How to evaluate double asterisk (star) in path?











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Any double asterisk in a path means all sub-directories.



Now if I have a path like this a/b/c/**/*.txt Which means I need all files under all sub-directories under c. How to get that in python?










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    up vote
    0
    down vote

    favorite












    Any double asterisk in a path means all sub-directories.



    Now if I have a path like this a/b/c/**/*.txt Which means I need all files under all sub-directories under c. How to get that in python?










    share|improve this question


























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      Any double asterisk in a path means all sub-directories.



      Now if I have a path like this a/b/c/**/*.txt Which means I need all files under all sub-directories under c. How to get that in python?










      share|improve this question















      Any double asterisk in a path means all sub-directories.



      Now if I have a path like this a/b/c/**/*.txt Which means I need all files under all sub-directories under c. How to get that in python?







      python-3.x path wildcard






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      share|improve this question








      edited Nov 11 at 16:37









      Uwe Keim

      27.3k30128210




      27.3k30128210










      asked Nov 11 at 16:35









      Anirban Nag 'tintinmj'

      3,36631936




      3,36631936
























          1 Answer
          1






          active

          oldest

          votes

















          up vote
          0
          down vote













          Using glob.



          From Docs:



          For example, consider a directory containing the following files: 1.gif, 2.txt, card.gif and a subdirectory sub which contains only the file 3.txt. glob() will produce the following results. Notice how any leading components of the path are preserved.



          >>> import glob
          >>> glob.glob('./[0-9].*')
          ['./1.gif', './2.txt']
          >>> glob.glob('*.gif')
          ['1.gif', 'card.gif']
          >>> glob.glob('?.gif')
          ['1.gif']
          >>> glob.glob('**/*.txt', recursive=True) #python 3.5+
          ['2.txt', 'sub/3.txt']
          >>> glob.glob('./**/', recursive=True)
          ['./', './sub/']


          EDIT:
          For python 3.4



          For older Python versions, use os.walk to recursively walk a directory and fnmatch.filter to match against a simple expression:



          import fnmatch
          import os

          matches =
          for root, dirnames, filenames in os.walk('src'):
          for filename in fnmatch.filter(filenames, '*.txt'):
          matches.append(os.path.join(root, filename))





          share|improve this answer























          • Two things not working. 1) recursive is not an argument. 2) If I do ./**/* it will go down only single sub-directory, whereas I need all sub-directories (multi-level) to traverse.
            – Anirban Nag 'tintinmj'
            Nov 11 at 18:34










          • hmm. what python version are you on? the docs i linked state python 3.5+ @AnirbanNag'tintinmj'
            – Paritosh Singh
            Nov 11 at 18:39










          • I'm using 3.4..
            – Anirban Nag 'tintinmj'
            Nov 11 at 18:46










          • you should upgrade if you can. otherwise you might want to make a custom function that does the job for you, but that sounds annoying. @AnirbanNag'tintinmj'
            – Paritosh Singh
            Nov 11 at 18:59










          • try the edit solution, and see if that works for you @AnirbanNag'tintinmj'
            – Paritosh Singh
            Nov 11 at 19:11











          Your Answer






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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes








          up vote
          0
          down vote













          Using glob.



          From Docs:



          For example, consider a directory containing the following files: 1.gif, 2.txt, card.gif and a subdirectory sub which contains only the file 3.txt. glob() will produce the following results. Notice how any leading components of the path are preserved.



          >>> import glob
          >>> glob.glob('./[0-9].*')
          ['./1.gif', './2.txt']
          >>> glob.glob('*.gif')
          ['1.gif', 'card.gif']
          >>> glob.glob('?.gif')
          ['1.gif']
          >>> glob.glob('**/*.txt', recursive=True) #python 3.5+
          ['2.txt', 'sub/3.txt']
          >>> glob.glob('./**/', recursive=True)
          ['./', './sub/']


          EDIT:
          For python 3.4



          For older Python versions, use os.walk to recursively walk a directory and fnmatch.filter to match against a simple expression:



          import fnmatch
          import os

          matches =
          for root, dirnames, filenames in os.walk('src'):
          for filename in fnmatch.filter(filenames, '*.txt'):
          matches.append(os.path.join(root, filename))





          share|improve this answer























          • Two things not working. 1) recursive is not an argument. 2) If I do ./**/* it will go down only single sub-directory, whereas I need all sub-directories (multi-level) to traverse.
            – Anirban Nag 'tintinmj'
            Nov 11 at 18:34










