Struggling with Join with and





.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ height:90px;width:728px;box-sizing:border-box;
}







0















I am trying to get the account number for a product by joining a table.



https://www.db-fiddle.com/f/q6GJFqFqrNrDgMd3fnmEwG/3



My account table is structured like:



| account_no | line_number | content |
| ---------- | ----------- | ------- |
| CQ01 | 5 | CUST1 |
| CQ01 | 6 | Q |
| CQ88 | 5 | CUST1 |
| CQ88 | 6 | P |
| CQ22 | 5 | CUST2 |
| CQ22 | 6 | P |


My product table is structured like



| warehouse | product | customer | location |
| --------- | ------- | -------- | -------- |
| 55 | ABC DEF | CUST1 | P |


My query I have built is



select p.*, a.account_no from products p
left join accounts a on
(a.content = p.customer and a.line_number = 5)
and
(a.content = p.location and a.line_number = 6);


unfortunately results in a NULL for account_no



| warehouse | product | customer | location | account_no |
| --------- | ------- | -------- | -------- | ---------- |
| 55 | ABC DEF | CUST1 | P | |


which is not the result I am after.



What am I doing wrong?



Thanks



EDIT:



My expected output would be:



| warehouse | product | customer | location | account_no |
| --------- | ------- | -------- | -------- | ---------- |
| 55 | ABC DEF | CUST1 | P | CQ88 |


As my accounts table only has account_no = 'CQ88' when line_number 5 is 'CUST1' and line_number 6 = 'P'










share|improve this question




















  • 1





    Please share your expected output.

    – Mayank Porwal
    Nov 16 '18 at 11:28











  • You need to join accounts twice, once for each line number.

    – dnoeth
    Nov 16 '18 at 11:28











  • db-fiddle.com/f/s6B4jcyhMtvGHCvp8FD5A3/0

    – dnoeth
    Nov 16 '18 at 11:35











  • @Ian go for my answer

    – Ravi
    Nov 16 '18 at 11:44




















0















I am trying to get the account number for a product by joining a table.



https://www.db-fiddle.com/f/q6GJFqFqrNrDgMd3fnmEwG/3



My account table is structured like:



| account_no | line_number | content |
| ---------- | ----------- | ------- |
| CQ01 | 5 | CUST1 |
| CQ01 | 6 | Q |
| CQ88 | 5 | CUST1 |
| CQ88 | 6 | P |
| CQ22 | 5 | CUST2 |
| CQ22 | 6 | P |


My product table is structured like



| warehouse | product | customer | location |
| --------- | ------- | -------- | -------- |
| 55 | ABC DEF | CUST1 | P |


My query I have built is



select p.*, a.account_no from products p
left join accounts a on
(a.content = p.customer and a.line_number = 5)
and
(a.content = p.location and a.line_number = 6);


unfortunately results in a NULL for account_no



| warehouse | product | customer | location | account_no |
| --------- | ------- | -------- | -------- | ---------- |
| 55 | ABC DEF | CUST1 | P | |


which is not the result I am after.



What am I doing wrong?



Thanks



EDIT:



My expected output would be:



| warehouse | product | customer | location | account_no |
| --------- | ------- | -------- | -------- | ---------- |
| 55 | ABC DEF | CUST1 | P | CQ88 |


As my accounts table only has account_no = 'CQ88' when line_number 5 is 'CUST1' and line_number 6 = 'P'










share|improve this question




















  • 1





    Please share your expected output.

    – Mayank Porwal
    Nov 16 '18 at 11:28











  • You need to join accounts twice, once for each line number.

