Es6: Create an array of objects from a json
0
I have a json in the below format.
[
{"id": 1,
"name": "peter" },
{"id": 2,
"name": "john" },
{"id": 3,
"name": "justin" }
.
.
{"id": 500,
"name": "david" },
]
I am trying to create an array in batches of 10 in the below format
[
{
{"id": 1,
"name": "peter" },
.
.
{"id": 10,
"name": "nixon" },
},
{
{"id": 11,
"name": "nancy" },
.
.
{"id": 20,
"name": "underwood" },
}
.
.
]
I tried using reduce and tried for loop to loop through it, but was unsuccessful
ecmascript-6
asked Nov 12 at 14:13
indra257
150428
add a comment |
0
I have a json in the below format.
[
{"id": 1,
"name": "peter" },
{"id": 2,
"name": "john" },
{"id": 3,
"name": "justin" }
.
.
{"id": 500,
"name": "david" },
]
I am trying to create an array in batches of 10 in the below format
[
{
{"id": 1,
"name": "peter" },
.
.
{"id": 10,
"name": "nixon" },
},
{
{"id": 11,
"name": "nancy" },
.
.
{"id": 20,
"name": "underwood" },
}
.
.
]
I tried using reduce and tried for loop to loop through it, but was unsuccessful
ecmascript-6
asked Nov 12 at 14:13
indra257
150428
1
Possible duplicate of Splitting a JS array into N arrays
– k0pernikus
Nov 12 at 14:21
stackoverflow.com/q/8495687/457268
– k0pernikus
Nov 12 at 14:23
Objects should have key value pairs. You cannot put another object inside{}without a key.
– Dinesh Pandiyan
Nov 13 at 13:59
add a comment |
0
0
0
I have a json in the below format.
[
{"id": 1,
"name": "peter" },
{"id": 2,
"name": "john" },
{"id": 3,
"name": "justin" }
.
.
{"id": 500,
"name": "david" },
]
I am trying to create an array in batches of 10 in the below format
[
{
{"id": 1,
"name": "peter" },
.
.
{"id": 10,
"name": "nixon" },
},
{
{"id": 11,
"name": "nancy" },
.
.
{"id": 20,
"name": "underwood" },
}
.
.
]
I tried using reduce and tried for loop to loop through it, but was unsuccessful
ecmascript-6
asked Nov 12 at 14:13
indra257
150428
I have a json in the below format.
[
{"id": 1,
"name": "peter" },
{"id": 2,
"name": "john" },
{"id": 3,
"name": "justin" }
.
.
{"id": 500,
"name": "david" },
]
I am trying to create an array in batches of 10 in the below format
[
{
{"id": 1,
"name": "peter" },
.
.
{"id": 10,
"name": "nixon" },
},
{
{"id": 11,
"name": "nancy" },
.
.
{"id": 20,
"name": "underwood" },
}
.
.
]
I tried using reduce and tried for loop to loop through it, but was unsuccessful
ecmascript-6
ecmascript-6
asked Nov 12 at 14:13
indra257
150428
asked Nov 12 at 14:13
indra257
150428
asked Nov 12 at 14:13
indra257
150428
asked Nov 12 at 14:13
indra257
150428
asked Nov 12 at 14:13
indra257
150428
150428
1
Possible duplicate of Splitting a JS array into N arrays
– k0pernikus
Nov 12 at 14:21
stackoverflow.com/q/8495687/457268
– k0pernikus
Nov 12 at 14:23
Objects should have key value pairs. You cannot put another object inside{}without a key.
– Dinesh Pandiyan
Nov 13 at 13:59
add a comment |
1
Possible duplicate of Splitting a JS array into N arrays
– k0pernikus
Nov 12 at 14:21
stackoverflow.com/q/8495687/457268
– k0pernikus
Nov 12 at 14:23
Objects should have key value pairs. You cannot put another object inside{}without a key.
