screenshot using googlepagespeed api
up vote
0
down vote
favorite
1
Below is my code to capture the screenshot of of webpage. But i get the output of the same as how in the image below. Kindly suggest on what is the mistake i am committing. Also kindly suggest the method to save this screenshot to the server?
<?php
$url='https://www.google.com';
$stratedy = 'mobile' ;
$apiReqUrl = 'https://www.googleapis.com/pagespeedonline/v2/runPagespeed';
$apiKey = 'my_api_key' ;
$curl = curl_init();
curl_setopt($curl, CURL_OPTURL, $apiReqUrl.'?url='.$reqUrl.'
&key='.$apiKey.'&screenshot=true&strategy='.$stratedy);
curl_setopt($curl, CURLOPT_RETURNTRANSFER, TRUE);
$result=curl_exec($curl);
$data = json_decode($result, true);
$img = str_replace(array('_','-'), array('/','+'), $data['screenshot']
['data']);
echo '<img src="data:image/jpeg;base64,'.$img.'">';
?>
php google-api
edited Nov 12 at 11:02
Praveen Kumar Purushothaman
131k23133179
asked Nov 12 at 10:40
Keerthana A
176
add a comment |
up vote
0
down vote
favorite
1
Below is my code to capture the screenshot of of webpage. But i get the output of the same as how in the image below. Kindly suggest on what is the mistake i am committing. Also kindly suggest the method to save this screenshot to the server?
<?php
$url='https://www.google.com';
$stratedy = 'mobile' ;
$apiReqUrl = 'https://www.googleapis.com/pagespeedonline/v2/runPagespeed';
$apiKey = 'my_api_key' ;
$curl = curl_init();
curl_setopt($curl, CURL_OPTURL, $apiReqUrl.'?url='.$reqUrl.'
&key='.$apiKey.'&screenshot=true&strategy='.$stratedy);
curl_setopt($curl, CURLOPT_RETURNTRANSFER, TRUE);
$result=curl_exec($curl);
$data = json_decode($result, true);
$img = str_replace(array('_','-'), array('/','+'), $data['screenshot']
['data']);
echo '<img src="data:image/jpeg;base64,'.$img.'">';
?>
php google-api
edited Nov 12 at 11:02
Praveen Kumar Purushothaman
131k23133179
asked Nov 12 at 10:40
Keerthana A
176
Did you try this: Generating Screenshots of URLs using Google's secret magic API? It's my article and I have also given some example snippets.
– Praveen Kumar Purushothaman
Nov 12 at 10:41
add a comment |
up vote
0
down vote
favorite
1
up vote
0
down vote
favorite
1
1
Below is my code to capture the screenshot of of webpage. But i get the output of the same as how in the image below. Kindly suggest on what is the mistake i am committing. Also kindly suggest the method to save this screenshot to the server?
<?php
$url='https://www.google.com';
$stratedy = 'mobile' ;
$apiReqUrl = 'https://www.googleapis.com/pagespeedonline/v2/runPagespeed';
$apiKey = 'my_api_key' ;
$curl = curl_init();
curl_setopt($curl, CURL_OPTURL, $apiReqUrl.'?url='.$reqUrl.'
&key='.$apiKey.'&screenshot=true&strategy='.$stratedy);
curl_setopt($curl, CURLOPT_RETURNTRANSFER, TRUE);
$result=curl_exec($curl);
$data = json_decode($result, true);
$img = str_replace(array('_','-'), array('/','+'), $data['screenshot']
['data']);
echo '<img src="data:image/jpeg;base64,'.$img.'">';
?>
php google-api
edited Nov 12 at 11:02
Praveen Kumar Purushothaman
131k23133179
asked Nov 12 at 10:40
Keerthana A
176
Below is my code to capture the screenshot of of webpage. But i get the output of the same as how in the image below. Kindly suggest on what is the mistake i am committing. Also kindly suggest the method to save this screenshot to the server?
<?php
$url='https://www.google.com';
$stratedy = 'mobile' ;
$apiReqUrl = 'https://www.googleapis.com/pagespeedonline/v2/runPagespeed';
$apiKey = 'my_api_key' ;
$curl = curl_init();
curl_setopt($curl, CURL_OPTURL, $apiReqUrl.'?url='.$reqUrl.'
