Java function with Map.Class parameter in Scala
I'm trying to use a Jackson's ObjectMapper() function: convertValue.
It takes 2 parameters (3 overloads):
- (Object, Call)
- (Object, TypeReference)
- (Object, JavaType)
I have the following code:
val m = new ObjectMapper()
val map: Map[String, Object] = m.convertValue(bean, classOf[Map])
which doesn't work with error Type Mismatch. Expected JavaType actual Class[Map].
I tested with classOf[java.util.Map], Map.getClass, etc. but can't make it work.
How should I send that parameter?
scala
edited Nov 15 '18 at 16:44
P3trur0
2,2091523
asked Nov 15 '18 at 16:19
Fede E.Fede E.
4621614
add a comment |
I'm trying to use a Jackson's ObjectMapper() function: convertValue.
It takes 2 parameters (3 overloads):
- (Object, Call)
- (Object, TypeReference)
- (Object, JavaType)
I have the following code:
val m = new ObjectMapper()
val map: Map[String, Object] = m.convertValue(bean, classOf[Map])
which doesn't work with error Type Mismatch. Expected JavaType actual Class[Map].
I tested with classOf[java.util.Map], Map.getClass, etc. but can't make it work.
How should I send that parameter?
scala
edited Nov 15 '18 at 16:44
P3trur0
2,2091523
asked Nov 15 '18 at 16:19
Fede E.Fede E.
4621614
add a comment |
I'm trying to use a Jackson's ObjectMapper() function: convertValue.
It takes 2 parameters (3 overloads):
- (Object, Call)
- (Object, TypeReference)
- (Object, JavaType)
I have the following code:
val m = new ObjectMapper()
val map: Map[String, Object] = m.convertValue(bean, classOf[Map])
which doesn't work with error Type Mismatch. Expected JavaType actual Class[Map].
I tested with classOf[java.util.Map], Map.getClass, etc. but can't make it work.
How should I send that parameter?
scala
edited Nov 15 '18 at 16:44
P3trur0
2,2091523
asked Nov 15 '18 at 16:19
Fede E.Fede E.
4621614
I'm trying to use a Jackson's ObjectMapper() function: convertValue.
It takes 2 parameters (3 overloads):
- (Object, Call)
- (Object, TypeReference)
- (Object, JavaType)
I have the following code:
val m = new ObjectMapper()
val map: Map[String, Object] = m.convertValue(bean, classOf[Map])
which doesn't work with error Type Mismatch. Expected JavaType actual Class[Map].
I tested with classOf[java.util.Map], Map.getClass, etc. but can't make it work.
How should I send that parameter?
scala
scala
edited Nov 15 '18 at 16:44
P3trur0
2,2091523
asked Nov 15 '18 at 16:19
Fede E.Fede E.
4621614
edited Nov 15 '18 at 16:44
P3trur0
2,2091523
asked Nov 15 '18 at 16:19
Fede E.Fede E.
4621614
edited Nov 15 '18 at 16:44
P3trur0
2,2091523
edited Nov 15 '18 at 16:44
P3trur0
2,2091523
edited Nov 15 '18 at 16:44
P3trur0
2,2091523
2,2091523
asked Nov 15 '18 at 16:19
Fede E.Fede E.
4621614
asked Nov 15 '18 at 16:19
Fede E.Fede E.
4621614
asked Nov 15 '18 at 16:19
Fede E.Fede E.
4621614
4621614
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
Step 1: look at https://fasterxml.github.io/jackson-databind/javadoc/2.8/com/fasterxml/jackson/databind/JavaType.html. See
Instances can (only) be constructed by
com.fasterxml.jackson.databind.type.TypeFactory.
Step 2: look at https://fasterxml.github.io/jackson-databind/javadoc/2.8/com/fasterxml/jackson/databind/type/TypeFactory.html.
Then you can see it can be used as e.g.
m.getTypeFactory.constructMapType(classOf[java.util.Map[_, _]], classOf[YourKey], classOf[YourValue])
answered Nov 15 '18 at 16:28
Alexey RomanovAlexey Romanov
109k26214355
This throws me: java.lang.ClassCastException: java.util.LinkedHashMap cannot be cast to scala.runtime.Nothing$
– Fede E.
Nov 15 '18 at 16:55
add a comment |
You can use the mapper to get the JavaType, for example:
val stringType:JavaType = mapper.constructType(String.class);
You can try the following for your problem:
val m = new ObjectMapper()
val mapType:JavaType = mapper.constructType(java.util.Map.class)
val map: Map[String, Object] = m.convertValue(bean, mapType)
answered Nov 15 '18 at 16:38
chandrachandra
501311
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Step 1: look at https://fasterxml.github.io/jackson-databind/javadoc/2.8/com/fasterxml/jackson/databind/JavaType.html. See
Instances can (only) be constructed by
com.fasterxml.jackson.databind.type.TypeFactory.
Step 2: look at https://fasterxml.github.io/jackson-databind/javadoc/2.8/com/fasterxml/jackson/databind/type/TypeFactory.html.
Then you can see it can be used as e.g.
m.getTypeFactory.constructMapType(classOf[java.util.Map[_, _]], classOf[YourKey], classOf[YourValue])
answered Nov 15 '18 at 16:28
Alexey RomanovAlexey Romanov
109k26214355
This throws me: java.lang.ClassCastException: java.util.LinkedHashMap cannot be cast to scala.runtime.Nothing$
– Fede E.
