SQL: How to find all parents where parents have children with given id
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I have a question about a parent / child join table. I have a join table called parent_children. The table contains a parent_id and child_id. So like this:
parent_id | child_id
1 1
1 2
1 3
2 1
2 3
3 1
3 4
What I want is to find all parents who have children in a certain list. So let's say the list contains 1 and 3 then I want parent_id 1 and 2. If the list contains 4 I want parent_id 3. How do I do this?
sql join
add a comment |
I have a question about a parent / child join table. I have a join table called parent_children. The table contains a parent_id and child_id. So like this:
parent_id | child_id
1 1
1 2
1 3
2 1
2 3
3 1
3 4
What I want is to find all parents who have children in a certain list. So let's say the list contains 1 and 3 then I want parent_id 1 and 2. If the list contains 4 I want parent_id 3. How do I do this?
sql join
Child 1 has three parents?
– jarlh
Nov 16 '18 at 15:53
add a comment |
I have a question about a parent / child join table. I have a join table called parent_children. The table contains a parent_id and child_id. So like this:
parent_id | child_id
1 1
1 2
1 3
2 1
2 3
3 1
3 4
What I want is to find all parents who have children in a certain list. So let's say the list contains 1 and 3 then I want parent_id 1 and 2. If the list contains 4 I want parent_id 3. How do I do this?
sql join
I have a question about a parent / child join table. I have a join table called parent_children. The table contains a parent_id and child_id. So like this:
parent_id | child_id
1 1
1 2
1 3
2 1
2 3
3 1
3 4
What I want is to find all parents who have children in a certain list. So let's say the list contains 1 and 3 then I want parent_id 1 and 2. If the list contains 4 I want parent_id 3. How do I do this?
sql join
sql join
edited Nov 16 '18 at 15:52
melpomene
62.5k55195
62.5k55195
asked Nov 16 '18 at 15:50
Martijn HiemstraMartijn Hiemstra
127211
127211
Child 1 has three parents?
– jarlh
Nov 16 '18 at 15:53
add a comment |
Child 1 has three parents?
– jarlh
Nov 16 '18 at 15:53
Child 1 has three parents?
– jarlh
Nov 16 '18 at 15:53
Child 1 has three parents?
– jarlh
Nov 16 '18 at 15:53
add a comment |
2 Answers
2
active
oldest
votes
You can use group by
, where
, and having
:
select parent_id
from t
where child_id in (1, 3)
group by parent_id
having count(*) = 2; -- "2" is the number of items in the list
This assumes no duplicate parent/child rows in the table. If this is possible, then use count(distinct child_id) = 2
.
This is brilliant. Thanks for the answer. I don't know how on earth you came up with that.
– Martijn Hiemstra
Nov 16 '18 at 19:00
add a comment |
So you basically need to count the number of occurrences in the IN list of your input.
The following can help.
create table parent_children(parent_id int, child_id int)
insert into parent_children values(1,1)
insert into parent_children values(1,2)
insert into parent_children values(1,3)
insert into parent_children values(2,1)
insert into parent_children values(2,3)
insert into parent_children values(3,1)
insert into parent_children values(3,4)
with list_data
as(select *
from (values(1),(3))as t(x)
)
select a.x
from list_data a
left join parent_children b
on a.x=b.child_id
group by a.x
having count(*) = count(distinct b.parent_id)
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can use group by
, where
, and having
:
select parent_id
from t
where child_id in (1, 3)
group by parent_id
having count(*) = 2; -- "2" is the number of items in the list
This assumes no duplicate parent/child rows in the table. If this is possible, then use count(distinct child_id) = 2
.
This is brilliant. Thanks for the answer. I don't know how on earth you came up with that.
– Martijn Hiemstra
Nov 16 '18 at 19:00
add a comment |
You can use group by
, where
, and having
:
select parent_id
from t
where child_id in (1, 3)
group by parent_id
having count(*) = 2; -- "2" is the number of items in the list
This assumes no duplicate parent/child rows in the table. If this is possible, then use count(distinct child_id) = 2
.
