Dates aren't adjusting for timezone
INSPDATE is a datetime field in an MS SQL database. Normally when we pull in a date, the browser automatically corrects it to our EST, but it doesn't work on this inspection report I'm creating. I've tried
echo date('m/d/Y g:i a ', strtotime($row['INSPDATE']));
But that returns the date from 1970 (12/31/1969 7:00 pm) and isn't pulling in the value from the database.
Below is what I was using that returns the date just as it's saved in the db. I know there's a way to subtract 18000 to this to adjust to EST (-5 hrs), but I'm not sure where to put it. I get error messages about mixing up datetimes and non-numeric values.
<?php
require_once ('connection.php');
$sql = "SELECT INSPDATE, FACILID FROM dbo.SWFACILITYINSPECTION WHERE FACILID = 'E667'";
$query = sqlsrv_query( $conn, $sql );
while ($row=sqlsrv_fetch_array( $query )) {
//This will show dates, but it's database time (UTC, so +5 hours)
echo date_format($row['INSPDATE'], 'm/d/Y g:i a ');
}
?>
sql-server-2012 php-7
add a comment |
INSPDATE is a datetime field in an MS SQL database. Normally when we pull in a date, the browser automatically corrects it to our EST, but it doesn't work on this inspection report I'm creating. I've tried
echo date('m/d/Y g:i a ', strtotime($row['INSPDATE']));
But that returns the date from 1970 (12/31/1969 7:00 pm) and isn't pulling in the value from the database.
Below is what I was using that returns the date just as it's saved in the db. I know there's a way to subtract 18000 to this to adjust to EST (-5 hrs), but I'm not sure where to put it. I get error messages about mixing up datetimes and non-numeric values.
<?php
require_once ('connection.php');
$sql = "SELECT INSPDATE, FACILID FROM dbo.SWFACILITYINSPECTION WHERE FACILID = 'E667'";
$query = sqlsrv_query( $conn, $sql );
while ($row=sqlsrv_fetch_array( $query )) {
//This will show dates, but it's database time (UTC, so +5 hours)
echo date_format($row['INSPDATE'], 'm/d/Y g:i a ');
}
?>
sql-server-2012 php-7
You probably don't want to hard code the offset because it almost always fluctuates.
– Ross Bush
Nov 12 at 14:21
You mean fluctuating for like daylight saving time? It doesn't actually matter that much. These are inspection reports for a small county government. They just need something more accurate than +5 hours.
– KVarney
Nov 12 at 14:35
add a comment |
INSPDATE is a datetime field in an MS SQL database. Normally when we pull in a date, the browser automatically corrects it to our EST, but it doesn't work on this inspection report I'm creating. I've tried
echo date('m/d/Y g:i a ', strtotime($row['INSPDATE']));
But that returns the date from 1970 (12/31/1969 7:00 pm) and isn't pulling in the value from the database.
Below is what I was using that returns the date just as it's saved in the db. I know there's a way to subtract 18000 to this to adjust to EST (-5 hrs), but I'm not sure where to put it. I get error messages about mixing up datetimes and non-numeric values.
<?php
require_once ('connection.php');
$sql = "SELECT INSPDATE, FACILID FROM dbo.SWFACILITYINSPECTION WHERE FACILID = 'E667'";
$query = sqlsrv_query( $conn, $sql );
while ($row=sqlsrv_fetch_array( $query )) {
//This will show dates, but it's database time (UTC, so +5 hours)
echo date_format($row['INSPDATE'], 'm/d/Y g:i a ');
}
?>
sql-server-2012 php-7
INSPDATE is a datetime field in an MS SQL database. Normally when we pull in a date, the browser automatically corrects it to our EST, but it doesn't work on this inspection report I'm creating. I've tried
echo date('m/d/Y g:i a ', strtotime($row['INSPDATE']));
But that returns the date from 1970 (12/31/1969 7:00 pm) and isn't pulling in the value from the database.
Below is what I was using that returns the date just as it's saved in the db. I know there's a way to subtract 18000 to this to adjust to EST (-5 hrs), but I'm not sure where to put it. I get error messages about mixing up datetimes and non-numeric values.
<?php
require_once ('connection.php');
$sql = "SELECT INSPDATE, FACILID FROM dbo.SWFACILITYINSPECTION WHERE FACILID = 'E667'";
$query = sqlsrv_query( $conn, $sql );
while ($row=sqlsrv_fetch_array( $query )) {
//This will show dates, but it's database time (UTC, so +5 hours)
echo date_format($row['INSPDATE'], 'm/d/Y g:i a ');
}
?>
sql-server-2012 php-7
sql-server-2012 php-7
asked Nov 12 at 14:15
KVarney
156
156
You probably don't want to hard code the offset because it almost always fluctuates.
