How can I put two or more arrays into a single array?





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1















I want to take the values of the three arrays put them together into one array and output it but I have no idea how to do this. I would appreciate any answers to lead me in the right direction.



    // num is user entered as number of times to output
int skuNum = new int[num];
int letters = new int[4];
int l_p_Num = new int[4];

int count = 1;
// Fill numbers array
for (int s: skuNum) {
System.out.print(String.format("%05d", (s + count)) + " ");
count++;
// Fill letters array
for(int i: letters) {
i = (rnd.nextInt(26) + 'A');
System.out.print((char)i);
}
System.out.print(" ");
for(int q: l_p_Num) {
q = rnd.nextInt(9) + 0;
System.out.print(q);
}
System.out.println();
}









share|improve this question























  • How are you going to order the values in the new array? Just put all of one array's values in then the next array, then the 3rd?

    – Ryan Wilson
    Nov 16 '18 at 20:51













  • What I want is to have a new array with the three arrays values in an index. What I have will give me 00001 DVAH 4238. 00001 is in the first array, DVAH in the second, and 4238 in the third. What I now want is 00001 DVAH 4238 in a single array.

    – J J
    Nov 16 '18 at 20:53








  • 3





    What does that mean??

    – shmosel
    Nov 16 '18 at 20:53











  • Have a look at my answer :)

    – Emanuel Graf
    Nov 16 '18 at 21:10


















1















I want to take the values of the three arrays put them together into one array and output it but I have no idea how to do this. I would appreciate any answers to lead me in the right direction.



    // num is user entered as number of times to output
int skuNum = new int[num];
int letters = new int[4];
int l_p_Num = new int[4];

int count = 1;
// Fill numbers array
for (int s: skuNum) {
System.out.print(String.format("%05d", (s + count)) + " ");
count++;
// Fill letters array
for(int i: letters) {
i = (rnd.nextInt(26) + 'A');
System.out.print((char)i);
}
System.out.print(" ");
for(int q: l_p_Num) {
q = rnd.nextInt(9) + 0;
System.out.print(q);
}
System.out.println();
}









share|improve this question























  • How are you going to order the values in the new array? Just put all of one array's values in then the next array, then the 3rd?

    – Ryan Wilson
    Nov 16 '18 at 20:51













  • What I want is to have a new array with the three arrays values in an index. What I have will give me 00001 DVAH 4238. 00001 is in the first array, DVAH in the second, and 4238 in the third. What I now want is 00001 DVAH 4238 in a single array.

    – J J
    Nov 16 '18 at 20:53








  • 3





    What does that mean??

    – shmosel
    Nov 16 '18 at 20:53











  • Have a look at my answer :)

    – Emanuel Graf
    Nov 16 '18 at 21:10














1












1








1


0






I want to take the values of the three arrays put them together into one array and output it but I have no idea how to do this. I would appreciate any answers to lead me in the right direction.



    // num is user entered as number of times to output
int skuNum = new int[num];
int letters = new int[4];
int l_p_Num = new int[4];

int count = 1;
// Fill numbers array
for (int s: skuNum) {
System.out.print(String.format("%05d", (s + count)) + " ");
count++;
// Fill letters array
for(int i: letters) {
i = (rnd.nextInt(26) + 'A');
System.out.print((char)i);
}
System.out.print(" ");
for(int q: l_p_Num) {
q = rnd.nextInt(9) + 0;
System.out.print(q);
}
System.out.println();
}









share|improve this question














I want to take the values of the three arrays put them together into one array and output it but I have no idea how to do this. I would appreciate any answers to lead me in the right direction.



