Correct way to execute multiple reactive operations





.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ height:90px;width:728px;box-sizing:border-box;
}







0















I get from a reactive repository a Mono<FooBar> based on it's value I have to create two other objects save them using reactive repositories, modify FooBar object and save it as well.



As I'm new to reactive programming I landed with the following solution, which is working, but I'm not sure if I'm using correctly the reactive API:



@Test
void createAndSave() {
Mono<FooBar> fooBarMono = findFooBar() // returns Mono<FooBar>
.map(fooBar -> {
createAndSaveLoremBar(fooBar).subscribe(); // returns Mono<LoremBar>
createAndSaveDoloremBar(fooBar).subscribe(); // returns Mono<DoloremBar>

fooBar.setActive(true);

return saveFooBar(fooBar); // returns Mono<FooBar>
}).flatMap(Function.identity());

StepVerifier.create(fooBarMono)
.expectNextMatches(Objects::nonNull)
.expectComplete()
.verify();

}


from console log:



   saved lorem bar
saved dolorem bar
saved foo bar









share|improve this question























  • Is it required to save lorem bar and dolorem bar before activating fooBar? And what about errors on lorem and dolorem saving? Should we ignore or propagate errors?

    – Alexander Pankin
    Nov 16 '18 at 23:09













  • @AlexanderPankin the order of saving doesn't matter; errors should be propagated if possible

    – A5300
    Nov 17 '18 at 11:59




















0















I get from a reactive repository a Mono<FooBar> based on it's value I have to create two other objects save them using reactive repositories, modify FooBar object and save it as well.



As I'm new to reactive programming I landed with the following solution, which is working, but I'm not sure if I'm using correctly the reactive API:



@Test
void createAndSave() {
Mono<FooBar> fooBarMono = findFooBar() // returns Mono<FooBar>
.map(fooBar -> {
createAndSaveLoremBar(fooBar).subscribe(); // returns Mono<LoremBar>
createAndSaveDoloremBar(fooBar).subscribe(); // returns Mono<DoloremBar>

fooBar.setActive(true);

return saveFooBar(fooBar); // returns Mono<FooBar>
}).flatMap(Function.identity());

StepVerifier.create(fooBarMono)
.expectNextMatches(Objects::nonNull)
.expectComplete()
.verify();

}


from console log:



   saved lorem bar
saved dolorem bar
saved foo bar









share|improve this question























  • Is it required to save lorem bar and dolorem bar before activating fooBar? And what about errors on lorem and dolorem saving? Should we ignore or propagate errors?

    – Alexander Pankin
    Nov 16 '18 at 23:09













  • @AlexanderPankin the order of saving doesn't matter; errors should be propagated if possible

    – A5300
    Nov 17 '18 at 11:59
















0












0








0








I get from a reactive repository a Mono<FooBar> based on it's value I have to create two other objects save them using reactive repositories, modify FooBar object and save it as well.



As I'm new to reactive programming I landed with the following solution, which is working, but I'm not sure if I'm using correctly the reactive API:



@Test
void createAndSave() {
Mono<FooBar> fooBarMono = findFooBar() // returns Mono<FooBar>
.map(fooBar -> {
createAndSaveLoremBar(fooBar).subscribe(); // returns Mono<LoremBar>
createAndSaveDoloremBar(fooBar).subscribe(); // returns Mono<DoloremBar>

fooBar.setActive(true);

return saveFooBar(fooBar); // returns Mono<FooBar>
}).flatMap(Function.identity());

StepVerifier.create(fooBarMono)
.expectNextMatches(Objects::nonNull)
.expectComplete()
.verify();

}


from console log:



   saved lorem bar
saved dolorem bar
saved foo bar









share|improve this question














I get from a reactive repository a Mono<FooBar> based on it's value I have to create two other objects save them using reactive repositories, modify FooBar object and save it as well.



As I'm new to reactive programming I landed with the following solution, which is working, but I'm not sure if I'm using correctly the reactive API:



@Test
void createAndSave() {
Mono<FooBar> fooBarMono = findFooBar() // returns Mono<FooBar>
.map(fooBar -> {
createAndSaveLoremBar(fooBar).subscribe(); // returns Mono<LoremBar>
createAndSaveDoloremBar(fooBar).subscribe(); // returns Mono<DoloremBar>

fooBar.setActive(true);

return saveFooBar(fooBar); // returns Mono<FooBar>
}).flatMap(Function.identity());

StepVerifier.create(fooBarMono)
.expectNextMatches(Objects::nonNull)
.expectComplete()
.verify();

}


from console log:



   saved lorem bar
saved dolorem bar
saved foo bar






spring-data-mongodb spring-webflow project-reactor






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 16 '18 at 20:44









A5300A5300

828




828













  • Is it required to save lorem bar and dolorem bar before activating fooBar? And what about errors on lorem and dolorem saving? Should we ignore or propagate errors?