– Ross Bush
Nov 12 at 14:21
You mean fluctuating for like daylight saving time? It doesn't actually matter that much. These are inspection reports for a small county government. They just need something more accurate than +5 hours.
– KVarney
Nov 12 at 14:35
add a comment |
You probably don't want to hard code the offset because it almost always fluctuates.
– Ross Bush
Nov 12 at 14:21
You mean fluctuating for like daylight saving time? It doesn't actually matter that much. These are inspection reports for a small county government. They just need something more accurate than +5 hours.
– KVarney
Nov 12 at 14:35
You probably don't want to hard code the offset because it almost always fluctuates.
– Ross Bush
Nov 12 at 14:21
You probably don't want to hard code the offset because it almost always fluctuates.
– Ross Bush
Nov 12 at 14:21
You mean fluctuating for like daylight saving time? It doesn't actually matter that much. These are inspection reports for a small county government. They just need something more accurate than +5 hours.
– KVarney
Nov 12 at 14:35
You mean fluctuating for like daylight saving time? It doesn't actually matter that much. These are inspection reports for a small county government. They just need something more accurate than +5 hours.
– KVarney
Nov 12 at 14:35
add a comment |
1 Answer
1
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oldest
votes
You should always do this conversion in application logic, since your sql is inline, I suppose you could embed the calculation in your sql. If I knew PHP better, I would be more inclined to learn the date math using the language of the application, that way you could build a time zone library to use on dates elsewhere and free your queries,store procedures up to be, just queries and stored procedures that return data.
DECLARE @Offset INT = -5
SELECT INSPDATE_UTC=INSPDATE, INSPDATE_LOCAL = DATEADD(HOUR, @Offset,INSPDATE)
Thank you! This was perfect!
– KVarney
Nov 13 at 16:00
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
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oldest
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active
oldest
votes
You should always do this conversion in application logic, since your sql is inline, I suppose you could embed the calculation in your sql. If I knew PHP better, I would be more inclined to learn the date math using the language of the application, that way you could build a time zone library to use on dates elsewhere and free your queries,store procedures up to be, just queries and stored procedures that return data.
DECLARE @Offset INT = -5
SELECT INSPDATE_UTC=INSPDATE, INSPDATE_LOCAL = DATEADD(HOUR, @Offset,INSPDATE)
Thank you! This was perfect!
– KVarney
Nov 13 at 16:00
add a comment |
You should always do this conversion in application logic, since your sql is inline, I suppose you could embed the calculation in your sql. If I knew PHP better, I would be more inclined to learn the date math using the language of the application, that way you could build a time zone library to use on dates elsewhere and free your queries,store procedures up to be, just queries and stored procedures that return data.
DECLARE @Offset INT = -5
SELECT INSPDATE_UTC=INSPDATE, INSPDATE_LOCAL = DATEADD(HOUR, @Offset,INSPDATE)
Thank you! This was perfect!
– KVarney
Nov 13 at 16:00
add a comment |
You should always do this conversion in application logic, since your sql is inline, I suppose you could embed the calculation in your sql. If I knew PHP better, I would be more inclined to learn the date math using the language of the application, that way you could build a time zone library to use on dates elsewhere and free your queries,store procedures up to be, just queries and stored procedures that return data.
DECLARE @Offset INT = -5
SELECT INSPDATE_UTC=INSPDATE, INSPDATE_LOCAL = DATEADD(HOUR, @Offset,INSPDATE)
You should always do this conversion in application logic, since your sql is inline, I suppose you could embed the calculation in your sql. If I knew PHP better, I would be more inclined to learn the date math using the language of the application, that way you could build a time zone library to use on dates elsewhere and free your queries,store procedures up to be, just queries and stored procedures that return data.
DECLARE @Offset INT = -5
SELECT INSPDATE_UTC=INSPDATE, INSPDATE_LOCAL = DATEADD(HOUR, @Offset,INSPDATE)
answered Nov 12 at 14:41
Ross Bush
10.8k21941
10.8k21941
Thank you! This was perfect!
– KVarney
Nov 13 at 16:00
add a comment |
Thank you! This was perfect!
– KVarney
Nov 13 at 16:00
Thank you! This was perfect!
– KVarney
Nov 13 at 16:00
Thank you! This was perfect!
– KVarney
Nov 13 at 16:00
add a comment |
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You probably don't want to hard code the offset because it almost always fluctuates.
– Ross Bush
Nov 12 at 14:21
You mean fluctuating for like daylight saving time? It doesn't actually matter that much. These are inspection reports for a small county government. They just need something more accurate than +5 hours.
– KVarney
Nov 12 at 14:35