Index out of range error even though number of values matches number of rows





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I'm trying to set some images to image views in a tableview, and I have the number of rows set to return keys.count, which after printing is confirmed to be 5, which is perfect.



Now in cellForRowAt I get the images in an array, then attempt to set the images to my cell's image view.



override func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
if indexPath.section == 0 {
let cell = tableView.dequeueReusableCell(withIdentifier: "stockCell", for: indexPath) as! StockCell

let stock = stockData[keys[indexPath.row]]!

var images = [String]()
stock.news.forEach { images.append($0.image) }
print("nnNumber of Images: (images.count)nnn")

if let companyImageUrl = URL(string: images[indexPath.row]) {
ImageService.getImage(url: companyImageUrl) { (image) in
cell.companyLogoImageView.image = image
}
}

return cell
}
}


I put a print statement in there to print the images.count (there should be 5), but the console shows 2, then 5 (x3), then 2 again - this is causing the index out of range error presumably, it's seeing 2 when there should be 5:



enter image description here



Why is images.count showing 2 in the first and last spots, but 5 in the rest?



EDIT: Rest of code



Fetching the data (in viewDidLoad):



    fetchData(url: stockApiUrl) { (result: FetchResult<[String:Stock]>) -> (Void) in
switch result {
case .success(let object):
self.stockData = object
self.keys = Array(object.keys)
print("stockData: nn(self.stockData)")
case .failure(let error):
print("Error decoding JSON: nn(error)")
}
DispatchQueue.main.async {
self.tableView.reloadData()
}
}


Data is set to a dictionary, with a separate array for the keys:



var stockData = [String:Stock]()
var keys = [String]()


Structs for decoding JSON:



struct Welcome: Decodable {
let aapl, fb, msft, tsla, goog: Stock

enum CodingKeys: String, CodingKey {
case aapl = "AAPL"
case fb = "FB"
case msft = "MSFT"
case tsla = "TSLA"
case goog = "GOOG"
}
}

struct Stock: Decodable {
let quote: Quote
let news: [News]
}

struct Quote: Decodable {
let symbol: String
let companyName: String
let latestPrice: Double
}

struct News: Decodable {
let url: String
let image: String
}









share|improve this question

























  • I don't get it, how are we supposed to know what stock.news contains?

    – Joakim Danielson
    Nov 16 '18 at 17:45











  • Sorry I wasn't sure if that part was necessary, I edited my question to add the rest of the code.

    – KingTim
    Nov 16 '18 at 17:48


















0















I'm trying to set some images to image views in a tableview, and I have the number of rows set to return keys.count, which after printing is confirmed to be 5, which is perfect.



Now in cellForRowAt I get the images in an array, then attempt to set the images to my cell's image view.



override func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
if indexPath.section == 0 {
let cell = tableView.dequeueReusableCell(withIdentifier: "stockCell", for: indexPath) as! StockCell

let stock = stockData[keys[indexPath.row]]!

var images = [String]()
stock.news.forEach { images.append($0.image) }
print("nnNumber of Images: (images.count)nnn")

if let companyImageUrl = URL(string: images[indexPath.row]) {
ImageService.getImage(url: companyImageUrl) { (image) in
cell.companyLogoImageView.image = image
}
}

return cell
}
}


I put a print statement in there to print the images.count (there should be 5), but the console shows 2, then 5 (x3), then 2 again - this is causing the index out of range error presumably, it's seeing 2 when there should be 5:



enter image description here



Why is images.count showing 2 in the first and last spots, but 5 in the rest?



