Using Subquery select to get column value












0















I have the following query:



SELECT 
p.fsym_id,
b.p_co_sec_name_desc AS Company_Name,
p.p_date,
p.p_price AS Unadjusted_Price,
b.region AS Region,
f_splitadjprice(p.fsym_id,p.p_date,p.p_price) AS O_Split_Adjusted_Price,
f_prevunadjprice(p.fsym_id,p.p_date,Previous_Date,p.p_price),
(
SELECT MAX(f.p_date)
FROM fp_v2_fp_basic_prices AS f
WHERE f.fsym_id = p.fsym_id AND f.p_date<p.p_date
) Previous_Date

FROM
fp_v2_fp_basic_prices p

LEFT JOIN (
SELECT r2.region, b2.p_co_sec_name_desc, b2.fsym_id
FROM fp_v2_fp_sec_coverage b2
LEFT JOIN sym_v1_sym_region r2 ON b2.fsym_id = r2.fsym_id
WHERE r2.region = "EUR") b
ON b.fsym_id =p.fsym_id;


I get the error, "Previous_date not on column list" when trying to call the function f_prevundadjprice. Basically what I want to do is create the column previous date using (SELECT MAX..) and then use the value from this column in the function f_prevunadjprice.










share|improve this question




















  • 1





    Use a subquery. You can't use an alias in the same select.

    – Gordon Linoff
    Nov 15 '18 at 16:26











  • @GordonLinoff How would you rewrite the query? I tried but I could not get it to work. Also, why is the same SELECT? I have the (SELECT MAX..) in parentheses, so does this not get computed first? is this not already a subquery?

    – Chris
    Nov 15 '18 at 16:27













  • Posting a broken query without telling us what you are trying to do will not help us help you. Tell us what you try to do so that we can get a better understanding. Read this. stackoverflow.com/help/how-to-ask

    – Eric
    Nov 15 '18 at 17:17











  • @Eric I tried to correct it.

    – Chris
    Nov 15 '18 at 17:26
















0















I have the following query:



SELECT 
p.fsym_id,
b.p_co_sec_name_desc AS Company_Name,
p.p_date,
p.p_price AS Unadjusted_Price,
b.region AS Region,
f_splitadjprice(p.fsym_id,p.p_date,p.p_price) AS O_Split_Adjusted_Price,
f_prevunadjprice(p.fsym_id,p.p_date,Previous_Date,p.p_price),
(
SELECT MAX(f.p_date)
FROM fp_v2_fp_basic_prices AS f
WHERE f.fsym_id = p.fsym_id AND f.p_date<p.p_date
) Previous_Date

FROM
fp_v2_fp_basic_prices p

LEFT JOIN (
SELECT r2.region, b2.p_co_sec_name_desc, b2.fsym_id
FROM fp_v2_fp_sec_coverage b2
LEFT JOIN sym_v1_sym_region r2 ON b2.fsym_id = r2.fsym_id
WHERE r2.region = "EUR") b
ON b.fsym_id =p.fsym_id;


I get the error, "Previous_date not on column list" when trying to call the function f_prevundadjprice. Basically what I want to do is create the column previous date using (SELECT MAX..) and then use the value from this column in the function f_prevunadjprice.










share|improve this question




















  • 1





    Use a subquery. You can't use an alias in the same select.

    – Gordon Linoff
    Nov 15 '18 at 16:26











  • @GordonLinoff How would you rewrite the query? I tried but I could not get it to work. Also, why is the same SELECT? I have the (SELECT MAX..) in parentheses, so does this not get computed first? is this not already a subquery?

    – Chris
    Nov 15 '18 at 16:27













  • Posting a broken query without telling us what you are trying to do will not help us help you. Tell us what you try to do so that we can get a better understanding. Read this. stackoverflow.com/help/how-to-ask

    – Eric
    Nov 15 '18 at 17:17











  • @Eric I tried to correct it.

