Uncaught TypeError in call to jQuery plugin
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0
I am creating a plugin using jQuery to page a table. Initially, my code looks like this:
(function($) {
$.paginate = function(options) {
var settings = $.extend({}, $.fn.paginate.defaults, options);
};
$.paginate.defaults = {
pageSize: 10,
nextText: 'Next',
prevText: 'Prev',
firstText: '<<'
lastText: '>>'
}
})(jQuery);
And the call to the plugin like this:
<script type="text/javascript">
$(document).ready(function(){
$(".table").paginate({
pageSize: 10
});
});
</script>
However, the paginate function is not being found by jQuery. Can you tell me where I'm going wrong?
javascript jquery jquery-plugins
asked Nov 16 '18 at 18:41
Claudivan MoreiraClaudivan Moreira
563
add a comment |
0
I am creating a plugin using jQuery to page a table. Initially, my code looks like this:
(function($) {
$.paginate = function(options) {
var settings = $.extend({}, $.fn.paginate.defaults, options);
};
$.paginate.defaults = {
pageSize: 10,
nextText: 'Next',
prevText: 'Prev',
firstText: '<<'
lastText: '>>'
}
})(jQuery);
And the call to the plugin like this:
<script type="text/javascript">
$(document).ready(function(){
$(".table").paginate({
pageSize: 10
});
});
</script>
However, the paginate function is not being found by jQuery. Can you tell me where I'm going wrong?
javascript jquery jquery-plugins
asked Nov 16 '18 at 18:41
Claudivan MoreiraClaudivan Moreira
563
add a comment |
0
0
0
I am creating a plugin using jQuery to page a table. Initially, my code looks like this:
(function($) {
$.paginate = function(options) {
var settings = $.extend({}, $.fn.paginate.defaults, options);
};
$.paginate.defaults = {
pageSize: 10,
nextText: 'Next',
prevText: 'Prev',
firstText: '<<'
lastText: '>>'
}
})(jQuery);
And the call to the plugin like this:
<script type="text/javascript">
$(document).ready(function(){
$(".table").paginate({
pageSize: 10
});
});
</script>
However, the paginate function is not being found by jQuery. Can you tell me where I'm going wrong?
javascript jquery jquery-plugins
asked Nov 16 '18 at 18:41
Claudivan MoreiraClaudivan Moreira
563
I am creating a plugin using jQuery to page a table. Initially, my code looks like this:
(function($) {
$.paginate = function(options) {
var settings = $.extend({}, $.fn.paginate.defaults, options);
};
$.paginate.defaults = {
pageSize: 10,
nextText: 'Next',
prevText: 'Prev',
firstText: '<<'
lastText: '>>'
}
})(jQuery);
And the call to the plugin like this:
<script type="text/javascript">
$(document).ready(function(){
$(".table").paginate({
pageSize: 10
});
});
</script>
However, the paginate function is not being found by jQuery. Can you tell me where I'm going wrong?
javascript jquery jquery-plugins
javascript jquery jquery-plugins
asked Nov 16 '18 at 18:41
Claudivan MoreiraClaudivan Moreira
563
asked Nov 16 '18 at 18:41
Claudivan MoreiraClaudivan Moreira
563
asked Nov 16 '18 at 18:41
Claudivan MoreiraClaudivan Moreira
563
asked Nov 16 '18 at 18:41
Claudivan MoreiraClaudivan Moreira
563
asked Nov 16 '18 at 18:41
Claudivan MoreiraClaudivan Moreira
563
563
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
2
You are messing up with use of $.fn
The plugin method needs to be assigned to $.fn in order to use $(selector).myPlugin()
$.fn.paginate = function(options) {...
Then you have a mismatch between
$.paginate.defaults
And
$.extend({}, $.fn.paginate.defaults
// ^^ fn here but not above
answered Nov 16 '18 at 18:44
charlietflcharlietfl
142k1391126
Same problem this way. I tried to change the form of the call, but it did not work, too:$(function() { $('tabela').paginate({ pageSize: 4 }); });
– Claudivan Moreira
Nov 16 '18 at 19:02
Any errors in console? note that'tabela'is invalid selector. There are lots of resources on web about how to create plugins and even tools to generate base plugin code
– charlietfl
Nov 16 '18 at 19:05
That's it. I modified the selector and added a "," after thefirstTextfield and it worked. Strange that the browser did not show syntax error previously. After these adjustments, it worked. Thank you.
– Claudivan Moreira
Nov 16 '18 at 19:11
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
2
You are messing up with use of $.fn
The plugin method needs to be assigned to $.fn in order to use $(selector).myPlugin()
$.fn.paginate = function(options) {...
