How to loop through an object array and output the array with a specific object property javascript
0
var obo = [{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
},
{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
},
{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
},
{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
}, {
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
}, {
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
}
]
I want to loop through and return the array. i have tried splice its not working
var obo = [{
"userid": "tomi",
"location": "kwara"
},
{
"userid": "tomi",
"location": "kwara"
},
{
"userid": "tomi",
"location": "kwara"
}
]
Am trying to populate the array so as not to have parcelid in it
javascript arrays object
edited Nov 15 '18 at 16:58
Mohammad
15.8k123664
asked Nov 15 '18 at 16:16
OpenwellOpenwell
12
add a comment |
0
var obo = [{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
},
{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
},
{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
},
{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
}, {
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
}, {
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
}
]
I want to loop through and return the array. i have tried splice its not working
var obo = [{
"userid": "tomi",
"location": "kwara"
},
{
"userid": "tomi",
"location": "kwara"
},
{
"userid": "tomi",
"location": "kwara"
}
]
Am trying to populate the array so as not to have parcelid in it
javascript arrays object
edited Nov 15 '18 at 16:58
Mohammad
15.8k123664
asked Nov 15 '18 at 16:16
OpenwellOpenwell
12
1
What is your specific property, which property in the array are you looking for?
– squeekyDave
Nov 15 '18 at 16:22
add a comment |
0
0
0
0
var obo = [{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
},
{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
},
{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
},
{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
}, {
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
}, {
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
}
]
I want to loop through and return the array. i have tried splice its not working
var obo = [{
"userid": "tomi",
"location": "kwara"
},
{
"userid": "tomi",
"location": "kwara"
},
{
"userid": "tomi",
"location": "kwara"
}
]
Am trying to populate the array so as not to have parcelid in it
javascript arrays object
edited Nov 15 '18 at 16:58
Mohammad
15.8k123664
asked Nov 15 '18 at 16:16
OpenwellOpenwell
12
var obo = [{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
},
{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
},
{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
},
{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
}, {
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
}, {
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
}
]
I want to loop through and return the array. i have tried splice its not working
var obo = [{
"userid": "tomi",
"location": "kwara"
},
{
"userid": "tomi",
"location": "kwara"
},
{
"userid": "tomi",
"location": "kwara"
}
]
Am trying to populate the array so as not to have parcelid in it
javascript arrays object
javascript arrays object
edited Nov 15 '18 at 16:58
Mohammad
15.8k123664
asked Nov 15 '18 at 16:16
OpenwellOpenwell
12
edited Nov 15 '18 at 16:58
Mohammad
15.8k123664
asked Nov 15 '18 at 16:16
OpenwellOpenwell
12
edited Nov 15 '18 at 16:58
Mohammad
15.8k123664
edited Nov 15 '18 at 16:58
Mohammad
15.8k123664
edited Nov 15 '18 at 16:58
Mohammad
15.8k123664
15.8k123664
asked Nov 15 '18 at 16:16
OpenwellOpenwell
12
asked Nov 15 '18 at 16:16
OpenwellOpenwell
12
asked Nov 15 '18 at 16:16
OpenwellOpenwell
12
12
1
What is your specific property, which property in the array are you looking for?
– squeekyDave
Nov 15 '18 at 16:22
add a comment |
1
What is your specific property, which property in the array are you looking for?
– squeekyDave
Nov 15 '18 at 16:22
1
1
What is your specific property, which property in the array are you looking for?
– squeekyDave
Nov 15 '18 at 16:22
What is your specific property, which property in the array are you looking for?