    // num is user entered as number of times to output
int skuNum = new int[num];
int letters = new int[4];
int l_p_Num = new int[4];

int count = 1;
// Fill numbers array
for (int s: skuNum) {
System.out.print(String.format("%05d", (s + count)) + " ");
count++;
// Fill letters array
for(int i: letters) {
i = (rnd.nextInt(26) + 'A');
System.out.print((char)i);
}
System.out.print(" ");
for(int q: l_p_Num) {
q = rnd.nextInt(9) + 0;
System.out.print(q);
}
System.out.println();
}






java arrays






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asked Nov 16 '18 at 20:47









J JJ J

83




83













  • How are you going to order the values in the new array? Just put all of one array's values in then the next array, then the 3rd?

    – Ryan Wilson
    Nov 16 '18 at 20:51













  • What I want is to have a new array with the three arrays values in an index. What I have will give me 00001 DVAH 4238. 00001 is in the first array, DVAH in the second, and 4238 in the third. What I now want is 00001 DVAH 4238 in a single array.

    – J J
    Nov 16 '18 at 20:53








  • 3





    What does that mean??

    – shmosel
    Nov 16 '18 at 20:53











  • Have a look at my answer :)

    – Emanuel Graf
    Nov 16 '18 at 21:10



















  • How are you going to order the values in the new array? Just put all of one array's values in then the next array, then the 3rd?

    – Ryan Wilson
    Nov 16 '18 at 20:51













  • What I want is to have a new array with the three arrays values in an index. What I have will give me 00001 DVAH 4238. 00001 is in the first array, DVAH in the second, and 4238 in the third. What I now want is 00001 DVAH 4238 in a single array.

    – J J
    Nov 16 '18 at 20:53








  • 3





    What does that mean??

    – shmosel
    Nov 16 '18 at 20:53











  • Have a look at my answer :)

    – Emanuel Graf
    Nov 16 '18 at 21:10

















How are you going to order the values in the new array? Just put all of one array's values in then the next array, then the 3rd?

– Ryan Wilson
Nov 16 '18 at 20:51







How are you going to order the values in the new array? Just put all of one array's values in then the next array, then the 3rd?

– Ryan Wilson
Nov 16 '18 at 20:51















What I want is to have a new array with the three arrays values in an index. What I have will give me 00001 DVAH 4238. 00001 is in the first array, DVAH in the second, and 4238 in the third. What I now want is 00001 DVAH 4238 in a single array.

– J J
Nov 16 '18 at 20:53







What I want is to have a new array with the three arrays values in an index. What I have will give me 00001 DVAH 4238. 00001 is in the first array, DVAH in the second, and 4238 in the third. What I now want is 00001 DVAH 4238 in a single array.

– J J
Nov 16 '18 at 20:53






3




3





What does that mean??

– shmosel
Nov 16 '18 at 20:53





What does that mean??

– shmosel
Nov 16 '18 at 20:53













Have a look at my answer :)

– Emanuel Graf
Nov 16 '18 at 21:10





Have a look at my answer :)

– Emanuel Graf
Nov 16 '18 at 21:10












4 Answers
4






active

oldest

votes


















0














You can use:



int arrays = {skuNum, letters, l_p_Num};


or



int arrays = new int {skuNum, letters, l_p_Num};


to create array of arrays and iterate through each array with for loops:



for (int i = 0; i < arrays .length; i++) {
// each array from arrays
for (int j = 0; j < arrays [i].length; j++) {
//each int value from each array
System.out.println(arrays[i][j]);
}
}


To display the result in your "00001 DVAH 4238" format



for (int i=0; i<skuNum.length; i++) {
String row = String.valueOf(skuNum[i]) + String.valueOf(letters[i]) + String.valueOf(l_p_Num[i]);
System.out.println(row);
}





share|improve this answer


























  • This worked for me but I'm still a beginner so I don't know what exactly I have to do to get rid of this: [I@6bdf28bb [I@6b71769e [I@2752f6e2

    – J J
    Nov 16 '18 at 21:05











  • I added an example to display result in your custom format

    – Centos
    Nov 16 '18 at 22:00



















3














A possible java 8 solution is the following:



    int skuNum = new int[num];
int letters = new int {1, 2, 3, 4};
int l_p_Num = new int {11, 12, 13, 14};