    – dnoeth
    Nov 16 '18 at 11:28











  • db-fiddle.com/f/s6B4jcyhMtvGHCvp8FD5A3/0

    – dnoeth
    Nov 16 '18 at 11:35











  • @Ian go for my answer

    – Ravi
    Nov 16 '18 at 11:44
















0












0








0








I am trying to get the account number for a product by joining a table.



https://www.db-fiddle.com/f/q6GJFqFqrNrDgMd3fnmEwG/3



My account table is structured like:



| account_no | line_number | content |
| ---------- | ----------- | ------- |
| CQ01 | 5 | CUST1 |
| CQ01 | 6 | Q |
| CQ88 | 5 | CUST1 |
| CQ88 | 6 | P |
| CQ22 | 5 | CUST2 |
| CQ22 | 6 | P |


My product table is structured like



| warehouse | product | customer | location |
| --------- | ------- | -------- | -------- |
| 55 | ABC DEF | CUST1 | P |


My query I have built is



select p.*, a.account_no from products p
left join accounts a on
(a.content = p.customer and a.line_number = 5)
and
(a.content = p.location and a.line_number = 6);


unfortunately results in a NULL for account_no



| warehouse | product | customer | location | account_no |
| --------- | ------- | -------- | -------- | ---------- |
| 55 | ABC DEF | CUST1 | P | |


which is not the result I am after.



What am I doing wrong?



Thanks



EDIT:



My expected output would be:



| warehouse | product | customer | location | account_no |
| --------- | ------- | -------- | -------- | ---------- |
| 55 | ABC DEF | CUST1 | P | CQ88 |


As my accounts table only has account_no = 'CQ88' when line_number 5 is 'CUST1' and line_number 6 = 'P'










share|improve this question
















I am trying to get the account number for a product by joining a table.



https://www.db-fiddle.com/f/q6GJFqFqrNrDgMd3fnmEwG/3



My account table is structured like:



| account_no | line_number | content |
| ---------- | ----------- | ------- |
| CQ01 | 5 | CUST1 |
| CQ01 | 6 | Q |
| CQ88 | 5 | CUST1 |
| CQ88 | 6 | P |
| CQ22 | 5 | CUST2 |
| CQ22 | 6 | P |


My product table is structured like



| warehouse | product | customer | location |
| --------- | ------- | -------- | -------- |
| 55 | ABC DEF | CUST1 | P |


My query I have built is



select p.*, a.account_no from products p
left join accounts a on
(a.content = p.customer and a.line_number = 5)
and
(a.content = p.location and a.line_number = 6);


unfortunately results in a NULL for account_no



| warehouse | product | customer | location | account_no |
| --------- | ------- | -------- | -------- | ---------- |
| 55 | ABC DEF | CUST1 | P | |


which is not the result I am after.



What am I doing wrong?



Thanks



EDIT:



My expected output would be:



| warehouse | product | customer | location | account_no |
| --------- | ------- | -------- | -------- | ---------- |
| 55 | ABC DEF | CUST1 | P | CQ88 |


As my accounts table only has account_no = 'CQ88' when line_number 5 is 'CUST1' and line_number 6 = 'P'







sql






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 16 '18 at 11:40







Ian

















asked Nov 16 '18 at 11:26









IanIan

556




556








  • 1





    Please share your expected output.

    – Mayank Porwal
    Nov 16 '18 at 11:28











  • You need to join accounts twice, once for each line number.

    – dnoeth
    Nov 16 '18 at 11:28











  • db-fiddle.com/f/s6B4jcyhMtvGHCvp8FD5A3/0

    – dnoeth
    Nov 16 '18 at 11:35











  • @Ian go for my answer

    – Ravi
    Nov 16 '18 at 11:44
















  • 1





    Please share your expected output.

    – Mayank Porwal
    Nov 16 '18 at 11:28











  • You need to join accounts twice, once for each line number.

    – dnoeth
    Nov 16 '18 at 11:28











  • db-fiddle.com/f/s6B4jcyhMtvGHCvp8FD5A3/0

    – dnoeth
    Nov 16 '18 at 11:35











  • @Ian go for my answer

    – Ravi
    Nov 16 '18 at 11:44










1




1





Please share your expected output.

– Mayank Porwal
Nov 16 '18 at 11:28





Please share your expected output.

– Mayank Porwal
Nov 16 '18 at 11:28













You need to join accounts twice, once for each line number.

– dnoeth
Nov 16 '18 at 11:28





You need to join accounts twice, once for each line number.

