Using Decodable to get the object and document ID with Firestore
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I have a simple User class which has the following fields:
{
"localIdentifier": "xyc9870",
"isOnline": false,
"username": "ZS"
}
I want to use Swift's Decodable to easily turn the QueryDocumentSnapshot into a type safe Swift struct. I also want to make sure that I get the documentID from the QueryDocumentSnapshot for updating the object later.
This is what I'm currently using to decode but obviously it misses the documentId
struct User: Decodable {
let localIdentifier: String
let username: String
let isOnline: Bool
}
Would love a hand here. Thanks!
swift firebase google-cloud-firestore
asked Nov 16 '18 at 15:45
Zack ShapiroZack Shapiro
1,20194384
add a comment |
I have a simple User class which has the following fields:
{
"localIdentifier": "xyc9870",
"isOnline": false,
"username": "ZS"
}
I want to use Swift's Decodable to easily turn the QueryDocumentSnapshot into a type safe Swift struct. I also want to make sure that I get the documentID from the QueryDocumentSnapshot for updating the object later.
This is what I'm currently using to decode but obviously it misses the documentId
struct User: Decodable {
let localIdentifier: String
let username: String
let isOnline: Bool
}
Would love a hand here. Thanks!
swift firebase google-cloud-firestore
asked Nov 16 '18 at 15:45
Zack ShapiroZack Shapiro
1,20194384
add a comment |
I have a simple User class which has the following fields:
{
"localIdentifier": "xyc9870",
"isOnline": false,
"username": "ZS"
}
I want to use Swift's Decodable to easily turn the QueryDocumentSnapshot into a type safe Swift struct. I also want to make sure that I get the documentID from the QueryDocumentSnapshot for updating the object later.
This is what I'm currently using to decode but obviously it misses the documentId
struct User: Decodable {
let localIdentifier: String
let username: String
let isOnline: Bool
}
Would love a hand here. Thanks!
swift firebase google-cloud-firestore
asked Nov 16 '18 at 15:45
Zack ShapiroZack Shapiro
1,20194384
I have a simple User class which has the following fields:
{
"localIdentifier": "xyc9870",
"isOnline": false,
"username": "ZS"
}
I want to use Swift's Decodable to easily turn the QueryDocumentSnapshot into a type safe Swift struct. I also want to make sure that I get the documentID from the QueryDocumentSnapshot for updating the object later.
This is what I'm currently using to decode but obviously it misses the documentId
struct User: Decodable {
let localIdentifier: String
let username: String
let isOnline: Bool
}
Would love a hand here. Thanks!
swift firebase google-cloud-firestore
swift firebase google-cloud-firestore
asked Nov 16 '18 at 15:45
Zack ShapiroZack Shapiro
1,20194384
asked Nov 16 '18 at 15:45
Zack ShapiroZack Shapiro
1,20194384
asked Nov 16 '18 at 15:45
Zack ShapiroZack Shapiro
1,20194384
asked Nov 16 '18 at 15:45
Zack ShapiroZack Shapiro
1,20194384
asked Nov 16 '18 at 15:45
Zack ShapiroZack Shapiro
1,20194384
1,20194384
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
I wrote myself a small convenience extension that just brings the documentID into the data JSON and then I can use the simple struct below
extension QueryDocumentSnapshot {
func prepareForDecoding() -> [String: Any] {
var data = self.data()
data["documentId"] = self.documentID
return data
}
}
Decode using:
struct User: Decodable {
let documentId: String
let localIdentifier: String
let username: String
let isOnline: Bool
}
if let user = try? JSONDecoder().decode(User.self, fromJSONObject: doc.prepareForDecoding()) {
...
}
Edit:
My JSONDecoder extension
extension JSONDecoder {
func decode<T>(_ type: T.Type, fromJSONObject object: Any) throws -> T where T: Decodable {
return try decode(T.self, from: try JSONSerialization.data(withJSONObject: object, options: ))
}
}
answered Nov 16 '18 at 16:05
Zack ShapiroZack Shapiro
1,20194384
Hi Zack, there is no method fromJSONObject of JSONDecoder(). How can you decode it?
– Asif Raza
Nov 20 '18 at 9:37
Asif, I just added my extension that allows me to do this
– Zack Shapiro
Nov 20 '18 at 20:24
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
I wrote myself a small convenience extension that just brings the documentID into the data JSON and then I can use the simple struct below
extension QueryDocumentSnapshot {
func prepareForDecoding() -> [String: Any] {
var data = self.data()
data["documentId"] = self.documentID
return data
}
}
Decode using:
struct User: Decodable {
let documentId: String
let localIdentifier: String
let username: String
let isOnline: Bool
}
if let user = try? JSONDecoder().decode(User.self, fromJSONObject: doc.prepareForDecoding()) {
...