          • hmm. what python version are you on? the docs i linked state python 3.5+ @AnirbanNag'tintinmj'
            – Paritosh Singh
            Nov 11 at 18:39










          • I'm using 3.4..
            – Anirban Nag 'tintinmj'
            Nov 11 at 18:46










          • you should upgrade if you can. otherwise you might want to make a custom function that does the job for you, but that sounds annoying. @AnirbanNag'tintinmj'
            – Paritosh Singh
            Nov 11 at 18:59










          • try the edit solution, and see if that works for you @AnirbanNag'tintinmj'
            – Paritosh Singh
            Nov 11 at 19:11















          up vote
          0
          down vote













          Using glob.



          From Docs:



          For example, consider a directory containing the following files: 1.gif, 2.txt, card.gif and a subdirectory sub which contains only the file 3.txt. glob() will produce the following results. Notice how any leading components of the path are preserved.



          >>> import glob
          >>> glob.glob('./[0-9].*')
          ['./1.gif', './2.txt']
          >>> glob.glob('*.gif')
          ['1.gif', 'card.gif']
          >>> glob.glob('?.gif')
          ['1.gif']
          >>> glob.glob('**/*.txt', recursive=True) #python 3.5+
          ['2.txt', 'sub/3.txt']
          >>> glob.glob('./**/', recursive=True)
          ['./', './sub/']


          EDIT:
          For python 3.4



          For older Python versions, use os.walk to recursively walk a directory and fnmatch.filter to match against a simple expression:



          import fnmatch
          import os

          matches =
          for root, dirnames, filenames in os.walk('src'):
          for filename in fnmatch.filter(filenames, '*.txt'):
          matches.append(os.path.join(root, filename))





          share|improve this answer























          • Two things not working. 1) recursive is not an argument. 2) If I do ./**/* it will go down only single sub-directory, whereas I need all sub-directories (multi-level) to traverse.
            – Anirban Nag 'tintinmj'
            Nov 11 at 18:34










          • hmm. what python version are you on? the docs i linked state python 3.5+ @AnirbanNag'tintinmj'
            – Paritosh Singh
            Nov 11 at 18:39










          • I'm using 3.4..
            – Anirban Nag 'tintinmj'
            Nov 11 at 18:46










          • you should upgrade if you can. otherwise you might want to make a custom function that does the job for you, but that sounds annoying. @AnirbanNag'tintinmj'
            – Paritosh Singh
            Nov 11 at 18:59










          • try the edit solution, and see if that works for you @AnirbanNag'tintinmj'
            – Paritosh Singh
            Nov 11 at 19:11













          up vote
          0
          down vote










          up vote
          0
          down vote









          Using glob.



          From Docs:



          For example, consider a directory containing the following files: 1.gif, 2.txt, card.gif and a subdirectory sub which contains only the file 3.txt. glob() will produce the following results. Notice how any leading components of the path are preserved.



          >>> import glob
          >>> glob.glob('./[0-9].*')
          ['./1.gif', './2.txt']
          >>> glob.glob('*.gif')
          ['1.gif', 'card.gif']
          >>> glob.glob('?.gif')
          ['1.gif']
          >>> glob.glob('**/*.txt', recursive=True) #python 3.5+
          ['2.txt', 'sub/3.txt']
          >>> glob.glob('./**/', recursive=True)
          ['./', './sub/']


          EDIT:
          For python 3.4



          For older Python versions, use os.walk to recursively walk a directory and fnmatch.filter to match against a simple expression:



          import fnmatch
          import os

          matches =
          for root, dirnames, filenames in os.walk('src'):
          for filename in fnmatch.filter(filenames, '*.txt'):
          matches.append(os.path.join(root, filename))





          share|improve this answer














          Using glob.



          From Docs:



          For example, consider a directory containing the following files: 1.gif, 2.txt, card.gif and a subdirectory sub which contains only the file 3.txt. glob() will produce the following results. Notice how any leading components of the path are preserved.