    – Alexander Pankin
    Nov 16 '18 at 23:09













  • @AlexanderPankin the order of saving doesn't matter; errors should be propagated if possible

    – A5300
    Nov 17 '18 at 11:59





















  • Is it required to save lorem bar and dolorem bar before activating fooBar? And what about errors on lorem and dolorem saving? Should we ignore or propagate errors?

    – Alexander Pankin
    Nov 16 '18 at 23:09













  • @AlexanderPankin the order of saving doesn't matter; errors should be propagated if possible

    – A5300
    Nov 17 '18 at 11:59



















Is it required to save lorem bar and dolorem bar before activating fooBar? And what about errors on lorem and dolorem saving? Should we ignore or propagate errors?

– Alexander Pankin
Nov 16 '18 at 23:09







Is it required to save lorem bar and dolorem bar before activating fooBar? And what about errors on lorem and dolorem saving? Should we ignore or propagate errors?

– Alexander Pankin
Nov 16 '18 at 23:09















@AlexanderPankin the order of saving doesn't matter; errors should be propagated if possible

– A5300
Nov 17 '18 at 11:59







@AlexanderPankin the order of saving doesn't matter; errors should be propagated if possible

– A5300
Nov 17 '18 at 11:59














2 Answers
2






active

oldest

votes


















0














At first, mutating objects in the asynchronous (reactive) world is not a good idea.



Anyway, in your solution possible errors on lorem and dolorem saving are ignored. You can improve it like so:



Mono<FooBar> fooBarMono = findFooBar()
.flatMap(fooBar -> Flux.merge(
createAndSaveLoremBar(fooBar),
createAndSaveDoloremBar(fooBar)) // asynchronously saving lorem and dolorem
.then(Mono.fromCallable(() -> { // if there wasn't errors, mutate and save fooBar
fooBar.setActive(true);
return fooBar;
}).flatMap(fooBar1 -> saveFooBar(fooBar1))));


If you could create copy of your fooBar with true active flag, the code could be simpler. For example with lombok.



@Builder(toBuilder = true)
public class FooBar {
...
}

Mono<FooBar> fooBarMono = findFooBar()
.flatMap(fooBar -> Flux.merge(
createAndSaveLoremBar(fooBar),
createAndSaveDoloremBar(fooBar))
.then(saveFooBar(fooBar.toBuilder().active(true).build())));


And if you are not interested in the result of your saveFooBar(...) but only in the completion signal, you could make all three saves asynchronously:



Flux<Object> flux = findFooBar()
.flatMapMany(fooBar -> Flux.merge(
createAndSaveLoremBar(fooBar),
createAndSaveDoloremBar(fooBar),
saveFooBar(fooBar.toBuilder().active(true).build())));


Actually, in the last approach you could collect all three results and you should prefer this approach, but I don't have enough information about your classes and requirements for creating full example.






share|improve this answer































    0














    I think the bellow solution is a little bit more readable. Anyway Alexander is correct you should never ever modify the input. You see we are borrowing a lot of concept form functional programming. For example you call Function.identity() this is called
    identity functor. Both Fluxand Mono are monads. And there is a concept that is secret for these guys called Referential transparency that imperative update break.



        final Mono<FooBar> fooBarMono1 = findFooBar()
    .zipWhen((fooBar) -> createAndSaveLoremBar(fooBar))
    .map(tuple -> tuple.getT1())
    .zipWhen((fooBar) -> createAndSaveDoloremBar(fooBar))
    .map(tuple -> tuple.getT1())
    .map(fooBar -> new FooBar(true))
    .flatMap(fooBar -> saveFooBar(fooBar));


    Or more concise:



        final Mono<FooBar> fooBarMono1 = findFooBar()
    .zipWhen((fooBar) -> createAndSaveLoremBar(fooBar)
    .then(createAndSaveDoloremBar(fooBar)))
    .map(tuple -> tuple.getT1())
    .map(fooBar -> new FooBar(true))
    .flatMap(fooBar -> saveFooBar(fooBar));





    share|improve this answer
























      Your Answer






      StackExchange.ifUsing("editor", function () {
      StackExchange.using("externalEditor", function () {
      StackExchange.using("snippets", function () {
      StackExchange.snippets.init();
      });
      });
      }, "code-snippets");

