How to evaluate double asterisk (star) in path?
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Any double asterisk in a path means all sub-directories.
Now if I have a path like this a/b/c/**/*.txt
Which means I need all files under all sub-directories under c
. How to get that in python?
python-3.x path wildcard
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up vote
0
down vote
favorite
Any double asterisk in a path means all sub-directories.
Now if I have a path like this a/b/c/**/*.txt
Which means I need all files under all sub-directories under c
. How to get that in python?
python-3.x path wildcard
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
Any double asterisk in a path means all sub-directories.
Now if I have a path like this a/b/c/**/*.txt
Which means I need all files under all sub-directories under c
. How to get that in python?
python-3.x path wildcard
Any double asterisk in a path means all sub-directories.
Now if I have a path like this a/b/c/**/*.txt
Which means I need all files under all sub-directories under c
. How to get that in python?
python-3.x path wildcard
python-3.x path wildcard
edited Nov 11 at 16:37
Uwe Keim
27.3k30128210
27.3k30128210
asked Nov 11 at 16:35
Anirban Nag 'tintinmj'
3,36631936
3,36631936
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add a comment |
1 Answer
1
active
oldest
votes
up vote
0
down vote
Using glob.
From Docs:
For example, consider a directory containing the following files: 1.gif, 2.txt, card.gif and a subdirectory sub which contains only the file 3.txt. glob() will produce the following results. Notice how any leading components of the path are preserved.
>>> import glob
>>> glob.glob('./[0-9].*')
['./1.gif', './2.txt']
>>> glob.glob('*.gif')
['1.gif', 'card.gif']
>>> glob.glob('?.gif')
['1.gif']
>>> glob.glob('**/*.txt', recursive=True) #python 3.5+
['2.txt', 'sub/3.txt']
>>> glob.glob('./**/', recursive=True)
['./', './sub/']
EDIT:
For python 3.4
For older Python versions, use os.walk to recursively walk a directory and fnmatch.filter to match against a simple expression:
import fnmatch
import os
matches =
for root, dirnames, filenames in os.walk('src'):
for filename in fnmatch.filter(filenames, '*.txt'):
matches.append(os.path.join(root, filename))
Two things not working. 1)recursive
is not an argument. 2) If I do./**/*
it will go down only single sub-directory, whereas I need all sub-directories (multi-level) to traverse.
– Anirban Nag 'tintinmj'
Nov 11 at 18:34
hmm. what python version are you on? the docs i linked state python 3.5+ @AnirbanNag'tintinmj'
– Paritosh Singh
Nov 11 at 18:39
I'm using 3.4..
– Anirban Nag 'tintinmj'
Nov 11 at 18:46
you should upgrade if you can. otherwise you might want to make a custom function that does the job for you, but that sounds annoying. @AnirbanNag'tintinmj'
– Paritosh Singh
Nov 11 at 18:59
try the edit solution, and see if that works for you @AnirbanNag'tintinmj'
– Paritosh Singh
Nov 11 at 19:11
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
Using glob.
From Docs:
For example, consider a directory containing the following files: 1.gif, 2.txt, card.gif and a subdirectory sub which contains only the file 3.txt. glob() will produce the following results. Notice how any leading components of the path are preserved.
>>> import glob
>>> glob.glob('./[0-9].*')
['./1.gif', './2.txt']
>>> glob.glob('*.gif')
['1.gif', 'card.gif']
>>> glob.glob('?.gif')
['1.gif']
>>> glob.glob('**/*.txt', recursive=True) #python 3.5+
['2.txt', 'sub/3.txt']
>>> glob.glob('./**/', recursive=True)
['./', './sub/']
EDIT:
For python 3.4
For older Python versions, use os.walk to recursively walk a directory and fnmatch.filter to match against a simple expression:
import fnmatch
import os
matches =
for root, dirnames, filenames in os.walk('src'):
for filename in fnmatch.filter(filenames, '*.txt'):
matches.append(os.path.join(root, filename))
Two things not working. 1)recursive
is not an argument. 2) If I do./**/*
it will go down only single sub-directory, whereas I need all sub-directories (multi-level) to traverse.
