How to listen scroll event for x scroll and y scroll Individually
up vote
0
down vote
favorite
I want to listen scroll event and handler them by two function for two scroll.
One need a throttleTime() to save resource and the other cannot use throttleTime() because it need trigger immediately and it doesn't cast too much.
Now I add two fromEvent to handle them but question is they will both be fired if scroll event is triggered.
fromEvent(this.vscroll.nativeElement, 'scroll').pipe(throttleTime(200)).subscribe((e) => {
if (this.timer) {
clearTimeout(this.timer);
this.timer = null;
this.timer = setTimeout(() => {
this.updateShow();
}, 201);
} else {
this.timer = setTimeout(() => {
this.updateShow();
}, 201);
}
});
fromEvent(this.vscroll.nativeElement, 'scroll').subscribe((e) => {
(document.body.querySelector('#headerScroll') as HTMLElement).style.marginLeft = -this.vscroll.nativeElement.scrollLeft + 'px';
});
In my component those two function won't happen at the same time, so what should i do to make it only trigger one function and prevent from the other being executed.
javascript typescript javascript-events rxjs6
asked Nov 12 at 9:13
Loic
506
add a comment |
up vote
0
down vote
favorite
I want to listen scroll event and handler them by two function for two scroll.
One need a throttleTime() to save resource and the other cannot use throttleTime() because it need trigger immediately and it doesn't cast too much.
Now I add two fromEvent to handle them but question is they will both be fired if scroll event is triggered.
fromEvent(this.vscroll.nativeElement, 'scroll').pipe(throttleTime(200)).subscribe((e) => {
if (this.timer) {
clearTimeout(this.timer);
this.timer = null;
this.timer = setTimeout(() => {
this.updateShow();
}, 201);
} else {
this.timer = setTimeout(() => {
this.updateShow();
}, 201);
}
});
fromEvent(this.vscroll.nativeElement, 'scroll').subscribe((e) => {
(document.body.querySelector('#headerScroll') as HTMLElement).style.marginLeft = -this.vscroll.nativeElement.scrollLeft + 'px';
});
In my component those two function won't happen at the same time, so what should i do to make it only trigger one function and prevent from the other being executed.
javascript typescript javascript-events rxjs6
asked Nov 12 at 9:13
Loic
506
Put them in the same event handler, call 2 functions based on the condition whether there was a vertical scroll or a horizontal one.
– Dennis Lukas
Nov 12 at 9:56
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I want to listen scroll event and handler them by two function for two scroll.
One need a throttleTime() to save resource and the other cannot use throttleTime() because it need trigger immediately and it doesn't cast too much.
Now I add two fromEvent to handle them but question is they will both be fired if scroll event is triggered.
fromEvent(this.vscroll.nativeElement, 'scroll').pipe(throttleTime(200)).subscribe((e) => {
if (this.timer) {
clearTimeout(this.timer);
this.timer = null;
this.timer = setTimeout(() => {
this.updateShow();
}, 201);
} else {
this.timer = setTimeout(() => {
this.updateShow();
}, 201);
}
});
fromEvent(this.vscroll.nativeElement, 'scroll').subscribe((e) => {
(document.body.querySelector('#headerScroll') as HTMLElement).style.marginLeft = -this.vscroll.nativeElement.scrollLeft + 'px';
});
In my component those two function won't happen at the same time, so what should i do to make it only trigger one function and prevent from the other being executed.
javascript typescript javascript-events rxjs6
asked Nov 12 at 9:13
Loic
506
I want to listen scroll event and handler them by two function for two scroll.
One need a throttleTime() to save resource and the other cannot use throttleTime() because it need trigger immediately and it doesn't cast too much.
Now I add two fromEvent to handle them but question is they will both be fired if scroll event is triggered.
fromEvent(this.vscroll.nativeElement, 'scroll').pipe(throttleTime(200)).subscribe((e) => {
if (this.timer) {
clearTimeout(this.timer);
this.timer = null;
this.timer = setTimeout(() => {
this.updateShow();
}, 201);
} else {
this.timer = setTimeout(() => {
this.updateShow();
}, 201);
}
});
fromEvent(this.vscroll.nativeElement, 'scroll').subscribe((e) => {
(document.body.querySelector('#headerScroll') as HTMLElement).style.marginLeft = -this.vscroll.nativeElement.scrollLeft + 'px';
});
In my component those two function won't happen at the same time, so what should i do to make it only trigger one function and prevent from the other being executed.
javascript typescript javascript-events rxjs6
javascript typescript javascript-events rxjs6
asked Nov 12 at 9:13
Loic
506
asked Nov 12 at 9:13
Loic
506
asked Nov 12 at 9:13
Loic
506
asked Nov 12 at 9:13
Loic
506
asked Nov 12 at 9:13
Loic
506
506
Put them in the same event handler, call 2 functions based on the condition whether there was a vertical scroll or a horizontal one.
– Dennis Lukas
Nov 12 at 9:56
add a comment |
Put them in the same event handler, call 2 functions based on the condition whether there was a vertical scroll or a horizontal one.
– Dennis Lukas
Nov 12 at 9:56
Put them in the same event handler, call 2 functions based on the condition whether there was a vertical scroll or a horizontal one.
– Dennis Lukas
Nov 12 at 9:56
Put them in the same event handler, call 2 functions based on the condition whether there was a vertical scroll or a horizontal one.
