Can I apply exp function directly on a list or matrix?











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down vote

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Can I raise a list to the power of e Like



np.exp(L)


instead of using a for loop for every single element? And does it apply to Arrays and Matrices too?










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  • 4




    Try it and see.
    – coldspeed
    Nov 12 at 10:47















up vote
-2
down vote

favorite












Can I raise a list to the power of e Like



np.exp(L)


instead of using a for loop for every single element? And does it apply to Arrays and Matrices too?










share|improve this question


















  • 4




    Try it and see.
    – coldspeed
    Nov 12 at 10:47













up vote
-2
down vote

favorite









up vote
-2
down vote

favorite











Can I raise a list to the power of e Like



np.exp(L)


instead of using a for loop for every single element? And does it apply to Arrays and Matrices too?










share|improve this question













Can I raise a list to the power of e Like



np.exp(L)


instead of using a for loop for every single element? And does it apply to Arrays and Matrices too?







python exponential






share|improve this question













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asked Nov 12 at 10:46









Fariman Kashani

3928




3928








  • 4




    Try it and see.
    – coldspeed
    Nov 12 at 10:47














  • 4




    Try it and see.
    – coldspeed
    Nov 12 at 10:47








4




4




Try it and see.
– coldspeed
Nov 12 at 10:47




Try it and see.
– coldspeed
Nov 12 at 10:47












2 Answers
2






active

oldest

votes

















up vote
1
down vote



accepted










looks like yes, yes you can



>>> import numpy as np
>>> L=np.array([1,2,3,4,5])
>>> np.exp(L)
array([ 2.71828183, 7.3890561 , 20.08553692, 54.59815003,
148.4131591 ])


even if it's just a plain list and not a numpy array:



>>> L = [1,2,3,4,5]
>>> np.exp(L)
array([ 2.71828183, 7.3890561 , 20.08553692, 54.59815003,
148.4131591 ])
>>>





share|improve this answer




























    up vote
    1
    down vote













    instead of loop if think you can use np.vectorize()



    Speeding up your code (2): vectorizing the loops with Numpy






    share|improve this answer





















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      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes








      up vote
      1
      down vote



      accepted










      looks like yes, yes you can



      >>> import numpy as np
      >>> L=np.array([1,2,3,4,5])
      >>> np.exp(L)
      array([ 2.71828183, 7.3890561 , 20.08553692, 54.59815003,
      148.4131591 ])


      even if it's just a plain list and not a numpy array:



      >>> L = [1,2,3,4,5]
      >>> np.exp(L)
      array([ 2.71828183, 7.3890561 , 20.08553692, 54.59815003,
      148.4131591 ])
      >>>





      share|improve this answer

























        up vote
        1
        down vote



        accepted










        looks like yes, yes you can



        >>> import numpy as np
        >>> L=np.array([1,2,3,4,5])
        >>> np.exp(L)
        array([ 2.71828183, 7.3890561 , 20.08553692, 54.59815003,
        148.4131591 ])


        even if it's just a plain list and not a numpy array:



        >>> L = [1,2,3,4,5]
        >>> np.exp(L)
        array([ 2.71828183, 7.3890561 , 20.08553692, 54.59815003,
        148.4131591 ])
        >>>





        share|improve this answer























          up vote
          1
          down vote



          accepted







          up vote
          1
          down vote



          accepted






          looks like yes, yes you can



          >>> import numpy as np
          >>> L=np.array([1,2,3,4,5])
          >>> np.exp(L)
          array([ 2.71828183, 7.3890561 , 20.08553692, 54.59815003,
          148.4131591 ])


          even if it's just a plain list and not a numpy array:



          >>> L = [1,2,3,4,5]
          >>> np.exp(L)
          array([ 2.71828183, 7.3890561 , 20.08553692, 54.59815003,
          148.4131591 ])
          >>>





          share|improve this answer












          looks like yes, yes you can



          >>> import numpy as np
          >>> L=np.array([1,2,3,4,5])
          >>> np.exp(L)
          array([ 2.71828183, 7.3890561 , 20.08553692, 54.59815003,
          148.4131591 ])


          even if it's just a plain list and not a numpy array:



          >>> L = [1,2,3,4,5]
          >>> np.exp(L)
          array([ 2.71828183, 7.3890561 , 20.08553692, 54.59815003,
          148.4131591 ])
          >>>






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 12 at 10:48









          vencaslac

          1,002217




          1,002217
























              up vote
              1
              down vote













              instead of loop if think you can use np.vectorize()



              Speeding up your code (2): vectorizing the loops with Numpy






              share|improve this answer

























                up vote
                1
                down vote













                instead of loop if think you can use np.vectorize()



                Speeding up your code (2): vectorizing the loops with Numpy






                share|improve this answer























                  up vote
                  1
                  down vote










                  up vote
                  1
                  down vote









                  instead of loop if think you can use np.vectorize()



                  Speeding up your code (2): vectorizing the loops with Numpy






                  share|improve this answer












                  instead of loop if think you can use np.vectorize()



                  Speeding up your code (2): vectorizing the loops with Numpy







                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 12 at 10:52









                  Baptiste Gavalda

                  16011




                  16011






























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