Parse HTML tags into dict
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ height:90px;width:728px;box-sizing:border-box;
}
0
I have html data that is almost being parsed using BeautifulSoup, but running into issue how to get the start and end time as they are right next to each other.
Here is the data:
[u'Start', u'End', u'2018-11-14 05:00 GMT (Greenwich Mean Time)', u'2018-11-14 11:00 GMT (Greenwich Mean Time)', u'2018-11-14 00:00 EST (Eastern Standard Time)', u'2018-11-14 06:00 EST (Eastern Standard Time)', u'Customer Name', u'Circuit ID', u'Alt Circuit ID', u'Bandwidth', u'A Location', u'Z Location', u'Impact Type', u'Maximum Duration', u'Order Number', u'Status', u'COMPANY, LLC', u'BDKN1111', u'N/A', u'10GIG-E LAN', u'CT USA', u'KINGS MOUNTAIN', u'Outage', u'1 hour ', u'xa0', u'Alternate Night', u'COMPANY, LLC', u'BDKN1112', u'N/A', u'10GIG-E LAN', u'BRISTOL', u'KINGS MOUNTAIN', u'Outage', u'1 hour ', u'xa0', u'Alternate Night', u'COMPANY, LLC', u'BDKF1011', u'N/A', u'10GIG-E LAN', u'BRISTOL', u'OMAHA ', u'Outage', u'1 hour ', u'xa0', u'Alternate Night']
Here is the code: Data is above list.
for i in data:
pattern = re.compile(r'([1-9]{4}|[0-9]{4})-([0-9]{2})-([0-9]{2}) ([0-9]{2}:[0-9]{2} GMT)')
if re.search(pattern, i):
match = re.search(pattern, i)
match = match.group().split()
output["startdate"] = match[0]
if match[1] not in output["endtime"]:
output["endtime"] = match[1:-1]
Trying to capture start data and time, and end data and time. Some reason it is overwriting previous value.
python html list parsing
asked Nov 16 '18 at 18:47
miumiu
164
add a comment |
0
I have html data that is almost being parsed using BeautifulSoup, but running into issue how to get the start and end time as they are right next to each other.
Here is the data:
[u'Start', u'End', u'2018-11-14 05:00 GMT (Greenwich Mean Time)', u'2018-11-14 11:00 GMT (Greenwich Mean Time)', u'2018-11-14 00:00 EST (Eastern Standard Time)', u'2018-11-14 06:00 EST (Eastern Standard Time)', u'Customer Name', u'Circuit ID', u'Alt Circuit ID', u'Bandwidth', u'A Location', u'Z Location', u'Impact Type', u'Maximum Duration', u'Order Number', u'Status', u'COMPANY, LLC', u'BDKN1111', u'N/A', u'10GIG-E LAN', u'CT USA', u'KINGS MOUNTAIN', u'Outage', u'1 hour ', u'xa0', u'Alternate Night', u'COMPANY, LLC', u'BDKN1112', u'N/A', u'10GIG-E LAN', u'BRISTOL', u'KINGS MOUNTAIN', u'Outage', u'1 hour ', u'xa0', u'Alternate Night', u'COMPANY, LLC', u'BDKF1011', u'N/A', u'10GIG-E LAN', u'BRISTOL', u'OMAHA ', u'Outage', u'1 hour ', u'xa0', u'Alternate Night']
Here is the code: Data is above list.
for i in data:
pattern = re.compile(r'([1-9]{4}|[0-9]{4})-([0-9]{2})-([0-9]{2}) ([0-9]{2}:[0-9]{2} GMT)')
if re.search(pattern, i):
match = re.search(pattern, i)
match = match.group().split()
output["startdate"] = match[0]
if match[1] not in output["endtime"]:
output["endtime"] = match[1:-1]
Trying to capture start data and time, and end data and time. Some reason it is overwriting previous value.
python html list parsing
asked Nov 16 '18 at 18:47
miumiu
164
add a comment |
0
0
0
I have html data that is almost being parsed using BeautifulSoup, but running into issue how to get the start and end time as they are right next to each other.