    – Chris
    Nov 15 '18 at 17:26














0












0








0








I have the following query:



SELECT 
p.fsym_id,
b.p_co_sec_name_desc AS Company_Name,
p.p_date,
p.p_price AS Unadjusted_Price,
b.region AS Region,
f_splitadjprice(p.fsym_id,p.p_date,p.p_price) AS O_Split_Adjusted_Price,
f_prevunadjprice(p.fsym_id,p.p_date,Previous_Date,p.p_price),
(
SELECT MAX(f.p_date)
FROM fp_v2_fp_basic_prices AS f
WHERE f.fsym_id = p.fsym_id AND f.p_date<p.p_date
) Previous_Date

FROM
fp_v2_fp_basic_prices p

LEFT JOIN (
SELECT r2.region, b2.p_co_sec_name_desc, b2.fsym_id
FROM fp_v2_fp_sec_coverage b2
LEFT JOIN sym_v1_sym_region r2 ON b2.fsym_id = r2.fsym_id
WHERE r2.region = "EUR") b
ON b.fsym_id =p.fsym_id;


I get the error, "Previous_date not on column list" when trying to call the function f_prevundadjprice. Basically what I want to do is create the column previous date using (SELECT MAX..) and then use the value from this column in the function f_prevunadjprice.










share|improve this question
















I have the following query:



SELECT 
p.fsym_id,
b.p_co_sec_name_desc AS Company_Name,
p.p_date,
p.p_price AS Unadjusted_Price,
b.region AS Region,
f_splitadjprice(p.fsym_id,p.p_date,p.p_price) AS O_Split_Adjusted_Price,
f_prevunadjprice(p.fsym_id,p.p_date,Previous_Date,p.p_price),
(
SELECT MAX(f.p_date)
FROM fp_v2_fp_basic_prices AS f
WHERE f.fsym_id = p.fsym_id AND f.p_date<p.p_date
) Previous_Date

FROM
fp_v2_fp_basic_prices p

LEFT JOIN (
SELECT r2.region, b2.p_co_sec_name_desc, b2.fsym_id
FROM fp_v2_fp_sec_coverage b2
LEFT JOIN sym_v1_sym_region r2 ON b2.fsym_id = r2.fsym_id
WHERE r2.region = "EUR") b
ON b.fsym_id =p.fsym_id;


I get the error, "Previous_date not on column list" when trying to call the function f_prevundadjprice. Basically what I want to do is create the column previous date using (SELECT MAX..) and then use the value from this column in the function f_prevunadjprice.







mysql sql






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 15 '18 at 17:22







Chris

















asked Nov 15 '18 at 16:24









ChrisChris

1089




1089








  • 1





    Use a subquery. You can't use an alias in the same select.

    – Gordon Linoff
    Nov 15 '18 at 16:26











  • @GordonLinoff How would you rewrite the query? I tried but I could not get it to work. Also, why is the same SELECT? I have the (SELECT MAX..) in parentheses, so does this not get computed first? is this not already a subquery?

    – Chris
    Nov 15 '18 at 16:27













  • Posting a broken query without telling us what you are trying to do will not help us help you. Tell us what you try to do so that we can get a better understanding. Read this. stackoverflow.com/help/how-to-ask

    – Eric
    Nov 15 '18 at 17:17











  • @Eric I tried to correct it.

    – Chris
    Nov 15 '18 at 17:26














  • 1





    Use a subquery. You can't use an alias in the same select.

    – Gordon Linoff
    Nov 15 '18 at 16:26











  • @GordonLinoff How would you rewrite the query? I tried but I could not get it to work. Also, why is the same SELECT? I have the (SELECT MAX..) in parentheses, so does this not get computed first? is this not already a subquery?

    – Chris
    Nov 15 '18 at 16:27













  • Posting a broken query without telling us what you are trying to do will not help us help you. Tell us what you try to do so that we can get a better understanding. Read this. stackoverflow.com/help/how-to-ask

    – Eric
    Nov 15 '18 at 17:17











  • @Eric I tried to correct it.

    – Chris
    Nov 15 '18 at 17:26








1




1





Use a subquery. You can't use an alias in the same select.

– Gordon Linoff
Nov 15 '18 at 16:26





Use a subquery. You can't use an alias in the same select.

– Gordon Linoff
Nov 15 '18 at 16:26













@GordonLinoff How would you rewrite the query? I tried but I could not get it to work. Also, why is the same SELECT? I have the (SELECT MAX..) in parentheses, so does this not get computed first? is this not already a subquery?

– Chris
Nov 15 '18 at 16:27







@GordonLinoff How would you rewrite the query? I tried but I could not get it to work. Also, why is the same SELECT? I have the (SELECT MAX..) in parentheses, so does this not get computed first? is this not already a subquery?