&key='.$apiKey.'&screenshot=true&strategy='.$stratedy);
curl_setopt($curl, CURLOPT_RETURNTRANSFER, TRUE);
$result=curl_exec($curl);
$data = json_decode($result, true);
$img = str_replace(array('_','-'), array('/','+'), $data['screenshot']
['data']);
echo '<img src="data:image/jpeg;base64,'.$img.'">';
?>
php google-api
php google-api
edited Nov 12 at 11:02
Praveen Kumar Purushothaman
131k23133179
asked Nov 12 at 10:40
Keerthana A
176
edited Nov 12 at 11:02
Praveen Kumar Purushothaman
131k23133179
asked Nov 12 at 10:40
Keerthana A
176
edited Nov 12 at 11:02
Praveen Kumar Purushothaman
131k23133179
edited Nov 12 at 11:02
Praveen Kumar Purushothaman
131k23133179
edited Nov 12 at 11:02
Praveen Kumar Purushothaman
131k23133179
131k23133179
asked Nov 12 at 10:40
Keerthana A
176
asked Nov 12 at 10:40
Keerthana A
176
asked Nov 12 at 10:40
Keerthana A
176
176
Did you try this: Generating Screenshots of URLs using Google's secret magic API? It's my article and I have also given some example snippets.
– Praveen Kumar Purushothaman
Nov 12 at 10:41
add a comment |
Did you try this: Generating Screenshots of URLs using Google's secret magic API? It's my article and I have also given some example snippets.
– Praveen Kumar Purushothaman
Nov 12 at 10:41
Did you try this: Generating Screenshots of URLs using Google's secret magic API? It's my article and I have also given some example snippets.
– Praveen Kumar Purushothaman
Nov 12 at 10:41
Did you try this: Generating Screenshots of URLs using Google's secret magic API? It's my article and I have also given some example snippets.
– Praveen Kumar Purushothaman
Nov 12 at 10:41
add a comment |
1 Answer
1
active
oldest
votes
up vote
1
down vote
If you can, try using the HTML version from Generating Screenshots of URLs using Google's secret magic API. All you need to do is to call the API and it's free (I guess).
For example in PHP:
<?php
$url = "https://praveen.science/";
// Hit the Google PageSpeed Insights API.
// Catch: Your server needs to allow file_get_contents() to make this run. Or you need to use cURL.
$response = file_get_contents('https://www.googleapis.com/pagespeedonline/v2/runPagespeed?screenshot=true&url='.urlencode($url));
// Convert the JSON response into an array.
$googlePagespeedObject = json_decode($response, true);
// Grab the Screenshot data.
$screenshot = $googlePagespeedObject['screenshot']['data'];
// Fix url encoded base64
$screenshot = str_replace(array('_','-'), array('/','+'), $screenshot);
// Build the Data URI scheme and spit out an <img /> Tag.
echo "<img src="data:image/jpeg;base64,{$screenshot}" alt="Screenshot" />";
// Or.. base64 decode and store
file_put_contents('...', base64_decode($screenshot));
Or in JavaScript:
$(function() {
// Get the URL.
var url = "https://praveen.science/";
// Prepare the URL.
url = encodeURIComponent(url);
// Hit the Google Page Speed API.
$.get("https://www.googleapis.com/pagespeedonline/v1/runPagespeed?screenshot=true&strategy=mobile&url=" + url, function(data) {
// Get the screenshot data.
var screenshot = data.screenshot;
// Convert the Google's Data to Data URI scheme.
var imageData = screenshot.data.replace(/_/g, "/").replace(/-/g, "+");
// Build the Data URI.
var dataURI = "data:" + screenshot.mime_type + ";base64," + imageData;
// Set the image's source.
