merge values in column in a row with the quotes separator “|”, based on a comparison with the values of...











up vote
1
down vote

favorite
1












as the title suggests I'm trying to find a way to treat some data in a spreadsheet to google app.
I think the best way is to directly set an example and thank you in advance for your support as always.



simply:



sheet1 (colA, colB)

sheet2 (colA', colB')

sheet1
colA colB
1 xxx 40
2 xxx 42
3 yyy 42
4 yyy 44
. ... etc.


sheet2

colA' colB'

1 xxx 40 | 42

2 yyy 42 | 44

3 ... .. | .. (etc.)


I would be grateful for a hint of code to google app script.
thanks





EDIT (in progress)



hi,



I hope that by sharing the file answer your questions.



the sheet already exist, the code is written in part and I would need help on this.



there is no duplication in ColumnB for article xxx or yyy or zzz etc. ..



in sheet "sheet_demo" indicates that the script should be.



Spreadsheeet demo





function merge_col() {

var sheet = SpreadsheetApp.openById("0AiuqXkUqDMgzdFM5aVNxeEhPbWFmbGhybl9TVkt4ZWc");
var ss_sorg = sheet.getSheetByName('sheet1');
var ss_dest = sheet.getSheetByName('sheet2');

var sorg_data = ss_sorg.getRange("A2:C").getValues();
var dest_data = ss_dest.getRange("A2:C").getValues();
var dest_Cod = ;
var dest_Des = ;
var temp_Cod, temp_Des;

for (var i = 0; i < sorg_data.length; i++) {

temp_Cod = null;
temp_Des = null;

for (var j = 1; j < sorg_data.length; j++) {

if (sorg_data[i][0] == sorg_data[j][0].toString().match(sorg_data[i][0]) && sorg_data[i][0] != "") {

temp_Cod = sorg_data[i][1];
temp_Des = sorg_data[i][2];

break;
}
}

dest_Cod.push([temp_Cod]);
dest_Cod.join('|');
dest_Des.push([temp_Des]);
dest_Des.join('|');
}
if (dest_Cod.length > 0 || dest_Des.lenght > 0) {
ss_dest.getRange(2, 2, dest_Cod.length, 1).setValues(dest_Cod); Logger.log(dest_Cod)
ss_dest.getRange(2, 3, dest_Des.length, 1).setValues(dest_Des); Logger.log(dest_Des)
}
}


EDIT (FINAL)
TKS Serge!



function merge_col() {
var ss = SpreadsheetApp.getActive().getSheetByName('sheet1');
var data = ss.getDataRange().getValues();
var header = data.shift();
var col1 = data[1][0];
var col2 = '';
var col3 = '';
var dataSheet2 = [header];
for(var i=0 ; i<data.length ; i++){
Logger.log(data[i][0]+' - '+col1+' - '+data[i][2])
if(col1==data[i][0]){
col1 = data[i][0];
col2+=data[i][1]+' | ';
col3+=data[i][2]+' | ';
}else{
dataSheet2.push([col1,col2,col3]);
var col1 = data[i][0];
col2 = data[i][1]+' | ';
col3 = data[i][2]+' | ';
}
}
dataSheet2.push([col1,col2,col3]);
Logger.log(dataSheet2);
var sheet2 = SpreadsheetApp.getActiveSpreadsheet().getSheetByName('sheet2');
sheet2.clear();
sheet2.getRange(1, 1, dataSheet2.length, dataSheet2[0].length).setValues(dataSheet2);
}









share|improve this question
























  • Just a few questions: have you tried some code? Are there more than 2 occurrence of the same item xxx or yyy? Does sheet already exist?
    – Serge insas
    Feb 10 '14 at 16:42










  • Thanks, now it's perfectly clear :-)
    – Serge insas
    Feb 11 '14 at 6:35















up vote
1
down vote

favorite
1












as the title suggests I'm trying to find a way to treat some data in a spreadsheet to google app.
I think the best way is to directly set an example and thank you in advance for your support as always.



simply:



sheet1 (colA, colB)

sheet2 (colA', colB')

sheet1
colA colB
1 xxx 40
2 xxx 42
3 yyy 42
4 yyy 44
. ... etc.


sheet2

colA' colB'

1 xxx 40 | 42

2 yyy 42 | 44

3 ... .. | .. (etc.)