– dnoeth
Nov 16 '18 at 11:28













db-fiddle.com/f/s6B4jcyhMtvGHCvp8FD5A3/0

– dnoeth
Nov 16 '18 at 11:35





db-fiddle.com/f/s6B4jcyhMtvGHCvp8FD5A3/0

– dnoeth
Nov 16 '18 at 11:35













@Ian go for my answer

– Ravi
Nov 16 '18 at 11:44







@Ian go for my answer

– Ravi
Nov 16 '18 at 11:44














4 Answers
4






active

oldest

votes


















0














The problem is with your ON conditions:



(a.content = p.customer and a.line_number = 5)
and
(a.content = p.location and a.line_number = 6);


Since you have used an AND operator, so both conditions need to be True for a match to be found. And there's no single row in Accounts table having line number both 5 and 6.



So, change and to or. It should solve your issue.



Let me know if it works.






share|improve this answer































    0














    I am guessing you want two joins:



    select p.*,
    a5.account_no as customer_account_no,
    a6.account_no as location_account_no
    from products p left join
    accounts a5
    on a5.content = p.customer and
    a5.line_number = 5 left join
    accounts a6
    on a6.content = p.location and
    a6.line_number = 6;





    share|improve this answer































      0














      I solved it.



      I needed to re-structure my accounts table so there were one row per account_no



      https://www.db-fiddle.com/f/q6GJFqFqrNrDgMd3fnmEwG/6



      I then performed a simple join



      select p.*, new_accounts.account_no from products p
      left join (
      select distinct a.account_no, concat(b.content , '-',c.content) as 'custloc' from accounts a
      left join (select * from accounts where line_number = 5) b on a.account_no = b.account_no
      left join (select * from accounts where line_number = 6) c on a.account_no = c.account_no
      ) new_accounts ON concat(p.customer,'-',p.location) = new_accounts.custloc;


      resulted in



      | warehouse | product | customer | location | account_no |
      | --------- | ------- | -------- | -------- | ---------- |
      | 55 | ABC DEF | CUST1 | P | CQ88 |





      share|improve this answer































        -1














        select p.*, a.account_no from products p
        inner join accounts a on
        (a.content = p.customer and a.line_number = 5)
        inner join accounts b on
        (b.content = p.location and b.line_number = 6) and a.account_no = b.account_no





        share|improve this answer
























        • Thanks, sadly this picks up two rows. It results with an account_no "CQ01" which is not what I need. In my accounts table, CQ01 has a reference to CUST1 and location "Q", but my product is looking for CUST1 and location "P"

          – Ian
          Nov 16 '18 at 11:50











        • Not possible to return two rows

          – Ravi
          Nov 16 '18 at 11:57











        • What does that do? How does it answer the question? Don't just blurt out code. Explain yourself ! stackoverflow.com/help/how-to-answer

          – Rob
          Nov 16 '18 at 12:13












        Your Answer






        StackExchange.ifUsing("editor", function () {
        StackExchange.using("externalEditor", function () {
        StackExchange.using("snippets", function () {
        StackExchange.snippets.init();
        });
        });
        }, "code-snippets");

        StackExchange.ready(function() {
        var channelOptions = {
        tags: "".split(" "),
        id: "1"
        };
        initTagRenderer("".split(" "), "".split(" "), channelOptions);

        StackExchange.using("externalEditor", function() {
        // Have to fire editor after snippets, if snippets enabled
        if (StackExchange.settings.snippets.snippetsEnabled) {
        StackExchange.using("snippets", function() {
        createEditor();
        });
        }
        else {
        createEditor();
        }
        });

        function createEditor() {
        StackExchange.prepareEditor({
        heartbeatType: 'answer',
        autoActivateHeartbeat: false,
        convertImagesToLinks: true,
        noModals: true,
        showLowRepImageUploadWarning: true,
        reputationToPostImages: 10,
        bindNavPrevention: true,
        postfix: "",
        imageUploader: {
        brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
        contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
        allowUrls: true
        },
        onDemand: true,
        discardSelector: ".discard-answer"
        ,immediatelyShowMarkdownHelp:true
        });


        }
        });














        draft saved

        draft discarded


















        StackExchange.ready(
        function () {
        StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53336949%2fstruggling-with-join-with-and%23new-answer', 'question_page');
        }
        );

        Post as a guest















        Required, but never shown

























        4 Answers
        4






        active

        oldest

        votes








        4 Answers
        4






        active

        oldest

        votes









        active

        oldest

        votes






        active

        oldest

        votes









        0














        The problem is with your ON conditions:



        (a.content = p.customer and a.line_number = 5)
        and
        (a.content = p.location and a.line_number = 6);


        Since you have used an AND operator, so both conditions need to be True for a match to be found. And there's no single row in Accounts table having line number both 5 and 6.