EDIT: Rest of code



Fetching the data (in viewDidLoad):



    fetchData(url: stockApiUrl) { (result: FetchResult<[String:Stock]>) -> (Void) in
switch result {
case .success(let object):
self.stockData = object
self.keys = Array(object.keys)
print("stockData: nn(self.stockData)")
case .failure(let error):
print("Error decoding JSON: nn(error)")
}
DispatchQueue.main.async {
self.tableView.reloadData()
}
}


Data is set to a dictionary, with a separate array for the keys:



var stockData = [String:Stock]()
var keys = [String]()


Structs for decoding JSON:



struct Welcome: Decodable {
let aapl, fb, msft, tsla, goog: Stock

enum CodingKeys: String, CodingKey {
case aapl = "AAPL"
case fb = "FB"
case msft = "MSFT"
case tsla = "TSLA"
case goog = "GOOG"
}
}

struct Stock: Decodable {
let quote: Quote
let news: [News]
}

struct Quote: Decodable {
let symbol: String
let companyName: String
let latestPrice: Double
}

struct News: Decodable {
let url: String
let image: String
}









share|improve this question

























  • I don't get it, how are we supposed to know what stock.news contains?

    – Joakim Danielson
    Nov 16 '18 at 17:45











  • Sorry I wasn't sure if that part was necessary, I edited my question to add the rest of the code.

    – KingTim
    Nov 16 '18 at 17:48














0












0








0








I'm trying to set some images to image views in a tableview, and I have the number of rows set to return keys.count, which after printing is confirmed to be 5, which is perfect.



Now in cellForRowAt I get the images in an array, then attempt to set the images to my cell's image view.



override func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
if indexPath.section == 0 {
let cell = tableView.dequeueReusableCell(withIdentifier: "stockCell", for: indexPath) as! StockCell

let stock = stockData[keys[indexPath.row]]!

var images = [String]()
stock.news.forEach { images.append($0.image) }
print("nnNumber of Images: (images.count)nnn")

if let companyImageUrl = URL(string: images[indexPath.row]) {
ImageService.getImage(url: companyImageUrl) { (image) in
cell.companyLogoImageView.image = image
}
}

return cell
}
}


I put a print statement in there to print the images.count (there should be 5), but the console shows 2, then 5 (x3), then 2 again - this is causing the index out of range error presumably, it's seeing 2 when there should be 5:



enter image description here



Why is images.count showing 2 in the first and last spots, but 5 in the rest?



EDIT: Rest of code



Fetching the data (in viewDidLoad):



    fetchData(url: stockApiUrl) { (result: FetchResult<[String:Stock]>) -> (Void) in
switch result {
case .success(let object):
self.stockData = object
self.keys = Array(object.keys)
print("stockData: nn(self.stockData)")
case .failure(let error):
print("Error decoding JSON: nn(error)")
}
DispatchQueue.main.async {
self.tableView.reloadData()
}
}


Data is set to a dictionary, with a separate array for the keys:



var stockData = [String:Stock]()
var keys = [String]()


Structs for decoding JSON:



struct Welcome: Decodable {
let aapl, fb, msft, tsla, goog: Stock

enum CodingKeys: String, CodingKey {
case aapl = "AAPL"
case fb = "FB"
case msft = "MSFT"
case tsla = "TSLA"
case goog = "GOOG"
}
}

struct Stock: Decodable {
let quote: Quote
let news: [News]
}

struct Quote: Decodable {
let symbol: String
let companyName: String
let latestPrice: Double
}

struct News: Decodable {
let url: String
let image: String
}









share|improve this question
















I'm trying to set some images to image views in a tableview, and I have the number of rows set to return keys.count, which after printing is confirmed to be 5, which is perfect.



Now in cellForRowAt I get the images in an array, then attempt to set the images to my cell's image view.



override func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
if indexPath.section == 0 {
let cell = tableView.dequeueReusableCell(withIdentifier: "stockCell", for: indexPath) as! StockCell

let stock = stockData[keys[indexPath.row]]!

var images = [String]()
stock.news.forEach { images.append($0.image) }
print("nnNumber of Images: (images.count)nnn")

if let companyImageUrl = URL(string: images[indexPath.row]) {
ImageService.getImage(url: companyImageUrl) { (image) in
cell.companyLogoImageView.image = image
}
}

return cell
}
}


I put a print statement in there to print the images.count (there should be 5), but the console shows 2, then 5 (x3), then 2 again - this is causing the index out of range error presumably, it's seeing 2 when there should be 5:



enter image description here



Why is images.count showing 2 in the first and last spots, but 5 in the rest?