          >>> import glob
          >>> glob.glob('./[0-9].*')
          ['./1.gif', './2.txt']
          >>> glob.glob('*.gif')
          ['1.gif', 'card.gif']
          >>> glob.glob('?.gif')
          ['1.gif']
          >>> glob.glob('**/*.txt', recursive=True) #python 3.5+
          ['2.txt', 'sub/3.txt']
          >>> glob.glob('./**/', recursive=True)
          ['./', './sub/']


          EDIT:
          For python 3.4



          For older Python versions, use os.walk to recursively walk a directory and fnmatch.filter to match against a simple expression:



          import fnmatch
          import os

          matches =
          for root, dirnames, filenames in os.walk('src'):
          for filename in fnmatch.filter(filenames, '*.txt'):
          matches.append(os.path.join(root, filename))






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Nov 11 at 19:10

























          answered Nov 11 at 16:54









          Paritosh Singh

          4908




          4908












          • Two things not working. 1) recursive is not an argument. 2) If I do ./**/* it will go down only single sub-directory, whereas I need all sub-directories (multi-level) to traverse.
            – Anirban Nag 'tintinmj'
            Nov 11 at 18:34










          • hmm. what python version are you on? the docs i linked state python 3.5+ @AnirbanNag'tintinmj'
            – Paritosh Singh
            Nov 11 at 18:39










          • I'm using 3.4..
            – Anirban Nag 'tintinmj'
            Nov 11 at 18:46










          • you should upgrade if you can. otherwise you might want to make a custom function that does the job for you, but that sounds annoying. @AnirbanNag'tintinmj'
            – Paritosh Singh
            Nov 11 at 18:59










          • try the edit solution, and see if that works for you @AnirbanNag'tintinmj'
            – Paritosh Singh
            Nov 11 at 19:11


















          • Two things not working. 1) recursive is not an argument. 2) If I do ./**/* it will go down only single sub-directory, whereas I need all sub-directories (multi-level) to traverse.
            – Anirban Nag 'tintinmj'
            Nov 11 at 18:34










          • hmm. what python version are you on? the docs i linked state python 3.5+ @AnirbanNag'tintinmj'
            – Paritosh Singh
            Nov 11 at 18:39










          • I'm using 3.4..
            – Anirban Nag 'tintinmj'
            Nov 11 at 18:46










          • you should upgrade if you can. otherwise you might want to make a custom function that does the job for you, but that sounds annoying. @AnirbanNag'tintinmj'
            – Paritosh Singh
            Nov 11 at 18:59










          • try the edit solution, and see if that works for you @AnirbanNag'tintinmj'
            – Paritosh Singh
            Nov 11 at 19:11
















          Two things not working. 1) recursive is not an argument. 2) If I do ./**/* it will go down only single sub-directory, whereas I need all sub-directories (multi-level) to traverse.
          – Anirban Nag 'tintinmj'
          Nov 11 at 18:34




          Two things not working. 1) recursive is not an argument. 2) If I do ./**/* it will go down only single sub-directory, whereas I need all sub-directories (multi-level) to traverse.
          – Anirban Nag 'tintinmj'
          Nov 11 at 18:34












          hmm. what python version are you on? the docs i linked state python 3.5+ @AnirbanNag'tintinmj'
          – Paritosh Singh
          Nov 11 at 18:39




          hmm. what python version are you on? the docs i linked state python 3.5+ @AnirbanNag'tintinmj'
          – Paritosh Singh
          Nov 11 at 18:39












          I'm using 3.4..
          – Anirban Nag 'tintinmj'
          Nov 11 at 18:46




          I'm using 3.4..
          – Anirban Nag 'tintinmj'
          Nov 11 at 18:46












          you should upgrade if you can. otherwise you might want to make a custom function that does the job for you, but that sounds annoying. @AnirbanNag'tintinmj'
          – Paritosh Singh
          Nov 11 at 18:59




          you should upgrade if you can. otherwise you might want to make a custom function that does the job for you, but that sounds annoying. @AnirbanNag'tintinmj'
          – Paritosh Singh
          Nov 11 at 18:59












          try the edit solution, and see if that works for you @AnirbanNag'tintinmj'
          – Paritosh Singh
          Nov 11 at 19:11




          try the edit solution, and see if that works for you @AnirbanNag'tintinmj'
          – Paritosh Singh
          Nov 11 at 19:11


















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