– Dinesh Pandiyan
Nov 13 at 13:59
1
1
Possible duplicate of Splitting a JS array into N arrays
– k0pernikus
Nov 12 at 14:21
Possible duplicate of Splitting a JS array into N arrays
– k0pernikus
Nov 12 at 14:21
stackoverflow.com/q/8495687/457268
– k0pernikus
Nov 12 at 14:23
stackoverflow.com/q/8495687/457268
– k0pernikus
Nov 12 at 14:23
Objects should have key value pairs. You cannot put another object inside
{} without a key.– Dinesh Pandiyan
Nov 13 at 13:59
Objects should have key value pairs. You cannot put another object inside
{} without a key.– Dinesh Pandiyan
Nov 13 at 13:59
add a comment |
1 Answer
1
active
oldest
votes
0
Here's a demo.
const str = "abcdefghigklmnopqrstuvwxyz";
let data = ;
for(let i = 0; i < 26; i++){
data.push({id : i, name: str.charAt(i)});
}
let res = data.reduce((acc, d) => {
let groupId = Math.floor(d.id / 10);
acc[groupId] = acc[groupId] || {};
acc[groupId][d.id] = d;
return acc;
}, {});
console.log(Object.values(res));If you can ensure that id is the same sequence as their position in array, i think simply slice will better.
answered Nov 13 at 13:51
user8510613
938
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
Here's a demo.
const str = "abcdefghigklmnopqrstuvwxyz";
let data = ;
for(let i = 0; i < 26; i++){
data.push({id : i, name: str.charAt(i)});
}
let res = data.reduce((acc, d) => {
let groupId = Math.floor(d.id / 10);
acc[groupId] = acc[groupId] || {};
acc[groupId][d.id] = d;
return acc;
}, {});
console.log(Object.values(res));If you can ensure that id is the same sequence as their position in array, i think simply slice will better.
answered Nov 13 at 13:51
user8510613
938
add a comment |
0
Here's a demo.
const str = "abcdefghigklmnopqrstuvwxyz";
let data = ;
for(let i = 0; i < 26; i++){
data.push({id : i, name: str.charAt(i)});
}
let res = data.reduce((acc, d) => {
let groupId = Math.floor(d.id / 10);
acc[groupId] = acc[groupId] || {};
acc[groupId][d.id] = d;
return acc;
}, {});
console.log(Object.values(res));If you can ensure that id is the same sequence as their position in array, i think simply slice will better.
answered Nov 13 at 13:51
user8510613
938
add a comment |
0
0
0
Here's a demo.
const str = "abcdefghigklmnopqrstuvwxyz";
let data = ;
for(let i = 0; i < 26; i++){
data.push({id : i, name: str.charAt(i)});
}
let res = data.reduce((acc, d) => {
let groupId = Math.floor(d.id / 10);
acc[groupId] = acc[groupId] || {};
acc[groupId][d.id] = d;
return acc;
}, {});
console.log(Object.values(res));If you can ensure that id is the same sequence as their position in array, i think simply slice will better.
answered Nov 13 at 13:51
user8510613
938
Here's a demo.
const str = "abcdefghigklmnopqrstuvwxyz";
let data = ;
for(let i = 0; i < 26; i++){
data.push({id : i, name: str.charAt(i)});
}
let res = data.reduce((acc, d) => {
let groupId = Math.floor(d.id / 10);
acc[groupId] = acc[groupId] || {};
acc[groupId][d.id] = d;
return acc;
}, {});
console.log(Object.values(res));If you can ensure that id is the same sequence as their position in array, i think simply slice will better.
const str = "abcdefghigklmnopqrstuvwxyz";
let data = ;
for(let i = 0; i < 26; i++){
data.push({id : i, name: str.charAt(i)});
}
let res = data.reduce((acc, d) => {
let groupId = Math.floor(d.id / 10);
acc[groupId] = acc[groupId] || {};
acc[groupId][d.id] = d;
return acc;
}, {});
console.log(Object.values(res));const str = "abcdefghigklmnopqrstuvwxyz";
let data = ;
for(let i = 0; i < 26; i++){
data.push({id : i, name: str.charAt(i)});
}
let res = data.reduce((acc, d) => {
let groupId = Math.floor(d.id / 10);
acc[groupId] = acc[groupId] || {};
acc[groupId][d.id] = d;
return acc;
}, {});
console.log(Object.values(res));answered Nov 13 at 13:51
user8510613
938
answered Nov 13 at 13:51
user8510613
938
answered Nov 13 at 13:51
user8510613
938
answered Nov 13 at 13:51
user8510613
938
938
add a comment |
add a comment |
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1
Possible duplicate of Splitting a JS array into N arrays
– k0pernikus
Nov 12 at 14:21
stackoverflow.com/q/8495687/457268
– k0pernikus
Nov 12 at 14:23
Objects should have key value pairs. You cannot put another object inside
{}without a key.– Dinesh Pandiyan
Nov 13 at 13:59