}
Edit:
My JSONDecoder extension
extension JSONDecoder {
func decode<T>(_ type: T.Type, fromJSONObject object: Any) throws -> T where T: Decodable {
return try decode(T.self, from: try JSONSerialization.data(withJSONObject: object, options: ))
}
}
answered Nov 16 '18 at 16:05
Zack ShapiroZack Shapiro
1,20194384
Hi Zack, there is no method fromJSONObject of JSONDecoder(). How can you decode it?
– Asif Raza
Nov 20 '18 at 9:37
Asif, I just added my extension that allows me to do this
– Zack Shapiro
Nov 20 '18 at 20:24
add a comment |
I wrote myself a small convenience extension that just brings the documentID into the data JSON and then I can use the simple struct below
extension QueryDocumentSnapshot {
func prepareForDecoding() -> [String: Any] {
var data = self.data()
data["documentId"] = self.documentID
return data
}
}
Decode using:
struct User: Decodable {
let documentId: String
let localIdentifier: String
let username: String
let isOnline: Bool
}
if let user = try? JSONDecoder().decode(User.self, fromJSONObject: doc.prepareForDecoding()) {
...
}
Edit:
My JSONDecoder extension
extension JSONDecoder {
func decode<T>(_ type: T.Type, fromJSONObject object: Any) throws -> T where T: Decodable {
return try decode(T.self, from: try JSONSerialization.data(withJSONObject: object, options: ))
}
}
answered Nov 16 '18 at 16:05
Zack ShapiroZack Shapiro
1,20194384
Hi Zack, there is no method fromJSONObject of JSONDecoder(). How can you decode it?
– Asif Raza
Nov 20 '18 at 9:37
Asif, I just added my extension that allows me to do this
– Zack Shapiro
Nov 20 '18 at 20:24
add a comment |
I wrote myself a small convenience extension that just brings the documentID into the data JSON and then I can use the simple struct below
extension QueryDocumentSnapshot {
func prepareForDecoding() -> [String: Any] {
var data = self.data()
data["documentId"] = self.documentID
return data
}
}
Decode using:
struct User: Decodable {
let documentId: String
let localIdentifier: String
let username: String
let isOnline: Bool
}
if let user = try? JSONDecoder().decode(User.self, fromJSONObject: doc.prepareForDecoding()) {
...
}
Edit:
My JSONDecoder extension
extension JSONDecoder {
func decode<T>(_ type: T.Type, fromJSONObject object: Any) throws -> T where T: Decodable {
return try decode(T.self, from: try JSONSerialization.data(withJSONObject: object, options: ))
}
}
answered Nov 16 '18 at 16:05
Zack ShapiroZack Shapiro
1,20194384
I wrote myself a small convenience extension that just brings the documentID into the data JSON and then I can use the simple struct below
extension QueryDocumentSnapshot {
func prepareForDecoding() -> [String: Any] {
var data = self.data()
data["documentId"] = self.documentID
return data
}
}
Decode using:
struct User: Decodable {
let documentId: String
let localIdentifier: String
let username: String
let isOnline: Bool
}
if let user = try? JSONDecoder().decode(User.self, fromJSONObject: doc.prepareForDecoding()) {
...
}
Edit:
My JSONDecoder extension
extension JSONDecoder {
func decode<T>(_ type: T.Type, fromJSONObject object: Any) throws -> T where T: Decodable {
return try decode(T.self, from: try JSONSerialization.data(withJSONObject: object, options: ))
}
}
answered Nov 16 '18 at 16:05
Zack ShapiroZack Shapiro
1,20194384
edited Nov 20 '18 at 20:24
answered Nov 16 '18 at 16:05
Zack ShapiroZack Shapiro
1,20194384
answered Nov 16 '18 at 16:05
Zack ShapiroZack Shapiro
1,20194384
answered Nov 16 '18 at 16:05
Zack ShapiroZack Shapiro
1,20194384
1,20194384
Hi Zack, there is no method fromJSONObject of JSONDecoder(). How can you decode it?
– Asif Raza
Nov 20 '18 at 9:37
Asif, I just added my extension that allows me to do this
– Zack Shapiro
Nov 20 '18 at 20:24
add a comment |
Hi Zack, there is no method fromJSONObject of JSONDecoder(). How can you decode it?
– Asif Raza
Nov 20 '18 at 9:37
Asif, I just added my extension that allows me to do this
– Zack Shapiro
Nov 20 '18 at 20:24
Hi Zack, there is no method fromJSONObject of JSONDecoder(). How can you decode it?
– Asif Raza
Nov 20 '18 at 9:37
Hi Zack, there is no method fromJSONObject of JSONDecoder(). How can you decode it?
– Asif Raza
Nov 20 '18 at 9:37
Asif, I just added my extension that allows me to do this
– Zack Shapiro
Nov 20 '18 at 20:24
Asif, I just added my extension that allows me to do this
– Zack Shapiro
Nov 20 '18 at 20:24
add a comment |
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