EDIT: Rest of code



Fetching the data (in viewDidLoad):



    fetchData(url: stockApiUrl) { (result: FetchResult<[String:Stock]>) -> (Void) in
switch result {
case .success(let object):
self.stockData = object
self.keys = Array(object.keys)
print("stockData: nn(self.stockData)")
case .failure(let error):
print("Error decoding JSON: nn(error)")
}
DispatchQueue.main.async {
self.tableView.reloadData()
}
}


Data is set to a dictionary, with a separate array for the keys:



var stockData = [String:Stock]()
var keys = [String]()


Structs for decoding JSON:



struct Welcome: Decodable {
let aapl, fb, msft, tsla, goog: Stock

enum CodingKeys: String, CodingKey {
case aapl = "AAPL"
case fb = "FB"
case msft = "MSFT"
case tsla = "TSLA"
case goog = "GOOG"
}
}

struct Stock: Decodable {
let quote: Quote
let news: [News]
}

struct Quote: Decodable {
let symbol: String
let companyName: String
let latestPrice: Double
}

struct News: Decodable {
let url: String
let image: String
}






ios swift uitableview






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edited Nov 16 '18 at 18:17









rmaddy

247k27328391




247k27328391










asked Nov 16 '18 at 17:39









KingTimKingTim

5261821




5261821













  • I don't get it, how are we supposed to know what stock.news contains?

    – Joakim Danielson
    Nov 16 '18 at 17:45











  • Sorry I wasn't sure if that part was necessary, I edited my question to add the rest of the code.

    – KingTim
    Nov 16 '18 at 17:48



















  • I don't get it, how are we supposed to know what stock.news contains?

    – Joakim Danielson
    Nov 16 '18 at 17:45











  • Sorry I wasn't sure if that part was necessary, I edited my question to add the rest of the code.

    – KingTim
    Nov 16 '18 at 17:48

















I don't get it, how are we supposed to know what stock.news contains?

– Joakim Danielson
Nov 16 '18 at 17:45





I don't get it, how are we supposed to know what stock.news contains?

– Joakim Danielson
Nov 16 '18 at 17:45













Sorry I wasn't sure if that part was necessary, I edited my question to add the rest of the code.

– KingTim
Nov 16 '18 at 17:48





Sorry I wasn't sure if that part was necessary, I edited my question to add the rest of the code.

– KingTim
Nov 16 '18 at 17:48












2 Answers
2






active

oldest

votes


















0














Add another print and make sure that the quantity of news is also different for each row. Then find out why it is different.



stock.news.forEach { images.append($0.image) }
print("nnNumber of Images: (images.count)nnn")
print("nnNumber of stock.news: (stock.news.count)nnn")





share|improve this answer
























  • Ok, printing stock.news.count shows the same irregularity as images.count, except now both counts are 5, 5, 2, 2, 5.

    – KingTim
    Nov 16 '18 at 18:11













  • This isn't an answer, this is a debugging comment. Please wait until you have enough reputation to post comments.

    – rmaddy
    Nov 16 '18 at 18:17













  • Ok. But I thought it was. The question: "Why is images.count showing 2 in the first and last spots, but 5 in the rest?" And the answer: "because stock.news is different in each row".

    – Sergey
    Nov 16 '18 at 18:22





















0














You are assuming that you have 5 images because keys.count is 5 and this is wrong since keys.count tells you that you have 5 stocks in the dictionary you created from the json message.



Now each stock has an news array attached to it that I assume contains news articles/messages related to the stock for one day or similar so this array could then contain from 0 up to an infinite (not likely) amount of news articles. (in this case the number of articles ranges between 2 and 5).



Anyway, you can not rely on keys.count when reading the news array but instead for each array check news.count.



So this code needs to be changed but I am not sure how



if let companyImageUrl = URL(string: images[indexPath.row]) {
ImageService.getImage(url: companyImageUrl) { (image) in
cell.companyLogoImageView.image = image
}
}


Will you show all images? then you need to surround this with a loop somehow but I get the feeling you only want to show one image so maybe change URL(string: images[indexPath.row]) to URL(string: images[0])






share|improve this answer
























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    2 Answers
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    2 Answers
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    0














    Add another print and make sure that the quantity of news is also different for each row. Then find out why it is different.



    stock.news.forEach { images.append($0.image) }
    print("nnNumber of Images: (images.count)nnn")
    print("nnNumber of stock.news: (stock.news.count)nnn")





    share|improve this answer
























    • Ok, printing stock.news.count shows the same irregularity as images.count, except now both counts are 5, 5, 2, 2, 5.