IntStream joined = IntStream.concat(IntStream.concat(IntStream.of(skuNum), IntStream.of(letters)), IntStream.of(l_p_Num));

System.out.println(joined
.boxed()
.map(String::valueOf)
.collect(Collectors.joining(",")));





share|improve this answer

































    0














    Declare a new int array to hold all the numbers and then use System.arraycopy() to copy the smaller arrays into the result array:



    int skuNum = new int[num]; // 1, 2
    int letters = new int[4]; // 4, 5, 6, 7
    int l_p_Num = new int[4]; // 9, 8, 7, 6

    int result = new int[num + 8];
    System.arraycopy(skuNum, 0, result, 0, num);
    System.arraycopy(letters, 0, result, num, 4);
    System.arraycopy(l_p_Num, 0, result, num + 4, 4);

    System.out.println(Arrays.toString(result));


    will output:



    [1, 2, 4, 5, 6, 7, 9, 8, 7, 6]





    share|improve this answer





















    • 1





      All that'll give is 0's

      – J J
      Nov 16 '18 at 20:59



















    0














    So this is without the Java generics, just with for loops



    int skuNum = {1,2,3};
    int letters = {4,5,6};
    int l_p_Num = {7,8,9};

    int finalInt = new int[skuNum.length+letters.length+l_p_Num.length];

    for (int i = 0; i<skuNum.length;i++) {
    finalInt[i] =skuNum[i];

    }

    for (int i = 0; i<letters.length;i++) {
    finalInt[i+skuNum.length] =letters[i];

    }
    for (int i = 0; i<l_p_Num.length;i++) {
    finalInt[i+skuNum.length+letters.length] =l_p_Num[i];

    }
    for (int i : finalInt)
    System.out.print(i);


    Result:



    123456789


    If you want to have strings in it see this code:



            int skuNum = {1,2,3};
    String letters = {"asd","asd","aefuh"};
    int l_p_Num = {7,8,9};

    String finalArray = new String[skuNum.length+letters.length+l_p_Num.length];

    for (int i = 0; i<skuNum.length;i++) {
    finalArray[i] =String.valueOf(skuNum[i]);

    }

    for (int i = 0; i<letters.length;i++) {
    finalArray[i+skuNum.length] =letters[i];

    }
    for (int i = 0; i<l_p_Num.length;i++) {
    finalArray[i+skuNum.length+letters.length] = String.valueOf(l_p_Num[i]);

    }
    for (String st : finalArray)
    System.out.print(st);





    share|improve this answer


























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      4 Answers
      4






      active

      oldest

      votes








      4 Answers
      4






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      0














      You can use:



      int arrays = {skuNum, letters, l_p_Num};


      or



      int arrays = new int {skuNum, letters, l_p_Num};


      to create array of arrays and iterate through each array with for loops:



      for (int i = 0; i < arrays .length; i++) {
      // each array from arrays
      for (int j = 0; j < arrays [i].length; j++) {
      //each int value from each array
      System.out.println(arrays[i][j]);
      }
      }


      To display the result in your "00001 DVAH 4238" format



      for (int i=0; i<skuNum.length; i++) {
      String row = String.valueOf(skuNum[i]) + String.valueOf(letters[i]) + String.valueOf(l_p_Num[i]);
      System.out.println(row);
      }





      share|improve this answer


























      • This worked for me but I'm still a beginner so I don't know what exactly I have to do to get rid of this: [I@6bdf28bb [I@6b71769e [I@2752f6e2