        So, change and to or. It should solve your issue.



        Let me know if it works.






        share|improve this answer




























          0














          The problem is with your ON conditions:



          (a.content = p.customer and a.line_number = 5)
          and
          (a.content = p.location and a.line_number = 6);


          Since you have used an AND operator, so both conditions need to be True for a match to be found. And there's no single row in Accounts table having line number both 5 and 6.



          So, change and to or. It should solve your issue.



          Let me know if it works.






          share|improve this answer


























            0












            0








            0







            The problem is with your ON conditions:



            (a.content = p.customer and a.line_number = 5)
            and
            (a.content = p.location and a.line_number = 6);


            Since you have used an AND operator, so both conditions need to be True for a match to be found. And there's no single row in Accounts table having line number both 5 and 6.



            So, change and to or. It should solve your issue.



            Let me know if it works.






            share|improve this answer













            The problem is with your ON conditions:



            (a.content = p.customer and a.line_number = 5)
            and
            (a.content = p.location and a.line_number = 6);


            Since you have used an AND operator, so both conditions need to be True for a match to be found. And there's no single row in Accounts table having line number both 5 and 6.



            So, change and to or. It should solve your issue.



            Let me know if it works.







            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered Nov 16 '18 at 11:32









            Mayank PorwalMayank Porwal

            5,0182725




            5,0182725

























                0














                I am guessing you want two joins:



                select p.*,
                a5.account_no as customer_account_no,
                a6.account_no as location_account_no
                from products p left join
                accounts a5
                on a5.content = p.customer and
                a5.line_number = 5 left join
                accounts a6
                on a6.content = p.location and
                a6.line_number = 6;





                share|improve this answer




























                  0














                  I am guessing you want two joins:



                  select p.*,
                  a5.account_no as customer_account_no,
                  a6.account_no as location_account_no
                  from products p left join
                  accounts a5
                  on a5.content = p.customer and
                  a5.line_number = 5 left join
                  accounts a6
                  on a6.content = p.location and
                  a6.line_number = 6;





                  share|improve this answer


























                    0












                    0








                    0







                    I am guessing you want two joins:



                    select p.*,
                    a5.account_no as customer_account_no,
                    a6.account_no as location_account_no
                    from products p left join
                    accounts a5
                    on a5.content = p.customer and
                    a5.line_number = 5 left join
                    accounts a6
                    on a6.content = p.location and
                    a6.line_number = 6;





                    share|improve this answer













                    I am guessing you want two joins:



                    select p.*,
                    a5.account_no as customer_account_no,
                    a6.account_no as location_account_no
                    from products p left join
                    accounts a5
                    on a5.content = p.customer and
                    a5.line_number = 5 left join
                    accounts a6
                    on a6.content = p.location and
                    a6.line_number = 6;






                    share|improve this answer












                    share|improve this answer



                    share|improve this answer










                    answered Nov 16 '18 at 11:34









                    Gordon LinoffGordon Linoff

                    794k37318421




                    794k37318421























                        0














                        I solved it.



                        I needed to re-structure my accounts table so there were one row per account_no



                        https://www.db-fiddle.com/f/q6GJFqFqrNrDgMd3fnmEwG/6



                        I then performed a simple join



                        select p.*, new_accounts.account_no from products p
                        left join (
                        select distinct a.account_no, concat(b.content , '-',c.content) as 'custloc' from accounts a
                        left join (select * from accounts where line_number = 5) b on a.account_no = b.account_no
                        left join (select * from accounts where line_number = 6) c on a.account_no = c.account_no
                        ) new_accounts ON concat(p.customer,'-',p.location) = new_accounts.custloc;


                        resulted in



                        | warehouse | product | customer | location | account_no |
                        | --------- | ------- | -------- | -------- | ---------- |
                        | 55 | ABC DEF | CUST1 | P | CQ88 |





                        share|improve this answer




























                          0














                          I solved it.



