How can I see a specific object's attribute on a DataGridView's cell?
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1
I want to be as clear as possible with this:
I have this class called "Tipo de Gasto"
public class CTipoGasto
{
public static List<CTipoGasto> listaTipoGasto = new List<CTipoGasto>();
public string descripción { get; set; }
public int ID { get; set; }
}
And as it is shown below, this object is an attribute of another object called "Gasto"
public class CGasto
{
public static List<CGasto> listaGasto = new List<CGasto>();
public string descripcion { get; set; }
public int ID { get; set; }
public CTipoGasto tipoDeGasto { get; set; } //here
public DateTime fecha { get; set; }
public double precio { get; set; }
}
Each one of those two lists are Data Sources of two different "Data Grid View", but the Gasto's attribute public CTipoGasto tipoDeGasto { get; set; } is shown like this on Gasto's DGV:
So I wanted to know how do I have to do to show TipodeGasto's attribute "Descripción"
c# winforms
edited Nov 16 '18 at 16:09
LarsTech
70.6k12109161
add a comment |
1
I want to be as clear as possible with this:
I have this class called "Tipo de Gasto"
public class CTipoGasto
{
public static List<CTipoGasto> listaTipoGasto = new List<CTipoGasto>();
public string descripción { get; set; }
public int ID { get; set; }
}
And as it is shown below, this object is an attribute of another object called "Gasto"
public class CGasto
{
public static List<CGasto> listaGasto = new List<CGasto>();
public string descripcion { get; set; }
public int ID { get; set; }
public CTipoGasto tipoDeGasto { get; set; } //here
public DateTime fecha { get; set; }
public double precio { get; set; }
}
Each one of those two lists are Data Sources of two different "Data Grid View", but the Gasto's attribute public CTipoGasto tipoDeGasto { get; set; } is shown like this on Gasto's DGV:
So I wanted to know how do I have to do to show TipodeGasto's attribute "Descripción"
c# winforms
edited Nov 16 '18 at 16:09
LarsTech
70.6k12109161
add a comment |
1
1
1
I want to be as clear as possible with this:
I have this class called "Tipo de Gasto"
public class CTipoGasto
{
public static List<CTipoGasto> listaTipoGasto = new List<CTipoGasto>();
public string descripción { get; set; }
public int ID { get; set; }
}
And as it is shown below, this object is an attribute of another object called "Gasto"
public class CGasto
{
public static List<CGasto> listaGasto = new List<CGasto>();
public string descripcion { get; set; }
public int ID { get; set; }
public CTipoGasto tipoDeGasto { get; set; } //here
public DateTime fecha { get; set; }
public double precio { get; set; }
}
Each one of those two lists are Data Sources of two different "Data Grid View", but the Gasto's attribute public CTipoGasto tipoDeGasto { get; set; } is shown like this on Gasto's DGV:
So I wanted to know how do I have to do to show TipodeGasto's attribute "Descripción"
c# winforms
edited Nov 16 '18 at 16:09
LarsTech
70.6k12109161
I want to be as clear as possible with this:
I have this class called "Tipo de Gasto"
public class CTipoGasto
{
public static List<CTipoGasto> listaTipoGasto = new List<CTipoGasto>();
public string descripción { get; set; }
public int ID { get; set; }
}
And as it is shown below, this object is an attribute of another object called "Gasto"
public class CGasto
{
public static List<CGasto> listaGasto = new List<CGasto>();
public string descripcion { get; set; }
public int ID { get; set; }
public CTipoGasto tipoDeGasto { get; set; } //here
public DateTime fecha { get; set; }
public double precio { get; set; }
}
Each one of those two lists are Data Sources of two different "Data Grid View", but the Gasto's attribute public CTipoGasto tipoDeGasto { get; set; } is shown like this on Gasto's DGV:
So I wanted to know how do I have to do to show TipodeGasto's attribute "Descripción"
c# winforms
c# winforms
edited Nov 16 '18 at 16:09
LarsTech
70.6k12109161
edited Nov 16 '18 at 16:09
LarsTech
70.6k12109161
edited Nov 16 '18 at 16:09
LarsTech
70.6k12109161
edited Nov 16 '18 at 16:09
LarsTech
70.6k12109161
edited Nov 16 '18 at 16:09
LarsTech
70.6k12109161
70.6k12109161
asked Nov 16 '18 at 15:49
user9779039
add a comment |
add a comment |
1 Answer
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Override the ToString function of your class:
public class CTipoGasto
{
public static List<CTipoGasto> listaTipoGasto = new List<CTipoGasto>();
public string descripción { get; set; }
public int ID { get; set; }
public override string ToString() {
return descripción;
}
}
answered Nov 16 '18 at 16:09
LarsTechLarsTech
70.6k12109161
Oh thanks! But.. is the "ID" Attribute hidden or something after that?