– squeekyDave
Nov 15 '18 at 16:22
add a comment |
4 Answers
4
active
oldest
votes
4
You can use .map() with some object destructuring:
var data = [
{"parcelId": "009", "userid": "tomi", "location": "kwara"},
{"parcelId": "009", "userid": "tomi", "location": "kwara"},
{"parcelId": "009", "userid": "tomi", "location": "kwara"}
];
var result = data.map(({userid, location, ...rest}) => ({userid, location}));
console.log(result);.as-console-wrapper { max-height: 100% !important; top: 0; }References:
- Array.prototype.map()
- Object Destructuring
answered Nov 15 '18 at 16:20
Mohammad UsmanMohammad Usman
21.2k124558
add a comment |
0
You need to use .map()
obo = obo.map(function(item){
return {
userid: item.userid,
location: item.location
};
});
var obo = [
{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
},
{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
},
{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
}
];
obo = obo.map(function(item){
return {
userid: item.userid,
location: item.location
};
});
console.log(obo);answered Nov 15 '18 at 16:20
MohammadMohammad
15.8k123664
Sincedeletemutates original can do it in any loop. No real need to create new array using map() if using mutation approach
– charlietfl
Nov 15 '18 at 16:21
add a comment |
0
How about that with Array.prototype.map()?
var obo = [{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
},
{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
},
{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
}
]
var expected = ;
obo.map((elm, ind) => {
expected.push({
"userid": elm.userid,
"location": elm.location
})
})
console.log(expected)answered Nov 15 '18 at 16:23
Always SunnyAlways Sunny
16.7k32848
add a comment |
0
You can try something like this
obo = obo.map(el => {
let obj = {
userid: el.userid,
location: el.location
};
return obj;
});
or for a one liner, you can do this
obo = obo.map(({userid,location})=>({userid,location})));
answered Nov 15 '18 at 16:24
theapologisttheapologist
576215
add a comment |
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
4
You can use .map() with some object destructuring:
var data = [
{"parcelId": "009", "userid": "tomi", "location": "kwara"},
{"parcelId": "009", "userid": "tomi", "location": "kwara"},
{"parcelId": "009", "userid": "tomi", "location": "kwara"}
];
var result = data.map(({userid, location, ...rest}) => ({userid, location}));
console.log(result);.as-console-wrapper { max-height: 100% !important; top: 0; }References:
- Array.prototype.map()
- Object Destructuring
answered Nov 15 '18 at 16:20
Mohammad UsmanMohammad Usman
21.2k124558
add a comment |
4
You can use .map() with some object destructuring:
var data = [
{"parcelId": "009", "userid": "tomi", "location": "kwara"},
{"parcelId": "009", "userid": "tomi", "location": "kwara"},
{"parcelId": "009", "userid": "tomi", "location": "kwara"}
];
var result = data.map(({userid, location, ...rest}) => ({userid, location}));
console.log(result);.as-console-wrapper { max-height: 100% !important; top: 0; }References:
- Array.prototype.map()
- Object Destructuring
answered Nov 15 '18 at 16:20
Mohammad UsmanMohammad Usman
21.2k124558
add a comment |
4
4
4
You can use .map() with some object destructuring:
var data = [
{"parcelId": "009", "userid": "tomi", "location": "kwara"},
{"parcelId": "009", "userid": "tomi", "location": "kwara"},
{"parcelId": "009", "userid": "tomi", "location": "kwara"}
];
var result = data.map(({userid, location, ...rest}) => ({userid, location}));
console.log(result);.as-console-wrapper { max-height: 100% !important; top: 0; }References:
- Array.prototype.map()
- Object Destructuring
answered Nov 15 '18 at 16:20
Mohammad UsmanMohammad Usman
21.2k124558
You can use .map() with some object destructuring:
var data = [
{"parcelId": "009", "userid": "tomi", "location": "kwara"},
{"parcelId": "009", "userid": "tomi", "location": "kwara"},
{"parcelId": "009", "userid": "tomi", "location": "kwara"}
];
var result = data.map(({userid, location, ...rest}) => ({userid, location}));
console.log(result);.as-console-wrapper { max-height: 100% !important; top: 0; }References:
- Array.prototype.map()
- Object Destructuring
var data = [
{"parcelId": "009", "userid": "tomi", "location": "kwara"},
{"parcelId": "009", "userid": "tomi", "location": "kwara"},
{"parcelId": "009", "userid": "tomi", "location": "kwara"}
];
var result = data.map(({userid, location, ...rest}) => ({userid, location}));
