In Python, how do I rotate a matrix 90 degrees counterclockwise?











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0
down vote

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>>> def rotate_matrix( k: List[List[int]]):
"""
For example, if I have:
m = [[1,2,3],
[2,3,3],
[5,4,3]]
rotate_matrix(m) should give me [[3,3,3],[2,3,4],[1,2,5]].
"""


Edit: Preferably without numpy.










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  • I answered your question - using python only, as you asked. If you agree that my answer is correct and faithful to the intent of your question, then please accept and/or up vote it. Or, please let me know what else you need, I am happy to try to help you. Thank you
    – DrM
    Nov 14 at 14:53












  • I've tried the code in python IDLE and for some reason, it's outputting the original matrix instead of rotating it. Can you please help?
    – user10634718
    Nov 15 at 12:46










  • I just copied the code from the answer and ran it, it is perfect. Please check that you are printing the right array in your code, c.f. print( new_matrix )
    – DrM
    Nov 15 at 13:13















up vote
0
down vote

favorite












>>> def rotate_matrix( k: List[List[int]]):
"""
For example, if I have:
m = [[1,2,3],
[2,3,3],
[5,4,3]]
rotate_matrix(m) should give me [[3,3,3],[2,3,4],[1,2,5]].
"""


Edit: Preferably without numpy.










share|improve this question
























  • I answered your question - using python only, as you asked. If you agree that my answer is correct and faithful to the intent of your question, then please accept and/or up vote it. Or, please let me know what else you need, I am happy to try to help you. Thank you
    – DrM
    Nov 14 at 14:53












  • I've tried the code in python IDLE and for some reason, it's outputting the original matrix instead of rotating it. Can you please help?
    – user10634718
    Nov 15 at 12:46










  • I just copied the code from the answer and ran it, it is perfect. Please check that you are printing the right array in your code, c.f. print( new_matrix )
    – DrM
    Nov 15 at 13:13













up vote
0
down vote

favorite









up vote
0
down vote

favorite











>>> def rotate_matrix( k: List[List[int]]):
"""
For example, if I have:
m = [[1,2,3],
[2,3,3],
[5,4,3]]
rotate_matrix(m) should give me [[3,3,3],[2,3,4],[1,2,5]].
"""


Edit: Preferably without numpy.










share|improve this question















>>> def rotate_matrix( k: List[List[int]]):
"""
For example, if I have:
m = [[1,2,3],
[2,3,3],
[5,4,3]]
rotate_matrix(m) should give me [[3,3,3],[2,3,4],[1,2,5]].
"""


Edit: Preferably without numpy.







python






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share|improve this question













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edited Nov 11 at 21:22









Yvette Colomb

19.9k1369107




19.9k1369107










asked Nov 11 at 16:34









user10634718

141




141












  • I answered your question - using python only, as you asked. If you agree that my answer is correct and faithful to the intent of your question, then please accept and/or up vote it. Or, please let me know what else you need, I am happy to try to help you. Thank you
    – DrM
    Nov 14 at 14:53












  • I've tried the code in python IDLE and for some reason, it's outputting the original matrix instead of rotating it. Can you please help?
    – user10634718
    Nov 15 at 12:46










  • I just copied the code from the answer and ran it, it is perfect. Please check that you are printing the right array in your code, c.f. print( new_matrix )
    – DrM
    Nov 15 at 13:13


















  • I answered your question - using python only, as you asked. If you agree that my answer is correct and faithful to the intent of your question, then please accept and/or up vote it. Or, please let me know what else you need, I am happy to try to help you. Thank you
    – DrM
    Nov 14 at 14:53












  • I've tried the code in python IDLE and for some reason, it's outputting the original matrix instead of rotating it. Can you please help?
    – user10634718
    Nov 15 at 12:46










  • I just copied the code from the answer and ran it, it is perfect. Please check that you are printing the right array in your code, c.f. print( new_matrix )
    – DrM
    Nov 15 at 13:13
















I answered your question - using python only, as you asked. If you agree that my answer is correct and faithful to the intent of your question, then please accept and/or up vote it. Or, please let me know what else you need, I am happy to try to help you. Thank you
– DrM
Nov 14 at 14:53