Then you have a mismatch between
$.paginate.defaults
And
$.extend({}, $.fn.paginate.defaults
// ^^ fn here but not above
answered Nov 16 '18 at 18:44
charlietflcharlietfl
142k1391126
Same problem this way. I tried to change the form of the call, but it did not work, too:$(function() { $('tabela').paginate({ pageSize: 4 }); });
– Claudivan Moreira
Nov 16 '18 at 19:02
Any errors in console? note that'tabela'is invalid selector. There are lots of resources on web about how to create plugins and even tools to generate base plugin code
– charlietfl
Nov 16 '18 at 19:05
That's it. I modified the selector and added a "," after thefirstTextfield and it worked. Strange that the browser did not show syntax error previously. After these adjustments, it worked. Thank you.
– Claudivan Moreira
Nov 16 '18 at 19:11
add a comment |
2
You are messing up with use of $.fn
The plugin method needs to be assigned to $.fn in order to use $(selector).myPlugin()
$.fn.paginate = function(options) {...
Then you have a mismatch between
$.paginate.defaults
And
$.extend({}, $.fn.paginate.defaults
// ^^ fn here but not above
answered Nov 16 '18 at 18:44
charlietflcharlietfl
142k1391126
Same problem this way. I tried to change the form of the call, but it did not work, too:$(function() { $('tabela').paginate({ pageSize: 4 }); });
– Claudivan Moreira
Nov 16 '18 at 19:02
Any errors in console? note that'tabela'is invalid selector. There are lots of resources on web about how to create plugins and even tools to generate base plugin code
– charlietfl
Nov 16 '18 at 19:05
That's it. I modified the selector and added a "," after thefirstTextfield and it worked. Strange that the browser did not show syntax error previously. After these adjustments, it worked. Thank you.
– Claudivan Moreira
Nov 16 '18 at 19:11
add a comment |
2
2
2
You are messing up with use of $.fn
The plugin method needs to be assigned to $.fn in order to use $(selector).myPlugin()
$.fn.paginate = function(options) {...
Then you have a mismatch between
$.paginate.defaults
And
$.extend({}, $.fn.paginate.defaults
// ^^ fn here but not above
answered Nov 16 '18 at 18:44
charlietflcharlietfl
142k1391126
You are messing up with use of $.fn
The plugin method needs to be assigned to $.fn in order to use $(selector).myPlugin()
$.fn.paginate = function(options) {...
Then you have a mismatch between
$.paginate.defaults
And
$.extend({}, $.fn.paginate.defaults
// ^^ fn here but not above
answered Nov 16 '18 at 18:44
charlietflcharlietfl
142k1391126
edited Nov 16 '18 at 18:52
answered Nov 16 '18 at 18:44
charlietflcharlietfl
142k1391126
answered Nov 16 '18 at 18:44
charlietflcharlietfl
142k1391126
answered Nov 16 '18 at 18:44
charlietflcharlietfl
142k1391126
142k1391126
Same problem this way. I tried to change the form of the call, but it did not work, too:$(function() { $('tabela').paginate({ pageSize: 4 }); });
– Claudivan Moreira
Nov 16 '18 at 19:02
Any errors in console? note that'tabela'is invalid selector. There are lots of resources on web about how to create plugins and even tools to generate base plugin code
– charlietfl
Nov 16 '18 at 19:05
That's it. I modified the selector and added a "," after thefirstTextfield and it worked. Strange that the browser did not show syntax error previously. After these adjustments, it worked. Thank you.
– Claudivan Moreira
Nov 16 '18 at 19:11
add a comment |
Same problem this way. I tried to change the form of the call, but it did not work, too:$(function() { $('tabela').paginate({ pageSize: 4 }); });
– Claudivan Moreira
Nov 16 '18 at 19:02
Any errors in console? note that'tabela'is invalid selector. There are lots of resources on web about how to create plugins and even tools to generate base plugin code
– charlietfl
Nov 16 '18 at 19:05
That's it. I modified the selector and added a "," after thefirstTextfield and it worked. Strange that the browser did not show syntax error previously. After these adjustments, it worked. Thank you.
– Claudivan Moreira
Nov 16 '18 at 19:11
Same problem this way. I tried to change the form of the call, but it did not work, too:
$(function() { $('tabela').paginate({ pageSize: 4 }); });– Claudivan Moreira
Nov 16 '18 at 19:02
Same problem this way. I tried to change the form of the call, but it did not work, too:
$(function() { $('tabela').paginate({ pageSize: 4 }); });– Claudivan Moreira
Nov 16 '18 at 19:02
Any errors in console? note that
'tabela' is invalid selector. There are lots of resources on web about how to create plugins and even tools to generate base plugin code– charlietfl
Nov 16 '18 at 19:05
Any errors in console? note that
'tabela' is invalid selector. There are lots of resources on web about how to create plugins and even tools to generate base plugin code– charlietfl
Nov 16 '18 at 19:05
That's it. I modified the selector and added a "," after the
firstText field and it worked. Strange that the browser did not show syntax error previously. After these adjustments, it worked. Thank you.– Claudivan Moreira
Nov 16 '18 at 19:11
That's it. I modified the selector and added a "," after the
firstText field and it worked. Strange that the browser did not show syntax error previously. After these adjustments, it worked. Thank you.– Claudivan Moreira
Nov 16 '18 at 19:11
add a comment |
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