– Anirban Nag 'tintinmj'
Nov 11 at 18:34
hmm. what python version are you on? the docs i linked state python 3.5+ @AnirbanNag'tintinmj'
– Paritosh Singh
Nov 11 at 18:39
I'm using 3.4..
– Anirban Nag 'tintinmj'
Nov 11 at 18:46
you should upgrade if you can. otherwise you might want to make a custom function that does the job for you, but that sounds annoying. @AnirbanNag'tintinmj'
– Paritosh Singh
Nov 11 at 18:59
try the edit solution, and see if that works for you @AnirbanNag'tintinmj'
– Paritosh Singh
Nov 11 at 19:11
add a comment |
up vote
0
down vote
Using glob.
From Docs:
For example, consider a directory containing the following files: 1.gif, 2.txt, card.gif and a subdirectory sub which contains only the file 3.txt. glob() will produce the following results. Notice how any leading components of the path are preserved.
>>> import glob
>>> glob.glob('./[0-9].*')
['./1.gif', './2.txt']
>>> glob.glob('*.gif')
['1.gif', 'card.gif']
>>> glob.glob('?.gif')
['1.gif']
>>> glob.glob('**/*.txt', recursive=True) #python 3.5+
['2.txt', 'sub/3.txt']
>>> glob.glob('./**/', recursive=True)
['./', './sub/']
EDIT:
For python 3.4
For older Python versions, use os.walk to recursively walk a directory and fnmatch.filter to match against a simple expression:
import fnmatch
import os
matches =
for root, dirnames, filenames in os.walk('src'):
for filename in fnmatch.filter(filenames, '*.txt'):
matches.append(os.path.join(root, filename))
Two things not working. 1)recursive
is not an argument. 2) If I do./**/*
it will go down only single sub-directory, whereas I need all sub-directories (multi-level) to traverse.
– Anirban Nag 'tintinmj'
Nov 11 at 18:34
hmm. what python version are you on? the docs i linked state python 3.5+ @AnirbanNag'tintinmj'
– Paritosh Singh
Nov 11 at 18:39
I'm using 3.4..
– Anirban Nag 'tintinmj'
Nov 11 at 18:46
you should upgrade if you can. otherwise you might want to make a custom function that does the job for you, but that sounds annoying. @AnirbanNag'tintinmj'
– Paritosh Singh
Nov 11 at 18:59
try the edit solution, and see if that works for you @AnirbanNag'tintinmj'
– Paritosh Singh
Nov 11 at 19:11
add a comment |
up vote
0
down vote
up vote
0
down vote
Using glob.
From Docs:
For example, consider a directory containing the following files: 1.gif, 2.txt, card.gif and a subdirectory sub which contains only the file 3.txt. glob() will produce the following results. Notice how any leading components of the path are preserved.
>>> import glob
>>> glob.glob('./[0-9].*')
['./1.gif', './2.txt']
>>> glob.glob('*.gif')
['1.gif', 'card.gif']
>>> glob.glob('?.gif')
['1.gif']
>>> glob.glob('**/*.txt', recursive=True) #python 3.5+
['2.txt', 'sub/3.txt']
>>> glob.glob('./**/', recursive=True)
['./', './sub/']
EDIT:
For python 3.4
For older Python versions, use os.walk to recursively walk a directory and fnmatch.filter to match against a simple expression:
import fnmatch
import os
matches =
for root, dirnames, filenames in os.walk('src'):
for filename in fnmatch.filter(filenames, '*.txt'):
matches.append(os.path.join(root, filename))
Using glob.
From Docs:
For example, consider a directory containing the following files: 1.gif, 2.txt, card.gif and a subdirectory sub which contains only the file 3.txt. glob() will produce the following results. Notice how any leading components of the path are preserved.