– Dennis Lukas
Nov 12 at 9:56
add a comment |
1 Answer
1
active
oldest
votes
up vote
0
down vote
Create your single function but store the previous X and Y scroll positions so you can see if they've changed between calls:
var scrollY = 0;
var scrollX = 0;
function onScroll(){
var doc = document.documentElement;
if(doc.scrollLeft !== scrollX) {
scrollX = doc.scrollLeft;
//Put behaviour for X scroll here
$("p").text("X SCROLLED!");
}
if(doc.scrollTop !== scrollY) {
scrollY = doc.scrollTop;
//Put behaviour for Y scroll here
$("p").text("Y SCROLLED!");
}
}
window.addEventListener('scroll', onScroll);<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div style="width:1000px; height:1000px; background-color:rebeccapurple; color:#FFF">
<p style="position: fixed;"></p>
</div>answered Nov 12 at 10:06
Glitcher
951513
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53258982%2fhow-to-listen-scroll-event-for-x-scroll-and-y-scroll-individually%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
Create your single function but store the previous X and Y scroll positions so you can see if they've changed between calls:
var scrollY = 0;
var scrollX = 0;
function onScroll(){
var doc = document.documentElement;
if(doc.scrollLeft !== scrollX) {
scrollX = doc.scrollLeft;
//Put behaviour for X scroll here
$("p").text("X SCROLLED!");
}
if(doc.scrollTop !== scrollY) {
scrollY = doc.scrollTop;
//Put behaviour for Y scroll here
$("p").text("Y SCROLLED!");
}
}
window.addEventListener('scroll', onScroll);<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div style="width:1000px; height:1000px; background-color:rebeccapurple; color:#FFF">
<p style="position: fixed;"></p>
</div>answered Nov 12 at 10:06
Glitcher
951513
add a comment |
up vote
0
down vote
Create your single function but store the previous X and Y scroll positions so you can see if they've changed between calls:
var scrollY = 0;
var scrollX = 0;
function onScroll(){
var doc = document.documentElement;
if(doc.scrollLeft !== scrollX) {
scrollX = doc.scrollLeft;
//Put behaviour for X scroll here
$("p").text("X SCROLLED!");
}
if(doc.scrollTop !== scrollY) {
scrollY = doc.scrollTop;
//Put behaviour for Y scroll here
$("p").text("Y SCROLLED!");
}
}
window.addEventListener('scroll', onScroll);<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div style="width:1000px; height:1000px; background-color:rebeccapurple; color:#FFF">
<p style="position: fixed;"></p>
</div>answered Nov 12 at 10:06
Glitcher
951513
add a comment |
up vote
0
down vote
up vote
0
down vote
Create your single function but store the previous X and Y scroll positions so you can see if they've changed between calls:
var scrollY = 0;
var scrollX = 0;
function onScroll(){
var doc = document.documentElement;
if(doc.scrollLeft !== scrollX) {
scrollX = doc.scrollLeft;
//Put behaviour for X scroll here
$("p").text("X SCROLLED!");
}
if(doc.scrollTop !== scrollY) {
scrollY = doc.scrollTop;
//Put behaviour for Y scroll here
$("p").text("Y SCROLLED!");
}
}
window.addEventListener('scroll', onScroll);<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div style="width:1000px; height:1000px; background-color:rebeccapurple; color:#FFF">
<p style="position: fixed;"></p>
</div>answered Nov 12 at 10:06
Glitcher
951513
Create your single function but store the previous X and Y scroll positions so you can see if they've changed between calls:
var scrollY = 0;
var scrollX = 0;
function onScroll(){
var doc = document.documentElement;
if(doc.scrollLeft !== scrollX) {
scrollX = doc.scrollLeft;
//Put behaviour for X scroll here
$("p").text("X SCROLLED!");
}
if(doc.scrollTop !== scrollY) {
scrollY = doc.scrollTop;
//Put behaviour for Y scroll here
$("p").text("Y SCROLLED!");
}
}
window.addEventListener('scroll', onScroll);<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div style="width:1000px; height:1000px; background-color:rebeccapurple; color:#FFF">
<p style="position: fixed;"></p>
</div>var scrollY = 0;
var scrollX = 0;
function onScroll(){
var doc = document.documentElement;
if(doc.scrollLeft !== scrollX) {
scrollX = doc.scrollLeft;
//Put behaviour for X scroll here
$("p").text("X SCROLLED!");
}
if(doc.scrollTop !== scrollY) {
scrollY = doc.scrollTop;
//Put behaviour for Y scroll here
$("p").text("Y SCROLLED!");
}
}
window.addEventListener('scroll', onScroll);<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div style="width:1000px; height:1000px; background-color:rebeccapurple; color:#FFF">
<p style="position: fixed;"></p>
</div>var scrollY = 0;
var scrollX = 0;
function onScroll(){
var doc = document.documentElement;
if(doc.scrollLeft !== scrollX) {
scrollX = doc.scrollLeft;
//Put behaviour for X scroll here
$("p").text("X SCROLLED!");
}
if(doc.scrollTop !== scrollY) {
scrollY = doc.scrollTop;
//Put behaviour for Y scroll here
$("p").text("Y SCROLLED!");
}
}
window.addEventListener('scroll', onScroll);<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div style="width:1000px; height:1000px; background-color:rebeccapurple; color:#FFF">
<p style="position: fixed;"></p>
</div>answered Nov 12 at 10:06
Glitcher
951513
edited Nov 12 at 10:12
answered Nov 12 at 10:06
Glitcher
951513
answered Nov 12 at 10:06
Glitcher
951513
answered Nov 12 at 10:06
Glitcher
951513
951513
add a comment |
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53258982%2fhow-to-listen-scroll-event-for-x-scroll-and-y-scroll-individually%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Put them in the same event handler, call 2 functions based on the condition whether there was a vertical scroll or a horizontal one.
– Dennis Lukas
Nov 12 at 9:56