I answered your question - using python only, as you asked. If you agree that my answer is correct and faithful to the intent of your question, then please accept and/or up vote it. Or, please let me know what else you need, I am happy to try to help you. Thank you
– DrM
Nov 14 at 14:53














I've tried the code in python IDLE and for some reason, it's outputting the original matrix instead of rotating it. Can you please help?
– user10634718
Nov 15 at 12:46




I've tried the code in python IDLE and for some reason, it's outputting the original matrix instead of rotating it. Can you please help?
– user10634718
Nov 15 at 12:46












I just copied the code from the answer and ran it, it is perfect. Please check that you are printing the right array in your code, c.f. print( new_matrix )
– DrM
Nov 15 at 13:13




I just copied the code from the answer and ran it, it is perfect. Please check that you are printing the right array in your code, c.f. print( new_matrix )
– DrM
Nov 15 at 13:13












2 Answers
2






active

oldest

votes

















up vote
2
down vote













You could use the numpy function rot90



import numpy as np
m = np.array([[1,2,3],
[2,3,3],
[5,4,3]])

def rotate_matrix(mat):
return np.rot90(mat)





share|improve this answer




























    up vote
    1
    down vote













    Here is the counter clockwise matrix rotation as one line in pure python (i.e., without numpy):



    new_matrix = [[m[j][i] for j in range(len(m))] for i in range(len(m[0])-1,-1,-1)]


    If you want to do this in a function, then



    def rotate_matrix( m ):
    return [[m[j][i] for j in range(len(m))] for i in range(len(m[0])-1,-1,-1)]


    and either way, the result for



    m = [ [1,2,3], [2,3,3], [5,4,3]]


    is



    [[3, 3, 3], [2, 3, 4], [1, 2, 5]]


    Aside, if you want the usual transpose, then the simple one line pure python version is



    [[m[j][i] for j in range(len(m))] for i in range(len(m[0]))]





    share|improve this answer























    • I've tried the code in python IDLE and for some reason, it's outputting the original matrix instead of rotating it. Can you please help?
      – user10634718
      Nov 15 at 12:45










    • I just copied the code from here and ran it, it is perfect. Please check that you are printing the right array in your code, c.f. print( new_matrix )
      – DrM
      Nov 15 at 13:11











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    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    2
    down vote













    You could use the numpy function rot90



    import numpy as np
    m = np.array([[1,2,3],
    [2,3,3],
    [5,4,3]])

    def rotate_matrix(mat):
    return np.rot90(mat)





    share|improve this answer

























      up vote
      2
      down vote













      You could use the numpy function rot90



      import numpy as np
      m = np.array([[1,2,3],
      [2,3,3],
      [5,4,3]])

      def rotate_matrix(mat):
      return np.rot90(mat)





      share|improve this answer























        up vote
        2
        down vote










        up vote
        2
        down vote









        You could use the numpy function rot90



        import numpy as np
        m = np.array([[1,2,3],
        [2,3,3],
        [5,4,3]])

        def rotate_matrix(mat):
        return np.rot90(mat)





        share|improve this answer












        You could use the numpy function rot90



        import numpy as np
        m = np.array([[1,2,3],
        [2,3,3],
        [5,4,3]])

        def rotate_matrix(mat):
        return np.rot90(mat)






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 11 at 16:40









        Vikhyat Agarwal

        420214




        420214
























            up vote
            1
            down vote













            Here is the counter clockwise matrix rotation as one line in pure python (i.e., without numpy):



            new_matrix = [[m[j][i] for j in range(len(m))] for i in range(len(m[0])-1,-1,-1)]


            If you want to do this in a function, then



            def rotate_matrix( m ):
            return [[m[j][i] for j in range(len(m))] for i in range(len(m[0])-1,-1,-1)]


            and either way, the result for



            m = [ [1,2,3], [2,3,3], [5,4,3]]


            is



            [[3, 3, 3], [2, 3, 4], [1, 2, 5]]


            Aside, if you want the usual transpose, then the simple one line pure python version is



            [[m[j][i] for j in range(len(m))] for i in range(len(m[0]))]





            share|improve this answer























            • I've tried the code in python IDLE and for some reason, it's outputting the original matrix instead of rotating it. Can you please help?
              – user10634718
              Nov 15 at 12:45