>>> import glob
>>> glob.glob('./[0-9].*')
['./1.gif', './2.txt']
>>> glob.glob('*.gif')
['1.gif', 'card.gif']
>>> glob.glob('?.gif')
['1.gif']
>>> glob.glob('**/*.txt', recursive=True) #python 3.5+
['2.txt', 'sub/3.txt']
>>> glob.glob('./**/', recursive=True)
['./', './sub/']
EDIT:
For python 3.4
For older Python versions, use os.walk to recursively walk a directory and fnmatch.filter to match against a simple expression:
import fnmatch
import os
matches =
for root, dirnames, filenames in os.walk('src'):
for filename in fnmatch.filter(filenames, '*.txt'):
matches.append(os.path.join(root, filename))
edited Nov 11 at 19:10
answered Nov 11 at 16:54
Paritosh Singh
4908
4908
Two things not working. 1)recursive
is not an argument. 2) If I do./**/*
it will go down only single sub-directory, whereas I need all sub-directories (multi-level) to traverse.
– Anirban Nag 'tintinmj'
Nov 11 at 18:34
hmm. what python version are you on? the docs i linked state python 3.5+ @AnirbanNag'tintinmj'
– Paritosh Singh
Nov 11 at 18:39
I'm using 3.4..
– Anirban Nag 'tintinmj'
Nov 11 at 18:46
you should upgrade if you can. otherwise you might want to make a custom function that does the job for you, but that sounds annoying. @AnirbanNag'tintinmj'
– Paritosh Singh
Nov 11 at 18:59
try the edit solution, and see if that works for you @AnirbanNag'tintinmj'
– Paritosh Singh
Nov 11 at 19:11
add a comment |
Two things not working. 1)recursive
is not an argument. 2) If I do./**/*
it will go down only single sub-directory, whereas I need all sub-directories (multi-level) to traverse.
– Anirban Nag 'tintinmj'
Nov 11 at 18:34
hmm. what python version are you on? the docs i linked state python 3.5+ @AnirbanNag'tintinmj'
– Paritosh Singh
Nov 11 at 18:39
I'm using 3.4..
– Anirban Nag 'tintinmj'
Nov 11 at 18:46
you should upgrade if you can. otherwise you might want to make a custom function that does the job for you, but that sounds annoying. @AnirbanNag'tintinmj'
– Paritosh Singh
Nov 11 at 18:59
try the edit solution, and see if that works for you @AnirbanNag'tintinmj'
– Paritosh Singh
Nov 11 at 19:11
Two things not working. 1)
recursive
is not an argument. 2) If I do ./**/*
it will go down only single sub-directory, whereas I need all sub-directories (multi-level) to traverse.– Anirban Nag 'tintinmj'
Nov 11 at 18:34
Two things not working. 1)
recursive
is not an argument. 2) If I do ./**/*
it will go down only single sub-directory, whereas I need all sub-directories (multi-level) to traverse.– Anirban Nag 'tintinmj'
Nov 11 at 18:34
hmm. what python version are you on? the docs i linked state python 3.5+ @AnirbanNag'tintinmj'
– Paritosh Singh
Nov 11 at 18:39
hmm. what python version are you on? the docs i linked state python 3.5+ @AnirbanNag'tintinmj'
– Paritosh Singh
Nov 11 at 18:39
I'm using 3.4..
– Anirban Nag 'tintinmj'
Nov 11 at 18:46
I'm using 3.4..
– Anirban Nag 'tintinmj'
Nov 11 at 18:46
you should upgrade if you can. otherwise you might want to make a custom function that does the job for you, but that sounds annoying. @AnirbanNag'tintinmj'
– Paritosh Singh
Nov 11 at 18:59
you should upgrade if you can. otherwise you might want to make a custom function that does the job for you, but that sounds annoying. @AnirbanNag'tintinmj'
– Paritosh Singh
Nov 11 at 18:59
try the edit solution, and see if that works for you @AnirbanNag'tintinmj'
– Paritosh Singh
Nov 11 at 19:11
try the edit solution, and see if that works for you @AnirbanNag'tintinmj'
– Paritosh Singh
Nov 11 at 19:11
add a comment |
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