I would be grateful for a hint of code to google app script.
thanks





EDIT (in progress)



hi,



I hope that by sharing the file answer your questions.



the sheet already exist, the code is written in part and I would need help on this.



there is no duplication in ColumnB for article xxx or yyy or zzz etc. ..



in sheet "sheet_demo" indicates that the script should be.



Spreadsheeet demo





function merge_col() {

var sheet = SpreadsheetApp.openById("0AiuqXkUqDMgzdFM5aVNxeEhPbWFmbGhybl9TVkt4ZWc");
var ss_sorg = sheet.getSheetByName('sheet1');
var ss_dest = sheet.getSheetByName('sheet2');

var sorg_data = ss_sorg.getRange("A2:C").getValues();
var dest_data = ss_dest.getRange("A2:C").getValues();
var dest_Cod = ;
var dest_Des = ;
var temp_Cod, temp_Des;

for (var i = 0; i < sorg_data.length; i++) {

temp_Cod = null;
temp_Des = null;

for (var j = 1; j < sorg_data.length; j++) {

if (sorg_data[i][0] == sorg_data[j][0].toString().match(sorg_data[i][0]) && sorg_data[i][0] != "") {

temp_Cod = sorg_data[i][1];
temp_Des = sorg_data[i][2];

break;
}
}

dest_Cod.push([temp_Cod]);
dest_Cod.join('|');
dest_Des.push([temp_Des]);
dest_Des.join('|');
}
if (dest_Cod.length > 0 || dest_Des.lenght > 0) {
ss_dest.getRange(2, 2, dest_Cod.length, 1).setValues(dest_Cod); Logger.log(dest_Cod)
ss_dest.getRange(2, 3, dest_Des.length, 1).setValues(dest_Des); Logger.log(dest_Des)
}
}


EDIT (FINAL)
TKS Serge!



function merge_col() {
var ss = SpreadsheetApp.getActive().getSheetByName('sheet1');
var data = ss.getDataRange().getValues();
var header = data.shift();
var col1 = data[1][0];
var col2 = '';
var col3 = '';
var dataSheet2 = [header];
for(var i=0 ; i<data.length ; i++){
Logger.log(data[i][0]+' - '+col1+' - '+data[i][2])
if(col1==data[i][0]){
col1 = data[i][0];
col2+=data[i][1]+' | ';
col3+=data[i][2]+' | ';
}else{
dataSheet2.push([col1,col2,col3]);
var col1 = data[i][0];
col2 = data[i][1]+' | ';
col3 = data[i][2]+' | ';
}
}
dataSheet2.push([col1,col2,col3]);
Logger.log(dataSheet2);
var sheet2 = SpreadsheetApp.getActiveSpreadsheet().getSheetByName('sheet2');
sheet2.clear();
sheet2.getRange(1, 1, dataSheet2.length, dataSheet2[0].length).setValues(dataSheet2);
}









share|improve this question
























  • Just a few questions: have you tried some code? Are there more than 2 occurrence of the same item xxx or yyy? Does sheet already exist?
    – Serge insas
    Feb 10 '14 at 16:42










  • Thanks, now it's perfectly clear :-)
    – Serge insas
    Feb 11 '14 at 6:35













up vote
1
down vote

favorite
1









up vote
1
down vote

favorite
1






1





as the title suggests I'm trying to find a way to treat some data in a spreadsheet to google app.
I think the best way is to directly set an example and thank you in advance for your support as always.



simply:



sheet1 (colA, colB)

sheet2 (colA', colB')

sheet1
colA colB
1 xxx 40
2 xxx 42
3 yyy 42
4 yyy 44
. ... etc.


sheet2

colA' colB'

1 xxx 40 | 42

2 yyy 42 | 44

3 ... .. | .. (etc.)


