How can i plus a integer value after get sum result using jquery?

.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ height:90px;width:728px;box-sizing:border-box;
}

Actually, I want to get integer value this is working when i'm inserting value suppose i insert value 4+5 in input then I'm getting it in my result then I'm gettting it in another div with result like if I get 4+5 then it should be 9.

But i'm getting [object Object]

What is wrong in my code?

$(document).ready(function(){

      

    $('button').click(function(){

         var oldValue;

         var getValue;

        var boxValue;

        

        oldValue = $('.box').text();

        getValue = $('.getValue').val();

       boxValue = $('.box').text(oldValue + getValue);

        

        $('.finalResult').text(boxValue);

    });

});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<button>Button</button> 

    <input type="text" class="getValue">

    

    <div class="box"></div>

    <div class="finalResult"></div>

asked Nov 16 '18 at 13:55

Rohit Verma

1,63221126

$('.finalResult').text(oldValue + getValue) should solve

– Medet Tleukabiluly
Nov 16 '18 at 13:56

What's the value of oldValue? What it is holding and what is its type?

– Zainul Abideen
Nov 16 '18 at 14:03

So you are setting text() with a jQuery object!

– epascarello
Nov 16 '18 at 14:18

@Medet Tleukabiluly i'm getting same value on both result.

– Rohit Verma
Nov 16 '18 at 16:06

add a comment |

But i'm getting [object Object]

What is wrong in my code?

$(document).ready(function(){

      

    $('button').click(function(){

         var oldValue;

         var getValue;

        var boxValue;

        

        oldValue = $('.box').text();

        getValue = $('.getValue').val();

       boxValue = $('.box').text(oldValue + getValue);

        

        $('.finalResult').text(boxValue);

    });

});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<button>Button</button> 

    <input type="text" class="getValue">

    

    <div class="box"></div>

    <div class="finalResult"></div>

asked Nov 16 '18 at 13:55

Rohit Verma

1,63221126

$('.finalResult').text(oldValue + getValue) should solve

– Medet Tleukabiluly
Nov 16 '18 at 13:56

What's the value of oldValue? What it is holding and what is its type?

– Zainul Abideen
Nov 16 '18 at 14:03

So you are setting text() with a jQuery object!

– epascarello
Nov 16 '18 at 14:18

@Medet Tleukabiluly i'm getting same value on both result.

– Rohit Verma
Nov 16 '18 at 16:06

add a comment |

But i'm getting [object Object]

What is wrong in my code?

$(document).ready(function(){

      

    $('button').click(function(){

         var oldValue;

         var getValue;

        var boxValue;

        

        oldValue = $('.box').text();

        getValue = $('.getValue').val();

       boxValue = $('.box').text(oldValue + getValue);

        

        $('.finalResult').text(boxValue);

    });

});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<button>Button</button> 

    <input type="text" class="getValue">

    

    <div class="box"></div>

    <div class="finalResult"></div>

asked Nov 16 '18 at 13:55

Rohit Verma

1,63221126

But i'm getting [object Object]

What is wrong in my code?

$(document).ready(function(){

      

    $('button').click(function(){

         var oldValue;

         var getValue;

        var boxValue;

        

        oldValue = $('.box').text();

        getValue = $('.getValue').val();

       boxValue = $('.box').text(oldValue + getValue);

        

        $('.finalResult').text(boxValue);

    });

});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<button>Button</button> 

    <input type="text" class="getValue">

    

    <div class="box"></div>

    <div class="finalResult"></div>

$(document).ready(function(){

      

    $('button').click(function(){

         var oldValue;

         var getValue;

        var boxValue;

        

        oldValue = $('.box').text();

        getValue = $('.getValue').val();

       boxValue = $('.box').text(oldValue + getValue);

        

        $('.finalResult').text(boxValue);

    });

});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<button>Button</button> 

    <input type="text" class="getValue">

    

    <div class="box"></div>

    <div class="finalResult"></div>

$(document).ready(function(){

      

    $('button').click(function(){

         var oldValue;

         var getValue;

        var boxValue;

        

        oldValue = $('.box').text();

        getValue = $('.getValue').val();

       boxValue = $('.box').text(oldValue + getValue);

        

        $('.finalResult').text(boxValue);

    });

});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<button>Button</button> 

    <input type="text" class="getValue">

    

    <div class="box"></div>

    <div class="finalResult"></div>

javascript jquery

asked Nov 16 '18 at 13:55

Rohit Verma

1,63221126

asked Nov 16 '18 at 13:55

Rohit Verma

1,63221126

asked Nov 16 '18 at 13:55

Rohit Verma

1,63221126

asked Nov 16 '18 at 13:55

Rohit Verma

1,63221126

asked Nov 16 '18 at 13:55

Rohit Verma

1,63221126

$('.finalResult').text(oldValue + getValue) should solve

– Medet Tleukabiluly
Nov 16 '18 at 13:56

What's the value of oldValue? What it is holding and what is its type?