Here is the data:
[u'Start', u'End', u'2018-11-14 05:00 GMT (Greenwich Mean Time)', u'2018-11-14 11:00 GMT (Greenwich Mean Time)', u'2018-11-14 00:00 EST (Eastern Standard Time)', u'2018-11-14 06:00 EST (Eastern Standard Time)', u'Customer Name', u'Circuit ID', u'Alt Circuit ID', u'Bandwidth', u'A Location', u'Z Location', u'Impact Type', u'Maximum Duration', u'Order Number', u'Status', u'COMPANY, LLC', u'BDKN1111', u'N/A', u'10GIG-E LAN', u'CT USA', u'KINGS MOUNTAIN', u'Outage', u'1 hour ', u'xa0', u'Alternate Night', u'COMPANY, LLC', u'BDKN1112', u'N/A', u'10GIG-E LAN', u'BRISTOL', u'KINGS MOUNTAIN', u'Outage', u'1 hour ', u'xa0', u'Alternate Night', u'COMPANY, LLC', u'BDKF1011', u'N/A', u'10GIG-E LAN', u'BRISTOL', u'OMAHA ', u'Outage', u'1 hour ', u'xa0', u'Alternate Night']
Here is the code: Data is above list.
for i in data:
pattern = re.compile(r'([1-9]{4}|[0-9]{4})-([0-9]{2})-([0-9]{2}) ([0-9]{2}:[0-9]{2} GMT)')
if re.search(pattern, i):
match = re.search(pattern, i)
match = match.group().split()
output["startdate"] = match[0]
if match[1] not in output["endtime"]:
output["endtime"] = match[1:-1]
Trying to capture start data and time, and end data and time. Some reason it is overwriting previous value.
python html list parsing
asked Nov 16 '18 at 18:47
miumiu
164
I have html data that is almost being parsed using BeautifulSoup, but running into issue how to get the start and end time as they are right next to each other.
Here is the data:
[u'Start', u'End', u'2018-11-14 05:00 GMT (Greenwich Mean Time)', u'2018-11-14 11:00 GMT (Greenwich Mean Time)', u'2018-11-14 00:00 EST (Eastern Standard Time)', u'2018-11-14 06:00 EST (Eastern Standard Time)', u'Customer Name', u'Circuit ID', u'Alt Circuit ID', u'Bandwidth', u'A Location', u'Z Location', u'Impact Type', u'Maximum Duration', u'Order Number', u'Status', u'COMPANY, LLC', u'BDKN1111', u'N/A', u'10GIG-E LAN', u'CT USA', u'KINGS MOUNTAIN', u'Outage', u'1 hour ', u'xa0', u'Alternate Night', u'COMPANY, LLC', u'BDKN1112', u'N/A', u'10GIG-E LAN', u'BRISTOL', u'KINGS MOUNTAIN', u'Outage', u'1 hour ', u'xa0', u'Alternate Night', u'COMPANY, LLC', u'BDKF1011', u'N/A', u'10GIG-E LAN', u'BRISTOL', u'OMAHA ', u'Outage', u'1 hour ', u'xa0', u'Alternate Night']
Here is the code: Data is above list.
for i in data:
pattern = re.compile(r'([1-9]{4}|[0-9]{4})-([0-9]{2})-([0-9]{2}) ([0-9]{2}:[0-9]{2} GMT)')
if re.search(pattern, i):
match = re.search(pattern, i)
match = match.group().split()
output["startdate"] = match[0]
if match[1] not in output["endtime"]:
output["endtime"] = match[1:-1]
Trying to capture start data and time, and end data and time. Some reason it is overwriting previous value.
python html list parsing
python html list parsing
asked Nov 16 '18 at 18:47
miumiu
164
asked Nov 16 '18 at 18:47
miumiu
164
asked Nov 16 '18 at 18:47
miumiu
164
asked Nov 16 '18 at 18:47
miumiu
164
asked Nov 16 '18 at 18:47
miumiu
164
164
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
0
I was able to figured it out. Thanks
answered Nov 16 '18 at 19:52
miumiu
164
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
I was able to figured it out. Thanks
answered Nov 16 '18 at 19:52
miumiu
164
add a comment |
0
I was able to figured it out. Thanks
answered Nov 16 '18 at 19:52
miumiu
164
add a comment |
0
0
0
I was able to figured it out. Thanks
answered Nov 16 '18 at 19:52
miumiu
164
I was able to figured it out. Thanks
answered Nov 16 '18 at 19:52
miumiu
164
answered Nov 16 '18 at 19:52
miumiu
164
answered Nov 16 '18 at 19:52
miumiu
164
answered Nov 16 '18 at 19:52
miumiu
164
164
add a comment |
add a comment |
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