How can is sum up an input range of numbers?

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Dear stackoverflow community!

I just started learning python and want to figure out how to write following program:`

number = int(input('Enter ten numbers:'))

for i in range(1, 10):

  while True:

    try:

      number = int(input("Enter another number: "))

      break

    except:

      print("This is a string") 

for i in range(1, 10):

  res = 0

  res += int(input())

  print('The sum of these 10 numbers is:', res)

I want the user to input 10 numbers and during the process I want to check if the numbers are actually integers. So the number input works, it checks if its an integer, but then how can make this work at the same time? (To sum up the 10 integers that I got as input) :

for i in range(1, 10):

  res = 0

  res += int(input())

  print('The sum of these 10 numbers is:', res)

So basically i want two conditions for those 10 numbers that I got as Input.

Thanks for your help.

asked Nov 16 '18 at 12:22

Proiegomena

3

you need to define res = 0 before the loop

– Chris_Rands
Nov 16 '18 at 12:24

You only need to loop once, not twice. Are you sure you know what input does? You seem to treat it as a storage variable of some kind.

– usr2564301
Nov 16 '18 at 12:25

1

range(1, 10) are only 9 values, since the "end" argument is not inclusive. Also you overwrite the value of your single variable number, you don't store the numbers anywhere. You also don't handle the error when the first input is not a number, since it is outside of try ... except.

– Christian König
Nov 16 '18 at 12:26

thanks for the input guys; I did know that looping twice doesnt work, I just wanted to visualize that I want to do 2 things with this loop basically x) @Chris_Rands; can you maybe elaborate?

– Proiegomena
Nov 16 '18 at 13:47

add a comment |

Dear stackoverflow community!

I just started learning python and want to figure out how to write following program:`

number = int(input('Enter ten numbers:'))

for i in range(1, 10):

  while True:

    try:

      number = int(input("Enter another number: "))

      break

    except:

      print("This is a string") 

for i in range(1, 10):

  res = 0

  res += int(input())

  print('The sum of these 10 numbers is:', res)

for i in range(1, 10):

  res = 0

  res += int(input())

  print('The sum of these 10 numbers is:', res)

So basically i want two conditions for those 10 numbers that I got as Input.

Thanks for your help.

asked Nov 16 '18 at 12:22

Proiegomena

3

you need to define res = 0 before the loop

– Chris_Rands
Nov 16 '18 at 12:24

You only need to loop once, not twice. Are you sure you know what input does? You seem to treat it as a storage variable of some kind.

– usr2564301
Nov 16 '18 at 12:25

1

range(1, 10) are only 9 values, since the "end" argument is not inclusive. Also you overwrite the value of your single variable number, you don't store the numbers anywhere. You also don't handle the error when the first input is not a number, since it is outside of try ... except.

– Christian König
Nov 16 '18 at 12:26

thanks for the input guys; I did know that looping twice doesnt work, I just wanted to visualize that I want to do 2 things with this loop basically x) @Chris_Rands; can you maybe elaborate?

– Proiegomena
Nov 16 '18 at 13:47

add a comment |

Dear stackoverflow community!

I just started learning python and want to figure out how to write following program:`

number = int(input('Enter ten numbers:'))

for i in range(1, 10):

  while True:

    try:

      number = int(input("Enter another number: "))

      break

    except:

      print("This is a string") 

for i in range(1, 10):

  res = 0

  res += int(input())

  print('The sum of these 10 numbers is:', res)

for i in range(1, 10):

  res = 0

  res += int(input())

  print('The sum of these 10 numbers is:', res)

So basically i want two conditions for those 10 numbers that I got as Input.

Thanks for your help.

asked Nov 16 '18 at 12:22

Proiegomena

Dear stackoverflow community!

I just started learning python and want to figure out how to write following program:`

number = int(input('Enter ten numbers:'))

for i in range(1, 10):

  while True:

    try:

      number = int(input("Enter another number: "))

      break

    except:

      print("This is a string") 

for i in range(1, 10):

  res = 0

  res += int(input())

  print('The sum of these 10 numbers is:', res)

for i in range(1, 10):

  res = 0

  res += int(input())

  print('The sum of these 10 numbers is:', res)

So basically i want two conditions for those 10 numbers that I got as Input.

Thanks for your help.

python sum range

asked Nov 16 '18 at 12:22

Proiegomena

asked Nov 16 '18 at 12:22

Proiegomena

asked Nov 16 '18 at 12:22

Proiegomena

asked Nov 16 '18 at 12:22

Proiegomena

asked Nov 16 '18 at 12:22

Proiegomena

3

you need to define res = 0 before the loop

– Chris_Rands
Nov 16 '18 at 12:24

You only need to loop once, not twice. Are you sure you know what input does? You seem to treat it as a storage variable of some kind.

– usr2564301
Nov 16 '18 at 12:25

1

range(1, 10) are only 9 values, since the "end" argument is not inclusive. Also you overwrite the value of your single variable number, you don't store the numbers anywhere. You also don't handle the error when the first input is not a number, since it is outside of try ... except.

– Christian König
Nov 16 '18 at 12:26

thanks for the input guys; I did know that looping twice doesnt work, I just wanted to visualize that I want to do 2 things with this loop basically x) @Chris_Rands; can you maybe elaborate?

– Proiegomena
Nov 16 '18 at 13:47

add a comment |

3

you need to define res = 0 before the loop

– Chris_Rands
Nov 16 '18 at 12:24

You only need to loop once, not twice. Are you sure you know what input does? You seem to treat it as a storage variable of some kind.

– usr2564301
Nov 16 '18 at 12:25

1

range(1, 10) are only 9 values, since the "end" argument is not inclusive. Also you overwrite the value of your single variable number, you don't store the numbers anywhere. You also don't handle the error when the first input is not a number, since it is outside of try ... except.