– Chris
Nov 15 '18 at 16:27















Posting a broken query without telling us what you are trying to do will not help us help you. Tell us what you try to do so that we can get a better understanding. Read this. stackoverflow.com/help/how-to-ask

– Eric
Nov 15 '18 at 17:17





Posting a broken query without telling us what you are trying to do will not help us help you. Tell us what you try to do so that we can get a better understanding. Read this. stackoverflow.com/help/how-to-ask

– Eric
Nov 15 '18 at 17:17













@Eric I tried to correct it.

– Chris
Nov 15 '18 at 17:26





@Eric I tried to correct it.

– Chris
Nov 15 '18 at 17:26












2 Answers
2






active

oldest

votes


















0














If you use p. to reference all the fields coming from fp_v2_fp_basic_prices , you should also do it in the next line:



f_prevunadjprice(p.fsym_id,p.p_date,Previous_Date,p.p_price)


try to change it by:



f_prevunadjprice(p.fsym_id,p.p_date,p.Previous_Date,p.p_price)


If you continue with the same error, you should ensure the table/view fp_v2_fp_basic_prices has a column named Previous_Date



You should also use AS here:



(
SELECT MAX(f.p_date)
FROM fp_v2_fp_basic_prices AS f
WHERE f.fsym_id = p.fsym_id AND f.p_date<p.p_date
) Previous_Date


So:



...) AS Previous_Date





share|improve this answer
























  • The table fp_v2.. does not have a column named Previous_Date. Please check my updated question :)

    – Chris
    Nov 15 '18 at 17:50













  • In that case the error is right, there's not any column called Previous_Date in column list. What you can do is to pass to the function the value of Prevuious_Date (SELECT MAX(f.p_date)...). Another way is to pass only f.p_date to the function, and calculate the Previous_Date inside the function...

    – Jortx
    Nov 16 '18 at 8:57





















0














you already have one subquery. If you were using TSQL you could outer apply the second one. MySQL doesn't support apply, so you'll have to left join to it:



SELECT 
p.fsym_id,
b.p_co_sec_name_desc AS Company_Name,
p.p_date,
p.p_price AS Unadjusted_Price,
b.region AS Region,
f_splitadjprice(p.fsym_id,p.p_date,p.p_price) AS O_Split_Adjusted_Price,
f_prevunadjprice(p.fsym_id,p.p_date,Previous_Date,p.p_price),
PreviousDate.maxdate

FROM
fp_v2_fp_basic_prices p

LEFT JOIN (
SELECT r2.region, b2.p_co_sec_name_desc, b2.fsym_id
FROM fp_v2_fp_sec_coverage b2
LEFT JOIN sym_v1_sym_region r2 ON b2.fsym_id = r2.fsym_id
WHERE r2.region = "EUR") b

ON b.fsym_id =p.fsym_id;

LEFT JOIN (

SELECT f.fsym_id,f.p_date,MAX(f.p_date) as maxdate
FROM fp_v2_fp_basic_prices AS f
group by f.fsym_id, f.p_date
) Previous_Date

on Previous_Date.fsym_id = p.fsym_id and AND Previous_Date.p_date<p.p_date





share|improve this answer


























  • How is SQL reading this query? What is being done first? The use of parentheses also looks weird to me. There is a missing ).

    – Chris
    Nov 15 '18 at 16:53













  • HI Chris, amended the missing bracket. So SQL gets all the data from fp_basic_prices. It joins to the results of the first subquery as a table, aliased as b.. Then joins to the results of the second subquery which gets all of the maxdates grouped by fsym_id, but is joined to by that Id so only one value is returned to the end result.

    – iainc
    Nov 16 '18 at 16:04













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2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









0














If you use p. to reference all the fields coming from fp_v2_fp_basic_prices , you should also do it in the next line:



f_prevunadjprice(p.fsym_id,p.p_date,Previous_Date,p.p_price)


try to change it by:



f_prevunadjprice(p.fsym_id,p.p_date,p.Previous_Date,p.p_price)


If you continue with the same error, you should ensure the table/view fp_v2_fp_basic_prices has a column named Previous_Date



You should also use AS here:



(
SELECT MAX(f.p_date)
FROM fp_v2_fp_basic_prices AS f
WHERE f.fsym_id = p.fsym_id AND f.p_date<p.p_date
) Previous_Date


So:



...) AS Previous_Date





share|improve this answer
























  • The table fp_v2.. does not have a column named Previous_Date. Please check my updated question :)

    – Chris
    Nov 15 '18 at 17:50













  • In that case the error is right, there's not any column called Previous_Date in column list. What you can do is to pass to the function the value of Prevuious_Date (SELECT MAX(f.p_date)...). Another way is to pass only f.p_date to the function, and calculate the Previous_Date inside the function...

