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Write a program that prompts for the user to input a sentence. Then check this sentence to make sure the first word of the sentence is capitalized and the sentence ends with a punctuation mark. If it is not properly written, fix the sentence, print the type of error, and print the fixed sentence.

I was following the provided instructions for this class and keep getting an invalid syntax error for the fourth line of code. Was wondering if anyone knew why and could show me how to fix it or another way of writing this program.

import string



sentence = input("Enter a sentence ")



class acceptSentence():



    punctuationcount = lambda a,b:len(list(filter(lambda c: c in b,a)))



    numberofpunctuationcount =  punctuationcount(sentence,string.punctuation)



for each in sentence:

    if each.startswith(each.upper()):

        print ("Starts with Capital letter ",each)



        break



    if (numberofpunctuations >=1):



        print("Sentence Ends with punctuation")



    else:

        print("Error : there is no punctuion mark at end of setence")





        obj = acceptSentence()

        obj.calculate(sentence)

Your code is not properly indented, which is what leads to an IndentationError when executing it. Your lambda filter also spits out a SyntaxError because of the incorrect spelling of "lambda". Your if-else statement is also misaligned, be careful how you indent your code.

Here's a simpler alternative to your program:

import string



sentence = input("Enter a sentence:")



first_word = sentence.split()[0] # .split() gives you a list of words in the sentence, 0 is the index of the first word;



capitalized_first_word = first_word.title() # .title() capitalizes a string;



# Check whether the first word is not equal to the capitalized word:

if first_word != capitalized_first_word:

    print ("Sentence does not start with a capital letter.")

    # Replace the first word in the sentence with the capitalized word:

    sentence = sentence.replace(first_word, capitalized_first_word)



# Check if the sentence does not end with a punctuation mark, -1 is the index of the last character in the sentence:

if not sentence[-1] in string.punctuation:

    print("Sentence does not end with punctuation.")

    # Add punctuation to the end of the sentence:

    sentence += '.'



# Print the sentence:

print(sentence)

Look into string indexing for more details.

Just do:

sentence = input("Enter a sentence ").lstrip()  # remove trailing whitespaces



# check if first character is uppercase

if not sentence[0].isupper():

    print("Sentence does not start with uppercase character")

    # correct the sentence

    sentence = sentence[0].upper() + sentence[1:]



# check if last character is a punctuation 

# (feel free to add other punctuations)

if sentence[-1] not in (['.']):

    print("Sentence does not end with punctuation character")

    # correct the sentence

    sentence += '.'



#finally print the correct sentence

print(sentence)

Based on the description you may be overthinking the task: it speaks about a single sentence, and then you just have to make sure that the first letter is upper case and there is punctuation at the end:

def sentence():

  text=input("Please type a sentence here: ")



  if text[0].isalpha() and not text[0].isupper(): # Begins with letter, but not uppercase?

    text=text[0].upper()+text[1:]                 # Make it uppercase then

    print("Sentences should start in uppercase");



  if text[-1] not in [".","!","?"]:               # Does not end with punctuation?

    text+="."                                     # Append a period then

    print("Sentences should end with punctuation mark")



  return text

It can be both extended (like .strip()-ing whitespace, just add it to the input-line), or even shortened (the first if can be removed, since there is nothing wrong with calling .upper() on something what is uppercase already). However since the error has to be printed, the if has to stay in this particular case.