Square Brackets Javascript Object Key
Can anyone explain how the why/how the below method of assigning keys in javascript works?
a = "b"
c = {[a]: "d"}
return:
Object {b: "d"}
javascript
add a comment |
Can anyone explain how the why/how the below method of assigning keys in javascript works?
a = "b"
c = {[a]: "d"}
return:
Object {b: "d"}
javascript
@Tushar: There is no call toObjecthere. That's completely unrelated.
– Felix Kling
Sep 11 '15 at 4:52
@FelixKling Array is treated as object,typeof
– Tushar
Sep 11 '15 at 4:53
@Tushar: arrays are objects, but there is no array here and, again, no call toObject.
– Felix Kling
Sep 11 '15 at 4:54
Yes, but whiletypeof == "object",Array.prototype.constructor != Object.prototype.constructor, nor is the behavior the same.
– Sean Vieira
Sep 11 '15 at 5:04
add a comment |
Can anyone explain how the why/how the below method of assigning keys in javascript works?
a = "b"
c = {[a]: "d"}
return:
Object {b: "d"}
javascript
Can anyone explain how the why/how the below method of assigning keys in javascript works?
a = "b"
c = {[a]: "d"}
return:
Object {b: "d"}
javascript
javascript
edited Sep 11 '15 at 4:47
Tushar
67.3k1192120
67.3k1192120
asked Sep 11 '15 at 4:40
lcharbon
5321510
5321510
@Tushar: There is no call toObjecthere. That's completely unrelated.
– Felix Kling
Sep 11 '15 at 4:52
@FelixKling Array is treated as object,typeof
– Tushar
Sep 11 '15 at 4:53
@Tushar: arrays are objects, but there is no array here and, again, no call toObject.
– Felix Kling
Sep 11 '15 at 4:54
Yes, but whiletypeof == "object",Array.prototype.constructor != Object.prototype.constructor, nor is the behavior the same.
– Sean Vieira
Sep 11 '15 at 5:04
add a comment |
@Tushar: There is no call toObjecthere. That's completely unrelated.
– Felix Kling
Sep 11 '15 at 4:52
@FelixKling Array is treated as object,typeof
– Tushar
Sep 11 '15 at 4:53
@Tushar: arrays are objects, but there is no array here and, again, no call toObject.
– Felix Kling
Sep 11 '15 at 4:54
Yes, but whiletypeof == "object",Array.prototype.constructor != Object.prototype.constructor, nor is the behavior the same.
– Sean Vieira
Sep 11 '15 at 5:04
@Tushar: There is no call to
Object here. That's completely unrelated.– Felix Kling
Sep 11 '15 at 4:52
@Tushar: There is no call to
Object here. That's completely unrelated.– Felix Kling
Sep 11 '15 at 4:52
@FelixKling Array is treated as object,
typeof – Tushar
Sep 11 '15 at 4:53
@FelixKling Array is treated as object,
typeof – Tushar
Sep 11 '15 at 4:53
@Tushar: arrays are objects, but there is no array here and, again, no call to
Object.– Felix Kling
Sep 11 '15 at 4:54
@Tushar: arrays are objects, but there is no array here and, again, no call to
Object.– Felix Kling
Sep 11 '15 at 4:54
Yes, but while
typeof == "object", Array.prototype.constructor != Object.prototype.constructor, nor is the behavior the same.– Sean Vieira
Sep 11 '15 at 5:04
Yes, but while
typeof == "object", Array.prototype.constructor != Object.prototype.constructor, nor is the behavior the same.– Sean Vieira
Sep 11 '15 at 5:04
add a comment |
2 Answers
2
active
oldest
votes
It's the new ES2015 (the EcmaScript spec formally known as ES6) computed property name syntax. It's a shorthand for the someObject[someKey] assignment that you know from ES3/5:
var a = "b"
var c = {[a]: "d"}
is syntactic sugar for:
var a = "b"
var c = {}
c[a] = "d"
It's not only ES6
– Tushar
Sep 11 '15 at 4:47
@Tushar - where else does this work? It throws for me in a normal ES5 environment (Node 0.10).
– Sean Vieira
Sep 11 '15 at 4:51
add a comment |
Really the use of gives an excellent way to use actual value of variable as key/property while creating JavaScript objects.
I'm pretty much statisfied with the above answer and I appreciate it as it allowed me to write this with a little example.
I've executed the code line by line on Node REPL (Node shell).
> var key = "fullName"; // Assignment
undefined
>
> var obj = {key: "Rishikesh Agrawani"} // Here key's value will not be used
undefined
> obj // Inappropriate, which we don't want
{ key: 'Rishikesh Agrawani' }
>
> // Let's fix
undefined
> var obj2 = {[key]: "Rishikesh Agrawani"}
undefined
> obj2
{ fullName: 'Rishikesh Agrawani' }
>
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
It's the new ES2015 (the EcmaScript spec formally known as ES6) computed property name syntax. It's a shorthand for the someObject[someKey] assignment that you know from ES3/5:
var a = "b"
var c = {[a]: "d"}
is syntactic sugar for:
var a = "b"
var c = {}
c[a] = "d"
It's not only ES6
– Tushar
Sep 11 '15 at 4:47
@Tushar - where else does this work? It throws for me in a normal ES5 environment (Node 0.10).