console.log(result);.as-console-wrapper { max-height: 100% !important; top: 0; }var data = [
{"parcelId": "009", "userid": "tomi", "location": "kwara"},
{"parcelId": "009", "userid": "tomi", "location": "kwara"},
{"parcelId": "009", "userid": "tomi", "location": "kwara"}
];
var result = data.map(({userid, location, ...rest}) => ({userid, location}));
console.log(result);.as-console-wrapper { max-height: 100% !important; top: 0; }answered Nov 15 '18 at 16:20
Mohammad UsmanMohammad Usman
21.2k124558
edited Nov 15 '18 at 16:25
answered Nov 15 '18 at 16:20
Mohammad UsmanMohammad Usman
21.2k124558
answered Nov 15 '18 at 16:20
Mohammad UsmanMohammad Usman
21.2k124558
answered Nov 15 '18 at 16:20
Mohammad UsmanMohammad Usman
21.2k124558
21.2k124558
add a comment |
add a comment |
0
You need to use .map()
obo = obo.map(function(item){
return {
userid: item.userid,
location: item.location
};
});
var obo = [
{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
},
{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
},
{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
}
];
obo = obo.map(function(item){
return {
userid: item.userid,
location: item.location
};
});
console.log(obo);answered Nov 15 '18 at 16:20
MohammadMohammad
15.8k123664
Sincedeletemutates original can do it in any loop. No real need to create new array using map() if using mutation approach
– charlietfl
Nov 15 '18 at 16:21
add a comment |
0
You need to use .map()
obo = obo.map(function(item){
return {
userid: item.userid,
location: item.location
};
});
var obo = [
{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
},
{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
},
{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
}
];
obo = obo.map(function(item){
return {
userid: item.userid,
location: item.location
};
});
console.log(obo);answered Nov 15 '18 at 16:20
MohammadMohammad
15.8k123664
Sincedeletemutates original can do it in any loop. No real need to create new array using map() if using mutation approach
– charlietfl
Nov 15 '18 at 16:21
add a comment |
0
0
0
You need to use .map()
obo = obo.map(function(item){
return {
userid: item.userid,
location: item.location
};
});
var obo = [
{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
},
{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
},
{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
}
];
obo = obo.map(function(item){
return {
userid: item.userid,
location: item.location
};
});
console.log(obo);answered Nov 15 '18 at 16:20
MohammadMohammad
15.8k123664
You need to use .map()
obo = obo.map(function(item){
return {
userid: item.userid,
location: item.location
};
});
var obo = [
{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
},
{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
},
{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
}
];
obo = obo.map(function(item){
return {
userid: item.userid,
location: item.location
};
});
console.log(obo);var obo = [
{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
},
{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
},
{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
}
];
obo = obo.map(function(item){
return {
userid: item.userid,
location: item.location
};
});
console.log(obo);var obo = [
{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
},
{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
},
{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
}
];
obo = obo.map(function(item){
return {
userid: item.userid,
location: item.location
};
});
console.log(obo);answered Nov 15 '18 at 16:20
MohammadMohammad
15.8k123664
edited Nov 15 '18 at 16:21
answered Nov 15 '18 at 16:20
MohammadMohammad
15.8k123664
answered Nov 15 '18 at 16:20
MohammadMohammad
15.8k123664
answered Nov 15 '18 at 16:20
MohammadMohammad
15.8k123664
15.8k123664
Sincedeletemutates original can do it in any loop. No real need to create new array using map() if using mutation approach
– charlietfl
Nov 15 '18 at 16:21
add a comment |
Sincedeletemutates original can do it in any loop. No real need to create new array using map() if using mutation approach
– charlietfl
Nov 15 '18 at 16:21
Since
delete mutates original can do it in any loop. No real need to create new array using map() if using mutation approach– charlietfl
Nov 15 '18 at 16:21
Since
delete mutates original can do it in any loop. No real need to create new array using map() if using mutation approach– charlietfl
Nov 15 '18 at 16:21
add a comment |
0
How about that with Array.prototype.map()?