– Zainul Abideen
Nov 16 '18 at 14:03

So you are setting text() with a jQuery object!

– epascarello
Nov 16 '18 at 14:18

@Medet Tleukabiluly i'm getting same value on both result.

– Rohit Verma
Nov 16 '18 at 16:06

add a comment |

$('.finalResult').text(oldValue + getValue) should solve

– Medet Tleukabiluly
Nov 16 '18 at 13:56

What's the value of oldValue? What it is holding and what is its type?

– Zainul Abideen
Nov 16 '18 at 14:03

So you are setting text() with a jQuery object!

– epascarello
Nov 16 '18 at 14:18

@Medet Tleukabiluly i'm getting same value on both result.

– Rohit Verma
Nov 16 '18 at 16:06

$('.finalResult').text(oldValue + getValue) should solve

– Medet Tleukabiluly
Nov 16 '18 at 13:56

What's the value of oldValue? What it is holding and what is its type?

– Zainul Abideen
Nov 16 '18 at 14:03

So you are setting text() with a jQuery object!

– epascarello
Nov 16 '18 at 14:18

@Medet Tleukabiluly i'm getting same value on both result.

– Rohit Verma
Nov 16 '18 at 16:06

add a comment |

4 Answers
4

active

oldest

votes

$(document).ready(function(){

      

    $('button').click(function(){

         var oldValue;

         var getValue;

         var boxValue;

        

        oldValue = $('.box').text();

        getValue = $('.getValue').val();

        boxValue = $('.box').text(oldValue + getValue);

        

        $('.finalResult').text(Number(oldValue || '0') + eval(getValue));

    });

});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<button>Button</button> 

    <input type="text" class="getValue">

    

    <div class="box"></div>

    <div class="finalResult"></div>

answered Nov 16 '18 at 14:03

Medet Tleukabiluly

6,47522246

your code is working fine but what use of eval() in this code?

– Rohit Verma
Nov 16 '18 at 16:15

add a comment |

$(document).ready(function(){

      

    $('button').click(function(){

         var oldValue;

         var getValue;

         var boxValue;

        

        oldValue = $('.box').text();

        getValue = $('.getValue').val();

        if(!isNaN(oldValue) && !isNaN(getValue) )

        {

       boxValue = $('.box').text(oldValue + getValue);// in this line you are setting a value and assignig it to boxValue

        $('.finalResult').text(boxValue.text());//I am replacing this line

       }

    });

});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<button>Button</button> 

    <input type="text" class="getValue">

    

    <div class="box">0</div>

    <div class="finalResult"></div>

see this fiddle

answered Nov 16 '18 at 14:04

Negi Rox

1,9141512

add a comment |

I'm not quite sure what your ultimate goal is, but the [Object Object] occurs because you are placing the jQuery representation of .box into the DOM, which is an object.

Try changing these lines ...

    oldValue = +$('.box').text() || 0;

    getValue = +$('.getValue').val();



    $('.finalResult').text(boxValue.text());

The first two lines are one way to ensure you have a number; the last places the correct "text".

answered Nov 16 '18 at 14:05

rfornal

4,32952235

add a comment |

You are getting [objec object] because you are actually trying to set an object in the div, below see the problem line. What you are doing is that you calculate the some and set the result .finalResult div but you are actually assigning the div to a variable and jquery is treating that variable as an object

$(document).ready(function(){



    $('button').click(function(){

         var oldValue;

         var getValue;

        var boxValue;



        oldValue = $('.box').text();

        getValue = $('.getValue').val();

       boxValue = $('.box').text(oldValue + getValue); //<-- problem



        $('.finalResult').text(boxValue);

    });

});

change the following line

$('.finalResult').text(boxValue);

with this one

$('.finalResult').text(boxValue.text());

answered Nov 16 '18 at 14:12

RopAli Munshi

702516

add a comment |

Your Answer

StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});