I would be grateful for a hint of code to google app script.
thanks





EDIT (in progress)



hi,



I hope that by sharing the file answer your questions.



the sheet already exist, the code is written in part and I would need help on this.



there is no duplication in ColumnB for article xxx or yyy or zzz etc. ..



in sheet "sheet_demo" indicates that the script should be.



Spreadsheeet demo





function merge_col() {

var sheet = SpreadsheetApp.openById("0AiuqXkUqDMgzdFM5aVNxeEhPbWFmbGhybl9TVkt4ZWc");
var ss_sorg = sheet.getSheetByName('sheet1');
var ss_dest = sheet.getSheetByName('sheet2');

var sorg_data = ss_sorg.getRange("A2:C").getValues();
var dest_data = ss_dest.getRange("A2:C").getValues();
var dest_Cod = ;
var dest_Des = ;
var temp_Cod, temp_Des;

for (var i = 0; i < sorg_data.length; i++) {

temp_Cod = null;
temp_Des = null;

for (var j = 1; j < sorg_data.length; j++) {

if (sorg_data[i][0] == sorg_data[j][0].toString().match(sorg_data[i][0]) && sorg_data[i][0] != "") {

temp_Cod = sorg_data[i][1];
temp_Des = sorg_data[i][2];

break;
}
}

dest_Cod.push([temp_Cod]);
dest_Cod.join('|');
dest_Des.push([temp_Des]);
dest_Des.join('|');
}
if (dest_Cod.length > 0 || dest_Des.lenght > 0) {
ss_dest.getRange(2, 2, dest_Cod.length, 1).setValues(dest_Cod); Logger.log(dest_Cod)
ss_dest.getRange(2, 3, dest_Des.length, 1).setValues(dest_Des); Logger.log(dest_Des)
}
}


EDIT (FINAL)
TKS Serge!



function merge_col() {
var ss = SpreadsheetApp.getActive().getSheetByName('sheet1');
var data = ss.getDataRange().getValues();
var header = data.shift();
var col1 = data[1][0];
var col2 = '';
var col3 = '';
var dataSheet2 = [header];
for(var i=0 ; i<data.length ; i++){
Logger.log(data[i][0]+' - '+col1+' - '+data[i][2])
if(col1==data[i][0]){
col1 = data[i][0];
col2+=data[i][1]+' | ';
col3+=data[i][2]+' | ';
}else{
dataSheet2.push([col1,col2,col3]);
var col1 = data[i][0];
col2 = data[i][1]+' | ';
col3 = data[i][2]+' | ';
}
}
dataSheet2.push([col1,col2,col3]);
Logger.log(dataSheet2);
var sheet2 = SpreadsheetApp.getActiveSpreadsheet().getSheetByName('sheet2');
sheet2.clear();
sheet2.getRange(1, 1, dataSheet2.length, dataSheet2[0].length).setValues(dataSheet2);
}









share|improve this question















as the title suggests I'm trying to find a way to treat some data in a spreadsheet to google app.
I think the best way is to directly set an example and thank you in advance for your support as always.



simply:



sheet1 (colA, colB)

sheet2 (colA', colB')

sheet1
colA colB
1 xxx 40
2 xxx 42
3 yyy 42
4 yyy 44
. ... etc.


sheet2

colA' colB'

1 xxx 40 | 42

2 yyy 42 | 44

3 ... .. | .. (etc.)


I would be grateful for a hint of code to google app script.
thanks





EDIT (in progress)



hi,



I hope that by sharing the file answer your questions.



the sheet already exist, the code is written in part and I would need help on this.



there is no duplication in ColumnB for article xxx or yyy or zzz etc. ..



in sheet "sheet_demo" indicates that the script should be.