        – J J
        Nov 16 '18 at 21:05











      • I added an example to display result in your custom format

        – Centos
        Nov 16 '18 at 22:00
















      0














      You can use:



      int arrays = {skuNum, letters, l_p_Num};


      or



      int arrays = new int {skuNum, letters, l_p_Num};


      to create array of arrays and iterate through each array with for loops:



      for (int i = 0; i < arrays .length; i++) {
      // each array from arrays
      for (int j = 0; j < arrays [i].length; j++) {
      //each int value from each array
      System.out.println(arrays[i][j]);
      }
      }


      To display the result in your "00001 DVAH 4238" format



      for (int i=0; i<skuNum.length; i++) {
      String row = String.valueOf(skuNum[i]) + String.valueOf(letters[i]) + String.valueOf(l_p_Num[i]);
      System.out.println(row);
      }





      share|improve this answer


























      • This worked for me but I'm still a beginner so I don't know what exactly I have to do to get rid of this: [I@6bdf28bb [I@6b71769e [I@2752f6e2

        – J J
        Nov 16 '18 at 21:05











      • I added an example to display result in your custom format

        – Centos
        Nov 16 '18 at 22:00














      0












      0








      0







      You can use:



      int arrays = {skuNum, letters, l_p_Num};


      or



      int arrays = new int {skuNum, letters, l_p_Num};


      to create array of arrays and iterate through each array with for loops:



      for (int i = 0; i < arrays .length; i++) {
      // each array from arrays
      for (int j = 0; j < arrays [i].length; j++) {
      //each int value from each array
      System.out.println(arrays[i][j]);
      }
      }


      To display the result in your "00001 DVAH 4238" format



      for (int i=0; i<skuNum.length; i++) {
      String row = String.valueOf(skuNum[i]) + String.valueOf(letters[i]) + String.valueOf(l_p_Num[i]);
      System.out.println(row);
      }





      share|improve this answer















      You can use:



      int arrays = {skuNum, letters, l_p_Num};


      or



      int arrays = new int {skuNum, letters, l_p_Num};


      to create array of arrays and iterate through each array with for loops:



      for (int i = 0; i < arrays .length; i++) {
      // each array from arrays
      for (int j = 0; j < arrays [i].length; j++) {
      //each int value from each array
      System.out.println(arrays[i][j]);
      }
      }


      To display the result in your "00001 DVAH 4238" format



      for (int i=0; i<skuNum.length; i++) {
      String row = String.valueOf(skuNum[i]) + String.valueOf(letters[i]) + String.valueOf(l_p_Num[i]);
      System.out.println(row);
      }






      share|improve this answer














      share|improve this answer



      share|improve this answer








      edited Nov 16 '18 at 21:46

























      answered Nov 16 '18 at 20:58









      CentosCentos

      200110




      200110













      • This worked for me but I'm still a beginner so I don't know what exactly I have to do to get rid of this: [I@6bdf28bb [I@6b71769e [I@2752f6e2

        – J J
        Nov 16 '18 at 21:05











      • I added an example to display result in your custom format

        – Centos
        Nov 16 '18 at 22:00



















      • This worked for me but I'm still a beginner so I don't know what exactly I have to do to get rid of this: [I@6bdf28bb [I@6b71769e [I@2752f6e2

        – J J
        Nov 16 '18 at 21:05











      • I added an example to display result in your custom format

        – Centos
        Nov 16 '18 at 22:00

















      This worked for me but I'm still a beginner so I don't know what exactly I have to do to get rid of this: [I@6bdf28bb [I@6b71769e [I@2752f6e2

      – J J
      Nov 16 '18 at 21:05





      This worked for me but I'm still a beginner so I don't know what exactly I have to do to get rid of this: [I@6bdf28bb [I@6b71769e [I@2752f6e2

      – J J
      Nov 16 '18 at 21:05













      I added an example to display result in your custom format

      – Centos
      Nov 16 '18 at 22:00





      I added an example to display result in your custom format

      – Centos
      Nov 16 '18 at 22:00













      3














      A possible java 8 solution is the following:



          int skuNum = new int[num];
      int letters = new int {1, 2, 3, 4};
      int l_p_Num = new int {11, 12, 13, 14};