$("img").attr("src", dataURI);
});
});<script src="https://code.jquery.com/jquery-2.2.4.js"></script>
<h1>Hard Coded Screenshot of my Website:</h1>
<img src="//placehold.it/300x50?text=Loading+Screenshot..." alt="Screenshot" />answered Nov 12 at 10:43
Praveen Kumar Purushothaman
131k23133179
This didnt work for me :(
– Keerthana A
Nov 12 at 10:55
Added your PHP version, hope you don't mind, the OP wanted in PHP.. nice blog.. ✓ +1
– Lawrence Cherone
Nov 12 at 10:56
@LawrenceCherone Thanks...:)Doesn't rot. Lives till I live.:)
– Praveen Kumar Purushothaman
Nov 12 at 10:56
@KeerthanaA Did it work in your PC at all? When you clicked on the Run code snippet, did you see the screenshot getting generated?
– Praveen Kumar Purushothaman
Nov 12 at 10:57
@PraveenKumarPurushothaman Nope its not running Gives me the following error. { "message": "Uncaught ReferenceError: $ is not defined", "filename": "stacksnippets.net/js", "lineno": 15, "colno": 9 }
– Keerthana A
Nov 12 at 11:10
|
show 1 more comment
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1 Answer
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active
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votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
If you can, try using the HTML version from Generating Screenshots of URLs using Google's secret magic API. All you need to do is to call the API and it's free (I guess).
For example in PHP:
<?php
$url = "https://praveen.science/";
// Hit the Google PageSpeed Insights API.
// Catch: Your server needs to allow file_get_contents() to make this run. Or you need to use cURL.
$response = file_get_contents('https://www.googleapis.com/pagespeedonline/v2/runPagespeed?screenshot=true&url='.urlencode($url));
// Convert the JSON response into an array.
$googlePagespeedObject = json_decode($response, true);
// Grab the Screenshot data.
$screenshot = $googlePagespeedObject['screenshot']['data'];
// Fix url encoded base64
$screenshot = str_replace(array('_','-'), array('/','+'), $screenshot);
// Build the Data URI scheme and spit out an <img /> Tag.
echo "<img src="data:image/jpeg;base64,{$screenshot}" alt="Screenshot" />";
// Or.. base64 decode and store
file_put_contents('...', base64_decode($screenshot));
Or in JavaScript:
$(function() {
// Get the URL.
var url = "https://praveen.science/";
// Prepare the URL.
url = encodeURIComponent(url);
// Hit the Google Page Speed API.
$.get("https://www.googleapis.com/pagespeedonline/v1/runPagespeed?screenshot=true&strategy=mobile&url=" + url, function(data) {
// Get the screenshot data.
var screenshot = data.screenshot;
// Convert the Google's Data to Data URI scheme.
var imageData = screenshot.data.replace(/_/g, "/").replace(/-/g, "+");
// Build the Data URI.
var dataURI = "data:" + screenshot.mime_type + ";base64," + imageData;
// Set the image's source.
$("img").attr("src", dataURI);
});
});<script src="https://code.jquery.com/jquery-2.2.4.js"></script>
<h1>Hard Coded Screenshot of my Website:</h1>
<img src="//placehold.it/300x50?text=Loading+Screenshot..." alt="Screenshot" />answered Nov 12 at 10:43
Praveen Kumar Purushothaman
131k23133179
This didnt work for me :(
– Keerthana A
Nov 12 at 10:55
Added your PHP version, hope you don't mind, the OP wanted in PHP.. nice blog.. ✓ +1
– Lawrence Cherone
Nov 12 at 10:56
@LawrenceCherone Thanks...:)Doesn't rot. Lives till I live.:)
– Praveen Kumar Purushothaman
Nov 12 at 10:56
@KeerthanaA Did it work in your PC at all? When you clicked on the Run code snippet, did you see the screenshot getting generated?
– Praveen Kumar Purushothaman
Nov 12 at 10:57
@PraveenKumarPurushothaman Nope its not running Gives me the following error. { "message": "Uncaught ReferenceError: $ is not defined", "filename": "stacksnippets.net/js", "lineno": 15, "colno": 9 }
– Keerthana A
Nov 12 at 11:10
|
show 1 more comment
up vote
1
down vote
If you can, try using the HTML version from Generating Screenshots of URLs using Google's secret magic API. All you need to do is to call the API and it's free (I guess).
For example in PHP:
<?php
$url = "https://praveen.science/";
// Hit the Google PageSpeed Insights API.
// Catch: Your server needs to allow file_get_contents() to make this run. Or you need to use cURL.