    – Jortx
    Nov 16 '18 at 8:57


















0














If you use p. to reference all the fields coming from fp_v2_fp_basic_prices , you should also do it in the next line:



f_prevunadjprice(p.fsym_id,p.p_date,Previous_Date,p.p_price)


try to change it by:



f_prevunadjprice(p.fsym_id,p.p_date,p.Previous_Date,p.p_price)


If you continue with the same error, you should ensure the table/view fp_v2_fp_basic_prices has a column named Previous_Date



You should also use AS here:



(
SELECT MAX(f.p_date)
FROM fp_v2_fp_basic_prices AS f
WHERE f.fsym_id = p.fsym_id AND f.p_date<p.p_date
) Previous_Date


So:



...) AS Previous_Date





share|improve this answer
























  • The table fp_v2.. does not have a column named Previous_Date. Please check my updated question :)

    – Chris
    Nov 15 '18 at 17:50













  • In that case the error is right, there's not any column called Previous_Date in column list. What you can do is to pass to the function the value of Prevuious_Date (SELECT MAX(f.p_date)...). Another way is to pass only f.p_date to the function, and calculate the Previous_Date inside the function...

    – Jortx
    Nov 16 '18 at 8:57
















0












0








0







If you use p. to reference all the fields coming from fp_v2_fp_basic_prices , you should also do it in the next line:



f_prevunadjprice(p.fsym_id,p.p_date,Previous_Date,p.p_price)


try to change it by:



f_prevunadjprice(p.fsym_id,p.p_date,p.Previous_Date,p.p_price)


If you continue with the same error, you should ensure the table/view fp_v2_fp_basic_prices has a column named Previous_Date



You should also use AS here:



(
SELECT MAX(f.p_date)
FROM fp_v2_fp_basic_prices AS f
WHERE f.fsym_id = p.fsym_id AND f.p_date<p.p_date
) Previous_Date


So:



...) AS Previous_Date





share|improve this answer













If you use p. to reference all the fields coming from fp_v2_fp_basic_prices , you should also do it in the next line:



f_prevunadjprice(p.fsym_id,p.p_date,Previous_Date,p.p_price)


try to change it by:



f_prevunadjprice(p.fsym_id,p.p_date,p.Previous_Date,p.p_price)


If you continue with the same error, you should ensure the table/view fp_v2_fp_basic_prices has a column named Previous_Date



You should also use AS here:



(
SELECT MAX(f.p_date)
FROM fp_v2_fp_basic_prices AS f
WHERE f.fsym_id = p.fsym_id AND f.p_date<p.p_date
) Previous_Date


So:



...) AS Previous_Date






share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 15 '18 at 16:53









JortxJortx

3411215




3411215













  • The table fp_v2.. does not have a column named Previous_Date. Please check my updated question :)

    – Chris
    Nov 15 '18 at 17:50













  • In that case the error is right, there's not any column called Previous_Date in column list. What you can do is to pass to the function the value of Prevuious_Date (SELECT MAX(f.p_date)...). Another way is to pass only f.p_date to the function, and calculate the Previous_Date inside the function...

    – Jortx
    Nov 16 '18 at 8:57





















  • The table fp_v2.. does not have a column named Previous_Date. Please check my updated question :)

    – Chris
    Nov 15 '18 at 17:50













  • In that case the error is right, there's not any column called Previous_Date in column list. What you can do is to pass to the function the value of Prevuious_Date (SELECT MAX(f.p_date)...). Another way is to pass only f.p_date to the function, and calculate the Previous_Date inside the function...

    – Jortx
    Nov 16 '18 at 8:57



















The table fp_v2.. does not have a column named Previous_Date. Please check my updated question :)

– Chris
Nov 15 '18 at 17:50







The table fp_v2.. does not have a column named Previous_Date. Please check my updated question :)

– Chris
Nov 15 '18 at 17:50















In that case the error is right, there's not any column called Previous_Date in column list. What you can do is to pass to the function the value of Prevuious_Date (SELECT MAX(f.p_date)...). Another way is to pass only f.p_date to the function, and calculate the Previous_Date inside the function...