Spreadsheeet demo





function merge_col() {

var sheet = SpreadsheetApp.openById("0AiuqXkUqDMgzdFM5aVNxeEhPbWFmbGhybl9TVkt4ZWc");
var ss_sorg = sheet.getSheetByName('sheet1');
var ss_dest = sheet.getSheetByName('sheet2');

var sorg_data = ss_sorg.getRange("A2:C").getValues();
var dest_data = ss_dest.getRange("A2:C").getValues();
var dest_Cod = ;
var dest_Des = ;
var temp_Cod, temp_Des;

for (var i = 0; i < sorg_data.length; i++) {

temp_Cod = null;
temp_Des = null;

for (var j = 1; j < sorg_data.length; j++) {

if (sorg_data[i][0] == sorg_data[j][0].toString().match(sorg_data[i][0]) && sorg_data[i][0] != "") {

temp_Cod = sorg_data[i][1];
temp_Des = sorg_data[i][2];

break;
}
}

dest_Cod.push([temp_Cod]);
dest_Cod.join('|');
dest_Des.push([temp_Des]);
dest_Des.join('|');
}
if (dest_Cod.length > 0 || dest_Des.lenght > 0) {
ss_dest.getRange(2, 2, dest_Cod.length, 1).setValues(dest_Cod); Logger.log(dest_Cod)
ss_dest.getRange(2, 3, dest_Des.length, 1).setValues(dest_Des); Logger.log(dest_Des)
}
}


EDIT (FINAL)
TKS Serge!



function merge_col() {
var ss = SpreadsheetApp.getActive().getSheetByName('sheet1');
var data = ss.getDataRange().getValues();
var header = data.shift();
var col1 = data[1][0];
var col2 = '';
var col3 = '';
var dataSheet2 = [header];
for(var i=0 ; i<data.length ; i++){
Logger.log(data[i][0]+' - '+col1+' - '+data[i][2])
if(col1==data[i][0]){
col1 = data[i][0];
col2+=data[i][1]+' | ';
col3+=data[i][2]+' | ';
}else{
dataSheet2.push([col1,col2,col3]);
var col1 = data[i][0];
col2 = data[i][1]+' | ';
col3 = data[i][2]+' | ';
}
}
dataSheet2.push([col1,col2,col3]);
Logger.log(dataSheet2);
var sheet2 = SpreadsheetApp.getActiveSpreadsheet().getSheetByName('sheet2');
sheet2.clear();
sheet2.getRange(1, 1, dataSheet2.length, dataSheet2[0].length).setValues(dataSheet2);
}






google-apps-script google-sheets






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edited Nov 11 at 6:20









Cœur

17k9102140




17k9102140










asked Feb 10 '14 at 15:42









gigisan76

83




83












  • Just a few questions: have you tried some code? Are there more than 2 occurrence of the same item xxx or yyy? Does sheet already exist?
    – Serge insas
    Feb 10 '14 at 16:42










  • Thanks, now it's perfectly clear :-)
    – Serge insas
    Feb 11 '14 at 6:35


















  • Just a few questions: have you tried some code? Are there more than 2 occurrence of the same item xxx or yyy? Does sheet already exist?
    – Serge insas
    Feb 10 '14 at 16:42










  • Thanks, now it's perfectly clear :-)
    – Serge insas
    Feb 11 '14 at 6:35
















Just a few questions: have you tried some code? Are there more than 2 occurrence of the same item xxx or yyy? Does sheet already exist?
– Serge insas
Feb 10 '14 at 16:42




Just a few questions: have you tried some code? Are there more than 2 occurrence of the same item xxx or yyy? Does sheet already exist?
– Serge insas
Feb 10 '14 at 16:42












Thanks, now it's perfectly clear :-)
– Serge insas
Feb 11 '14 at 6:35




Thanks, now it's perfectly clear :-)
– Serge insas
Feb 11 '14 at 6:35












2 Answers
2






active

oldest

votes

















up vote
0
down vote



accepted










Here is a code that does exactly what you expected using a simple loop and a comparison.