– Christian König
Nov 16 '18 at 12:26

thanks for the input guys; I did know that looping twice doesnt work, I just wanted to visualize that I want to do 2 things with this loop basically x) @Chris_Rands; can you maybe elaborate?

– Proiegomena
Nov 16 '18 at 13:47

you need to define res = 0 before the loop

– Chris_Rands
Nov 16 '18 at 12:24

You only need to loop once, not twice. Are you sure you know what input does? You seem to treat it as a storage variable of some kind.

– usr2564301
Nov 16 '18 at 12:25

range(1, 10) are only 9 values, since the "end" argument is not inclusive. Also you overwrite the value of your single variable number, you don't store the numbers anywhere. You also don't handle the error when the first input is not a number, since it is outside of try ... except.

– Christian König
Nov 16 '18 at 12:26

thanks for the input guys; I did know that looping twice doesnt work, I just wanted to visualize that I want to do 2 things with this loop basically x) @Chris_Rands; can you maybe elaborate?

– Proiegomena
Nov 16 '18 at 13:47

add a comment |

1 Answer
1

active

oldest

votes

You are simply checking the user input, not storing it somewhere. Use this instead:

numbers = 

while len(numbers) != 10:

    try:

      numbers.append(int(input("Enter another number: ")))

    except ValueError:

      print("This is not an integer!") 



res = sum(numbers)

print('The sum of these 10 numbers is: {}'.format(res))

answered Nov 16 '18 at 12:26

Ev. Kounis

11.4k21751

sum is of course the way to go, but you might point out the error in the OP's loop based summing.

– schwobaseggl
Nov 16 '18 at 12:36

oh yea, this approach with list makes way more sense. Thanks! I suppose I do know that I cant loop twice with for i in range(); however I did hope there's an easy solution how to add summing the parts to the "check if its an integer" loop.

– Proiegomena
Nov 16 '18 at 13:44

add a comment |

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1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

You are simply checking the user input, not storing it somewhere. Use this instead:

numbers = 

while len(numbers) != 10:

    try:

      numbers.append(int(input("Enter another number: ")))

    except ValueError:

      print("This is not an integer!") 



res = sum(numbers)

print('The sum of these 10 numbers is: {}'.format(res))

answered Nov 16 '18 at 12:26

Ev. Kounis

11.4k21751

sum is of course the way to go, but you might point out the error in the OP's loop based summing.

– schwobaseggl
Nov 16 '18 at 12:36

oh yea, this approach with list makes way more sense. Thanks! I suppose I do know that I cant loop twice with for i in range(); however I did hope there's an easy solution how to add summing the parts to the "check if its an integer" loop.

– Proiegomena
Nov 16 '18 at 13:44

add a comment |

You are simply checking the user input, not storing it somewhere. Use this instead:

numbers = 

while len(numbers) != 10:

    try:

      numbers.append(int(input("Enter another number: ")))

    except ValueError:

      print("This is not an integer!") 



res = sum(numbers)

print('The sum of these 10 numbers is: {}'.format(res))

answered Nov 16 '18 at 12:26

Ev. Kounis

11.4k21751

sum is of course the way to go, but you might point out the error in the OP's loop based summing.

– schwobaseggl
Nov 16 '18 at 12:36

oh yea, this approach with list makes way more sense. Thanks! I suppose I do know that I cant loop twice with for i in range(); however I did hope there's an easy solution how to add summing the parts to the "check if its an integer" loop.

– Proiegomena
Nov 16 '18 at 13:44

add a comment |

You are simply checking the user input, not storing it somewhere. Use this instead:

numbers = 

while len(numbers) != 10:

    try:

      numbers.append(int(input("Enter another number: ")))

    except ValueError:

      print("This is not an integer!") 



res = sum(numbers)

print('The sum of these 10 numbers is: {}'.format(res))

answered Nov 16 '18 at 12:26

Ev. Kounis

11.4k21751

You are simply checking the user input, not storing it somewhere. Use this instead:

numbers = 

while len(numbers) != 10:

    try:

      numbers.append(int(input("Enter another number: ")))

    except ValueError:

      print("This is not an integer!") 



res = sum(numbers)

print('The sum of these 10 numbers is: {}'.format(res))

answered Nov 16 '18 at 12:26

Ev. Kounis

11.4k21751

answered Nov 16 '18 at 12:26

Ev. Kounis

11.4k21751

answered Nov 16 '18 at 12:26

Ev. Kounis

11.4k21751

answered Nov 16 '18 at 12:26

Ev. Kounis

11.4k21751

sum is of course the way to go, but you might point out the error in the OP's loop based summing.

– schwobaseggl
Nov 16 '18 at 12:36

oh yea, this approach with list makes way more sense. Thanks! I suppose I do know that I cant loop twice with for i in range(); however I did hope there's an easy solution how to add summing the parts to the "check if its an integer" loop.

– Proiegomena
Nov 16 '18 at 13:44

add a comment |

sum is of course the way to go, but you might point out the error in the OP's loop based summing.

– schwobaseggl
Nov 16 '18 at 12:36

oh yea, this approach with list makes way more sense. Thanks! I suppose I do know that I cant loop twice with for i in range(); however I did hope there's an easy solution how to add summing the parts to the "check if its an integer" loop.

– Proiegomena
Nov 16 '18 at 13:44

sum is of course the way to go, but you might point out the error in the OP's loop based summing.

– schwobaseggl
Nov 16 '18 at 12:36

oh yea, this approach with list makes way more sense. Thanks! I suppose I do know that I cant loop twice with for i in range(); however I did hope there's an easy solution how to add summing the parts to the "check if its an integer" loop.

– Proiegomena
Nov 16 '18 at 13:44

add a comment |

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