– Jortx
Nov 16 '18 at 8:57







In that case the error is right, there's not any column called Previous_Date in column list. What you can do is to pass to the function the value of Prevuious_Date (SELECT MAX(f.p_date)...). Another way is to pass only f.p_date to the function, and calculate the Previous_Date inside the function...

– Jortx
Nov 16 '18 at 8:57















0














you already have one subquery. If you were using TSQL you could outer apply the second one. MySQL doesn't support apply, so you'll have to left join to it:



SELECT 
p.fsym_id,
b.p_co_sec_name_desc AS Company_Name,
p.p_date,
p.p_price AS Unadjusted_Price,
b.region AS Region,
f_splitadjprice(p.fsym_id,p.p_date,p.p_price) AS O_Split_Adjusted_Price,
f_prevunadjprice(p.fsym_id,p.p_date,Previous_Date,p.p_price),
PreviousDate.maxdate

FROM
fp_v2_fp_basic_prices p

LEFT JOIN (
SELECT r2.region, b2.p_co_sec_name_desc, b2.fsym_id
FROM fp_v2_fp_sec_coverage b2
LEFT JOIN sym_v1_sym_region r2 ON b2.fsym_id = r2.fsym_id
WHERE r2.region = "EUR") b

ON b.fsym_id =p.fsym_id;

LEFT JOIN (

SELECT f.fsym_id,f.p_date,MAX(f.p_date) as maxdate
FROM fp_v2_fp_basic_prices AS f
group by f.fsym_id, f.p_date
) Previous_Date

on Previous_Date.fsym_id = p.fsym_id and AND Previous_Date.p_date<p.p_date





share|improve this answer


























  • How is SQL reading this query? What is being done first? The use of parentheses also looks weird to me. There is a missing ).

    – Chris
    Nov 15 '18 at 16:53













  • HI Chris, amended the missing bracket. So SQL gets all the data from fp_basic_prices. It joins to the results of the first subquery as a table, aliased as b.. Then joins to the results of the second subquery which gets all of the maxdates grouped by fsym_id, but is joined to by that Id so only one value is returned to the end result.

    – iainc
    Nov 16 '18 at 16:04


















0














you already have one subquery. If you were using TSQL you could outer apply the second one. MySQL doesn't support apply, so you'll have to left join to it:



SELECT 
p.fsym_id,
b.p_co_sec_name_desc AS Company_Name,
p.p_date,
p.p_price AS Unadjusted_Price,
b.region AS Region,
f_splitadjprice(p.fsym_id,p.p_date,p.p_price) AS O_Split_Adjusted_Price,
f_prevunadjprice(p.fsym_id,p.p_date,Previous_Date,p.p_price),
PreviousDate.maxdate

FROM
fp_v2_fp_basic_prices p

LEFT JOIN (
SELECT r2.region, b2.p_co_sec_name_desc, b2.fsym_id
FROM fp_v2_fp_sec_coverage b2
LEFT JOIN sym_v1_sym_region r2 ON b2.fsym_id = r2.fsym_id
WHERE r2.region = "EUR") b

ON b.fsym_id =p.fsym_id;

LEFT JOIN (

SELECT f.fsym_id,f.p_date,MAX(f.p_date) as maxdate
FROM fp_v2_fp_basic_prices AS f
group by f.fsym_id, f.p_date
) Previous_Date

on Previous_Date.fsym_id = p.fsym_id and AND Previous_Date.p_date<p.p_date





share|improve this answer


























  • How is SQL reading this query? What is being done first? The use of parentheses also looks weird to me. There is a missing ).

    – Chris
    Nov 15 '18 at 16:53













  • HI Chris, amended the missing bracket. So SQL gets all the data from fp_basic_prices. It joins to the results of the first subquery as a table, aliased as b.. Then joins to the results of the second subquery which gets all of the maxdates grouped by fsym_id, but is joined to by that Id so only one value is returned to the end result.