– user9779039
Nov 17 '18 at 6:39
@juanzitelli To combine two properties, tryreturn ID.ToString() + ' ' + descripción;
– LarsTech
Nov 18 '18 at 21:09
That sounds great, but what I actually meant was: How can I show "TipoGasto" 's ID Property as another column in the datagridview just as with "descripción"
– user9779039
Nov 21 '18 at 5:00
@juanzitelli Depends. How are you filling the DataGridView? Using the DataSource? Or adding rows manually?
– LarsTech
Nov 21 '18 at 14:47
Data Source!dgvGrillaGasto.DataSource = null; dgvGrillaGasto.DataSource = CGasto.listaGasto; List<CGasto> listaFiltrada2 = new List<CGasto>(); if (txtBuscar.Text.Length > 0) { listaFiltrada2 = listaFiltrada2.FindAll(x => x.descripcion.ToUpper().Contains(txtBuscar.Text.ToUpper())); } dgvGrillaGasto.DataSource = listaFiltrada2;
– user9779039
Nov 21 '18 at 17:56
|
show 1 more comment
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
Override the ToString function of your class:
public class CTipoGasto
{
public static List<CTipoGasto> listaTipoGasto = new List<CTipoGasto>();
public string descripción { get; set; }
public int ID { get; set; }
public override string ToString() {
return descripción;
}
}
answered Nov 16 '18 at 16:09
LarsTechLarsTech
70.6k12109161
Oh thanks! But.. is the "ID" Attribute hidden or something after that?
– user9779039
Nov 17 '18 at 6:39
@juanzitelli To combine two properties, tryreturn ID.ToString() + ' ' + descripción;
– LarsTech
Nov 18 '18 at 21:09
That sounds great, but what I actually meant was: How can I show "TipoGasto" 's ID Property as another column in the datagridview just as with "descripción"
– user9779039
Nov 21 '18 at 5:00
@juanzitelli Depends. How are you filling the DataGridView? Using the DataSource? Or adding rows manually?
– LarsTech
Nov 21 '18 at 14:47
Data Source!dgvGrillaGasto.DataSource = null; dgvGrillaGasto.DataSource = CGasto.listaGasto; List<CGasto> listaFiltrada2 = new List<CGasto>(); if (txtBuscar.Text.Length > 0) { listaFiltrada2 = listaFiltrada2.FindAll(x => x.descripcion.ToUpper().Contains(txtBuscar.Text.ToUpper())); } dgvGrillaGasto.DataSource = listaFiltrada2;
– user9779039
Nov 21 '18 at 17:56
|
show 1 more comment
0
Override the ToString function of your class:
public class CTipoGasto
{
public static List<CTipoGasto> listaTipoGasto = new List<CTipoGasto>();
public string descripción { get; set; }
public int ID { get; set; }
public override string ToString() {
return descripción;
}
}
answered Nov 16 '18 at 16:09
LarsTechLarsTech
70.6k12109161
Oh thanks! But.. is the "ID" Attribute hidden or something after that?
– user9779039
Nov 17 '18 at 6:39
@juanzitelli To combine two properties, tryreturn ID.ToString() + ' ' + descripción;
– LarsTech
Nov 18 '18 at 21:09
That sounds great, but what I actually meant was: How can I show "TipoGasto" 's ID Property as another column in the datagridview just as with "descripción"
– user9779039
Nov 21 '18 at 5:00
@juanzitelli Depends. How are you filling the DataGridView? Using the DataSource? Or adding rows manually?
– LarsTech
Nov 21 '18 at 14:47
Data Source!dgvGrillaGasto.DataSource = null; dgvGrillaGasto.DataSource = CGasto.listaGasto; List<CGasto> listaFiltrada2 = new List<CGasto>(); if (txtBuscar.Text.Length > 0) { listaFiltrada2 = listaFiltrada2.FindAll(x => x.descripcion.ToUpper().Contains(txtBuscar.Text.ToUpper())); } dgvGrillaGasto.DataSource = listaFiltrada2;
– user9779039
Nov 21 '18 at 17:56
|
show 1 more comment
0
0
0
Override the ToString function of your class:
public class CTipoGasto
{
public static List<CTipoGasto> listaTipoGasto = new List<CTipoGasto>();
public string descripción { get; set; }
public int ID { get; set; }
public override string ToString() {
return descripción;
}
}
answered Nov 16 '18 at 16:09
LarsTechLarsTech
70.6k12109161
Override the ToString function of your class:
public class CTipoGasto
{
public static List<CTipoGasto> listaTipoGasto = new List<CTipoGasto>();
public string descripción { get; set; }
public int ID { get; set; }
public override string ToString() {
return descripción;
}
}
answered Nov 16 '18 at 16:09
LarsTechLarsTech
70.6k12109161
answered Nov 16 '18 at 16:09
LarsTechLarsTech
70.6k12109161
answered Nov 16 '18 at 16:09
LarsTechLarsTech
70.6k12109161
answered Nov 16 '18 at 16:09
LarsTechLarsTech
70.6k12109161
70.6k12109161
Oh thanks! But.. is the "ID" Attribute hidden or something after that?
