Apriori Algo and discretize column error while generating rules in R












0














While applying Assosciation Rules , using apriori algorithm . I got this error:-



grocery_rules <- apriori(pos, parameter = list(support = 0.01, confidence = 0.5)) 



Error in asMethod(object) : column(s) 2, 4, 5, 7, 8, 9, 10, 11, 12,
13, 14, 15, 16 not logical or a factor. Discretize the columns first.




And when I tried to discretize the column using
pos$Total.Products <- discretize(pos$Total.Products)




Error in discretize(pos$Total.Products) : Some breaks are not
unique, use fewer breaks for the data.











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  • apriori algorithm only works with trasactional data so first convert the column on which you are trying to run the algorithm to df_new <- as(df$column_name,"transactions")
    – Hunaidkhan
    Nov 12 at 10:51
















0














While applying Assosciation Rules , using apriori algorithm . I got this error:-



grocery_rules <- apriori(pos, parameter = list(support = 0.01, confidence = 0.5)) 



Error in asMethod(object) : column(s) 2, 4, 5, 7, 8, 9, 10, 11, 12,
13, 14, 15, 16 not logical or a factor. Discretize the columns first.




And when I tried to discretize the column using
pos$Total.Products <- discretize(pos$Total.Products)




Error in discretize(pos$Total.Products) : Some breaks are not
unique, use fewer breaks for the data.











share|improve this question
























  • apriori algorithm only works with trasactional data so first convert the column on which you are trying to run the algorithm to df_new <- as(df$column_name,"transactions")
    – Hunaidkhan
    Nov 12 at 10:51














0












0








0







While applying Assosciation Rules , using apriori algorithm . I got this error:-



grocery_rules <- apriori(pos, parameter = list(support = 0.01, confidence = 0.5)) 



Error in asMethod(object) : column(s) 2, 4, 5, 7, 8, 9, 10, 11, 12,
13, 14, 15, 16 not logical or a factor. Discretize the columns first.




And when I tried to discretize the column using
pos$Total.Products <- discretize(pos$Total.Products)




Error in discretize(pos$Total.Products) : Some breaks are not
unique, use fewer breaks for the data.











share|improve this question















While applying Assosciation Rules , using apriori algorithm . I got this error:-



grocery_rules <- apriori(pos, parameter = list(support = 0.01, confidence = 0.5)) 



Error in asMethod(object) : column(s) 2, 4, 5, 7, 8, 9, 10, 11, 12,
13, 14, 15, 16 not logical or a factor. Discretize the columns first.




And when I tried to discretize the column using
pos$Total.Products <- discretize(pos$Total.Products)




Error in discretize(pos$Total.Products) : Some breaks are not
unique, use fewer breaks for the data.








r rstudio apriori mining






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edited Nov 12 at 11:39









Vineeth Sai

2,37641023




2,37641023










asked Nov 12 at 10:26









Lakhan Singh Rajput

6




6












  • apriori algorithm only works with trasactional data so first convert the column on which you are trying to run the algorithm to df_new <- as(df$column_name,"transactions")
    – Hunaidkhan
    Nov 12 at 10:51


















  • apriori algorithm only works with trasactional data so first convert the column on which you are trying to run the algorithm to df_new <- as(df$column_name,"transactions")
    – Hunaidkhan
    Nov 12 at 10:51
















apriori algorithm only works with trasactional data so first convert the column on which you are trying to run the algorithm to df_new <- as(df$column_name,"transactions")
– Hunaidkhan
Nov 12 at 10:51




apriori algorithm only works with trasactional data so first convert the column on which you are trying to run the algorithm to df_new <- as(df$column_name,"transactions")
– Hunaidkhan
Nov 12 at 10:51

















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