$response = file_get_contents('https://www.googleapis.com/pagespeedonline/v2/runPagespeed?screenshot=true&url='.urlencode($url));
// Convert the JSON response into an array.
$googlePagespeedObject = json_decode($response, true);
// Grab the Screenshot data.
$screenshot = $googlePagespeedObject['screenshot']['data'];
// Fix url encoded base64
$screenshot = str_replace(array('_','-'), array('/','+'), $screenshot);
// Build the Data URI scheme and spit out an <img /> Tag.
echo "<img src="data:image/jpeg;base64,{$screenshot}" alt="Screenshot" />";
// Or.. base64 decode and store
file_put_contents('...', base64_decode($screenshot));
Or in JavaScript:
$(function() {
// Get the URL.
var url = "https://praveen.science/";
// Prepare the URL.
url = encodeURIComponent(url);
// Hit the Google Page Speed API.
$.get("https://www.googleapis.com/pagespeedonline/v1/runPagespeed?screenshot=true&strategy=mobile&url=" + url, function(data) {
// Get the screenshot data.
var screenshot = data.screenshot;
// Convert the Google's Data to Data URI scheme.
var imageData = screenshot.data.replace(/_/g, "/").replace(/-/g, "+");
// Build the Data URI.
var dataURI = "data:" + screenshot.mime_type + ";base64," + imageData;
// Set the image's source.
$("img").attr("src", dataURI);
});
});<script src="https://code.jquery.com/jquery-2.2.4.js"></script>
<h1>Hard Coded Screenshot of my Website:</h1>
<img src="//placehold.it/300x50?text=Loading+Screenshot..." alt="Screenshot" />answered Nov 12 at 10:43
Praveen Kumar Purushothaman
131k23133179
This didnt work for me :(
– Keerthana A
Nov 12 at 10:55
Added your PHP version, hope you don't mind, the OP wanted in PHP.. nice blog.. ✓ +1
– Lawrence Cherone
Nov 12 at 10:56
@LawrenceCherone Thanks...:)Doesn't rot. Lives till I live.:)
– Praveen Kumar Purushothaman
Nov 12 at 10:56
@KeerthanaA Did it work in your PC at all? When you clicked on the Run code snippet, did you see the screenshot getting generated?
– Praveen Kumar Purushothaman
Nov 12 at 10:57
@PraveenKumarPurushothaman Nope its not running Gives me the following error. { "message": "Uncaught ReferenceError: $ is not defined", "filename": "stacksnippets.net/js", "lineno": 15, "colno": 9 }
– Keerthana A
Nov 12 at 11:10
|
show 1 more comment
up vote
1
down vote
up vote
1
down vote
If you can, try using the HTML version from Generating Screenshots of URLs using Google's secret magic API. All you need to do is to call the API and it's free (I guess).
For example in PHP:
<?php
$url = "https://praveen.science/";
// Hit the Google PageSpeed Insights API.
// Catch: Your server needs to allow file_get_contents() to make this run. Or you need to use cURL.
$response = file_get_contents('https://www.googleapis.com/pagespeedonline/v2/runPagespeed?screenshot=true&url='.urlencode($url));
// Convert the JSON response into an array.
$googlePagespeedObject = json_decode($response, true);
// Grab the Screenshot data.
$screenshot = $googlePagespeedObject['screenshot']['data'];
// Fix url encoded base64
$screenshot = str_replace(array('_','-'), array('/','+'), $screenshot);
// Build the Data URI scheme and spit out an <img /> Tag.
echo "<img src="data:image/jpeg;base64,{$screenshot}" alt="Screenshot" />";
// Or.. base64 decode and store
file_put_contents('...', base64_decode($screenshot));
Or in JavaScript:
$(function() {
// Get the URL.
var url = "https://praveen.science/";
// Prepare the URL.
url = encodeURIComponent(url);
// Hit the Google Page Speed API.
$.get("https://www.googleapis.com/pagespeedonline/v1/runPagespeed?screenshot=true&strategy=mobile&url=" + url, function(data) {
// Get the screenshot data.
var screenshot = data.screenshot;
// Convert the Google's Data to Data URI scheme.
var imageData = screenshot.data.replace(/_/g, "/").replace(/-/g, "+");
// Build the Data URI.
var dataURI = "data:" + screenshot.mime_type + ";base64," + imageData;
// Set the image's source.