      StackExchange.ready(function() {
      var channelOptions = {
      tags: "".split(" "),
      id: "1"
      };
      initTagRenderer("".split(" "), "".split(" "), channelOptions);

      StackExchange.using("externalEditor", function() {
      // Have to fire editor after snippets, if snippets enabled
      if (StackExchange.settings.snippets.snippetsEnabled) {
      StackExchange.using("snippets", function() {
      createEditor();
      });
      }
      else {
      createEditor();
      }
      });

      function createEditor() {
      StackExchange.prepareEditor({
      heartbeatType: 'answer',
      autoActivateHeartbeat: false,
      convertImagesToLinks: true,
      noModals: true,
      showLowRepImageUploadWarning: true,
      reputationToPostImages: 10,
      bindNavPrevention: true,
      postfix: "",
      imageUploader: {
      brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
      contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
      allowUrls: true
      },
      onDemand: true,
      discardSelector: ".discard-answer"
      ,immediatelyShowMarkdownHelp:true
      });


      }
      });














      draft saved

      draft discarded


















      StackExchange.ready(
      function () {
      StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53345130%2fcorrect-way-to-execute-multiple-reactive-operations%23new-answer', 'question_page');
      }
      );

      Post as a guest















      Required, but never shown

























      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      0














      At first, mutating objects in the asynchronous (reactive) world is not a good idea.



      Anyway, in your solution possible errors on lorem and dolorem saving are ignored. You can improve it like so:



      Mono<FooBar> fooBarMono = findFooBar()
      .flatMap(fooBar -> Flux.merge(
      createAndSaveLoremBar(fooBar),
      createAndSaveDoloremBar(fooBar)) // asynchronously saving lorem and dolorem
      .then(Mono.fromCallable(() -> { // if there wasn't errors, mutate and save fooBar
      fooBar.setActive(true);
      return fooBar;
      }).flatMap(fooBar1 -> saveFooBar(fooBar1))));


      If you could create copy of your fooBar with true active flag, the code could be simpler. For example with lombok.



      @Builder(toBuilder = true)
      public class FooBar {
      ...
      }

      Mono<FooBar> fooBarMono = findFooBar()
      .flatMap(fooBar -> Flux.merge(
      createAndSaveLoremBar(fooBar),
      createAndSaveDoloremBar(fooBar))
      .then(saveFooBar(fooBar.toBuilder().active(true).build())));


      And if you are not interested in the result of your saveFooBar(...) but only in the completion signal, you could make all three saves asynchronously:



      Flux<Object> flux = findFooBar()
      .flatMapMany(fooBar -> Flux.merge(
      createAndSaveLoremBar(fooBar),
      createAndSaveDoloremBar(fooBar),
      saveFooBar(fooBar.toBuilder().active(true).build())));


      Actually, in the last approach you could collect all three results and you should prefer this approach, but I don't have enough information about your classes and requirements for creating full example.






      share|improve this answer




























        0














        At first, mutating objects in the asynchronous (reactive) world is not a good idea.



        Anyway, in your solution possible errors on lorem and dolorem saving are ignored. You can improve it like so:



        Mono<FooBar> fooBarMono = findFooBar()
        .flatMap(fooBar -> Flux.merge(
        createAndSaveLoremBar(fooBar),
        createAndSaveDoloremBar(fooBar)) // asynchronously saving lorem and dolorem
        .then(Mono.fromCallable(() -> { // if there wasn't errors, mutate and save fooBar
        fooBar.setActive(true);
        return fooBar;
        }).flatMap(fooBar1 -> saveFooBar(fooBar1))));


        If you could create copy of your fooBar with true active flag, the code could be simpler. For example with lombok.



        @Builder(toBuilder = true)
        public class FooBar {
        ...
        }

        Mono<FooBar> fooBarMono = findFooBar()
        .flatMap(fooBar -> Flux.merge(
        createAndSaveLoremBar(fooBar),
        createAndSaveDoloremBar(fooBar))
        .then(saveFooBar(fooBar.toBuilder().active(true).build())));


        And if you are not interested in the result of your saveFooBar(...) but only in the completion signal, you could make all three saves asynchronously:



        Flux<Object> flux = findFooBar()
        .flatMapMany(fooBar -> Flux.merge(
        createAndSaveLoremBar(fooBar),
        createAndSaveDoloremBar(fooBar),
        saveFooBar(fooBar.toBuilder().active(true).build())));


        Actually, in the last approach you could collect all three results and you should prefer this approach, but I don't have enough information about your classes and requirements for creating full example.






        share|improve this answer


























          0












          0








          0







          At first, mutating objects in the asynchronous (reactive) world is not a good idea.