}
});

draft saved

draft discarded

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53339247%2fhow-can-i-plus-a-integer-value-after-get-sum-result-using-jquery%23new-answer', 'question_page');
}
);

Post as a guest

Name

Required, but never shown

4 Answers
4

active

oldest

votes

4 Answers
4

active

oldest

votes

$(document).ready(function(){

      

    $('button').click(function(){

         var oldValue;

         var getValue;

         var boxValue;

        

        oldValue = $('.box').text();

        getValue = $('.getValue').val();

        boxValue = $('.box').text(oldValue + getValue);

        

        $('.finalResult').text(Number(oldValue || '0') + eval(getValue));

    });

});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<button>Button</button> 

    <input type="text" class="getValue">

    

    <div class="box"></div>

    <div class="finalResult"></div>

answered Nov 16 '18 at 14:03

Medet Tleukabiluly

6,47522246

your code is working fine but what use of eval() in this code?

– Rohit Verma
Nov 16 '18 at 16:15

add a comment |

$(document).ready(function(){

      

    $('button').click(function(){

         var oldValue;

         var getValue;

         var boxValue;

        

        oldValue = $('.box').text();

        getValue = $('.getValue').val();

        boxValue = $('.box').text(oldValue + getValue);

        

        $('.finalResult').text(Number(oldValue || '0') + eval(getValue));

    });

});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<button>Button</button> 

    <input type="text" class="getValue">

    

    <div class="box"></div>

    <div class="finalResult"></div>

answered Nov 16 '18 at 14:03

Medet Tleukabiluly

6,47522246

your code is working fine but what use of eval() in this code?

– Rohit Verma
Nov 16 '18 at 16:15

add a comment |

$(document).ready(function(){

      

    $('button').click(function(){

         var oldValue;

         var getValue;

         var boxValue;

        

        oldValue = $('.box').text();

        getValue = $('.getValue').val();

        boxValue = $('.box').text(oldValue + getValue);

        

        $('.finalResult').text(Number(oldValue || '0') + eval(getValue));

    });

});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<button>Button</button> 

    <input type="text" class="getValue">

    

    <div class="box"></div>

    <div class="finalResult"></div>

answered Nov 16 '18 at 14:03

Medet Tleukabiluly

6,47522246

$(document).ready(function(){

      

    $('button').click(function(){

         var oldValue;

         var getValue;

         var boxValue;

        

        oldValue = $('.box').text();

        getValue = $('.getValue').val();

        boxValue = $('.box').text(oldValue + getValue);

        

        $('.finalResult').text(Number(oldValue || '0') + eval(getValue));

    });

});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<button>Button</button> 

    <input type="text" class="getValue">

    

    <div class="box"></div>

    <div class="finalResult"></div>

$(document).ready(function(){

      

    $('button').click(function(){

         var oldValue;

         var getValue;

         var boxValue;

        

        oldValue = $('.box').text();

        getValue = $('.getValue').val();

        boxValue = $('.box').text(oldValue + getValue);

        

        $('.finalResult').text(Number(oldValue || '0') + eval(getValue));

    });

});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<button>Button</button> 

    <input type="text" class="getValue">

    

    <div class="box"></div>

    <div class="finalResult"></div>

$(document).ready(function(){

      

    $('button').click(function(){

         var oldValue;

         var getValue;

         var boxValue;

        

        oldValue = $('.box').text();

        getValue = $('.getValue').val();

        boxValue = $('.box').text(oldValue + getValue);

        

        $('.finalResult').text(Number(oldValue || '0') + eval(getValue));

    });

});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<button>Button</button> 

    <input type="text" class="getValue">

    

    <div class="box"></div>

    <div class="finalResult"></div>

answered Nov 16 '18 at 14:03

Medet Tleukabiluly

6,47522246

answered Nov 16 '18 at 14:03

Medet Tleukabiluly

6,47522246

answered Nov 16 '18 at 14:03

Medet Tleukabiluly

6,47522246

answered Nov 16 '18 at 14:03

Medet Tleukabiluly

6,47522246

your code is working fine but what use of eval() in this code?

– Rohit Verma
Nov 16 '18 at 16:15

add a comment |

your code is working fine but what use of eval() in this code?

– Rohit Verma
Nov 16 '18 at 16:15

your code is working fine but what use of eval() in this code?