$("img").attr("src", dataURI);
});
});<script src="https://code.jquery.com/jquery-2.2.4.js"></script>
<h1>Hard Coded Screenshot of my Website:</h1>
<img src="//placehold.it/300x50?text=Loading+Screenshot..." alt="Screenshot" />answered Nov 12 at 10:43
Praveen Kumar Purushothaman
131k23133179
If you can, try using the HTML version from Generating Screenshots of URLs using Google's secret magic API. All you need to do is to call the API and it's free (I guess).
For example in PHP:
<?php
$url = "https://praveen.science/";
// Hit the Google PageSpeed Insights API.
// Catch: Your server needs to allow file_get_contents() to make this run. Or you need to use cURL.
$response = file_get_contents('https://www.googleapis.com/pagespeedonline/v2/runPagespeed?screenshot=true&url='.urlencode($url));
// Convert the JSON response into an array.
$googlePagespeedObject = json_decode($response, true);
// Grab the Screenshot data.
$screenshot = $googlePagespeedObject['screenshot']['data'];
// Fix url encoded base64
$screenshot = str_replace(array('_','-'), array('/','+'), $screenshot);
// Build the Data URI scheme and spit out an <img /> Tag.
echo "<img src="data:image/jpeg;base64,{$screenshot}" alt="Screenshot" />";
// Or.. base64 decode and store
file_put_contents('...', base64_decode($screenshot));
Or in JavaScript:
$(function() {
// Get the URL.
var url = "https://praveen.science/";
// Prepare the URL.
url = encodeURIComponent(url);
// Hit the Google Page Speed API.
$.get("https://www.googleapis.com/pagespeedonline/v1/runPagespeed?screenshot=true&strategy=mobile&url=" + url, function(data) {
// Get the screenshot data.
var screenshot = data.screenshot;
// Convert the Google's Data to Data URI scheme.
var imageData = screenshot.data.replace(/_/g, "/").replace(/-/g, "+");
// Build the Data URI.
var dataURI = "data:" + screenshot.mime_type + ";base64," + imageData;
// Set the image's source.
$("img").attr("src", dataURI);
});
});<script src="https://code.jquery.com/jquery-2.2.4.js"></script>
<h1>Hard Coded Screenshot of my Website:</h1>
<img src="//placehold.it/300x50?text=Loading+Screenshot..." alt="Screenshot" />$(function() {
// Get the URL.
var url = "https://praveen.science/";
// Prepare the URL.
url = encodeURIComponent(url);
// Hit the Google Page Speed API.
$.get("https://www.googleapis.com/pagespeedonline/v1/runPagespeed?screenshot=true&strategy=mobile&url=" + url, function(data) {
// Get the screenshot data.
var screenshot = data.screenshot;
// Convert the Google's Data to Data URI scheme.
var imageData = screenshot.data.replace(/_/g, "/").replace(/-/g, "+");
// Build the Data URI.
var dataURI = "data:" + screenshot.mime_type + ";base64," + imageData;
// Set the image's source.
$("img").attr("src", dataURI);
});
});<script src="https://code.jquery.com/jquery-2.2.4.js"></script>
<h1>Hard Coded Screenshot of my Website:</h1>
<img src="//placehold.it/300x50?text=Loading+Screenshot..." alt="Screenshot" />$(function() {
// Get the URL.
var url = "https://praveen.science/";
// Prepare the URL.
url = encodeURIComponent(url);
// Hit the Google Page Speed API.
$.get("https://www.googleapis.com/pagespeedonline/v1/runPagespeed?screenshot=true&strategy=mobile&url=" + url, function(data) {
// Get the screenshot data.
var screenshot = data.screenshot;
// Convert the Google's Data to Data URI scheme.
var imageData = screenshot.data.replace(/_/g, "/").replace(/-/g, "+");
// Build the Data URI.
var dataURI = "data:" + screenshot.mime_type + ";base64," + imageData;
// Set the image's source.