                          I needed to re-structure my accounts table so there were one row per account_no



                          https://www.db-fiddle.com/f/q6GJFqFqrNrDgMd3fnmEwG/6



                          I then performed a simple join



                          select p.*, new_accounts.account_no from products p
                          left join (
                          select distinct a.account_no, concat(b.content , '-',c.content) as 'custloc' from accounts a
                          left join (select * from accounts where line_number = 5) b on a.account_no = b.account_no
                          left join (select * from accounts where line_number = 6) c on a.account_no = c.account_no
                          ) new_accounts ON concat(p.customer,'-',p.location) = new_accounts.custloc;


                          resulted in



                          | warehouse | product | customer | location | account_no |
                          | --------- | ------- | -------- | -------- | ---------- |
                          | 55 | ABC DEF | CUST1 | P | CQ88 |





                          share|improve this answer


























                            0












                            0








                            0







                            I solved it.



                            I needed to re-structure my accounts table so there were one row per account_no



                            https://www.db-fiddle.com/f/q6GJFqFqrNrDgMd3fnmEwG/6



                            I then performed a simple join



                            select p.*, new_accounts.account_no from products p
                            left join (
                            select distinct a.account_no, concat(b.content , '-',c.content) as 'custloc' from accounts a
                            left join (select * from accounts where line_number = 5) b on a.account_no = b.account_no
                            left join (select * from accounts where line_number = 6) c on a.account_no = c.account_no
                            ) new_accounts ON concat(p.customer,'-',p.location) = new_accounts.custloc;


                            resulted in



                            | warehouse | product | customer | location | account_no |
                            | --------- | ------- | -------- | -------- | ---------- |
                            | 55 | ABC DEF | CUST1 | P | CQ88 |





                            share|improve this answer













                            I solved it.



                            I needed to re-structure my accounts table so there were one row per account_no



                            https://www.db-fiddle.com/f/q6GJFqFqrNrDgMd3fnmEwG/6



                            I then performed a simple join



                            select p.*, new_accounts.account_no from products p
                            left join (
                            select distinct a.account_no, concat(b.content , '-',c.content) as 'custloc' from accounts a
                            left join (select * from accounts where line_number = 5) b on a.account_no = b.account_no
                            left join (select * from accounts where line_number = 6) c on a.account_no = c.account_no
                            ) new_accounts ON concat(p.customer,'-',p.location) = new_accounts.custloc;


                            resulted in



                            | warehouse | product | customer | location | account_no |
                            | --------- | ------- | -------- | -------- | ---------- |
                            | 55 | ABC DEF | CUST1 | P | CQ88 |






                            share|improve this answer












                            share|improve this answer



                            share|improve this answer










                            answered Nov 16 '18 at 12:12









                            IanIan

                            556




                            556























                                -1














                                select p.*, a.account_no from products p
                                inner join accounts a on
                                (a.content = p.customer and a.line_number = 5)
                                inner join accounts b on
                                (b.content = p.location and b.line_number = 6) and a.account_no = b.account_no





                                share|improve this answer
























                                • Thanks, sadly this picks up two rows. It results with an account_no "CQ01" which is not what I need. In my accounts table, CQ01 has a reference to CUST1 and location "Q", but my product is looking for CUST1 and location "P"

                                  – Ian
                                  Nov 16 '18 at 11:50











                                • Not possible to return two rows

                                  – Ravi
                                  Nov 16 '18 at 11:57











                                • What does that do? How does it answer the question? Don't just blurt out code. Explain yourself ! stackoverflow.com/help/how-to-answer

                                  – Rob
                                  Nov 16 '18 at 12:13
















                                -1














                                select p.*, a.account_no from products p
                                inner join accounts a on
                                (a.content = p.customer and a.line_number = 5)
                                inner join accounts b on
                                (b.content = p.location and b.line_number = 6) and a.account_no = b.account_no





                                share|improve this answer
























                                • Thanks, sadly this picks up two rows. It results with an account_no "CQ01" which is not what I need. In my accounts table, CQ01 has a reference to CUST1 and location "Q", but my product is looking for CUST1 and location "P"