          Anyway, in your solution possible errors on lorem and dolorem saving are ignored. You can improve it like so:



          Mono<FooBar> fooBarMono = findFooBar()
          .flatMap(fooBar -> Flux.merge(
          createAndSaveLoremBar(fooBar),
          createAndSaveDoloremBar(fooBar)) // asynchronously saving lorem and dolorem
          .then(Mono.fromCallable(() -> { // if there wasn't errors, mutate and save fooBar
          fooBar.setActive(true);
          return fooBar;
          }).flatMap(fooBar1 -> saveFooBar(fooBar1))));


          If you could create copy of your fooBar with true active flag, the code could be simpler. For example with lombok.



          @Builder(toBuilder = true)
          public class FooBar {
          ...
          }

          Mono<FooBar> fooBarMono = findFooBar()
          .flatMap(fooBar -> Flux.merge(
          createAndSaveLoremBar(fooBar),
          createAndSaveDoloremBar(fooBar))
          .then(saveFooBar(fooBar.toBuilder().active(true).build())));


          And if you are not interested in the result of your saveFooBar(...) but only in the completion signal, you could make all three saves asynchronously:



          Flux<Object> flux = findFooBar()
          .flatMapMany(fooBar -> Flux.merge(
          createAndSaveLoremBar(fooBar),
          createAndSaveDoloremBar(fooBar),
          saveFooBar(fooBar.toBuilder().active(true).build())));


          Actually, in the last approach you could collect all three results and you should prefer this approach, but I don't have enough information about your classes and requirements for creating full example.






          share|improve this answer













          At first, mutating objects in the asynchronous (reactive) world is not a good idea.



          Anyway, in your solution possible errors on lorem and dolorem saving are ignored. You can improve it like so:



          Mono<FooBar> fooBarMono = findFooBar()
          .flatMap(fooBar -> Flux.merge(
          createAndSaveLoremBar(fooBar),
          createAndSaveDoloremBar(fooBar)) // asynchronously saving lorem and dolorem
          .then(Mono.fromCallable(() -> { // if there wasn't errors, mutate and save fooBar
          fooBar.setActive(true);
          return fooBar;
          }).flatMap(fooBar1 -> saveFooBar(fooBar1))));


          If you could create copy of your fooBar with true active flag, the code could be simpler. For example with lombok.



          @Builder(toBuilder = true)
          public class FooBar {
          ...
          }

          Mono<FooBar> fooBarMono = findFooBar()
          .flatMap(fooBar -> Flux.merge(
          createAndSaveLoremBar(fooBar),
          createAndSaveDoloremBar(fooBar))
          .then(saveFooBar(fooBar.toBuilder().active(true).build())));


          And if you are not interested in the result of your saveFooBar(...) but only in the completion signal, you could make all three saves asynchronously:



          Flux<Object> flux = findFooBar()
          .flatMapMany(fooBar -> Flux.merge(
          createAndSaveLoremBar(fooBar),
          createAndSaveDoloremBar(fooBar),
          saveFooBar(fooBar.toBuilder().active(true).build())));


          Actually, in the last approach you could collect all three results and you should prefer this approach, but I don't have enough information about your classes and requirements for creating full example.







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 17 '18 at 16:32









          Alexander PankinAlexander Pankin

          1,06129




          1,06129

























              0














              I think the bellow solution is a little bit more readable. Anyway Alexander is correct you should never ever modify the input. You see we are borrowing a lot of concept form functional programming. For example you call Function.identity() this is called
              identity functor. Both Fluxand Mono are monads. And there is a concept that is secret for these guys called Referential transparency that imperative update break.



                  final Mono<FooBar> fooBarMono1 = findFooBar()
              .zipWhen((fooBar) -> createAndSaveLoremBar(fooBar))
              .map(tuple -> tuple.getT1())
              .zipWhen((fooBar) -> createAndSaveDoloremBar(fooBar))
              .map(tuple -> tuple.getT1())
              .map(fooBar -> new FooBar(true))
              .flatMap(fooBar -> saveFooBar(fooBar));


              Or more concise:



                  final Mono<FooBar> fooBarMono1 = findFooBar()
              .zipWhen((fooBar) -> createAndSaveLoremBar(fooBar)
              .then(createAndSaveDoloremBar(fooBar)))
              .map(tuple -> tuple.getT1())
              .map(fooBar -> new FooBar(true))
              .flatMap(fooBar -> saveFooBar(fooBar));





              share|improve this answer




























                0














                I think the bellow solution is a little bit more readable. Anyway Alexander is correct you should never ever modify the input. You see we are borrowing a lot of concept form functional programming. For example you call Function.identity() this is called
                identity functor. Both Fluxand Mono are monads. And there is a concept that is secret for these guys called Referential transparency that imperative update break.



