xml to json conversion and vice versa angular 4
I am working in a angular 4 project and i have to convert xml to json and vice versa.
I am successfull in achieving this by using below thread:
https://goessner.net/download/prj/jsonxml/
This is my sample xml :
<food><pizza type="cheese"/></food>
The parser converted it to json as below:
{
"food":{
"pizza":{"@type":"cheese"},
I have to write a selector where i need to render value of @type.
I have tried it like below:
//selector which returns @type
export const foodValueSelctr=
createSelector(paredJsonSelectore,
(json) => {
console.log(json.food.pizza.@type);
return json.food.pizza.@type;
});
At this line of code I get below error:
Module parse failed: Unexpected token (18:38)
You may need an appropriate loader to handle this file type.
How can I access this @type in code using dot notation ?
Also,
Can i use any other lib to achieve my functionality ?
javascript json angular object
edited Nov 14 '18 at 19:31
ADyson
24.3k112545
asked Nov 14 '18 at 19:09
pankajpankaj
3711521
add a comment |
I am working in a angular 4 project and i have to convert xml to json and vice versa.
I am successfull in achieving this by using below thread:
https://goessner.net/download/prj/jsonxml/
This is my sample xml :
<food><pizza type="cheese"/></food>
The parser converted it to json as below:
{
"food":{
"pizza":{"@type":"cheese"},
I have to write a selector where i need to render value of @type.
I have tried it like below:
//selector which returns @type
export const foodValueSelctr=
createSelector(paredJsonSelectore,
(json) => {
console.log(json.food.pizza.@type);
return json.food.pizza.@type;
});
At this line of code I get below error:
Module parse failed: Unexpected token (18:38)
You may need an appropriate loader to handle this file type.
How can I access this @type in code using dot notation ?
Also,
Can i use any other lib to achieve my functionality ?
javascript json angular object
edited Nov 14 '18 at 19:31
ADyson
24.3k112545
asked Nov 14 '18 at 19:09
pankajpankaj
3711521
1
can you trypizza["@type"]instead?
– ADyson
Nov 14 '18 at 19:20
@ADyson perfect thanks
– pankaj
Nov 14 '18 at 19:24
add a comment |
I am working in a angular 4 project and i have to convert xml to json and vice versa.
I am successfull in achieving this by using below thread:
https://goessner.net/download/prj/jsonxml/
This is my sample xml :
<food><pizza type="cheese"/></food>
The parser converted it to json as below:
{
"food":{
"pizza":{"@type":"cheese"},
I have to write a selector where i need to render value of @type.
I have tried it like below:
//selector which returns @type
export const foodValueSelctr=
createSelector(paredJsonSelectore,
(json) => {
console.log(json.food.pizza.@type);
return json.food.pizza.@type;
});
At this line of code I get below error:
Module parse failed: Unexpected token (18:38)
You may need an appropriate loader to handle this file type.
How can I access this @type in code using dot notation ?
Also,
Can i use any other lib to achieve my functionality ?
javascript json angular object
edited Nov 14 '18 at 19:31
ADyson
24.3k112545
asked Nov 14 '18 at 19:09
pankajpankaj
3711521
I am working in a angular 4 project and i have to convert xml to json and vice versa.
I am successfull in achieving this by using below thread:
https://goessner.net/download/prj/jsonxml/
This is my sample xml :
<food><pizza type="cheese"/></food>
The parser converted it to json as below:
{
"food":{
"pizza":{"@type":"cheese"},
I have to write a selector where i need to render value of @type.
I have tried it like below:
//selector which returns @type
export const foodValueSelctr=
createSelector(paredJsonSelectore,
(json) => {
console.log(json.food.pizza.@type);
return json.food.pizza.@type;
});
At this line of code I get below error:
Module parse failed: Unexpected token (18:38)
You may need an appropriate loader to handle this file type.
How can I access this @type in code using dot notation ?
Also,
Can i use any other lib to achieve my functionality ?
javascript json angular object
javascript json angular object
edited Nov 14 '18 at 19:31
ADyson
24.3k112545
asked Nov 14 '18 at 19:09
pankajpankaj
3711521
edited Nov 14 '18 at 19:31
ADyson
24.3k112545
asked Nov 14 '18 at 19:09
pankajpankaj
3711521
edited Nov 14 '18 at 19:31
ADyson
24.3k112545
edited Nov 14 '18 at 19:31
ADyson
24.3k112545
edited Nov 14 '18 at 19:31
ADyson
24.3k112545
24.3k112545
asked Nov 14 '18 at 19:09
pankajpankaj
3711521
asked Nov 14 '18 at 19:09
pankajpankaj
3711521
asked Nov 14 '18 at 19:09
pankajpankaj
3711521
3711521
1
can you trypizza["@type"]instead?
– ADyson
Nov 14 '18 at 19:20
@ADyson perfect thanks
– pankaj
Nov 14 '18 at 19:24
add a comment |
1
can you trypizza["@type"]instead?
– ADyson
Nov 14 '18 at 19:20
@ADyson perfect thanks
– pankaj
Nov 14 '18 at 19:24
1
1
can you try
pizza["@type"] instead?– ADyson
Nov 14 '18 at 19:20
can you try
pizza["@type"] instead?– ADyson
Nov 14 '18 at 19:20
@ADyson perfect thanks
– pankaj
Nov 14 '18 at 19:24
@ADyson perfect thanks
– pankaj
Nov 14 '18 at 19:24
add a comment |
1 Answer
1
active
oldest
votes
You can use the alternative syntax (known as "bracket notation") as follows:
console.log(json.food.pizza["@type"]);
See https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/Property_accessors for documentation.
answered Nov 14 '18 at 19:31
ADysonADyson
24.3k112545
add a comment |
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1 Answer
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1 Answer
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active
oldest
votes
active
oldest
votes
active
oldest
votes
You can use the alternative syntax (known as "bracket notation") as follows:
console.log(json.food.pizza["@type"]);
See https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/Property_accessors for documentation.
answered Nov 14 '18 at 19:31
ADysonADyson
24.3k112545
add a comment |
You can use the alternative syntax (known as "bracket notation") as follows:
console.log(json.food.pizza["@type"]);
See https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/Property_accessors for documentation.
answered Nov 14 '18 at 19:31
ADysonADyson
24.3k112545
add a comment |
You can use the alternative syntax (known as "bracket notation") as follows:
console.log(json.food.pizza["@type"]);
See https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/Property_accessors for documentation.
answered Nov 14 '18 at 19:31
ADysonADyson
24.3k112545
You can use the alternative syntax (known as "bracket notation") as follows:
console.log(json.food.pizza["@type"]);
See https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/Property_accessors for documentation.
answered Nov 14 '18 at 19:31
ADysonADyson
24.3k112545
answered Nov 14 '18 at 19:31
ADysonADyson
24.3k112545
answered Nov 14 '18 at 19:31
ADysonADyson
24.3k112545
answered Nov 14 '18 at 19:31
ADysonADyson
24.3k112545
24.3k112545
add a comment |
add a comment |
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1
can you try
pizza["@type"]instead?– ADyson
Nov 14 '18 at 19:20
@ADyson perfect thanks
– pankaj
Nov 14 '18 at 19:24