      – KingTim
      Nov 16 '18 at 18:11













    • This isn't an answer, this is a debugging comment. Please wait until you have enough reputation to post comments.

      – rmaddy
      Nov 16 '18 at 18:17













    • Ok. But I thought it was. The question: "Why is images.count showing 2 in the first and last spots, but 5 in the rest?" And the answer: "because stock.news is different in each row".

      – Sergey
      Nov 16 '18 at 18:22


















    0














    Add another print and make sure that the quantity of news is also different for each row. Then find out why it is different.



    stock.news.forEach { images.append($0.image) }
    print("nnNumber of Images: (images.count)nnn")
    print("nnNumber of stock.news: (stock.news.count)nnn")





    share|improve this answer
























    • Ok, printing stock.news.count shows the same irregularity as images.count, except now both counts are 5, 5, 2, 2, 5.

      – KingTim
      Nov 16 '18 at 18:11













    • This isn't an answer, this is a debugging comment. Please wait until you have enough reputation to post comments.

      – rmaddy
      Nov 16 '18 at 18:17













    • Ok. But I thought it was. The question: "Why is images.count showing 2 in the first and last spots, but 5 in the rest?" And the answer: "because stock.news is different in each row".

      – Sergey
      Nov 16 '18 at 18:22
















    0












    0








    0







    Add another print and make sure that the quantity of news is also different for each row. Then find out why it is different.



    stock.news.forEach { images.append($0.image) }
    print("nnNumber of Images: (images.count)nnn")
    print("nnNumber of stock.news: (stock.news.count)nnn")





    share|improve this answer













    Add another print and make sure that the quantity of news is also different for each row. Then find out why it is different.



    stock.news.forEach { images.append($0.image) }
    print("nnNumber of Images: (images.count)nnn")
    print("nnNumber of stock.news: (stock.news.count)nnn")






    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered Nov 16 '18 at 18:08









    SergeySergey

    26




    26













    • Ok, printing stock.news.count shows the same irregularity as images.count, except now both counts are 5, 5, 2, 2, 5.

      – KingTim
      Nov 16 '18 at 18:11













    • This isn't an answer, this is a debugging comment. Please wait until you have enough reputation to post comments.

      – rmaddy
      Nov 16 '18 at 18:17













    • Ok. But I thought it was. The question: "Why is images.count showing 2 in the first and last spots, but 5 in the rest?" And the answer: "because stock.news is different in each row".

      – Sergey
      Nov 16 '18 at 18:22





















    • Ok, printing stock.news.count shows the same irregularity as images.count, except now both counts are 5, 5, 2, 2, 5.

      – KingTim
      Nov 16 '18 at 18:11













    • This isn't an answer, this is a debugging comment. Please wait until you have enough reputation to post comments.

      – rmaddy
      Nov 16 '18 at 18:17













    • Ok. But I thought it was. The question: "Why is images.count showing 2 in the first and last spots, but 5 in the rest?" And the answer: "because stock.news is different in each row".

      – Sergey
      Nov 16 '18 at 18:22



















    Ok, printing stock.news.count shows the same irregularity as images.count, except now both counts are 5, 5, 2, 2, 5.

    – KingTim
    Nov 16 '18 at 18:11







    Ok, printing stock.news.count shows the same irregularity as images.count, except now both counts are 5, 5, 2, 2, 5.

    – KingTim
    Nov 16 '18 at 18:11















    This isn't an answer, this is a debugging comment. Please wait until you have enough reputation to post comments.

    – rmaddy
    Nov 16 '18 at 18:17







    This isn't an answer, this is a debugging comment. Please wait until you have enough reputation to post comments.

