.scala:39)
      at scala.collection.mutable.HashSet.$plus$eq(HashSet.scala:58)
      at alice.grid.collection.TestApp$.$anonfun$new$2(TestApp.scala:12)
      at scala.collection.immutable.Range.foreach$mVc$sp(Range.scala:155)
      at alice.grid.collection.TestApp$.delayedEndpoint$alice$grid$collection$TestApp$1(TestApp.scala:11)
      at alice.grid.collection.TestApp$delayedInit$body.apply(TestApp.scala:5)
      at scala.Function0.apply$mcV$sp(Function0.scala:34)
      at scala.Function0.apply$mcV$sp$(Function0.scala:34)
      at scala.runtime.AbstractFunction0.apply$mcV$sp(AbstractFunction0.scala:12)
      at scala.App.$anonfun$main$1$adapted(App.scala:76)
      at scala.collection.immutable.List.foreach(List.scala:388)
      at scala.App.main(App.scala:76)
      at scala.App.main$(App.scala:74)
      at alice.grid.collection.TestApp$.main(TestApp.scala:5)
      at alice.grid.collection.TestApp.main(TestApp.scala)
      at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
      at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62)
      at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
      at java.lang.reflect.Method.invoke(Method.java:498)






      scala hashset






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      asked Nov 16 '18 at 20:45









      MichaelSebMichaelSeb

      216




      216
























          1 Answer
          1






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          3














          No, there is no way, how to add that many items. If you check the source code at (FlatHashTable.scala:218), you will find:



          table = new Array[AnyRef](table.length * 2)


          lenth is an integer. At certain point, multiplying it by two will cause an overflow and the result is a negative number. Java does not allow to create an array with size specified by negative number.



          This is simply a limitation imposed by implementation of the HashSet.






          share|improve this answer


























          • Additionally, the max size of Java arrays is also limited roughly to max value of Integer, more precisely: stackoverflow.com/questions/3038392/…

            – ygor
            Nov 16 '18 at 21:14












          Your Answer






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          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          3














          No, there is no way, how to add that many items. If you check the source code at (FlatHashTable.scala:218), you will find:



          table = new Array[AnyRef](table.length * 2)


          lenth is an integer. At certain point, multiplying it by two will cause an overflow and the result is a negative number. Java does not allow to create an array with size specified by negative number.



          This is simply a limitation imposed by implementation of the HashSet.






          share|improve this answer


























          • Additionally, the max size of Java arrays is also limited roughly to max value of Integer, more precisely: stackoverflow.com/questions/3038392/…

            – ygor
            Nov 16 '18 at 21:14
















          3














          No, there is no way, how to add that many items. If you check the source code at (FlatHashTable.scala:218), you will find:



          table = new Array[AnyRef](table.length * 2)


          lenth is an integer. At certain point, multiplying it by two will cause an overflow and the result is a negative number. Java does not allow to create an array with size specified by negative number.



          This is simply a limitation imposed by implementation of the HashSet.






          share|improve this answer


























          • Additionally, the max size of Java arrays is also limited roughly to max value of Integer, more precisely: stackoverflow.com/questions/3038392/…

            – ygor
            Nov 16 '18 at 21:14














          3












          3








          3







          No, there is no way, how to add that many items. If you check the source code at (FlatHashTable.scala:218), you will find:



          table = new Array[AnyRef](table.length * 2)


          lenth is an integer. At certain point, multiplying it by two will cause an overflow and the result is a negative number. Java does not allow to create an array with size specified by negative number.



          This is simply a limitation imposed by implementation of the HashSet.






          share|improve this answer















          No, there is no way, how to add that many items. If you check the source code at (FlatHashTable.scala:218), you will find:



          table = new Array[AnyRef](table.length * 2)


          lenth is an integer. At certain point, multiplying it by two will cause an overflow and the result is a negative number. Java does not allow to create an array with size specified by negative number.



          This is simply a limitation imposed by implementation of the HashSet.







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Nov 16 '18 at 21:15

























          answered Nov 16 '18 at 21:10









          ygorygor

          1,1521616




          1,1521616













          • Additionally, the max size of Java arrays is also limited roughly to max value of Integer, more precisely: stackoverflow.com/questions/3038392/…

            – ygor
            Nov 16 '18 at 21:14



















          • Additionally, the max size of Java arrays is also limited roughly to max value of Integer, more precisely: stackoverflow.com/questions/3038392/…

            – ygor
            Nov 16 '18 at 21:14

















          Additionally, the max size of Java arrays is also limited roughly to max value of Integer, more precisely: stackoverflow.com/questions/3038392/…

          – ygor
          Nov 16 '18 at 21:14





          Additionally, the max size of Java arrays is also limited roughly to max value of Integer, more precisely: stackoverflow.com/questions/3038392/…

          – ygor
          Nov 16 '18 at 21:14




















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