                    final Mono<FooBar> fooBarMono1 = findFooBar()
                .zipWhen((fooBar) -> createAndSaveLoremBar(fooBar))
                .map(tuple -> tuple.getT1())
                .zipWhen((fooBar) -> createAndSaveDoloremBar(fooBar))
                .map(tuple -> tuple.getT1())
                .map(fooBar -> new FooBar(true))
                .flatMap(fooBar -> saveFooBar(fooBar));


                Or more concise:



                    final Mono<FooBar> fooBarMono1 = findFooBar()
                .zipWhen((fooBar) -> createAndSaveLoremBar(fooBar)
                .then(createAndSaveDoloremBar(fooBar)))
                .map(tuple -> tuple.getT1())
                .map(fooBar -> new FooBar(true))
                .flatMap(fooBar -> saveFooBar(fooBar));





                share|improve this answer


























                  0












                  0








                  0







                  I think the bellow solution is a little bit more readable. Anyway Alexander is correct you should never ever modify the input. You see we are borrowing a lot of concept form functional programming. For example you call Function.identity() this is called
                  identity functor. Both Fluxand Mono are monads. And there is a concept that is secret for these guys called Referential transparency that imperative update break.



                      final Mono<FooBar> fooBarMono1 = findFooBar()
                  .zipWhen((fooBar) -> createAndSaveLoremBar(fooBar))
                  .map(tuple -> tuple.getT1())
                  .zipWhen((fooBar) -> createAndSaveDoloremBar(fooBar))
                  .map(tuple -> tuple.getT1())
                  .map(fooBar -> new FooBar(true))
                  .flatMap(fooBar -> saveFooBar(fooBar));


                  Or more concise:



                      final Mono<FooBar> fooBarMono1 = findFooBar()
                  .zipWhen((fooBar) -> createAndSaveLoremBar(fooBar)
                  .then(createAndSaveDoloremBar(fooBar)))
                  .map(tuple -> tuple.getT1())
                  .map(fooBar -> new FooBar(true))
                  .flatMap(fooBar -> saveFooBar(fooBar));





                  share|improve this answer













                  I think the bellow solution is a little bit more readable. Anyway Alexander is correct you should never ever modify the input. You see we are borrowing a lot of concept form functional programming. For example you call Function.identity() this is called
                  identity functor. Both Fluxand Mono are monads. And there is a concept that is secret for these guys called Referential transparency that imperative update break.



                      final Mono<FooBar> fooBarMono1 = findFooBar()
                  .zipWhen((fooBar) -> createAndSaveLoremBar(fooBar))
                  .map(tuple -> tuple.getT1())
                  .zipWhen((fooBar) -> createAndSaveDoloremBar(fooBar))
                  .map(tuple -> tuple.getT1())
                  .map(fooBar -> new FooBar(true))
                  .flatMap(fooBar -> saveFooBar(fooBar));


                  Or more concise:



                      final Mono<FooBar> fooBarMono1 = findFooBar()
                  .zipWhen((fooBar) -> createAndSaveLoremBar(fooBar)
                  .then(createAndSaveDoloremBar(fooBar)))
                  .map(tuple -> tuple.getT1())
                  .map(fooBar -> new FooBar(true))
                  .flatMap(fooBar -> saveFooBar(fooBar));






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 25 '18 at 22:24









                  piotr szybickipiotr szybicki

                  7011511




                  7011511






























                      draft saved

                      draft discarded




















































                      Thanks for contributing an answer to Stack Overflow!


                      • Please be sure to answer the question. Provide details and share your research!

                      But avoid



                      • Asking for help, clarification, or responding to other answers.

                      • Making statements based on opinion; back them up with references or personal experience.


                      To learn more, see our tips on writing great answers.




                      draft saved


                      draft discarded














                      StackExchange.ready(
                      function () {
                      StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53345130%2fcorrect-way-to-execute-multiple-reactive-operations%23new-answer', 'question_page');
                      }
                      );

                      Post as a guest















                      Required, but never shown





















































                      Required, but never shown














                      Required, but never shown












                      Required, but never shown







                      Required, but never shown

































                      Required, but never shown














                      Required, but never shown












                      Required, but never shown







                      Required, but never shown







                      Popular posts from this blog

                      Bressuire

                      Vorschmack

                      Quarantine