            • I just copied the code from here and ran it, it is perfect. Please check that you are printing the right array in your code, c.f. print( new_matrix )
              – DrM
              Nov 15 at 13:11















            up vote
            1
            down vote













            Here is the counter clockwise matrix rotation as one line in pure python (i.e., without numpy):



            new_matrix = [[m[j][i] for j in range(len(m))] for i in range(len(m[0])-1,-1,-1)]


            If you want to do this in a function, then



            def rotate_matrix( m ):
            return [[m[j][i] for j in range(len(m))] for i in range(len(m[0])-1,-1,-1)]


            and either way, the result for



            m = [ [1,2,3], [2,3,3], [5,4,3]]


            is



            [[3, 3, 3], [2, 3, 4], [1, 2, 5]]


            Aside, if you want the usual transpose, then the simple one line pure python version is



            [[m[j][i] for j in range(len(m))] for i in range(len(m[0]))]





            share|improve this answer























            • I've tried the code in python IDLE and for some reason, it's outputting the original matrix instead of rotating it. Can you please help?
              – user10634718
              Nov 15 at 12:45










            • I just copied the code from here and ran it, it is perfect. Please check that you are printing the right array in your code, c.f. print( new_matrix )
              – DrM
              Nov 15 at 13:11













            up vote
            1
            down vote










            up vote
            1
            down vote









            Here is the counter clockwise matrix rotation as one line in pure python (i.e., without numpy):



            new_matrix = [[m[j][i] for j in range(len(m))] for i in range(len(m[0])-1,-1,-1)]


            If you want to do this in a function, then



            def rotate_matrix( m ):
            return [[m[j][i] for j in range(len(m))] for i in range(len(m[0])-1,-1,-1)]


            and either way, the result for



            m = [ [1,2,3], [2,3,3], [5,4,3]]


            is



            [[3, 3, 3], [2, 3, 4], [1, 2, 5]]


            Aside, if you want the usual transpose, then the simple one line pure python version is



            [[m[j][i] for j in range(len(m))] for i in range(len(m[0]))]





            share|improve this answer














            Here is the counter clockwise matrix rotation as one line in pure python (i.e., without numpy):



            new_matrix = [[m[j][i] for j in range(len(m))] for i in range(len(m[0])-1,-1,-1)]


            If you want to do this in a function, then



            def rotate_matrix( m ):
            return [[m[j][i] for j in range(len(m))] for i in range(len(m[0])-1,-1,-1)]


            and either way, the result for



            m = [ [1,2,3], [2,3,3], [5,4,3]]


            is



            [[3, 3, 3], [2, 3, 4], [1, 2, 5]]


            Aside, if you want the usual transpose, then the simple one line pure python version is



            [[m[j][i] for j in range(len(m))] for i in range(len(m[0]))]






            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited Nov 12 at 13:01

























            answered Nov 11 at 16:55









            DrM

            944314




            944314












            • I've tried the code in python IDLE and for some reason, it's outputting the original matrix instead of rotating it. Can you please help?
              – user10634718
              Nov 15 at 12:45










            • I just copied the code from here and ran it, it is perfect. Please check that you are printing the right array in your code, c.f. print( new_matrix )
              – DrM
              Nov 15 at 13:11


















            • I've tried the code in python IDLE and for some reason, it's outputting the original matrix instead of rotating it. Can you please help?
              – user10634718
              Nov 15 at 12:45










            • I just copied the code from here and ran it, it is perfect. Please check that you are printing the right array in your code, c.f. print( new_matrix )
              – DrM
              Nov 15 at 13:11
















            I've tried the code in python IDLE and for some reason, it's outputting the original matrix instead of rotating it. Can you please help?
            – user10634718
            Nov 15 at 12:45




            I've tried the code in python IDLE and for some reason, it's outputting the original matrix instead of rotating it. Can you please help?
            – user10634718
            Nov 15 at 12:45












            I just copied the code from here and ran it, it is perfect. Please check that you are printing the right array in your code, c.f. print( new_matrix )
            – DrM
            Nov 15 at 13:11




            I just copied the code from here and ran it, it is perfect. Please check that you are printing the right array in your code, c.f. print( new_matrix )
            – DrM
            Nov 15 at 13:11


















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