$("img").attr("src", dataURI);
});
});<script src="https://code.jquery.com/jquery-2.2.4.js"></script>
<h1>Hard Coded Screenshot of my Website:</h1>
<img src="//placehold.it/300x50?text=Loading+Screenshot..." alt="Screenshot" />answered Nov 12 at 10:43
Praveen Kumar Purushothaman
131k23133179
edited Nov 12 at 10:58
answered Nov 12 at 10:43
Praveen Kumar Purushothaman
131k23133179
answered Nov 12 at 10:43
Praveen Kumar Purushothaman
131k23133179
answered Nov 12 at 10:43
Praveen Kumar Purushothaman
131k23133179
131k23133179
This didnt work for me :(
– Keerthana A
Nov 12 at 10:55
Added your PHP version, hope you don't mind, the OP wanted in PHP.. nice blog.. ✓ +1
– Lawrence Cherone
Nov 12 at 10:56
@LawrenceCherone Thanks...:)Doesn't rot. Lives till I live.:)
– Praveen Kumar Purushothaman
Nov 12 at 10:56
@KeerthanaA Did it work in your PC at all? When you clicked on the Run code snippet, did you see the screenshot getting generated?
– Praveen Kumar Purushothaman
Nov 12 at 10:57
@PraveenKumarPurushothaman Nope its not running Gives me the following error. { "message": "Uncaught ReferenceError: $ is not defined", "filename": "stacksnippets.net/js", "lineno": 15, "colno": 9 }
– Keerthana A
Nov 12 at 11:10
|
show 1 more comment
This didnt work for me :(
– Keerthana A
Nov 12 at 10:55
Added your PHP version, hope you don't mind, the OP wanted in PHP.. nice blog.. ✓ +1
– Lawrence Cherone
Nov 12 at 10:56
@LawrenceCherone Thanks...:)Doesn't rot. Lives till I live.:)
– Praveen Kumar Purushothaman
Nov 12 at 10:56
@KeerthanaA Did it work in your PC at all? When you clicked on the Run code snippet, did you see the screenshot getting generated?
– Praveen Kumar Purushothaman
Nov 12 at 10:57
@PraveenKumarPurushothaman Nope its not running Gives me the following error. { "message": "Uncaught ReferenceError: $ is not defined", "filename": "stacksnippets.net/js", "lineno": 15, "colno": 9 }
– Keerthana A
Nov 12 at 11:10
This didnt work for me :(
– Keerthana A
Nov 12 at 10:55
This didnt work for me :(
– Keerthana A
Nov 12 at 10:55
Added your PHP version, hope you don't mind, the OP wanted in PHP.. nice blog.. ✓ +1
– Lawrence Cherone
Nov 12 at 10:56
Added your PHP version, hope you don't mind, the OP wanted in PHP.. nice blog.. ✓ +1
– Lawrence Cherone
Nov 12 at 10:56
@LawrenceCherone Thanks...
:) Doesn't rot. Lives till I live. :)– Praveen Kumar Purushothaman
Nov 12 at 10:56
@LawrenceCherone Thanks...
:) Doesn't rot. Lives till I live. :)– Praveen Kumar Purushothaman
Nov 12 at 10:56
@KeerthanaA Did it work in your PC at all? When you clicked on the Run code snippet, did you see the screenshot getting generated?
– Praveen Kumar Purushothaman
Nov 12 at 10:57
@KeerthanaA Did it work in your PC at all? When you clicked on the Run code snippet, did you see the screenshot getting generated?
– Praveen Kumar Purushothaman
Nov 12 at 10:57
@PraveenKumarPurushothaman Nope its not running Gives me the following error. { "message": "Uncaught ReferenceError: $ is not defined", "filename": "stacksnippets.net/js", "lineno": 15, "colno": 9 }
– Keerthana A
Nov 12 at 11:10
@PraveenKumarPurushothaman Nope its not running Gives me the following error. { "message": "Uncaught ReferenceError: $ is not defined", "filename": "stacksnippets.net/js", "lineno": 15, "colno": 9 }
– Keerthana A
Nov 12 at 11:10
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Did you try this: Generating Screenshots of URLs using Google's secret magic API? It's my article and I have also given some example snippets.
– Praveen Kumar Purushothaman
Nov 12 at 10:41