– Sean Vieira
Sep 11 '15 at 4:51
add a comment |
It's the new ES2015 (the EcmaScript spec formally known as ES6) computed property name syntax. It's a shorthand for the someObject[someKey] assignment that you know from ES3/5:
var a = "b"
var c = {[a]: "d"}
is syntactic sugar for:
var a = "b"
var c = {}
c[a] = "d"
It's not only ES6
– Tushar
Sep 11 '15 at 4:47
@Tushar - where else does this work? It throws for me in a normal ES5 environment (Node 0.10).
– Sean Vieira
Sep 11 '15 at 4:51
add a comment |
It's the new ES2015 (the EcmaScript spec formally known as ES6) computed property name syntax. It's a shorthand for the someObject[someKey] assignment that you know from ES3/5:
var a = "b"
var c = {[a]: "d"}
is syntactic sugar for:
var a = "b"
var c = {}
c[a] = "d"
It's the new ES2015 (the EcmaScript spec formally known as ES6) computed property name syntax. It's a shorthand for the someObject[someKey] assignment that you know from ES3/5:
var a = "b"
var c = {[a]: "d"}
is syntactic sugar for:
var a = "b"
var c = {}
c[a] = "d"
answered Sep 11 '15 at 4:46
Sean Vieira
112k23222227
112k23222227
It's not only ES6
– Tushar
Sep 11 '15 at 4:47
@Tushar - where else does this work? It throws for me in a normal ES5 environment (Node 0.10).
– Sean Vieira
Sep 11 '15 at 4:51
add a comment |
It's not only ES6
– Tushar
Sep 11 '15 at 4:47
@Tushar - where else does this work? It throws for me in a normal ES5 environment (Node 0.10).
– Sean Vieira
Sep 11 '15 at 4:51
It's not only ES6
– Tushar
Sep 11 '15 at 4:47
It's not only ES6
– Tushar
Sep 11 '15 at 4:47
@Tushar - where else does this work? It throws for me in a normal ES5 environment (Node 0.10).
– Sean Vieira
Sep 11 '15 at 4:51
@Tushar - where else does this work? It throws for me in a normal ES5 environment (Node 0.10).
– Sean Vieira
Sep 11 '15 at 4:51
add a comment |
Really the use of gives an excellent way to use actual value of variable as key/property while creating JavaScript objects.
I'm pretty much statisfied with the above answer and I appreciate it as it allowed me to write this with a little example.
I've executed the code line by line on Node REPL (Node shell).
> var key = "fullName"; // Assignment
undefined
>
> var obj = {key: "Rishikesh Agrawani"} // Here key's value will not be used
undefined
> obj // Inappropriate, which we don't want
{ key: 'Rishikesh Agrawani' }
>
> // Let's fix
undefined
> var obj2 = {[key]: "Rishikesh Agrawani"}
undefined
> obj2
{ fullName: 'Rishikesh Agrawani' }
>
add a comment |
Really the use of gives an excellent way to use actual value of variable as key/property while creating JavaScript objects.
I'm pretty much statisfied with the above answer and I appreciate it as it allowed me to write this with a little example.
I've executed the code line by line on Node REPL (Node shell).
> var key = "fullName"; // Assignment
undefined
>
> var obj = {key: "Rishikesh Agrawani"} // Here key's value will not be used
undefined
> obj // Inappropriate, which we don't want
{ key: 'Rishikesh Agrawani' }
>
> // Let's fix
undefined
> var obj2 = {[key]: "Rishikesh Agrawani"}
undefined
> obj2
{ fullName: 'Rishikesh Agrawani' }
>
add a comment |
Really the use of gives an excellent way to use actual value of variable as key/property while creating JavaScript objects.
I'm pretty much statisfied with the above answer and I appreciate it as it allowed me to write this with a little example.
I've executed the code line by line on Node REPL (Node shell).
> var key = "fullName"; // Assignment
undefined
>
> var obj = {key: "Rishikesh Agrawani"} // Here key's value will not be used
undefined
> obj // Inappropriate, which we don't want
{ key: 'Rishikesh Agrawani' }
>
> // Let's fix
undefined
> var obj2 = {[key]: "Rishikesh Agrawani"}
undefined
> obj2
{ fullName: 'Rishikesh Agrawani' }
>
Really the use of gives an excellent way to use actual value of variable as key/property while creating JavaScript objects.
I'm pretty much statisfied with the above answer and I appreciate it as it allowed me to write this with a little example.
I've executed the code line by line on Node REPL (Node shell).
> var key = "fullName"; // Assignment
undefined
>
> var obj = {key: "Rishikesh Agrawani"} // Here key's value will not be used
undefined
> obj // Inappropriate, which we don't want
{ key: 'Rishikesh Agrawani' }
>
> // Let's fix
undefined
> var obj2 = {[key]: "Rishikesh Agrawani"}
undefined
> obj2
{ fullName: 'Rishikesh Agrawani' }
>
answered Nov 2 at 17:08
hygull
3,14111228
3,14111228
add a comment |
add a comment |
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@Tushar: There is no call to
Objecthere. That's completely unrelated.– Felix Kling
Sep 11 '15 at 4:52
@FelixKling Array is treated as object,
typeof– Tushar
Sep 11 '15 at 4:53
@Tushar: arrays are objects, but there is no array here and, again, no call to
Object.– Felix Kling
Sep 11 '15 at 4:54
Yes, but while
typeof == "object",Array.prototype.constructor != Object.prototype.constructor, nor is the behavior the same.– Sean Vieira
Sep 11 '15 at 5:04