Nov 15 '18 at 16:55
add a comment |
Step 1: look at https://fasterxml.github.io/jackson-databind/javadoc/2.8/com/fasterxml/jackson/databind/JavaType.html. See
Instances can (only) be constructed by
com.fasterxml.jackson.databind.type.TypeFactory.
Step 2: look at https://fasterxml.github.io/jackson-databind/javadoc/2.8/com/fasterxml/jackson/databind/type/TypeFactory.html.
Then you can see it can be used as e.g.
m.getTypeFactory.constructMapType(classOf[java.util.Map[_, _]], classOf[YourKey], classOf[YourValue])
answered Nov 15 '18 at 16:28
Alexey RomanovAlexey Romanov
109k26214355
This throws me: java.lang.ClassCastException: java.util.LinkedHashMap cannot be cast to scala.runtime.Nothing$
– Fede E.
Nov 15 '18 at 16:55
add a comment |
Step 1: look at https://fasterxml.github.io/jackson-databind/javadoc/2.8/com/fasterxml/jackson/databind/JavaType.html. See
Instances can (only) be constructed by
com.fasterxml.jackson.databind.type.TypeFactory.
Step 2: look at https://fasterxml.github.io/jackson-databind/javadoc/2.8/com/fasterxml/jackson/databind/type/TypeFactory.html.
Then you can see it can be used as e.g.
m.getTypeFactory.constructMapType(classOf[java.util.Map[_, _]], classOf[YourKey], classOf[YourValue])
answered Nov 15 '18 at 16:28
Alexey RomanovAlexey Romanov
109k26214355
Step 1: look at https://fasterxml.github.io/jackson-databind/javadoc/2.8/com/fasterxml/jackson/databind/JavaType.html. See
Instances can (only) be constructed by
com.fasterxml.jackson.databind.type.TypeFactory.
Step 2: look at https://fasterxml.github.io/jackson-databind/javadoc/2.8/com/fasterxml/jackson/databind/type/TypeFactory.html.
Then you can see it can be used as e.g.
m.getTypeFactory.constructMapType(classOf[java.util.Map[_, _]], classOf[YourKey], classOf[YourValue])
answered Nov 15 '18 at 16:28
Alexey RomanovAlexey Romanov
109k26214355
answered Nov 15 '18 at 16:28
Alexey RomanovAlexey Romanov
109k26214355
answered Nov 15 '18 at 16:28
Alexey RomanovAlexey Romanov
109k26214355
answered Nov 15 '18 at 16:28
Alexey RomanovAlexey Romanov
109k26214355
109k26214355
This throws me: java.lang.ClassCastException: java.util.LinkedHashMap cannot be cast to scala.runtime.Nothing$
– Fede E.
Nov 15 '18 at 16:55
add a comment |
This throws me: java.lang.ClassCastException: java.util.LinkedHashMap cannot be cast to scala.runtime.Nothing$
– Fede E.
Nov 15 '18 at 16:55
This throws me: java.lang.ClassCastException: java.util.LinkedHashMap cannot be cast to scala.runtime.Nothing$
– Fede E.
Nov 15 '18 at 16:55
This throws me: java.lang.ClassCastException: java.util.LinkedHashMap cannot be cast to scala.runtime.Nothing$
– Fede E.
Nov 15 '18 at 16:55
add a comment |
You can use the mapper to get the JavaType, for example:
val stringType:JavaType = mapper.constructType(String.class);
You can try the following for your problem:
val m = new ObjectMapper()
val mapType:JavaType = mapper.constructType(java.util.Map.class)
val map: Map[String, Object] = m.convertValue(bean, mapType)
answered Nov 15 '18 at 16:38
chandrachandra
501311
add a comment |
You can use the mapper to get the JavaType, for example:
val stringType:JavaType = mapper.constructType(String.class);
You can try the following for your problem:
val m = new ObjectMapper()
val mapType:JavaType = mapper.constructType(java.util.Map.class)
val map: Map[String, Object] = m.convertValue(bean, mapType)
answered Nov 15 '18 at 16:38
chandrachandra
501311
add a comment |
You can use the mapper to get the JavaType, for example:
val stringType:JavaType = mapper.constructType(String.class);
You can try the following for your problem:
val m = new ObjectMapper()
val mapType:JavaType = mapper.constructType(java.util.Map.class)
val map: Map[String, Object] = m.convertValue(bean, mapType)
answered Nov 15 '18 at 16:38
chandrachandra
501311
You can use the mapper to get the JavaType, for example:
val stringType:JavaType = mapper.constructType(String.class);
You can try the following for your problem:
val m = new ObjectMapper()
val mapType:JavaType = mapper.constructType(java.util.Map.class)
val map: Map[String, Object] = m.convertValue(bean, mapType)
answered Nov 15 '18 at 16:38
chandrachandra
501311
answered Nov 15 '18 at 16:38
chandrachandra
501311
answered Nov 15 '18 at 16:38
chandrachandra
501311
answered Nov 15 '18 at 16:38
chandrachandra
501311
501311
add a comment |
add a comment |
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