– user9779039
Nov 17 '18 at 6:39
@juanzitelli To combine two properties, tryreturn ID.ToString() + ' ' + descripción;
– LarsTech
Nov 18 '18 at 21:09
That sounds great, but what I actually meant was: How can I show "TipoGasto" 's ID Property as another column in the datagridview just as with "descripción"
– user9779039
Nov 21 '18 at 5:00
@juanzitelli Depends. How are you filling the DataGridView? Using the DataSource? Or adding rows manually?
– LarsTech
Nov 21 '18 at 14:47
Data Source!dgvGrillaGasto.DataSource = null; dgvGrillaGasto.DataSource = CGasto.listaGasto; List<CGasto> listaFiltrada2 = new List<CGasto>(); if (txtBuscar.Text.Length > 0) { listaFiltrada2 = listaFiltrada2.FindAll(x => x.descripcion.ToUpper().Contains(txtBuscar.Text.ToUpper())); } dgvGrillaGasto.DataSource = listaFiltrada2;
– user9779039
Nov 21 '18 at 17:56
|
show 1 more comment
Oh thanks! But.. is the "ID" Attribute hidden or something after that?
– user9779039
Nov 17 '18 at 6:39
@juanzitelli To combine two properties, tryreturn ID.ToString() + ' ' + descripción;
– LarsTech
Nov 18 '18 at 21:09
That sounds great, but what I actually meant was: How can I show "TipoGasto" 's ID Property as another column in the datagridview just as with "descripción"
– user9779039
Nov 21 '18 at 5:00
@juanzitelli Depends. How are you filling the DataGridView? Using the DataSource? Or adding rows manually?
– LarsTech
Nov 21 '18 at 14:47
Data Source!dgvGrillaGasto.DataSource = null; dgvGrillaGasto.DataSource = CGasto.listaGasto; List<CGasto> listaFiltrada2 = new List<CGasto>(); if (txtBuscar.Text.Length > 0) { listaFiltrada2 = listaFiltrada2.FindAll(x => x.descripcion.ToUpper().Contains(txtBuscar.Text.ToUpper())); } dgvGrillaGasto.DataSource = listaFiltrada2;
– user9779039
Nov 21 '18 at 17:56
Oh thanks! But.. is the "ID" Attribute hidden or something after that?
– user9779039
Nov 17 '18 at 6:39
Oh thanks! But.. is the "ID" Attribute hidden or something after that?
– user9779039
Nov 17 '18 at 6:39
@juanzitelli To combine two properties, try
return ID.ToString() + ' ' + descripción;– LarsTech
Nov 18 '18 at 21:09
@juanzitelli To combine two properties, try
return ID.ToString() + ' ' + descripción;– LarsTech
Nov 18 '18 at 21:09
That sounds great, but what I actually meant was: How can I show "TipoGasto" 's ID Property as another column in the datagridview just as with "descripción"
– user9779039
Nov 21 '18 at 5:00
That sounds great, but what I actually meant was: How can I show "TipoGasto" 's ID Property as another column in the datagridview just as with "descripción"
– user9779039
Nov 21 '18 at 5:00
@juanzitelli Depends. How are you filling the DataGridView? Using the DataSource? Or adding rows manually?
– LarsTech
Nov 21 '18 at 14:47
@juanzitelli Depends. How are you filling the DataGridView? Using the DataSource? Or adding rows manually?
– LarsTech
Nov 21 '18 at 14:47
Data Source!
dgvGrillaGasto.DataSource = null; dgvGrillaGasto.DataSource = CGasto.listaGasto; List<CGasto> listaFiltrada2 = new List<CGasto>(); if (txtBuscar.Text.Length > 0) { listaFiltrada2 = listaFiltrada2.FindAll(x => x.descripcion.ToUpper().Contains(txtBuscar.Text.ToUpper())); } dgvGrillaGasto.DataSource = listaFiltrada2;– user9779039
Nov 21 '18 at 17:56
Data Source!
dgvGrillaGasto.DataSource = null; dgvGrillaGasto.DataSource = CGasto.listaGasto; List<CGasto> listaFiltrada2 = new List<CGasto>(); if (txtBuscar.Text.Length > 0) { listaFiltrada2 = listaFiltrada2.FindAll(x => x.descripcion.ToUpper().Contains(txtBuscar.Text.ToUpper())); } dgvGrillaGasto.DataSource = listaFiltrada2;– user9779039
Nov 21 '18 at 17:56
|
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