function merge_col() {
var ss = SpreadsheetApp.getActive().getSheetByName('sheet1');
var data = ss.getDataRange().getValues();
var header = data.shift();
var col1 = data[1][0];
var col2 = '';
var col3 = '';
var dataSheet2 = [header];
for(var i=0 ; i<data.length ; i++){
Logger.log(data[i][0]+' - '+col1+' - '+data[i][2])
if(col1==data[i][0]){
col1 = data[i][0];
col2+=data[i][1]+' | ';
col3+=data[i][2]+' | ';
}else{
dataSheet2.push([col1,col2,col3]);
var col1 = data[i][0];
col2 = data[i][1]+' | ';
col3 = data[i][2]+' | ';
}
}
dataSheet2.push([col1,col2,col3]);
Logger.log(dataSheet2);
var sheet2 = SpreadsheetApp.getActiveSpreadsheet().getSheetByName('sheet2');
sheet2.clear();
sheet2.getRange(1, 1, dataSheet2.length, dataSheet2[0].length).setValues(dataSheet2);
}





share|improve this answer





















  • excellent, it works fine. tks!
    – gigisan76
    Feb 11 '14 at 10:35










  • you're welcome, don't forget to mark as answered :-)
    – Serge insas
    Feb 11 '14 at 10:38


















up vote
0
down vote













have a look at this post, he want to do almost the same. Modifying 2 lines of the code and it's done:



function myFunction() {
var objList={};
var ss = SpreadsheetApp.getActive().getActiveSheet();
var data = ss.getDataRange().getValues();
for(var i in data){
// for(var j in data[i]){
if(typeof objList[data[i][0]]=="undefined"){
objList[data[i][0]]=; // new array
objList[data[i][0]].push(data[i][1]); // push the value of the second column
}
else{
objList[data[i][0]].push(data[i][1]);
}
//}
}
var objTable=;
for(var k in objList){
objTable.push([k,objList[k]]);
}
Logger.log(objTable);
ss.clear();
ss.getRange(1, 1, objTable.length, objTable[0].length).setValues(objTable);
}





share|improve this answer























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    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    0
    down vote



    accepted










    Here is a code that does exactly what you expected using a simple loop and a comparison.



    function merge_col() {
    var ss = SpreadsheetApp.getActive().getSheetByName('sheet1');
    var data = ss.getDataRange().getValues();
    var header = data.shift();
    var col1 = data[1][0];
    var col2 = '';
    var col3 = '';
    var dataSheet2 = [header];
    for(var i=0 ; i<data.length ; i++){
    Logger.log(data[i][0]+' - '+col1+' - '+data[i][2])
    if(col1==data[i][0]){
    col1 = data[i][0];
    col2+=data[i][1]+' | ';
    col3+=data[i][2]+' | ';
    }else{
    dataSheet2.push([col1,col2,col3]);
    var col1 = data[i][0];
    col2 = data[i][1]+' | ';
    col3 = data[i][2]+' | ';
    }
    }
    dataSheet2.push([col1,col2,col3]);
    Logger.log(dataSheet2);
    var sheet2 = SpreadsheetApp.getActiveSpreadsheet().getSheetByName('sheet2');
    sheet2.clear();
    sheet2.getRange(1, 1, dataSheet2.length, dataSheet2[0].length).setValues(dataSheet2);
    }





    share|improve this answer





















    • excellent, it works fine. tks!
      – gigisan76
      Feb 11 '14 at 10:35










    • you're welcome, don't forget to mark as answered :-)
      – Serge insas
      Feb 11 '14 at 10:38















    up vote
    0
    down vote



    accepted










    Here is a code that does exactly what you expected using a simple loop and a comparison.