    – rmaddy
    Nov 16 '18 at 18:17















    Ok. But I thought it was. The question: "Why is images.count showing 2 in the first and last spots, but 5 in the rest?" And the answer: "because stock.news is different in each row".

    – Sergey
    Nov 16 '18 at 18:22







    Ok. But I thought it was. The question: "Why is images.count showing 2 in the first and last spots, but 5 in the rest?" And the answer: "because stock.news is different in each row".

    – Sergey
    Nov 16 '18 at 18:22















    0














    You are assuming that you have 5 images because keys.count is 5 and this is wrong since keys.count tells you that you have 5 stocks in the dictionary you created from the json message.



    Now each stock has an news array attached to it that I assume contains news articles/messages related to the stock for one day or similar so this array could then contain from 0 up to an infinite (not likely) amount of news articles. (in this case the number of articles ranges between 2 and 5).



    Anyway, you can not rely on keys.count when reading the news array but instead for each array check news.count.



    So this code needs to be changed but I am not sure how



    if let companyImageUrl = URL(string: images[indexPath.row]) {
    ImageService.getImage(url: companyImageUrl) { (image) in
    cell.companyLogoImageView.image = image
    }
    }


    Will you show all images? then you need to surround this with a loop somehow but I get the feeling you only want to show one image so maybe change URL(string: images[indexPath.row]) to URL(string: images[0])






    share|improve this answer




























      0














      You are assuming that you have 5 images because keys.count is 5 and this is wrong since keys.count tells you that you have 5 stocks in the dictionary you created from the json message.



      Now each stock has an news array attached to it that I assume contains news articles/messages related to the stock for one day or similar so this array could then contain from 0 up to an infinite (not likely) amount of news articles. (in this case the number of articles ranges between 2 and 5).



      Anyway, you can not rely on keys.count when reading the news array but instead for each array check news.count.



      So this code needs to be changed but I am not sure how



      if let companyImageUrl = URL(string: images[indexPath.row]) {
      ImageService.getImage(url: companyImageUrl) { (image) in
      cell.companyLogoImageView.image = image
      }
      }


      Will you show all images? then you need to surround this with a loop somehow but I get the feeling you only want to show one image so maybe change URL(string: images[indexPath.row]) to URL(string: images[0])






      share|improve this answer


























        0












        0








        0







        You are assuming that you have 5 images because keys.count is 5 and this is wrong since keys.count tells you that you have 5 stocks in the dictionary you created from the json message.



        Now each stock has an news array attached to it that I assume contains news articles/messages related to the stock for one day or similar so this array could then contain from 0 up to an infinite (not likely) amount of news articles. (in this case the number of articles ranges between 2 and 5).



        Anyway, you can not rely on keys.count when reading the news array but instead for each array check news.count.



        So this code needs to be changed but I am not sure how



        if let companyImageUrl = URL(string: images[indexPath.row]) {
        ImageService.getImage(url: companyImageUrl) { (image) in
        cell.companyLogoImageView.image = image
        }
        }


        Will you show all images? then you need to surround this with a loop somehow but I get the feeling you only want to show one image so maybe change URL(string: images[indexPath.row]) to URL(string: images[0])






        share|improve this answer













        You are assuming that you have 5 images because keys.count is 5 and this is wrong since keys.count tells you that you have 5 stocks in the dictionary you created from the json message.



        Now each stock has an news array attached to it that I assume contains news articles/messages related to the stock for one day or similar so this array could then contain from 0 up to an infinite (not likely) amount of news articles. (in this case the number of articles ranges between 2 and 5).



        Anyway, you can not rely on keys.count when reading the news array but instead for each array check news.count.



        So this code needs to be changed but I am not sure how



        if let companyImageUrl = URL(string: images[indexPath.row]) {
        ImageService.getImage(url: companyImageUrl) { (image) in
        cell.companyLogoImageView.image = image
        }
        }


        Will you show all images? then you need to surround this with a loop somehow but I get the feeling you only want to show one image so maybe change URL(string: images[indexPath.row]) to URL(string: images[0])







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 16 '18 at 18:56









        Joakim DanielsonJoakim Danielson

        10.8k3725




        10.8k3725






























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