This is brilliant. Thanks for the answer. I don't know how on earth you came up with that.
– Martijn Hiemstra
Nov 16 '18 at 19:00
add a comment |
You can use group by
, where
, and having
:
select parent_id
from t
where child_id in (1, 3)
group by parent_id
having count(*) = 2; -- "2" is the number of items in the list
This assumes no duplicate parent/child rows in the table. If this is possible, then use count(distinct child_id) = 2
.
You can use group by
, where
, and having
:
select parent_id
from t
where child_id in (1, 3)
group by parent_id
having count(*) = 2; -- "2" is the number of items in the list
This assumes no duplicate parent/child rows in the table. If this is possible, then use count(distinct child_id) = 2
.
answered Nov 16 '18 at 15:52
Gordon LinoffGordon Linoff
797k37318423
797k37318423
This is brilliant. Thanks for the answer. I don't know how on earth you came up with that.
– Martijn Hiemstra
Nov 16 '18 at 19:00
add a comment |
This is brilliant. Thanks for the answer. I don't know how on earth you came up with that.
– Martijn Hiemstra
Nov 16 '18 at 19:00
This is brilliant. Thanks for the answer. I don't know how on earth you came up with that.
– Martijn Hiemstra
Nov 16 '18 at 19:00
This is brilliant. Thanks for the answer. I don't know how on earth you came up with that.
– Martijn Hiemstra
Nov 16 '18 at 19:00
add a comment |
So you basically need to count the number of occurrences in the IN list of your input.
The following can help.
create table parent_children(parent_id int, child_id int)
insert into parent_children values(1,1)
insert into parent_children values(1,2)
insert into parent_children values(1,3)
insert into parent_children values(2,1)
insert into parent_children values(2,3)
insert into parent_children values(3,1)
insert into parent_children values(3,4)
with list_data
as(select *
from (values(1),(3))as t(x)
)
select a.x
from list_data a
left join parent_children b
on a.x=b.child_id
group by a.x
having count(*) = count(distinct b.parent_id)
add a comment |
So you basically need to count the number of occurrences in the IN list of your input.
The following can help.
create table parent_children(parent_id int, child_id int)
insert into parent_children values(1,1)
insert into parent_children values(1,2)
insert into parent_children values(1,3)
insert into parent_children values(2,1)
insert into parent_children values(2,3)
insert into parent_children values(3,1)
insert into parent_children values(3,4)
with list_data
as(select *
from (values(1),(3))as t(x)
)
select a.x
from list_data a
left join parent_children b
on a.x=b.child_id
group by a.x
having count(*) = count(distinct b.parent_id)
add a comment |
So you basically need to count the number of occurrences in the IN list of your input.
The following can help.
create table parent_children(parent_id int, child_id int)
insert into parent_children values(1,1)
insert into parent_children values(1,2)
insert into parent_children values(1,3)
insert into parent_children values(2,1)
insert into parent_children values(2,3)
insert into parent_children values(3,1)
insert into parent_children values(3,4)
with list_data
as(select *
from (values(1),(3))as t(x)
)
select a.x
from list_data a
left join parent_children b
on a.x=b.child_id
group by a.x
having count(*) = count(distinct b.parent_id)
So you basically need to count the number of occurrences in the IN list of your input.
The following can help.
create table parent_children(parent_id int, child_id int)
insert into parent_children values(1,1)
insert into parent_children values(1,2)
insert into parent_children values(1,3)
insert into parent_children values(2,1)
insert into parent_children values(2,3)
insert into parent_children values(3,1)
insert into parent_children values(3,4)
with list_data
as(select *
from (values(1),(3))as t(x)
)
select a.x
from list_data a
left join parent_children b
on a.x=b.child_id
group by a.x
having count(*) = count(distinct b.parent_id)
answered Nov 16 '18 at 16:01
George JosephGeorge Joseph
1,590510
1,590510
add a comment |
add a comment |
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Child 1 has three parents?
– jarlh
Nov 16 '18 at 15:53