      IntStream joined = IntStream.concat(IntStream.concat(IntStream.of(skuNum), IntStream.of(letters)), IntStream.of(l_p_Num));

      System.out.println(joined
      .boxed()
      .map(String::valueOf)
      .collect(Collectors.joining(",")));





      share|improve this answer






























        3














        A possible java 8 solution is the following:



            int skuNum = new int[num];
        int letters = new int {1, 2, 3, 4};
        int l_p_Num = new int {11, 12, 13, 14};


        IntStream joined = IntStream.concat(IntStream.concat(IntStream.of(skuNum), IntStream.of(letters)), IntStream.of(l_p_Num));

        System.out.println(joined
        .boxed()
        .map(String::valueOf)
        .collect(Collectors.joining(",")));





        share|improve this answer




























          3












          3








          3







          A possible java 8 solution is the following:



              int skuNum = new int[num];
          int letters = new int {1, 2, 3, 4};
          int l_p_Num = new int {11, 12, 13, 14};


          IntStream joined = IntStream.concat(IntStream.concat(IntStream.of(skuNum), IntStream.of(letters)), IntStream.of(l_p_Num));

          System.out.println(joined
          .boxed()
          .map(String::valueOf)
          .collect(Collectors.joining(",")));





          share|improve this answer















          A possible java 8 solution is the following:



              int skuNum = new int[num];
          int letters = new int {1, 2, 3, 4};
          int l_p_Num = new int {11, 12, 13, 14};


          IntStream joined = IntStream.concat(IntStream.concat(IntStream.of(skuNum), IntStream.of(letters)), IntStream.of(l_p_Num));

          System.out.println(joined
          .boxed()
          .map(String::valueOf)
          .collect(Collectors.joining(",")));






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Nov 16 '18 at 21:26

























          answered Nov 16 '18 at 21:09









          yaccobyaccob

          668611




          668611























              0














              Declare a new int array to hold all the numbers and then use System.arraycopy() to copy the smaller arrays into the result array:



              int skuNum = new int[num]; // 1, 2
              int letters = new int[4]; // 4, 5, 6, 7
              int l_p_Num = new int[4]; // 9, 8, 7, 6

              int result = new int[num + 8];
              System.arraycopy(skuNum, 0, result, 0, num);
              System.arraycopy(letters, 0, result, num, 4);
              System.arraycopy(l_p_Num, 0, result, num + 4, 4);

              System.out.println(Arrays.toString(result));


              will output:



              [1, 2, 4, 5, 6, 7, 9, 8, 7, 6]





              share|improve this answer





















              • 1





                All that'll give is 0's

                – J J
                Nov 16 '18 at 20:59
















              0














              Declare a new int array to hold all the numbers and then use System.arraycopy() to copy the smaller arrays into the result array:



              int skuNum = new int[num]; // 1, 2
              int letters = new int[4]; // 4, 5, 6, 7
              int l_p_Num = new int[4]; // 9, 8, 7, 6

              int result = new int[num + 8];
              System.arraycopy(skuNum, 0, result, 0, num);
              System.arraycopy(letters, 0, result, num, 4);
              System.arraycopy(l_p_Num, 0, result, num + 4, 4);

              System.out.println(Arrays.toString(result));


              will output:



              [1, 2, 4, 5, 6, 7, 9, 8, 7, 6]





              share|improve this answer





















              • 1





                All that'll give is 0's

                – J J
                Nov 16 '18 at 20:59














              0












              0








              0







              Declare a new int array to hold all the numbers and then use System.arraycopy() to copy the smaller arrays into the result array:



              int skuNum = new int[num]; // 1, 2
              int letters = new int[4]; // 4, 5, 6, 7
              int l_p_Num = new int[4]; // 9, 8, 7, 6

              int result = new int[num + 8];
              System.arraycopy(skuNum, 0, result, 0, num);
              System.arraycopy(letters, 0, result, num, 4);
              System.arraycopy(l_p_Num, 0, result, num + 4, 4);