    function merge_col() {
    var ss = SpreadsheetApp.getActive().getSheetByName('sheet1');
    var data = ss.getDataRange().getValues();
    var header = data.shift();
    var col1 = data[1][0];
    var col2 = '';
    var col3 = '';
    var dataSheet2 = [header];
    for(var i=0 ; i<data.length ; i++){
    Logger.log(data[i][0]+' - '+col1+' - '+data[i][2])
    if(col1==data[i][0]){
    col1 = data[i][0];
    col2+=data[i][1]+' | ';
    col3+=data[i][2]+' | ';
    }else{
    dataSheet2.push([col1,col2,col3]);
    var col1 = data[i][0];
    col2 = data[i][1]+' | ';
    col3 = data[i][2]+' | ';
    }
    }
    dataSheet2.push([col1,col2,col3]);
    Logger.log(dataSheet2);
    var sheet2 = SpreadsheetApp.getActiveSpreadsheet().getSheetByName('sheet2');
    sheet2.clear();
    sheet2.getRange(1, 1, dataSheet2.length, dataSheet2[0].length).setValues(dataSheet2);
    }





    share|improve this answer





















    • excellent, it works fine. tks!
      – gigisan76
      Feb 11 '14 at 10:35










    • you're welcome, don't forget to mark as answered :-)
      – Serge insas
      Feb 11 '14 at 10:38













    up vote
    0
    down vote



    accepted







    up vote
    0
    down vote



    accepted






    Here is a code that does exactly what you expected using a simple loop and a comparison.



    function merge_col() {
    var ss = SpreadsheetApp.getActive().getSheetByName('sheet1');
    var data = ss.getDataRange().getValues();
    var header = data.shift();
    var col1 = data[1][0];
    var col2 = '';
    var col3 = '';
    var dataSheet2 = [header];
    for(var i=0 ; i<data.length ; i++){
    Logger.log(data[i][0]+' - '+col1+' - '+data[i][2])
    if(col1==data[i][0]){
    col1 = data[i][0];
    col2+=data[i][1]+' | ';
    col3+=data[i][2]+' | ';
    }else{
    dataSheet2.push([col1,col2,col3]);
    var col1 = data[i][0];
    col2 = data[i][1]+' | ';
    col3 = data[i][2]+' | ';
    }
    }
    dataSheet2.push([col1,col2,col3]);
    Logger.log(dataSheet2);
    var sheet2 = SpreadsheetApp.getActiveSpreadsheet().getSheetByName('sheet2');
    sheet2.clear();
    sheet2.getRange(1, 1, dataSheet2.length, dataSheet2[0].length).setValues(dataSheet2);
    }





    share|improve this answer












    Here is a code that does exactly what you expected using a simple loop and a comparison.



    function merge_col() {
    var ss = SpreadsheetApp.getActive().getSheetByName('sheet1');
    var data = ss.getDataRange().getValues();
    var header = data.shift();
    var col1 = data[1][0];
    var col2 = '';
    var col3 = '';
    var dataSheet2 = [header];
    for(var i=0 ; i<data.length ; i++){
    Logger.log(data[i][0]+' - '+col1+' - '+data[i][2])
    if(col1==data[i][0]){
    col1 = data[i][0];
    col2+=data[i][1]+' | ';
    col3+=data[i][2]+' | ';
    }else{
    dataSheet2.push([col1,col2,col3]);
    var col1 = data[i][0];
    col2 = data[i][1]+' | ';
    col3 = data[i][2]+' | ';
    }
    }
    dataSheet2.push([col1,col2,col3]);
    Logger.log(dataSheet2);
    var sheet2 = SpreadsheetApp.getActiveSpreadsheet().getSheetByName('sheet2');
    sheet2.clear();
    sheet2.getRange(1, 1, dataSheet2.length, dataSheet2[0].length).setValues(dataSheet2);
    }






    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered Feb 11 '14 at 9:41









    Serge insas

    34.8k45387




    34.8k45387












    • excellent, it works fine. tks!
      – gigisan76
      Feb 11 '14 at 10:35










    • you're welcome, don't forget to mark as answered :-)
      – Serge insas
      Feb 11 '14 at 10:38


