    – iainc
    Nov 16 '18 at 16:04
















0












0








0







you already have one subquery. If you were using TSQL you could outer apply the second one. MySQL doesn't support apply, so you'll have to left join to it:



SELECT 
p.fsym_id,
b.p_co_sec_name_desc AS Company_Name,
p.p_date,
p.p_price AS Unadjusted_Price,
b.region AS Region,
f_splitadjprice(p.fsym_id,p.p_date,p.p_price) AS O_Split_Adjusted_Price,
f_prevunadjprice(p.fsym_id,p.p_date,Previous_Date,p.p_price),
PreviousDate.maxdate

FROM
fp_v2_fp_basic_prices p

LEFT JOIN (
SELECT r2.region, b2.p_co_sec_name_desc, b2.fsym_id
FROM fp_v2_fp_sec_coverage b2
LEFT JOIN sym_v1_sym_region r2 ON b2.fsym_id = r2.fsym_id
WHERE r2.region = "EUR") b

ON b.fsym_id =p.fsym_id;

LEFT JOIN (

SELECT f.fsym_id,f.p_date,MAX(f.p_date) as maxdate
FROM fp_v2_fp_basic_prices AS f
group by f.fsym_id, f.p_date
) Previous_Date

on Previous_Date.fsym_id = p.fsym_id and AND Previous_Date.p_date<p.p_date





share|improve this answer















you already have one subquery. If you were using TSQL you could outer apply the second one. MySQL doesn't support apply, so you'll have to left join to it:



SELECT 
p.fsym_id,
b.p_co_sec_name_desc AS Company_Name,
p.p_date,
p.p_price AS Unadjusted_Price,
b.region AS Region,
f_splitadjprice(p.fsym_id,p.p_date,p.p_price) AS O_Split_Adjusted_Price,
f_prevunadjprice(p.fsym_id,p.p_date,Previous_Date,p.p_price),
PreviousDate.maxdate

FROM
fp_v2_fp_basic_prices p

LEFT JOIN (
SELECT r2.region, b2.p_co_sec_name_desc, b2.fsym_id
FROM fp_v2_fp_sec_coverage b2
LEFT JOIN sym_v1_sym_region r2 ON b2.fsym_id = r2.fsym_id
WHERE r2.region = "EUR") b

ON b.fsym_id =p.fsym_id;

LEFT JOIN (

SELECT f.fsym_id,f.p_date,MAX(f.p_date) as maxdate
FROM fp_v2_fp_basic_prices AS f
group by f.fsym_id, f.p_date
) Previous_Date

on Previous_Date.fsym_id = p.fsym_id and AND Previous_Date.p_date<p.p_date






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share|improve this answer








edited Nov 16 '18 at 16:03

























answered Nov 15 '18 at 16:48









iainciainc

283212




283212













  • How is SQL reading this query? What is being done first? The use of parentheses also looks weird to me. There is a missing ).

    – Chris
    Nov 15 '18 at 16:53













  • HI Chris, amended the missing bracket. So SQL gets all the data from fp_basic_prices. It joins to the results of the first subquery as a table, aliased as b.. Then joins to the results of the second subquery which gets all of the maxdates grouped by fsym_id, but is joined to by that Id so only one value is returned to the end result.

    – iainc
    Nov 16 '18 at 16:04





















  • How is SQL reading this query? What is being done first? The use of parentheses also looks weird to me. There is a missing ).

    – Chris
    Nov 15 '18 at 16:53













  • HI Chris, amended the missing bracket. So SQL gets all the data from fp_basic_prices. It joins to the results of the first subquery as a table, aliased as b.. Then joins to the results of the second subquery which gets all of the maxdates grouped by fsym_id, but is joined to by that Id so only one value is returned to the end result.

    – iainc
    Nov 16 '18 at 16:04



















How is SQL reading this query? What is being done first? The use of parentheses also looks weird to me. There is a missing ).

– Chris
Nov 15 '18 at 16:53







How is SQL reading this query? What is being done first? The use of parentheses also looks weird to me. There is a missing ).

– Chris
Nov 15 '18 at 16:53















HI Chris, amended the missing bracket. So SQL gets all the data from fp_basic_prices. It joins to the results of the first subquery as a table, aliased as b.. Then joins to the results of the second subquery which gets all of the maxdates grouped by fsym_id, but is joined to by that Id so only one value is returned to the end result.

– iainc
Nov 16 '18 at 16:04







HI Chris, amended the missing bracket. So SQL gets all the data from fp_basic_prices. It joins to the results of the first subquery as a table, aliased as b.. Then joins to the results of the second subquery which gets all of the maxdates grouped by fsym_id, but is joined to by that Id so only one value is returned to the end result.

– iainc
Nov 16 '18 at 16:04




















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