              System.out.println(Arrays.toString(result));


              will output:



              [1, 2, 4, 5, 6, 7, 9, 8, 7, 6]





              share|improve this answer















              Declare a new int array to hold all the numbers and then use System.arraycopy() to copy the smaller arrays into the result array:



              int skuNum = new int[num]; // 1, 2
              int letters = new int[4]; // 4, 5, 6, 7
              int l_p_Num = new int[4]; // 9, 8, 7, 6

              int result = new int[num + 8];
              System.arraycopy(skuNum, 0, result, 0, num);
              System.arraycopy(letters, 0, result, num, 4);
              System.arraycopy(l_p_Num, 0, result, num + 4, 4);

              System.out.println(Arrays.toString(result));


              will output:



              [1, 2, 4, 5, 6, 7, 9, 8, 7, 6]






              share|improve this answer














              share|improve this answer



              share|improve this answer








              edited Nov 16 '18 at 20:59

























              answered Nov 16 '18 at 20:54









              Karol DowbeckiKarol Dowbecki

              26.8k93860




              26.8k93860








              • 1





                All that'll give is 0's

                – J J
                Nov 16 '18 at 20:59














              • 1





                All that'll give is 0's

                – J J
                Nov 16 '18 at 20:59








              1




              1





              All that'll give is 0's

              – J J
              Nov 16 '18 at 20:59





              All that'll give is 0's

              – J J
              Nov 16 '18 at 20:59











              0














              So this is without the Java generics, just with for loops



              int skuNum = {1,2,3};
              int letters = {4,5,6};
              int l_p_Num = {7,8,9};

              int finalInt = new int[skuNum.length+letters.length+l_p_Num.length];

              for (int i = 0; i<skuNum.length;i++) {
              finalInt[i] =skuNum[i];

              }

              for (int i = 0; i<letters.length;i++) {
              finalInt[i+skuNum.length] =letters[i];

              }
              for (int i = 0; i<l_p_Num.length;i++) {
              finalInt[i+skuNum.length+letters.length] =l_p_Num[i];

              }
              for (int i : finalInt)
              System.out.print(i);


              Result:



              123456789


              If you want to have strings in it see this code:



                      int skuNum = {1,2,3};
              String letters = {"asd","asd","aefuh"};
              int l_p_Num = {7,8,9};

              String finalArray = new String[skuNum.length+letters.length+l_p_Num.length];

              for (int i = 0; i<skuNum.length;i++) {
              finalArray[i] =String.valueOf(skuNum[i]);

              }

              for (int i = 0; i<letters.length;i++) {
              finalArray[i+skuNum.length] =letters[i];

              }
              for (int i = 0; i<l_p_Num.length;i++) {
              finalArray[i+skuNum.length+letters.length] = String.valueOf(l_p_Num[i]);

              }
              for (String st : finalArray)
              System.out.print(st);





              share|improve this answer






























                0














                So this is without the Java generics, just with for loops



                int skuNum = {1,2,3};
                int letters = {4,5,6};
                int l_p_Num = {7,8,9};

                int finalInt = new int[skuNum.length+letters.length+l_p_Num.length];

                for (int i = 0; i<skuNum.length;i++) {
                finalInt[i] =skuNum[i];

                }

                for (int i = 0; i<letters.length;i++) {
                finalInt[i+skuNum.length] =letters[i];

                }
                for (int i = 0; i<l_p_Num.length;i++) {
                finalInt[i+skuNum.length+letters.length] =l_p_Num[i];

                }
                for (int i : finalInt)
                System.out.print(i);


                Result:



                123456789


                If you want to have strings in it see this code:



                        int skuNum = {1,2,3};
                String letters = {"asd","asd","aefuh"};
                int l_p_Num = {7,8,9};

                String finalArray = new String[skuNum.length+letters.length+l_p_Num.length];

                for (int i = 0; i<skuNum.length;i++) {
                finalArray[i] =String.valueOf(skuNum[i]);

                }

                for (int i = 0; i<letters.length;i++) {
                finalArray[i+skuNum.length] =letters[i];

                }
                for (int i = 0; i<l_p_Num.length;i++) {
                finalArray[i+skuNum.length+letters.length] = String.valueOf(l_p_Num[i]);

                }
                for (String st : finalArray)
                System.out.print(st);





                share|improve this answer




























                  0












                  0








                  0







                  So this is without the Java generics, just with for loops



                  int skuNum = {1,2,3};
                  int letters = {4,5,6};
                  int l_p_Num = {7,8,9};

                  int finalInt = new int[skuNum.length+letters.length+l_p_Num.length];

                  for (int i = 0; i<skuNum.length;i++) {
                  finalInt[i] =skuNum[i];

                  }

                  for (int i = 0; i<letters.length;i++) {
                  finalInt[i+skuNum.length] =letters[i];

                  }
                  for (int i = 0; i<l_p_Num.length;i++) {
                  finalInt[i+skuNum.length+letters.length] =l_p_Num[i];

                  }
                  for (int i : finalInt)
                  System.out.print(i);


                  Result:



                  123456789


                  If you want to have strings in it see this code:



                          int skuNum = {1,2,3};
                  String letters = {"asd","asd","aefuh"};
                  int l_p_Num = {7,8,9};

                  String finalArray = new String[skuNum.length+letters.length+l_p_Num.length];

                  for (int i = 0; i<skuNum.length;i++) {
                  finalArray[i] =String.valueOf(skuNum[i]);

                  }

                  for (int i = 0; i<letters.length;i++) {
                  finalArray[i+skuNum.length] =letters[i];

                  }
                  for (int i = 0; i<l_p_Num.length;i++) {
                  finalArray[i+skuNum.length+letters.length] = String.valueOf(l_p_Num[i]);

                  }
                  for (String st : finalArray)
                  System.out.print(st);





                  share|improve this answer















                  So this is without the Java generics, just with for loops



                  int skuNum = {1,2,3};
                  int letters = {4,5,6};
                  int l_p_Num = {7,8,9};

                  int finalInt = new int[skuNum.length+letters.length+l_p_Num.length];

                  for (int i = 0; i<skuNum.length;i++) {
                  finalInt[i] =skuNum[i];

                  }

                  for (int i = 0; i<letters.length;i++) {
                  finalInt[i+skuNum.length] =letters[i];

                  }
                  for (int i = 0; i<l_p_Num.length;i++) {
                  finalInt[i+skuNum.length+letters.length] =l_p_Num[i];

                  }
                  for (int i : finalInt)
                  System.out.print(i);


                  Result:



                  123456789


                  If you want to have strings in it see this code:



                          int skuNum = {1,2,3};
                  String letters = {"asd","asd","aefuh"};
                  int l_p_Num = {7,8,9};

                  String finalArray = new String[skuNum.length+letters.length+l_p_Num.length];

                  for (int i = 0; i<skuNum.length;i++) {
                  finalArray[i] =String.valueOf(skuNum[i]);

                  }

                  for (int i = 0; i<letters.length;i++) {
                  finalArray[i+skuNum.length] =letters[i];

                  }
                  for (int i = 0; i<l_p_Num.length;i++) {
                  finalArray[i+skuNum.length+letters.length] = String.valueOf(l_p_Num[i]);

                  }
                  for (String st : finalArray)
                  System.out.print(st);






                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited Nov 16 '18 at 21:08

























                  answered Nov 16 '18 at 21:00









                  Emanuel GrafEmanuel Graf

                  409827




                  409827






























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