– Rohit Verma
Nov 16 '18 at 16:15

add a comment |

$(document).ready(function(){

      

    $('button').click(function(){

         var oldValue;

         var getValue;

         var boxValue;

        

        oldValue = $('.box').text();

        getValue = $('.getValue').val();

        if(!isNaN(oldValue) && !isNaN(getValue) )

        {

       boxValue = $('.box').text(oldValue + getValue);// in this line you are setting a value and assignig it to boxValue

        $('.finalResult').text(boxValue.text());//I am replacing this line

       }

    });

});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<button>Button</button> 

    <input type="text" class="getValue">

    

    <div class="box">0</div>

    <div class="finalResult"></div>

see this fiddle

answered Nov 16 '18 at 14:04

Negi Rox

1,9141512

add a comment |

$(document).ready(function(){

      

    $('button').click(function(){

         var oldValue;

         var getValue;

         var boxValue;

        

        oldValue = $('.box').text();

        getValue = $('.getValue').val();

        if(!isNaN(oldValue) && !isNaN(getValue) )

        {

       boxValue = $('.box').text(oldValue + getValue);// in this line you are setting a value and assignig it to boxValue

        $('.finalResult').text(boxValue.text());//I am replacing this line

       }

    });

});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<button>Button</button> 

    <input type="text" class="getValue">

    

    <div class="box">0</div>

    <div class="finalResult"></div>

see this fiddle

answered Nov 16 '18 at 14:04

Negi Rox

1,9141512

add a comment |

$(document).ready(function(){

      

    $('button').click(function(){

         var oldValue;

         var getValue;

         var boxValue;

        

        oldValue = $('.box').text();

        getValue = $('.getValue').val();

        if(!isNaN(oldValue) && !isNaN(getValue) )

        {

       boxValue = $('.box').text(oldValue + getValue);// in this line you are setting a value and assignig it to boxValue

        $('.finalResult').text(boxValue.text());//I am replacing this line

       }

    });

});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<button>Button</button> 

    <input type="text" class="getValue">

    

    <div class="box">0</div>

    <div class="finalResult"></div>

see this fiddle

answered Nov 16 '18 at 14:04

Negi Rox

1,9141512

$(document).ready(function(){

      

    $('button').click(function(){

         var oldValue;

         var getValue;

         var boxValue;

        

        oldValue = $('.box').text();

        getValue = $('.getValue').val();

        if(!isNaN(oldValue) && !isNaN(getValue) )

        {

       boxValue = $('.box').text(oldValue + getValue);// in this line you are setting a value and assignig it to boxValue

        $('.finalResult').text(boxValue.text());//I am replacing this line

       }

    });

});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<button>Button</button> 

    <input type="text" class="getValue">

    

    <div class="box">0</div>

    <div class="finalResult"></div>

see this fiddle

$(document).ready(function(){

      

    $('button').click(function(){

         var oldValue;

         var getValue;

         var boxValue;

        

        oldValue = $('.box').text();

        getValue = $('.getValue').val();

        if(!isNaN(oldValue) && !isNaN(getValue) )

        {

       boxValue = $('.box').text(oldValue + getValue);// in this line you are setting a value and assignig it to boxValue

        $('.finalResult').text(boxValue.text());//I am replacing this line

       }

    });

});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<button>Button</button> 

    <input type="text" class="getValue">

    

    <div class="box">0</div>

    <div class="finalResult"></div>

$(document).ready(function(){

      

    $('button').click(function(){

         var oldValue;

         var getValue;

         var boxValue;

        

        oldValue = $('.box').text();

        getValue = $('.getValue').val();

        if(!isNaN(oldValue) && !isNaN(getValue) )

        {

       boxValue = $('.box').text(oldValue + getValue);// in this line you are setting a value and assignig it to boxValue

        $('.finalResult').text(boxValue.text());//I am replacing this line

       }

    });

});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<button>Button</button> 

    <input type="text" class="getValue">

    

    <div class="box">0</div>

    <div class="finalResult"></div>

answered Nov 16 '18 at 14:04

Negi Rox

1,9141512

answered Nov 16 '18 at 14:04

Negi Rox

1,9141512

answered Nov 16 '18 at 14:04

Negi Rox

1,9141512

answered Nov 16 '18 at 14:04

Negi Rox

1,9141512

add a comment |

I'm not quite sure what your ultimate goal is, but the [Object Object] occurs because you are placing the jQuery representation of .box into the DOM, which is an object.