                                  – Ian
                                  Nov 16 '18 at 11:50











                                • Not possible to return two rows

                                  – Ravi
                                  Nov 16 '18 at 11:57











                                • What does that do? How does it answer the question? Don't just blurt out code. Explain yourself ! stackoverflow.com/help/how-to-answer

                                  – Rob
                                  Nov 16 '18 at 12:13














                                -1












                                -1








                                -1







                                select p.*, a.account_no from products p
                                inner join accounts a on
                                (a.content = p.customer and a.line_number = 5)
                                inner join accounts b on
                                (b.content = p.location and b.line_number = 6) and a.account_no = b.account_no





                                share|improve this answer













                                select p.*, a.account_no from products p
                                inner join accounts a on
                                (a.content = p.customer and a.line_number = 5)
                                inner join accounts b on
                                (b.content = p.location and b.line_number = 6) and a.account_no = b.account_no






                                share|improve this answer












                                share|improve this answer



                                share|improve this answer










                                answered Nov 16 '18 at 11:42









                                RaviRavi

                                9821315




                                9821315













                                • Thanks, sadly this picks up two rows. It results with an account_no "CQ01" which is not what I need. In my accounts table, CQ01 has a reference to CUST1 and location "Q", but my product is looking for CUST1 and location "P"

                                  – Ian
                                  Nov 16 '18 at 11:50











                                • Not possible to return two rows

                                  – Ravi
                                  Nov 16 '18 at 11:57











                                • What does that do? How does it answer the question? Don't just blurt out code. Explain yourself ! stackoverflow.com/help/how-to-answer

                                  – Rob
                                  Nov 16 '18 at 12:13



















                                • Thanks, sadly this picks up two rows. It results with an account_no "CQ01" which is not what I need. In my accounts table, CQ01 has a reference to CUST1 and location "Q", but my product is looking for CUST1 and location "P"

                                  – Ian
                                  Nov 16 '18 at 11:50











                                • Not possible to return two rows

                                  – Ravi
                                  Nov 16 '18 at 11:57











                                • What does that do? How does it answer the question? Don't just blurt out code. Explain yourself ! stackoverflow.com/help/how-to-answer

                                  – Rob
                                  Nov 16 '18 at 12:13

















                                Thanks, sadly this picks up two rows. It results with an account_no "CQ01" which is not what I need. In my accounts table, CQ01 has a reference to CUST1 and location "Q", but my product is looking for CUST1 and location "P"

                                – Ian
                                Nov 16 '18 at 11:50





                                Thanks, sadly this picks up two rows. It results with an account_no "CQ01" which is not what I need. In my accounts table, CQ01 has a reference to CUST1 and location "Q", but my product is looking for CUST1 and location "P"

                                – Ian
                                Nov 16 '18 at 11:50













                                Not possible to return two rows

                                – Ravi
                                Nov 16 '18 at 11:57





                                Not possible to return two rows

                                – Ravi
                                Nov 16 '18 at 11:57













                                What does that do? How does it answer the question? Don't just blurt out code. Explain yourself ! stackoverflow.com/help/how-to-answer

                                – Rob
                                Nov 16 '18 at 12:13





                                What does that do? How does it answer the question? Don't just blurt out code. Explain yourself ! stackoverflow.com/help/how-to-answer

                                – Rob
                                Nov 16 '18 at 12:13


















                                draft saved

                                draft discarded




















































                                Thanks for contributing an answer to Stack Overflow!


                                • Please be sure to answer the question. Provide details and share your research!

                                But avoid



                                • Asking for help, clarification, or responding to other answers.

                                • Making statements based on opinion; back them up with references or personal experience.


                                To learn more, see our tips on writing great answers.




                                draft saved


                                draft discarded














                                StackExchange.ready(
                                function () {
                                StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53336949%2fstruggling-with-join-with-and%23new-answer', 'question_page');
                                }
                                );

                                Post as a guest















                                Required, but never shown





















































                                Required, but never shown














                                Required, but never shown












                                Required, but never shown







                                Required, but never shown

































                                Required, but never shown














                                Required, but never shown












                                Required, but never shown







                                Required, but never shown







                                Popular posts from this blog

                                List item for chat from Array inside array React Native

                                Thiostrepton

                                Caerphilly