    • excellent, it works fine. tks!
      – gigisan76
      Feb 11 '14 at 10:35










    • you're welcome, don't forget to mark as answered :-)
      – Serge insas
      Feb 11 '14 at 10:38
















    excellent, it works fine. tks!
    – gigisan76
    Feb 11 '14 at 10:35




    excellent, it works fine. tks!
    – gigisan76
    Feb 11 '14 at 10:35












    you're welcome, don't forget to mark as answered :-)
    – Serge insas
    Feb 11 '14 at 10:38




    you're welcome, don't forget to mark as answered :-)
    – Serge insas
    Feb 11 '14 at 10:38












    up vote
    0
    down vote













    have a look at this post, he want to do almost the same. Modifying 2 lines of the code and it's done:



    function myFunction() {
    var objList={};
    var ss = SpreadsheetApp.getActive().getActiveSheet();
    var data = ss.getDataRange().getValues();
    for(var i in data){
    // for(var j in data[i]){
    if(typeof objList[data[i][0]]=="undefined"){
    objList[data[i][0]]=; // new array
    objList[data[i][0]].push(data[i][1]); // push the value of the second column
    }
    else{
    objList[data[i][0]].push(data[i][1]);
    }
    //}
    }
    var objTable=;
    for(var k in objList){
    objTable.push([k,objList[k]]);
    }
    Logger.log(objTable);
    ss.clear();
    ss.getRange(1, 1, objTable.length, objTable[0].length).setValues(objTable);
    }





    share|improve this answer



























      up vote
      0
      down vote













      have a look at this post, he want to do almost the same. Modifying 2 lines of the code and it's done:



      function myFunction() {
      var objList={};
      var ss = SpreadsheetApp.getActive().getActiveSheet();
      var data = ss.getDataRange().getValues();
      for(var i in data){
      // for(var j in data[i]){
      if(typeof objList[data[i][0]]=="undefined"){
      objList[data[i][0]]=; // new array
      objList[data[i][0]].push(data[i][1]); // push the value of the second column
      }
      else{
      objList[data[i][0]].push(data[i][1]);
      }
      //}
      }
      var objTable=;
      for(var k in objList){
      objTable.push([k,objList[k]]);
      }
      Logger.log(objTable);
      ss.clear();
      ss.getRange(1, 1, objTable.length, objTable[0].length).setValues(objTable);
      }





      share|improve this answer

























        up vote
        0
        down vote










        up vote
        0
        down vote









        have a look at this post, he want to do almost the same. Modifying 2 lines of the code and it's done:



        function myFunction() {
        var objList={};
        var ss = SpreadsheetApp.getActive().getActiveSheet();
        var data = ss.getDataRange().getValues();
        for(var i in data){
        // for(var j in data[i]){
        if(typeof objList[data[i][0]]=="undefined"){
        objList[data[i][0]]=; // new array
        objList[data[i][0]].push(data[i][1]); // push the value of the second column
        }
        else{
        objList[data[i][0]].push(data[i][1]);
        }
        //}
        }
        var objTable=;
        for(var k in objList){
        objTable.push([k,objList[k]]);
        }
        Logger.log(objTable);
        ss.clear();
        ss.getRange(1, 1, objTable.length, objTable[0].length).setValues(objTable);
        }





        share|improve this answer














        have a look at this post, he want to do almost the same. Modifying 2 lines of the code and it's done:



        function myFunction() {
        var objList={};
        var ss = SpreadsheetApp.getActive().getActiveSheet();
        var data = ss.getDataRange().getValues();
        for(var i in data){
        // for(var j in data[i]){
        if(typeof objList[data[i][0]]=="undefined"){
        objList[data[i][0]]=; // new array
        objList[data[i][0]].push(data[i][1]); // push the value of the second column
        }
        else{
        objList[data[i][0]].push(data[i][1]);
        }
        //}
        }
        var objTable=;
        for(var k in objList){
        objTable.push([k,objList[k]]);
        }
        Logger.log(objTable);
        ss.clear();
        ss.getRange(1, 1, objTable.length, objTable[0].length).setValues(objTable);
        }






        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited May 23 '17 at 11:44









        Community

        11




        11










        answered Feb 11 '14 at 6:50









        Harold

        2,82711423




        2,82711423






























             

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