Try changing these lines ...

    oldValue = +$('.box').text() || 0;

    getValue = +$('.getValue').val();



    $('.finalResult').text(boxValue.text());

The first two lines are one way to ensure you have a number; the last places the correct "text".

answered Nov 16 '18 at 14:05

rfornal

4,32952235

add a comment |

I'm not quite sure what your ultimate goal is, but the [Object Object] occurs because you are placing the jQuery representation of .box into the DOM, which is an object.

Try changing these lines ...

    oldValue = +$('.box').text() || 0;

    getValue = +$('.getValue').val();



    $('.finalResult').text(boxValue.text());

The first two lines are one way to ensure you have a number; the last places the correct "text".

answered Nov 16 '18 at 14:05

rfornal

4,32952235

add a comment |

I'm not quite sure what your ultimate goal is, but the [Object Object] occurs because you are placing the jQuery representation of .box into the DOM, which is an object.

Try changing these lines ...

    oldValue = +$('.box').text() || 0;

    getValue = +$('.getValue').val();



    $('.finalResult').text(boxValue.text());

The first two lines are one way to ensure you have a number; the last places the correct "text".

answered Nov 16 '18 at 14:05

rfornal

4,32952235

I'm not quite sure what your ultimate goal is, but the [Object Object] occurs because you are placing the jQuery representation of .box into the DOM, which is an object.

Try changing these lines ...

    oldValue = +$('.box').text() || 0;

    getValue = +$('.getValue').val();



    $('.finalResult').text(boxValue.text());

The first two lines are one way to ensure you have a number; the last places the correct "text".

answered Nov 16 '18 at 14:05

rfornal

4,32952235

answered Nov 16 '18 at 14:05

rfornal

4,32952235

answered Nov 16 '18 at 14:05

rfornal

4,32952235

answered Nov 16 '18 at 14:05

rfornal

4,32952235

add a comment |

$(document).ready(function(){



    $('button').click(function(){

         var oldValue;

         var getValue;

        var boxValue;



        oldValue = $('.box').text();

        getValue = $('.getValue').val();

       boxValue = $('.box').text(oldValue + getValue); //<-- problem



        $('.finalResult').text(boxValue);

    });

});

change the following line

$('.finalResult').text(boxValue);

with this one

$('.finalResult').text(boxValue.text());

answered Nov 16 '18 at 14:12

RopAli Munshi

702516

add a comment |

$(document).ready(function(){



    $('button').click(function(){

         var oldValue;

         var getValue;

        var boxValue;



        oldValue = $('.box').text();

        getValue = $('.getValue').val();

       boxValue = $('.box').text(oldValue + getValue); //<-- problem



        $('.finalResult').text(boxValue);

    });

});

change the following line

$('.finalResult').text(boxValue);

with this one

$('.finalResult').text(boxValue.text());

answered Nov 16 '18 at 14:12

RopAli Munshi

702516

add a comment |

$(document).ready(function(){



    $('button').click(function(){

         var oldValue;

         var getValue;

        var boxValue;



        oldValue = $('.box').text();

        getValue = $('.getValue').val();

       boxValue = $('.box').text(oldValue + getValue); //<-- problem



        $('.finalResult').text(boxValue);

    });

});

change the following line

$('.finalResult').text(boxValue);

with this one

$('.finalResult').text(boxValue.text());

answered Nov 16 '18 at 14:12

RopAli Munshi

702516

$(document).ready(function(){



    $('button').click(function(){

         var oldValue;

         var getValue;

        var boxValue;



        oldValue = $('.box').text();

        getValue = $('.getValue').val();

       boxValue = $('.box').text(oldValue + getValue); //<-- problem



        $('.finalResult').text(boxValue);

    });

});

change the following line

$('.finalResult').text(boxValue);

with this one

$('.finalResult').text(boxValue.text());

answered Nov 16 '18 at 14:12

RopAli Munshi

702516

answered Nov 16 '18 at 14:12

RopAli Munshi

702516

answered Nov 16 '18 at 14:12

RopAli Munshi

702516

answered Nov 16 '18 at 14:12

RopAli Munshi

702516

add a comment |

draft saved

draft discarded

Thanks for contributing an answer to Stack Overflow!

Please be sure to answer the question. Provide details and share your research!

But avoid …

Asking for help, clarification, or responding to other answers.

Making statements based on opinion; back them up with references or personal experience.

To learn more, see our tips on writing great answers.

draft saved

draft discarded

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Post as a guest

Name

Required, but never shown

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Name

Required, but never shown

Name

Required, but never shown

This page is only for reference, If you need detailed information, please check here

搜尋此網誌

Vfrdtyky