var obo = [{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
},
{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
},
{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
}
]
var expected = ;
obo.map((elm, ind) => {
expected.push({
"userid": elm.userid,
"location": elm.location
})
})
console.log(expected)answered Nov 15 '18 at 16:23
Always SunnyAlways Sunny
16.7k32848
add a comment |
0
How about that with Array.prototype.map()?
var obo = [{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
},
{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
},
{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
}
]
var expected = ;
obo.map((elm, ind) => {
expected.push({
"userid": elm.userid,
"location": elm.location
})
})
console.log(expected)answered Nov 15 '18 at 16:23
Always SunnyAlways Sunny
16.7k32848
add a comment |
0
0
0
How about that with Array.prototype.map()?
var obo = [{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
},
{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
},
{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
}
]
var expected = ;
obo.map((elm, ind) => {
expected.push({
"userid": elm.userid,
"location": elm.location
})
})
console.log(expected)answered Nov 15 '18 at 16:23
Always SunnyAlways Sunny
16.7k32848
How about that with Array.prototype.map()?
var obo = [{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
},
{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
},
{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
}
]
var expected = ;
obo.map((elm, ind) => {
expected.push({
"userid": elm.userid,
"location": elm.location
})
})
console.log(expected)var obo = [{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
},
{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
},
{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
}
]
var expected = ;
obo.map((elm, ind) => {
expected.push({
"userid": elm.userid,
"location": elm.location
})
})
console.log(expected)var obo = [{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
},
{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
},
{
"parcelId": "009",
"userid": "tomi",
"location": "kwara"
}
]
var expected = ;
obo.map((elm, ind) => {
expected.push({
"userid": elm.userid,
"location": elm.location
})
})
console.log(expected)answered Nov 15 '18 at 16:23
Always SunnyAlways Sunny
16.7k32848
answered Nov 15 '18 at 16:23
Always SunnyAlways Sunny
16.7k32848
answered Nov 15 '18 at 16:23
Always SunnyAlways Sunny
16.7k32848
answered Nov 15 '18 at 16:23
Always SunnyAlways Sunny
16.7k32848
16.7k32848
add a comment |
add a comment |
0
You can try something like this
obo = obo.map(el => {
let obj = {
userid: el.userid,
location: el.location
};
return obj;
});
or for a one liner, you can do this
obo = obo.map(({userid,location})=>({userid,location})));
answered Nov 15 '18 at 16:24
theapologisttheapologist
576215
add a comment |
0
You can try something like this
obo = obo.map(el => {
let obj = {
userid: el.userid,
location: el.location
};
return obj;
});
or for a one liner, you can do this
obo = obo.map(({userid,location})=>({userid,location})));
answered Nov 15 '18 at 16:24
theapologisttheapologist
576215
add a comment |
0
0
0
You can try something like this
obo = obo.map(el => {
let obj = {
userid: el.userid,
location: el.location
};
return obj;
});
or for a one liner, you can do this
obo = obo.map(({userid,location})=>({userid,location})));
answered Nov 15 '18 at 16:24
theapologisttheapologist
576215
You can try something like this
obo = obo.map(el => {
let obj = {
userid: el.userid,
location: el.location
};
return obj;
});
or for a one liner, you can do this
obo = obo.map(({userid,location})=>({userid,location})));
answered Nov 15 '18 at 16:24
theapologisttheapologist
576215
answered Nov 15 '18 at 16:24
theapologisttheapologist
576215
answered Nov 15 '18 at 16:24
theapologisttheapologist
576215
answered Nov 15 '18 at 16:24
theapologisttheapologist
576215
576215
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What is your specific property, which property in the array are you looking for?
– squeekyDave
Nov 15 '18 at 16:22